1(3√2)2=2n this might be hard to do but I need help asap!! ty

Answer:

51.525cm

Step-by-step explanation:

There were four (4) "F"s. Therefore, the correct answer is option D: "4".

The total number of residents who gave a grade to the new dining plan is 234 + 148 + 87 + 9 = 478, which is less than the total number of residents in the residence hall (482). This means that 482 - 478 = 4 residents did not give a grade to the new dining plan.

Therefore, the number of residents who gave a grade of F to the new dining plan is 482 - (234 + 148 + 87 + 9) - 4 = 4.

Therefore, the answer is D: 4, meaning that there were 4 "Fs".

You can learn more about finding unknown quantity at

https://brainly.com/question/24180788

#SPJ4

Answer:

a) 0.222

b) 0.643

c) 0.811

Step-by-step explanation:

Answer:

24 miles

Step-by-step explanation:

(8/10)30=24

(8x30)/10

240/10

24

Answer:

24

Step-by-step explanation:

8/10 = 4/5

(4/5) times 30

= 4 times 6

= 24

Answer:

$680 was invested at 6%, and $820 was invested at 8%.

Step-by-step explanation:

Let's first let x be the amount she invested in the account with 8% interest, and y be the amount invested in the account with 6% interest.

We are given that the total amount invested was 1500, thus:

x + y = 1500

At the end of the year, she earned 106.40 in interest. Interest is taken by multiplying the amount invested and the rate. Time also plays a factor, but since she only invested for one year, and it isn't specified whether simple or compound interest is used, we can just use the interest rate and the amount.

Interest earned at 8% = 0.08x

Interest earned at 6% = 0.06y

Now, from the given: 0.08x + 0.06y = 106.40.

We can multiply this equation by 100 to remove the decimal part:

8x + 6y = 10640

We can substitute, from the earlier x + y = 1500, x = 1500-y:

8(1500 - y) + 6y = 10640

Solving for y,

12000 - 8y + 6y = 10640

-2y = -1360

y = $680

Then since x = 1500-y, x = $820.

To check,

680 + 820 = 1500, correct

820*0.08 + 680*0.06 = 65.6 + 40.8 = 106.4, correct.

Thus, $680 was invested at 6%, and $820 was invested at 8%.

Answer:

D.

Explanation:

Given:

Let's go ahead and simplify each of the functions as seen below;

Let's go ahead and multiply f(x) and g(x);

Answer:

Graph is image, and equation is from the work result below:

Step-by-step explanation:

Take two points find the slope and y-intercept:

Slope = -2

Y-intercept = (0,16)

Equation =

y  =  − 2 x  +  16

check work for one point (to make sure equation works):

(2,12)

y = -2x + 16

12 = -2(2) + 16

12 = -4 + 16

12 = 12

The equation is correct: y  =  − 2 x  +  16

Image below are the points given:

The volume of a cone will be 209.41 yard³.

What is volume of cone?

The area or volume that a cone takes up is referred to as its volume. Cones are measured by their volume in cubic units such as cm3, m3, in3, etc. By rotating a triangle at any of its vertices, a cone can be created. A cone is a robust, spherical, three-dimensional geometric figure.. Its surface area is curved. The perpendicular height is measured from base to vertex. Right circular cones and oblique cones are two different types of cones. While the vertex of an oblique cone is not vertically above the center of the base, it is in the right circular cone where it is vertically above the base.

So the

V = (1/3)πr²h.

Given, data r = 5yards

h = 8 yards

Volume = 1/3 * π * r ²* h

= 1/3 * 3.141*25*8

=209.41 yard³

Hence, the volume of a cone will be 209.41 yard³.

Learn more about volume of cone, by the following link

https://brainly.com/question/1082469

#SPJ1

Answer:

V≈340.34

Step-by-step explanation:

V=πr2h

3=π·52·13

3≈340.3392

Answer:

BODMAS RULE

(c-3)²=100

c²-6c+9=100

c²-6c=100-9

c²-6c=91

c²-6c-91=0

then factories

The answer would be (C) 20.

Answer:

The 2nd quartile, also known as the median, is the middle value of a dataset, or the value that separates the lower half of the data from the upper half. In a box-and-whisker plot, the 2nd quartile is represented by the line in the middle of the box.

In the given box-and-whisker plot, the 2nd quartile is 12.5, which is the middle value of the data set. This can be determined by looking at the scale on the x-axis and finding the value that is in the middle of the box.

Option B, 12.5, is the correct answer.

Step-by-step explanation:

Answer:

3.6 × 10^9

Step-by-step explanation:

When multipliying two numbers in scientific notation, the exponents in the factor of 10 will be added when the two expressions are multiplied.

Thus (1.2 ⋅ 10^28) ⋅ (3 ⋅ 10^−19) = ( 1.2 × 3 )

( 10^28 × 10^-19 ) = 3.6 × 10^(28-19) = 3.6 × 10^9

Answer:

D

Step-by-step explanation:

It would most likely have to be above 83 to bring the average down, so A and B are out. It would most likely be D, since it would equally be 5 between 80.5 and 85.5 to get an even 83.

$300 to $400

Step-by-step explanation:

Answer:

the value of a - b is 4.

Step-by-step explanation:

We have been given the following two equations:

a + b = 10 ------------(1)

a² - b² = 40 -------(2)

We can factor the left-hand side of equation (2) using the difference of squares identity:

(a + b)(a - b) = 40

Substituting equation (1) into this equation, we get:

10(a - b) = 40

Dividing both sides by 10, we get:

a - b = 4

Therefore, the value of a - b is 4.

Step-by-step explanation:

if I understand this correctly :

a + b = 10

a² - b² = 40

(a² - b²) = (a + b)(a - b) = 40

10(a - b) = 40

(a - b) = 4

The probability of making a Type I error using the decision rule above is 0.00045 or 0.045%.

The hypothesis for this testing situation are given below:H0: μ = 10.13HA: μ > 10.13μ denotes the actual population mean amount of mercury in tuna per ounce.

Therefore, the company has set a limit of 12 micrograms of mercury per ounce of albacore tuna. If the sample mean amount of mercury in tuna exceeds this amount, the production line will be stopped to find the source of contamination.

To calculate the chance of making a Type I error using the decision rule above, we will use the mean for the normal distribution in the graphing calculator, which is 10.13. The standard deviation is 2.03 and the sample size is 10 cans of tuna. We need to find the z-value that corresponds to a sample mean of 12 or greater.

The formula for calculating the z-value is shown below z = (x - μ) / (σ / sqrt(n))where x is the sample mean, μ is the population mean, σ is the population standard deviation, and n is the sample size.

Using the given information, we can calculate the z-value as follows:z = (12 - 10.13) / (2.03 / sqrt(10))z = 3.32Therefore, the probability of making a Type I error using the decision rule above is the area to the right of the z-value of 3.32. To calculate this probability, we can use a standard normal distribution table or a graphing calculator.

Using a graphing calculator, we can find the probability by graphing a standard normal distribution with a mean of 0 and a standard deviation of 1 and shading the area to the right of the z-value of 3.32.

The graphing calculator gives the probability of 0.00045.

For more such questions on decision rule

https://brainly.com/question/15704148

#SPJ8

Answer:

16.7%.

Step-by-step explanation:

In this case, we know that although the marble is selected, it is replaced, that is, the total value of marbles never changes.

We know that in total there are 6 (3 + 2 + 1)

The probability of drawing a red is:

3/6

The probability of getting a yellow is:

2/6

Therefore the probability of drawing a red and a yellow is:

3/6 * 2/6 = 6/36 = 1/6 = 0.167

In other words, the probability of this happening would be 16.7%.

7) The  probability that the two numbers have an even sum is: 0.5

8) The probability that the two are even is: 0.25

7) We want to find the probability that the two numbers have an even sum.

The only combinations that produces an even sum are:

(1, 3), (3, 1), (1, 1), (2, 2), (2, 4), (4, 2), (4, 4), (3, 3)

The other combinations of numbers are:

(1, 2), (1, 4), (2, 1), (4, 1), (2, 3), (3, 2), (3, 4), (4, 3)

Thus, we have a total of 16 combinations and the  probability that the two numbers have an even sum is:

P(two numbers with even sum) = 8/16 = 0.5

8) The probability that the two are even is:

4/16 = 1/4

= 0.25

Read more about spinner probability at: https://brainly.com/question/3765462

#SPJ1

The simplified fraction is −|a+b|2−c= -3/5 when a=4 , b=−1 , and c=−3

A fraction  indicates a portion of a whole or, more broadly, any number of equal parts. In everyday English, a fraction defines how many pieces of a specific size there are, for example, one-half, eight-fifths, and three-quarters. A common, vulgar, or simple fraction consists of a numerator displayed above a line (or before a slash like 12) and a non-zero denominator displayed below (or after) that line. Numerators and denominators are also employed in uncommon fractions, such as compound fractions, complex fractions, and mixed numerals.

The numerator and denominator of positive common fractions are both natural integers. The denominator represents a number of equal parts, while the numerator represents a number of equal parts.

Given,

a=4

b=-1

c=-3

= -|a +b|/2-c

= -|4-1|/2-(-3)

= -|3|/2+3

- |3|/5

= -3/5

Therefore, −|a+b|2−c= -3/5

To know more about fraction, visit:

https://brainly.com/question/10354322

#SPJ1

(i) I would first suggest writing this function as a product of the functions,

\(\displaystyle y = fgh = (4+3x^2)^{1/2} (x^2+1)^{-1/3} \pi^x\)

then apply the product rule. Hopefully it's clear which function each of f, g, and h refer to.

We then have, using the power and chain rules,

\(\displaystyle \frac{df}{dx} = \frac12 (4+3x^2)^{-1/2} \cdot 6x = \frac{3x}{(4+3x^2)^{1/2}}\)

\(\displaystyle \frac{dg}{dx} = -\frac13 (x^2+1)^{-4/3} \cdot 2x = -\frac{2x}{3(x^2+1)^{4/3}}\)

For the third function, we first rewrite in terms of the logarithmic and the exponential functions,

\(h = \pi^x = e^{\ln(\pi^x)} = e^{\ln(\pi)x}\)

Then by the chain rule,

\(\displaystyle \frac{dh}{dx} = e^{\ln(\pi)x} \cdot \ln(\pi) = \ln(\pi) \pi^x\)

By the product rule, we have

\(\displaystyle \frac{dy}{dx} = \frac{df}{dx}gh + f\frac{dg}{dx}h + fg\frac{dh}{dx}\)

\(\displaystyle \frac{dy}{dx} = \frac{3x}{(4+3x^2)^{1/2}} (x^2+1)^{-1/3} \pi^x - (4+3x^2)^{1/2} \frac{2x}{3(x^2+1)^{4/3}} \pi^x + (4+3x^2)^{1/2} (x^2+1)^{-1/3} \ln(\pi) \pi^x\)

\(\displaystyle \frac{dy}{dx} = \frac{3x}{(4+3x^2)^{1/2}} \frac{1}{(x^2+1)^{1/3}} \pi^x - (4+3x^2)^{1/2} \frac{2x}{3(x^2+1)^{4/3}} \pi^x + (4+3x^2)^{1/2} \frac{1}{ (x^2+1)^{1/3}} \ln(\pi) \pi^x\)

\(\displaystyle \frac{dy}{dx} = \boxed{\frac{\pi^x}{(4+3x^2)^{1/2} (x^2+1)^{1/3}} \left( 3x - \frac{2x(4+3x^2)}{3(x^2+1)} + (4+3x^2)\ln(\pi)\right)}\)

You could simplify this further if you like.

In Mathematica, you can confirm this by running

D[(4+3x^2)^(1/2) (x^2+1)^(-1/3) Pi^x, x]

The immediate result likely won't match up with what we found earlier, so you could try getting a result that more closely resembles it by following up with Simplify or FullSimplify, as in

FullSimplify[%]

(% refers to the last output)

If it still doesn't match, you can try running

Reduce[<our result> == %, {}]

and if our answer is indeed correct, this will return True. (I don't have access to M at the moment, so I can't check for myself.)

(ii) Given

\(\displaystyle \frac{xy^3}{1+\sec(y)} = e^{xy}\)

differentiating both sides with respect to x by the quotient and chain rules, taking y = y(x), gives

\(\displaystyle \frac{(1+\sec(y))\left(y^3+3xy^2 \frac{dy}{dx}\right) - xy^3\sec(y)\tan(y) \frac{dy}{dx}}{(1+\sec(y))^2} = e^{xy} \left(y + x\frac{dy}{dx}\right)\)

\(\displaystyle \frac{y^3(1+\sec(y)) + 3xy^2(1+\sec(y)) \frac{dy}{dx} - xy^3\sec(y)\tan(y) \frac{dy}{dx}}{(1+\sec(y))^2} = ye^{xy} + xe^{xy}\frac{dy}{dx}\)

\(\displaystyle \frac{y^3}{1+\sec(y)} + \frac{3xy^2}{1+\sec(y)} \frac{dy}{dx} - \frac{xy^3\sec(y)\tan(y)}{(1+\sec(y))^2} \frac{dy}{dx} = ye^{xy} + xe^{xy}\frac{dy}{dx}\)

\(\displaystyle \left(\frac{3xy^2}{1+\sec(y)} - \frac{xy^3\sec(y)\tan(y)}{(1+\sec(y))^2} - xe^{xy}\right) \frac{dy}{dx}= ye^{xy} - \frac{y^3}{1+\sec(y)}\)

\(\displaystyle \frac{dy}{dx}= \frac{ye^{xy} - \frac{y^3}{1+\sec(y)}}{\frac{3xy^2}{1+\sec(y)} - \frac{xy^3\sec(y)\tan(y)}{(1+\sec(y))^2} - xe^{xy}}\)

which could be simplified further if you wish.

In M, off the top of my head I would suggest verifying this solution by

Solve[D[x*y[x]^3/(1 + Sec[y[x]]) == E^(x*y[x]), x], y'[x]]

but I'm not entirely sure that will work. If you're using version 12 or older (you can check by running $Version), you can use a ResourceFunction,

ResourceFunction["ImplicitD"][<our equation>, x]

but I'm not completely confident that I have the right syntax, so you might want to consult the documentation.

The tuxedo was rented for 4 days.

Let's start by assigning variables to the unknowns. Let "x" be the number of additional days rented, and "d" be the total number of days rented (including the first day).

From the given information, we know that the flat fee for the rental is $150, so the cost of the additional days is the total cost minus the flat fee, which is $300 - $150 = $150. We also know that the cost for each additional day is $50. Therefore, we can set up the equation:

$150 + $50x = $300

Subtracting $150 from both sides, we get:

$50x = $150

Dividing both sides by $50, we get:

x = 3

So the tuxedo was rented for 3 additional days, making the total number of days rented:

d = 1 + 3 = 4

To learn more about rented here:

https://brainly.com/question/16489690

#SPJ1

Answer:

Hello your question has some missing parts attached is the missing part

answer : slightly skewed to the right ( B )

Step-by-step explanation:

From the attached histogram related to the question above, it can be seen that the the right tail is longer than the left tail and this can help us draw the conclusion that the overall shape of the distribution is slightly skewed to the right

Answer:

Step-by-step explanation:

\(\frac{d}{dx} [cos(3x^2) \sqrt[3]{5x^3 -1} +sin(4x^3)]^4\\\\=4[cos(3x^2) \sqrt[3]{5x^3 -1} +sin(4x^3)]^3\; \frac{d}{dx} [cos(3x^2) \sqrt[3]{5x^3 -1} +sin(4x^3)] --- eq(1)\)

Lets look at the derivative part:

\(\frac{d}{dx} [cos(3x^2) \sqrt[3]{5x^3 -1} +sin(4x^3)] \\\\= \frac{d}{dx}[cos(3x^2) \sqrt[3]{5x^3 -1} ] + \frac{d}{dx}[sin(4x^3)]\\\\=cos(3x^2) \frac{d}{dx}[ \sqrt[3]{5x^3 -1} ] + \sqrt[3]{5x^3 -1}\frac{d}{dx}[ cos(3x^2) ] + cos(4x^3) \frac{d}{dx}[4x^3]\\\\=cos(3x^2) \frac{1}{3} (5x^3 -1)^{\frac{1}{3} -1} \frac{d}{dx}[5x^3 -1] + \sqrt[3]{5x^3 -1} (-sin(3x^2))\frac{d}{dx}[ 3x^2] + cos(4x^3)[(4)(3)x^2]\)

\(=\frac{cos(3x^2) 5(3)x^2}{3(5x^3 - 1)^{\frac{2}{3} }} -\sqrt[3]{5x^3 -1}\; sin(3x^2) (3)(2)x + 12x^2 cos(4x^3)\\\\=\frac{5x^2cos(3x^2) }{(5x^3 - 1)^{\frac{2}{3} }} -6x\sqrt[3]{5x^3 -1}\; sin(3x^2) + 12x^2 cos(4x^3)\)

Substituting in eq(1), we have:

\(\frac{d}{dx} [cos(3x^2) \sqrt[3]{5x^3 -1} +sin(4x^3)]^4\\\\=4[cos(3x^2) \sqrt[3]{5x^3 -1} +sin(4x^3)]^3\; [\frac{5x^2cos(3x^2) }{(5x^3 - 1)^{\frac{2}{3} }} -6x\sqrt[3]{5x^3 -1}\; sin(3x^2) + 12x^2 cos(4x^3)]\)

Answer:

B. \( \frac{-4x + 7}{2(x - 2)} \)

Step-by-step explanation:

Simplify the given expression to determine its equivalent expression in the given options.

\( \frac{\frac{3}{x - 1} - 4}{2 - \frac{2}{x - 1}} \)

\( \frac{\frac{3}{x - 1} - \frac{4}{1}}{\frac{2}{1} - \frac{2}{x - 1}} \)

\( \frac{\frac{3 - 4(x - 1)}{x - 1}}{\frac{2(x - 1) - 2}{x - 1}} \)

\( \frac{\frac{3 - 4x + 4}{x - 1}}{\frac{2x - 2 - 2}{x - 1}} \)

\( \frac{\frac{-4x + 7}{x - 1}}{\frac{2x - 4}{x - 1}} \)

\( \frac{-4x + 7}{x - 1} * \frac{x - 1}{2x - 4} \)

(x - 1) cancels (x - 1)

\( \frac{-4x + 7}{1} * \frac{1}{2x - 4} \)

\( \frac{(-4x + 7)1}{1(2x - 4)} \)

\( \frac{-4x + 7}{2x - 4} \)

\( \frac{-4x + 7}{2(x - 2)} \)

Answer:

(Y-3)= -1/3(x-7)

Or

(Y-4)= -1/3(x-4)

Steb by step explanation:

The condition for the line is (7,3) and (4,4).

Point slope form of equation is in this format below.

(Y-y1)= m(x-x1)

We have the given parameters in the above format except the m

M = gradient

Gradient= (y2-y1)/(x2-x1)

Gradient=(4-3)/(4-7)

Gradient= 1/-3

Gradient= -1/3

So

(Y-y1)= m(x-x1)

(Y-3)= -1/3(x-7)

Or

(Y-4)= -1/3(x-4)

Answer:

6.92820323

Step-by-step explanation:

64÷-48= 6.92820323

Answer:

\(4i \sqrt{3} \)

hope this helps!