12. You start the day left with 3 assignments due tomorrow. Your work load seems to double every period!
That means you would have how many assignments due tomorrow by 1st period? 4th period? 8th period?
Write an equation for this scenario & answer all questions.

si comes 65 dulces de una caja de 120, te quedarán 120 - 65 = 55 dulces. la fracción será de 55/120, que se puede reducir así.

55/120 = 11/24

su respuesta es 11/24.

espero haber ayudado, buena suerte!

The size of the largest interior angle of the field is 69.86°

The law of cosines relates the lengths of the sides of a triangle to the cosine of one of its angles.

Given that, a triangular field has boundaries of lengths 170m, 195m and 210m, we need to find the size of the largest interior angle of the field,

We know that, angle opposite to the largest side is largest,

Therefore,

The largest angle is opposite is 210 m side, (say c)

Using the cosine rule,

210² = 170²+195²-2(170)(195)cosC

CosC = 170²+195²-210² / 2(170)(195)

CosC = 22825 / 66300

CosC = 0.344268477

C = 69.86°

Hence, the size of the largest interior angle of the field is 69.86°

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62.38% is the necessary discount. Basic discount calculations include multiplying the original price by the given percentage rate in decimal notation.

Suppose MP is 100. later Net SP

\($=(100-10) \%$\) of \($(100-24) \%$\) of \($(100-45) \%$\) of \(100 $=90 \%$\) of \($76\%$\) of \($55\%$\) of 100

\($$=\left(\frac{90}{100} \times \frac{76}{100} \times \frac{55}{100} \times 100\right)=37.62$$\)

Required discount \(=(100-68.40) \%=31.6 \%$\)\(=(100-37.62) \%=62.38 \%$\)

The simplest method for figuring out a discount is to multiply the original cost by the percentage rate in decimal notation. Any item's selling price is determined by deducting the discount from the purchase price.

An enormous, red percentage symbol with a black outline. If you multiply two percentages that are fractions of 100 or decimals, you can find the percentage of another percentage. Calculating, for instance, 50% of 40% results in (50/100) x (40/100) = 0.50 x 0.40 = 0.20 = 20/100 = 20%.

Therefore the correct answer is option D ) 62.38%

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The choice in the solution set of the equation 4x = 30 is x = 7.5

The equation is given as:

4x = 30

Divide both sides of the equation by 4

4x/4 = 30/4

Evaluate the quotients

x = 7.5

Hence, the choice in the solution set of the equation 4x = 30 is x = 7.5

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The exponential function obtained from the table is represented by the formula y is 650(1.045)x.

A function with the exponential shape is:

y = abˣ

where an is y's initial value, b are multipliers, and y and x are variables.

The bacterial population at x hours should be represented by y.

With 650 bacteria cells at the beginning, the group.

a = 650

4.5% is the growth rate.

b = 100% + 4.5% = 104.5% = 1.045

The exponential function obtained from the table is represented by the formula y = 650(1.045)x.

The exponential function obtained from the table is represented by the formula y is 650(1.045)x.

Thirty hours later:

y = 650(1.045)³⁰ = 2434.

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Answer: 2

Step-by-step explanation:

See attached image

Answer:

k is equal to 42

Step-by-step explanation:

Answer:

\(Rate = 6.7726\)

Step-by-step explanation:

Given

\(f(x) = x^x\) at \(x =2\)

Required

The instantaneous rate of change

We have:

\(f(x) = x^x\)

The instantaneous rate of change is:

\(\lim_{h \to 0} \frac{f(a + h) -f(a)}{h}\)

\(x =2\) implies that: \(a = 2\)

So, we have:

\(a = 2\)      \(h = 0.01\)

\(\frac{f(a + h) -f(a)}{h} = \frac{f(2 + 0.01) -f(2)}{0.01} = \frac{f(2.01) -f(2)}{0.01} = \frac{2.01^{2.01} - 2^2}{0.01} = 6.840403\)

Keep reducing h but set a constant at 2

\(h = 0.001\)

\(\frac{f(a + h) -f(a)}{h} = \frac{f(2 + 0.001) -f(2)}{0.001} = \frac{f(2.001) -f(2)}{0.001} = \frac{2.001^{2.001} - 2^2}{0.001} = 6.779327\)

\(h = 0.0001\)

\(\frac{f(a + h) -f(a)}{h} = \frac{f(2 + 0.0001) -f(2)}{0.0001} = \frac{f(2.0001) -f(2)}{0.0001} = \frac{2.0001^{2.0001} - 2^2}{0.0001} = 6.773262\)

\(h = 0.00001\)

\(\frac{f(a + h) -f(a)}{h} = \frac{f(2 + 0.00001) -f(2)}{0.00001} = \frac{f(2.00001) -f(2)}{0.00001} = \frac{2.00001^{2.00001} - 2^2}{0.00001} = 6.772656\)

\(h = 0.000001\)

\(\frac{f(a + h) -f(a)}{h} = \frac{f(2 + 0.000001) -f(2)}{0.000001} = \frac{f(2.000001) -f(2)}{0.000001} = \frac{2.000001^{2.000001} - 2^2}{0.000001} = 6.772595\)

\(h = 0.0000001\)

\(\frac{f(a + h) -f(a)}{h} = \frac{f(2 + 0.0000001) -f(2)}{0.0000001} = \frac{f(2.0000001) -f(2)}{0.0000001} = \frac{2.0000001^{2.0000001} - 2^2}{0.0000001} = 6.772589\)

\(h = 0.00000001\)

\(\frac{f(a + h) -f(a)}{h} = \frac{f(2 + 0.00000001) -f(2)}{0.00000001} = \frac{f(2.00000001) -f(2)}{0.00000001} = \frac{2.00000001^{2.00000001} - 2^2}{0.00000001} = 6.772589\)

Notice that:

\(\frac{f(a + h) -f(a)}{h} = 6.772589\) for \(h = 0.00000001\) and \(h = 0.0000001\)

Hence, the instantaneous rate of change is:

\(Rate = 6.772589\)

\(Rate = 6.7726\) ---- approximated

Answer:Second Graph

Step-by-step explanation:

Did it on Edge

Answer:

second graph

Step-by-step explanation:

Answer:

Y = 1/4x + 0 or Y = 1/4x

Step-by-step explanation:

Teacher circles the 4 because the point was (1,4)

Slope is rise over run

You risen 1 unit on the y-axis, then you went over 4 units on the axis, making the slope 1/4x

Answer: 8 in²

Step-by-step explanation:

A diameter of a sweet potato pie is 8 inches

Hence a radius of a sweet potato pie is 8/2=4  inches

A=πr²

π=3.14159≈3    

r=4 inches

Hence,

A=3(4²)

A=3(4*4)

A=3(16)

A=48 in²

The area of each slice is:

48:6=

8 in²

Answer:

82 degrees

Step-by-step explanation:

It took 3 hours for it to go from 78 to 72.

Which is a rate of -2 degrees per hour

We want to know what the temperature was two hours before it was 78 degrees so we'd do 78 - (-2) which is 82

Answer:

\(y = {x}^{2} - 2\)

Or if you want with the value of h too.

\(y = {(x - 0)}^{2} - 2\)

Step-by-step explanation:

\(y = a {(x - h)}^{2} + k\)

Find the value of h and k by using the formula.

\(h = - \frac{b}{2a} \\ k = \frac{4ac - {b}^{2} }{4a} \)

From y = x²-2

\(a = 1 \\ b = 0 \\ c = - 2\)

Substitute these values in the formula.

\(h = - \frac{0}{2(1)} \\ h = 0\)

Therefore, h = 0.

\(k = \frac{4(1)( - 2) - {0}^{2} }{4(1)} \\ k = \frac{ - 8}{4} \\ k = - 2\)

Therefore, k = - 2.

From the vertex form, the vertex is at (h, k) = (0,-2). Substitute h = 0, a = 1 and k = -2 in the equation.

\(y = a {(x - h)}^{2} + k \\ y = 1 {(x - 0)}^{2} - 2 \\ y = {(x)}^{2} - 2 \\ y = {x}^{2} - 2\)

These type of equation where b = 0 can also be both standard and vertex form.

The linear function is given as follows:

\(y = \sqrt{x} + 4\)

The slope-intercept equation for a linear function is presented as follows:

y = mx + b

In which:

The y-intercept is of 4, hence the parameter b is given as follows:

b = 4.

The line is inclined to 60° with the positive direction of X-axis, hence the slope m is given as follows:

m = tan(60º)

\(m = \sqrt{3}\)

Thus the function is given as follows:

\(y = \sqrt{x} + 4\)

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Using the Green's Theorem, the one along which the work done by the force is 11π/16.

In the given question we have to find the one along which the work done by the force is the greatest.

The given closed curves in the plane is

\(F(x,y)=\left(\frac{x^{2}y}{4} + \frac{y^3}{3}\right)\hat{i}+x\hat{j}\)

Suppose C be a simple smooth closed curve in the plane. It is also oriented counterclockwise.

Let S be the interior of C.

Let P = \(\frac{x^{2}y}{4} + \frac{y^3}{3}\) and Q = x

So the partial differentiation is

\(\frac{\partial P}{\partial y}=\frac{x^2}{4}+y^2\) and  \(\frac{\partial Q}{\partial x}\) = 1

By the Green's Theorem, work done by F is given as

W= \(\oint \vec{F}d\vec{r}\)

W= \(\iint_{S}\left ( \frac{\partial Q}{\partial x}-\frac{\partial P}{\partial y} \right )dxdy\)

W= \(\iint_{S}\left ( 1-\frac{x^2}{y}-y^2 \right )dxdy\)

Let C = x^2+y^2 = 1 and

x = rcosθ, y = rsinθ

0≤r≤1; 0≤θ≤2π

There;

W = \(\int_{r=0}^{1}\int_{\theta=0}^{2\pi}\left ( 1-\frac{r^2\cos^2\theta}{4}-r^2\sin^2\theta \right )\left|\frac{\partial(x,y)}{\partial{r,\theta}}\right|d\theta dr\)

and \(\frac{\partial (x,y)}{\partial(r, \theta)}=\left|\begin{matrix}\cos\theta &-r\sin\theta \\ \sin\theta & r\cos\theta\end{matrix} \right |\) = r

Thus;

W = \(\int_{r=0}^{1}\int_{\theta=0}^{2\pi}\left ( 1-\frac{r^2\cos^2\theta}{4}-r^2\sin^2\theta \right )rd\theta dr\)

After solving

W = 11π/16

Hence, the one along which the work done by the force is 11π/16.

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The right question is:

Among all simple smooth closed curves in the plane, oriented counterclockwise, find the one along which the work done by the force:

\(F(x,y)=\left(\frac{x^{2}y}{4} + \frac{y^3}{3}\right)\hat{i}+x\hat{j}\)

is the greatest. (Hint: First, use Green’s theorem to obtain an area integral—you will get partial credit if you only manage to complete this step.)

Answer:

-2

Step-by-step explanation:

Answer:

y=9x (O 1)

Step-by-step explanation:

9 times the number of gifts he bought which lets say is x will equal your answer (y).

Step-by-step explanation:

hope you can understand

a) The dot product of v and -v is -1.

b) The dot product of v + w and v – w is 2v.w

c) The dot product of v – 2w and v + 2w is 4||w||^2 - 4v.w

(a) For any unit vector v, the dot product of v and -v can be found as follows:

v · -v = ||v||||-v||cos(θ) = ||v||||v||cos(180°) = -||v||^2 = -1, where ||v|| represents the magnitude of the vector v and θ is the angle between the vectors.

Since v and -v are unit vectors, their magnitudes are equal to 1, so ||v||^2 = 1. Thus, the dot product of v and -v is -1.

(b) For any unit vectors v and w, the dot product of v + w and v – w can be found as follows:

(v + w) · (v – w) = ||v + w||||v – w||cos(θ) = (||v||||v|| + 2v · w + ||w||||w||)cos(θ) = 2v · w

where θ is the angle between the vectors v + w and v – w, and v · w is the dot product of v and w.

(c) For any unit vectors v and w, the dot product of v – 2w and v + 2w can be found as follows:

(v – 2w) · (v + 2w) = ||v – 2w||||v + 2w||cos(θ) = (||v||||v|| + 4||w||||w|| - 4v · w)cos(θ) = 4||w||^2 - 4v · w

where θ is the angle between the vectors v – 2w and v + 2w, and v · w is the dot product of v and w.

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Answer:

17.02

Step-by-step explanation:

Calculation for What is the variance of the stock's returns

First step is to calculate the E(R) Expected return

E(R) = .29(−0.115) + .32(0.02) + .39(0.252)

E(R) = .0713*100

E(R)=7.13%

Now let calculate the variance

σ2 = .29(−0.115 −0.0713.)^2 + 32(0.02−0.0713 )^2 + .39(0.252 −0.0713 )^2

σ2 = .1702*100

σ2=17.02%

Therefore the variance of the stock's returns will be 17.02%

Answer:

this is your answer

Step-by-step explanation:

please mark as brainlist

Answer:

From prove

Step-by-step explanation:

from prove

Explanation

Two angles are called complementary when their measures add to 90 degrees

By using a statistical calculator, the actual sample mean and sample standard deviation are:

Actual sample mean = 46.1500.

Actual ample standard deviation = 8.6256.

In Mathematics and Geometry, the sample mean for any set of data can be calculated by using the following formula:

Mean = ∑x/(n - 1)

In Mathematics and Geometry, the sample standard deviation for any set of data can be calculated by using the following formula:

Standard deviation, δx = √(1/N × ∑(x - \(\bar{x}\))²)

By using a statistical calculator, the actual sample mean and sample standard deviation are as follows;

Actual sample mean = 46.1500.

Actual ample standard deviation = 8.6256.

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

Answer:

43

Step-by-step explanation:

Green:  9 - 2(-3) = 9 + 6 = 15

Red:  -2(-3) + 4 = 6 + 4 = 10

Dark blue:  7x + 5 = 19

7x = 19 - 5 = 14

x = 14/7 = 2

Light blue:  6x + 3 = 21

6x = 21 - 3 = 18

x = 18/6 = 3

Red(Lt blue) - Dk blue + Green = 10(3) - 2 + 15 = 43

Answer:

The choose A.

y= – | x+1|–4

I hope I helped you^_^

The meaning of ran R = { v : there exist u, (u, v) ∈ R} is,

⇒ Defined as v, there exist u such that an order pair (u, v) is belon in relation R

We have to given that;

The meaning of,

⇒ ran R = { v : there exist u, (u, v) ∈ R}

Since, WE know that;

''ran R'' is stand for range of relation R.

Which is defined as,

⇒ ran R = { v : there exist u, (u, v) ∈ R}

That's mean,

Let us defined as v, there exist u such that an order pair (u, v) is belon in relation R.

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Answer:

no u may nit know this answet