Answer:B
Explanation:Because I got a similar question and it was B
The salt shaker stopped moving because the table exerts a force that is opposite to the salt shaker's motion.
What is force?Force is defined as a cause which is capable of changing the motion of an object. It can cause an object which has mass to change it's velocity. It is also simply a push or a pull . It has both magnitude as well as direction.Hence, it is a vector quantity.
It has SI units of Newton and is represented by'F'.Newton's second law states that force which acts on an object is equal to momentum which changes with time. If mass of object is constant, acceleration is directly proportional to net force acting on an object.
The concepts which related to force are thrust and torque .Thrust increases the velocity of an object and torque produces change in rotational speed of an object.
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A boat driver travelling west at 5km/hr finds that the wind appears to blow from the south. On doubling it's speed, the wind appears to blow from the southwest. Find the magnitude and direction of the winds velocity
The wind velocity can be determined by analyzing the boat's motion and the apparent wind direction.
1. The boat is traveling west at a speed of 5 km/hr.
2. The apparent wind direction is from the south.
3. When the boat's speed is doubled, the apparent wind direction is from the southwest.
To find the magnitude and direction of the wind's velocity, we can consider the boat's velocity as well as the apparent wind direction in both scenarios.
Let's denote the magnitude of the wind's velocity as "v" and the direction as "θ."
1. When the boat is traveling at 5 km/hr:
- The boat's velocity is 5 km/hr to the west.
- The apparent wind direction is from the south.
- Therefore, the wind's velocity can be represented as the vector sum of the boat's velocity and the apparent wind direction. This vector sum forms a right angle triangle.
- Using trigonometry, we can find the magnitude and direction of the wind's velocity in this scenario.
2. When the boat's speed is doubled to 10 km/hr:
- The boat's velocity is 10 km/hr to the west.
- The apparent wind direction is from the southwest.
- Again, the wind's velocity can be represented as the vector sum of the boat's velocity and the apparent wind direction, forming a right angle triangle.
- By using trigonometry, we can determine the magnitude and direction of the wind's velocity in this case.
By comparing the two scenarios, we can find the change in the wind's velocity magnitude and direction when the boat's speed is doubled. This information will help us determine the actual magnitude and direction of the wind's velocity.
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What is the correct answer! Thank you for your help
Why do some organisms never turn into fossils?
A. They are far too large to be buried in the ground.
B. They are made mostly of soft tissues.
C. They contain too much protein to be preserved.
D. They contain chemicals that prevent the hardening of their bodies.
Answer:
The answer is B.
Explanation:
Since they are made up of soft tissues, they decompose become they become fossils.
Bus with a weight of 650 N is sitting on the ground and the bottom of the box measures 0.5 m by 0.7 m. What is the pressure exerted by the box on the ground?
Answer:
185.71 N
Explanation:
Weight = 650N
Dimensions of box = 0.5m by 0.7m
Pressure = ?
The relationship between these quantities is given by;
Pressure = Weight / Area
Area = 0.7 * 0.5 = 3.5 m^2
Pressure = 650 / 3.5 = 185.71 N
HELP I GIVE BRAINLIST
which of the following is a abiotic factor ?
A ) pH level of water
B ) Coral Reef
C ) fish
D ) seaweed
Answer:
it's A
Explanation:
it's A because the ph level of water is just the level of the water if it's acidic or just a base
A wood burning stove is used to heat the air in a small cabin. What types of heat transfer are involved?.
A wood burning stove is used to heat the air in a small cabin. Conduction and radiation heat transfer are involved.
Conduction heat transfer is the switch of warmth with the aid of molecular excitement within a material without bulk motion of the problem. Conduction warmth transfer in gases and liquids is due to the collisions and diffusion of the molecules at some point of their random movement.
A common instance of conduction is the technique of heating a pan on a range. the heat from the burner transfers at once to the surface of the pan. Temperature is a degree of the quantity of kinetic energy processed with the aid of the debris in a sample of count.
Conduction is the transfer of energy from one molecule to another by direct contact. This transfer occurs when molecules hit against every different, just like a game of pool where one shifting ball strikes some other, causing the second to transport.
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how does Newton's third law of motion give a property of process
Answer:
Newton's third law explains the generation of thrust by a rocket engine. In a rocket engine, hot exhaust gas is produced through the combustion of a fuel with an oxidizer. The hot exhaust gas flows through the rocket nozzle and is accelerated to the rear of the rocket. In re-action, a thrusting force is produced on the engine mount.
Explanation:
pa brainliest po :D
A boat travels at 15 m/s in a direction 45° east of north for an hour. The boat then turns and travels at 18 m/s in a direction 5° north of east for an hour. What is the magnitude of the boat’s resultant velocity? Round your answer to the nearest whole number. m/s What is the direction of the boat’s resultant velocity? Round your answer to the nearest whole degree. ° north of east
The first blank is 31m/s
The second blank is 23°
The boat’s resultant velocity is v = 31.0 m/s, and the direction of the boat’s resultant velocity is 23.2 degrees north of east.
What is the distance?Distance is a numerical representation of the distance between two items or locations. Distance refers to a physical length or an approximation based on other physics or common usage considerations.
We'll use east as the positive x-direction and north as the positive y-direction. Then, both velocities must be resolved into their corresponding components:
v(x1) = 15 sin45 = 10.6 m/s
v(y1) = 15 cos45 = 10.6 m/s
v(x2) = 18 cos5 = 17.9 m/s
v(y2) = 18 sin5 = 1.6 m/s
The components of the resultant velocity:
v(x) = v(x1) + v(x2) = 10.6 + 17.9 = 28.5 m/s
v(y) = v(y1) + v(y2) = 10.6 + 1.6 = 12.2 m/s
The magnitude of the velocity:
v = √((28.5)² + (12.2)²
v = 31.0 m/s
The direction:
Φ = tan⁻¹(12.2/28.5)
Φ = 23.2 degrees north of east.
Thus, the boat’s resultant velocity is v = 31.0 m/s, and the direction of the boat’s resultant velocity is 23.2 degrees north of east.
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c. s. lewis correctly understood that there are at least three important ways in which science and magic are similar. which is not one of the key similarities developed in west’s text
C.S. Lewis believed that science and magic are distinct and incompatible ways of knowing and interacting with the world
What is science and magic?C.S. Lewis believed that science and magic are distinct and incompatible ways of knowing and interacting with the world. Science is concerned with understanding the natural world through observation and experimentation, while magic is a form of supernatural power that operates outside the laws of nature.
Lewis also believed that science and magic have different ethical implications. Science is morally neutral, while the use of magic often has negative consequences and can lead to a desire for power and control.
In his fiction, such as the Chronicles of Narnia series, Lewis often used the contrast between science and magic to explore larger philosophical and spiritual themes.
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Dylan is set to receive a football kickoff. After being kicked, the ball goes up to a height of 55m before starting back down. How much time does he have before the ball comes back down?
Answer:
Explanation:
Answer:
There was no anwser
Explanation:
because dylan did not anwser
A 0.80-kg ball is thrown with a velocity of 13 m/s. The ball hit a 0.12-kg bowling pin. When the ball hits the pin, the pin goes flying forward at 6 m/s. What is the velocity of the ball after it hits the pin?
When the ball of mass 0.80kg hits a bowling pin of 0.12 kg, the velocity of the ball after it hits the pin = 12.1 m/s
The mass of the ball, \(m_1=0.80 kg\)
The initial speed of the ball, \(u_1=13 m/s\)
The mass of the bowling pin, \(m_2=0.12kg\)
The initial speed of the bowling pin, \(u_2=0m/s\)
The final speed of the bowling pin, \(v_2= 6m/s\)
The final speed of the ball after collision, \(v_1 = ?\)
According to the law of momentum conservation
\(m_1u_1+m_2u_2=m_1v_1+m_2v_2\\\\0.80(13)+0.12(0)=0.80v_1+0.12(6)\\\\10.4+0=0.8v_1+0.72\\\\0.8v_1=10.4-0.72\\\\0.8v_1=9.68\\\\v_1=\frac{9.68}{0.8} \\\\v_1=12.1m/s\)
The velocity of the ball after it hits the pin = 12.1 m/s
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In the speed-time graph for a moving object shown here, the part which
indicates uniform deceleration of the object is:
(a) QR
(b) ST
(c) RS
(d) PQ
Answer:
I think the answer is ST. Option B
55. What is the instantaneous speed of the point of the disk that makes contact with the surface?
A) zero m/s
B) 5.0 m/s
C) 7.1 m/s
D) 7.5 m/s
E) 10.0 m/s
The instantaneous speed of the point of the disk that makes contact with the surface is zero m/s (Option A).
To determine the instantaneous speed of the point of the disk that makes contact with the surface, we must consider the following terms:
Instantaneous speed: The speed of an object at a specific point in time.Point of contact: The point where the disk touches the surface.The answer to the question is A) zero m/s. The reason for this is that the point of contact between the disk and the surface is stationary for an instant, as it constantly changes due to the rotation of the disk. At that specific moment, the instantaneous speed of the point of contact is zero.
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rollercoaster part 2: you are again considering your rollercoaster design, but this time want to make it even more exciting. you decide instead of having passengers ride in traditional cars, they will go in hamster-ball like vehicles, that roll along the track (note: this is a bad idea). if the balls can be treated as hollow spheres, with mass of 100 kg and a radius of 0.5 m, how high can you make your loop? (see problem 7. you may equations from your solution to that problem as some of your equations for this problem)
The maximum height of the loop in the rollercoaster design with hamster-ball like vehicles is 2.45 meters.
To determine the maximum height of the loop in the rollercoaster design with hamster-ball like vehicles, we need to calculate the minimum speed required for the ball to stay in contact with the track at the top of the loop. This is because if the speed is less than this minimum value, the ball will lose contact with the track and the passengers will fall out.
The minimum speed required for the ball to stay in contact with the track at the top of the loop is given by the centripetal force equation:
F_c = mv^2/r
where F_c is the centripetal force, m is the mass of the ball, v is the speed of the ball, and r is the radius of the loop.
At the top of the loop, the centripetal force is equal to the weight of the ball:
F_c = mg
where g is the acceleration due to gravity.
Therefore, we can write:
mg = mv^2/r
Solving for v, we get:
v = sqrt(gr)
For the ball to stay in contact with the track, the speed at the top of the loop must be equal to or greater than this minimum speed.
To calculate the maximum height of the loop, we need to find the minimum value of r that will satisfy this condition.
We know that at the top of the loop, the total energy of the ball is equal to its potential energy:
mgh = (1/2)mv^2
Substituting v = sqrt(gr), we get:
mgh = (1/2)mg^2r
Simplifying, we get:
h = (1/2)gr
Substituting m = 100 kg and r = 0.5 m, we get:
h = (1/2)(9.8 m/s^2)(0.5 m)
h = 2.45 m
Therefore, the maximum height of the loop in the rollercoaster design with hamster-ball like vehicles is 2.45 meters.
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i will mark brainliest if you get it right.
Answer:
Satellite D
Explanation:
It has more mass
Two equal, but oppositely charged particles are attracted to each other electrically. The size of the force of attraction is 87.96 N when they are separated by 24.04 cm. What is the magnitude of the charges in microCoulombs ?
The magnitude of the electric force between two charged particles is given by Coulomb's Law:
\(F=k\frac{|q_1q_2|}{r^2}\)Where q_1 and q_2 are the charges of the particles, r is the distance between the charged particles and k is the Coulomb's Constant:
\(k=8.99\times10^9N\frac{m^2}{C^2}\)Since the magnitude of both charges is the same, the equation becomes:
\(F=\frac{kq^2}{r^2}\)The force and the distance between the particles are given, the value of k is known and the charge q is unknown. Isolate q from the equation:
\(\begin{gathered} q^2=\frac{F}{k}r^2 \\ \\ \Rightarrow q=\sqrt{\frac{F}{k}r^2}=r\sqrt{\frac{F}{k}} \end{gathered}\)Replace the values of r=24.04*10^-2m, F=87.96N as well as the value of k to find the magnitude of the charges:
\(\begin{gathered} q=r\sqrt{\frac{F}{k}} \\ \\ =(24.04\times10^{-2}m)\times\sqrt{\frac{87.96N}{8.99\times10^9N\frac{m^2}{C^2}}} \\ \\ =23.779...\times10^{-6}C \\ \\ \approx23.78\mu C \end{gathered}\)Therefore, the magnitude of the charges in microCoulombs is: 23.78μC.
A car goes 15 miles at 45mph, then goes another 15 miles at 30mph. a. How long does the trip take? b. What is the average speed for the whole trip?
The trip takes a total of 1.5 hours and has an average speed of 40 mph.
To calculate the time taken for each leg of the trip, we can use the formula time = distance/speed.
For the first leg of the trip, the car travels 15 miles at a speed of 45 mph. Using the formula, we find that the time taken for this leg is 15/45 = 0.33 hours.
For the second leg of the trip, the car travels another 15 miles but at a speed of 30 mph. Using the formula, we find that the time taken for this leg is 15/30 = 0.5 hours.
To find the total time for the trip, we add the times for each leg: 0.33 hours + 0.5 hours = 0.83 hours.
To calculate the average speed for the entire trip, we use the formula average speed = total distance/total time. The total distance traveled is 15 miles + 15 miles = 30 miles. The total time taken is 0.83 hours. Plugging these values into the formula, we find that the average speed for the trip is 30/0.83 = 36.14 mph.
Therefore, the trip takes a total of 1.5 hours and has an average speed of 40 mph.
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what is electricity?
Explanation:
electricity is the flow of electrical power or charge
Explanation:
the flow of current is called electricity
WILL BRAINLIETS EASY Who created law of gravity who created brainly also will anyone be my gf im 16
Answer:
Sir Isaac Newton created law of gravity, Michał Borkowski, Tomasz Kraus, and Łukasz Haluch made Brainly
Explanation:
Answer:
Sir Isaac NewtonMichał Borkowski,Łukasz Haluch,Tomasz Krausumm ok.Explanation:
:)
kinetic energy, what is its velocity, as a fraction of the speed of light? you will have to assume the electron is moving relativistically.
A calculation gives the result that the electron is moving at about 2,200 kilometers per second. That's less than 1% of the speed of light,
So, it is 99%of speed of light = 300000×99÷100
= 297000 km/s
The speed of light which we know is 300,000 kilometers per second is the last speed limit to get. By adding energy to the electron, it becomes faster, but we see that as we get closer to the speed of light, we need to add even more energy just to bump it a bit faster.
To reach to 99.9% (just another 9.9 percentage points), we spend a total of over 11 million eV! So it's harder to push it faster.
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PLS ANSWER FAST TIMED TEST WILL GIVE BRAINLY!!!!!!!!!
True or False?
It is easier to carry an empty backpack than a backpack full of books. This is an example of Newton’s 2nd law.
Answer:
The answer iis true
Explanation:
It is much easier to carry your backpack when it is empty rather than when it's full of textbooks (or soaked from the rain).
Estimate the energy of the characteristic x-ray emitted from a tungsten target when an electron drops from an M shell ( n=3 state) to a vacancy in the K shell (n=1 state). The atomic number for tungsten is Z=74
The energy of the characteristic x-ray emitted from a tungsten target 1.36*10³ eV.
The energy of a characteristic x-ray emitted from a tungsten target when an electron drops from an M shell (n=3 state) to a vacancy in the K shell (n=1 state) can be estimated using the equation E =hcZ²Δn²/n². Here Z is the atomic number for tungsten (Z=74) and Δn is the difference between n1, the initial orbital, and n2, the final orbital, (n1 - n2). In this case n1= 3 and n2= 1 giving (3-1=2).
Using the equation E =(hc*74²*2²)/1² = (6.63*10-34*.993*17576)/1= 1.36*10³ eV. Therefore, the estimated energy of the characteristic x-ray emitted from the tungsten target when an electron drops from the M shell (n=3) to a vacancy in the K shell (n=1) is approximately 1.36*10³ eV.
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Navigate to the Uniform Circular Motion Interactive in the Physics Interactives section of The Physics Classroom website. https://www.physicsclassroom.com/Physics-Interactives/Circular-and -Satellite Motion Uniform-Circular-Motion/Uniform-Circular-Motion Interactive Experiment with the on-screen buttons in order to gain familiarity with the control of the animation. The object speed, radius of the circle, and object mass can be varied using the sliders or the buttons. The vector nature of velocity and acceleration can be displayed on the screen. A trace of the object's motion is shown. The acceleration of and the net force values are displayed in the animation window. The animation can be started, paused, continued or rewound. After gaining familiarity with the program, use it to answer the following questions.
The Uniform Circular Motion Interactive is a tool that allows users to explore the physics of uniform circular motion. The user can change the radius of the circle, the speed of the object, and the mass of the object.
When an object moves in a circle at a constant speed, it is said to be in uniform circular motion. The velocity of the object is constantly changing direction, even though the speed is constant. This means that the object is accelerating.
The acceleration of an object in uniform circular motion is directed towards the center of the circle. The magnitude of the acceleration is equal to the square of the speed of the object divided by the radius of the circle.
The net force on an object in uniform circular motion is always directed towards the center of the circle. The magnitude of the net force is equal to the mass of the object times the acceleration of the object.
The Uniform Circular Motion Interactive is a valuable tool for understanding the physics of uniform circular motion. It allows users to explore the effects of changing the radius of the circle, the speed of the object, and the mass of the object on the velocity, acceleration, and net force of the object.
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Hey can someone help me with this?
I dont quite understand it
The acceleration of a rocket increases as it rises up through the atmosphere.
The thrust exerted by the engines doesn't change, so why does the acceleration?
Answer:
What part of the Compromise of 1850 was most wanted by the South
California
Oversea slave trade expansion
The Fugitive Slave Law
Change the 36-30 line??????
Explanation:
A hair dryer uses 1100 W of power
when connected to a 110 V outlet.
What is the resistance of the hair
dryer?
Answer:10
Explanation:acellus
Which graph shows a vehicle traveling at a constant speed?
(look at the attached photo)
cehgg how far does a plane fly in 15 seconds while its velocity is changing from 145 m/s to 75 m/s at a uniform rate of acceleration?
The plane will travel a distance of 2175 meters while its velocity is changing from 145 m/s to 75 m/s at a uniform rate of acceleration.
What is a change in acceleration?The rate at which velocity changes in relation to time is known as acceleration. It is a vector quantity that gauges the magnitude and direction of a change in velocity. It can be calculated as the velocity's time-dependent derivative or as the velocity change divided by the time-dependent change. The metric for acceleration is meters per second squared (m/).
The difference between two levels of acceleration, either at different times or in distinct directions, is referred to as a change in acceleration. According to mathematics, it can be described as the difference between final acceleration and initial acceleration, as shown by the equation:
Δa = a2 - a1
where "a" stands for the acceleration change, "a2" for the final acceleration, and "a1" for the starting acceleration.
distance = (initial velocity x time) + (1/2) x acceleration x
acceleration = (final velocity - initial velocity) / time
we get:
acceleration = (75 - 145) / 15 = -5 m/
Now,
distance = (145 x 15) + (1/2) x (-5) x = 2175 m
Therefore, the plane will travel a distance of 2175 meters.
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Please answer!!! This is due today so please help me, thank you! :)
A lunar eclipse occurs when _______ shadow falls on _______.a. Earth's; the Moonb. the Moon's; Earthc. the Sun's; the Moond. the Sun's; Earth
A lunar eclipse occurs when earth's shadow fall on moon.
A lunar eclipse occurs when the Moon passes through the Earth's shadow. During a lunar eclipse, the Sun, Earth, and Moon are aligned such that the Earth is positioned between the Sun and the Moon. The Earth's shadow falls on the Moon, causing it to become partially or fully darkened. The type of lunar eclipse depends on how much of the Moon is obscured by the Earth's shadow, with a total lunar eclipse occurring when the Moon is completely surrounded by the Earth's shadow. Lunar eclipses are relatively common, with a few occurring each year, and are visible from a large portion of the Earth's surface. They are a popular event for astronomers and stargazers, providing a unique opportunity to observe the Moon in a different light.To know more about eclipse visit:
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. A boy wishes to make a catapult out of a rubber band of width 9mm and thickness 1.55mm. Determine the length of the band that he must use so that when he stretches it by 0.25 of its natural length and releases it the velocity of pebble of mass 0.006kg will be 30m/s. Take young modulus of the rubber to be 4×10^7 N/m^2
The length of the rubber band that the boy must use is 0.024 m or 24 mm.
What will be the length of the rubber required?To determine the length of the rubber band, we can use the formula for the potential energy stored in a stretched spring, which is also applicable to a stretched rubber band:
U = 1/2 kx²where U is the potential energy stored in the rubber band, k is the spring constant (or in this case, the rubber band constant), and x is the displacement of the rubber band from its natural length.
Since the rubber band is stretched by 0.25 of its natural length, the displacement x is 0.25 times the natural length of the rubber band.
We can solve for the rubber band constant k by using the formula for the velocity of a projectile launched by a spring (or in this case, a rubber band):
v = √(2mk/M)where v is the velocity of the projectile, m is the mass of the rubber band, M is the mass of the projectile, and k is the spring constant. We can rearrange this equation to solve for k:
k = (v² M) / (2 m)
We can now combine the two equations to solve for the length of the rubber band, L:
U = 1/2 k x²
U = 1/2 ((v² M) / (2 m)) (0.25 L)²
U = (v² M L²) / (32 m)
The potential energy stored in the rubber band must be equal to the kinetic energy of the projectile when it is launched:
U = 1/2 M v²
(v² M L²) / (32 m) = 1/2 M v²
L = ((16 m v²) / (k M))
L = ((16 m v²) / ((v² M) / (2 m) M))
L = √(32 m^2 / M)
L = (0.032 M)
Substituting the given values, we get:
L = √(0.032 * 0.006)
L = 0.024 m
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