11. A seesaw sits in static equilibrium. A child with a mass of 30 kg sits 1 m away from a pivot point. Another child sits 0.75 m away from the pivot point on the opposite side. The second child's mass is _____ kg.

Answers

Answer 1

Answer:

40 kg

Explanation:

Find the diagram relating to the question for proper explanation of the question below.

Using the principle of moment

Sum of clockwise moments = Sum of anticlockwise moments

Moment = Force * perpendicular distance

For anti-clockwise moment:

Since the 30 kg moves in the anticlockwise direction according to the diagram

ACW moment = 30 * 1 = 30 kgm

For clockwise moment

If another child sits 0.75 m away from the pivot point on the opposite side, moment of the child in clockwise direction = M * 0.75 = 0.75M (M is the mass of the unknown child).

Equating both moments we have;

0.75M = 30

M = 30/0.75

M = 40 kg

The second child's mass is 40 kg

11. A Seesaw Sits In Static Equilibrium. A Child With A Mass Of 30 Kg Sits 1 M Away From A Pivot Point.

Related Questions

S= 12 m/s D= ?t= 3 s What distance did the object traveling at 12m/s go in 10 points
3s? *
4 m
3 m
36 m

Answers

Answer:

distance travelled= 12 x 3=36 m

Ramp 1 Ramp 2 Ramp 3
Trial 1 0.95 s 0.78 s 1.31 s
Trial 2 0.87 s 0.75 s 1.27 s
Trial 3 0.92 s 0.80 s 1.44 s
Avg. Time 0.91 s 0.78 s 1.34 s

Which of the following conclusions can be made from the above data?

Answers

From this data it is clear that the time require to complete ramp 3 is more than any other, hence it can be large ramp or there are more objectless or  turns. Ramp 2 requires least time to complete, it can be shorter or having less number of obstacles.

An inclined plane, also known as a ramp, is a flat supporting surface that is slanted at an angle from the vertical direction, with one end higher than the other, and is used to help raise or reduce a weight. The inclined plane is one of the six traditional basic devices established by Renaissance scientists. Inclined aircraft are used to transport big cargoes over vertical obstructions. Examples include a ramp used to load items into a truck, a person going up a pedestrian ramp, and an automobile or railroad train climbing a gradient. it can have obstacles in the path

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1.00 kg of ice at -24.0°C is placed
in contact with a 1.00 kg block of a
metal at 5.00°C. They come to
equilibrium at -8.88°C. What is
the specific heat of the metal?

Answers

1.00 kg of ice at -24.0°C is placed in contact with a 1.00 kg block of a metal at 5.00°C. They come to equilibrium at -8.88°C.

We can use the principle of conservation of heat to solve this problem. The heat lost by the metal must equal the heat gained by the ice.

The heat lost by the metal is given by

Q1 = m1c1ΔT1

Where m1 is the mass of the metal, c1 is its specific heat, and ΔT1 is the change in temperature.

The heat gained by the ice is given by

Q2 = m2c2ΔT2

Where m2 is the mass of the ice, c2 is its specific heat, and ΔT2 is the change in temperature.

Since the two objects come to thermal equilibrium, we can set Q1 equal to Q2

m1c1ΔT1 = m2c2ΔT2

Solving for c1, we get

c1 = m2c2ΔT2 / (m1ΔT1)

By putting these values we get

c1 = (1.00 kg)(2.06 kJ/kg·K)(-24.0°C - (-8.88°C)) / [(1.00 kg)(5.00°C - (-8.88°C))]

c1 = 0.902 kJ/kg·K

Hence, the specific heat of the metal is 0.902 kJ/kg·K.

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PLEASE HELP
How much work is required to raise a 1200 kg rock 15 m?

Answers

Answer:

18000

Explanation:

the is to raise how much work is required is 18000

Work done to raise an object of mass 1200 kg to the height of 15 meters will be equal to 176,400 J.

What is Work?

In physics, the word "work" involves the measurement of energy transfer that takes place when an item is moved over a range by an externally applied, at least a portion of which is applied within the direction of the displacement.

The length of the path is multiplied by the element of a force acting all along the path to calculate work if the force is constant. The work W is theoretically equivalent towards the force f times the length d, or W = fd, to portray this concept.

As per the data given in the question,

Mass of the object, m = 1200 kg

Displacement, d = 15 meters

Then, use the equation of work done,

W = fd

W = (m×a)d

Substitute the values in above equation,

W = 1200 × 9.8 × 15

W = 176,400 J.

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If a cube that has a length, height, and width of 4 cm is broken down into 8 cubes of equal size, what is the surface area of the 8 new cubes?

Answers

Answer: When a cube is divided into smaller cubes of equal size, the length, height, and width of each new cube are one-third of the original cube.

So each new cube will have a length, height, and width of 4/3 cm.

To calculate the surface area of each new cube, we need to find the area of each face and then add them up. Each cube has six faces, so we can calculate the surface area of one cube by multiplying the area of one face by six.

The area of one face of the new cube is (4/3)*(4/3) = 16/9 cm².

So the surface area of one new cube is 6*(16/9) = 96/9 cm² = 10.67 cm² (rounded to two decimal places).

Since we have 8 new cubes, the total surface area is 8 times the surface area of one new cube:

Total surface area = 8 * 10.67 cm² = 85.33 cm² (rounded to two decimal places).

Therefore, the surface area of the 8 new cubes is 85.33 cm².

How much force is needed to support a 160-kg iron anchor when it is submerged in seawater? (Hint:
First find the anchor's volume.) Round your intermediate steps to three decimal places.

Answers

Answer:

To determine the force needed to support the 160-kg iron anchor submerged in seawater, we need to take into account the buoyant force acting on the anchor.

The buoyant force is the upward force exerted on the anchor due to the water it displaces, and it is equal to the weight of the water displaced by the anchor. The weight of the displaced water is equal to the volume of the anchor submerged in water multiplied by the density of seawater.

First, we need to calculate the volume of the anchor. We can assume that the anchor is a rectangular solid with dimensions 1 m x 1 m x 0.5 m. Therefore, the volume of the anchor is:

Volume of anchor = length x width x height = 1 m x 1 m x 0.5 m = 0.5 cubic meters

The density of seawater is approximately 1025 kg/m^3. Therefore, the weight of the water displaced by the anchor is:

Weight of water displaced = volume of anchor x density of seawater

= 0.5 cubic meters x 1025 kg/m^3

= 512.5 kg

According to Archimedes' principle, the buoyant force acting on the anchor is equal to the weight of the water displaced by the anchor, which is 512.5 kg. Therefore, the force needed to support the 160-kg iron anchor when it is submerged in seawater is:

Force = weight of the anchor - buoyant force

= 160 kg x 9.81 m/s^2 - 512.5 kg x 9.81 m/s^2

= 1173.6 N

Therefore, approximately 1173.6 newtons of force are needed to support the 160-kg iron anchor when it is submerged in seawater.

On a brisk walk, a person burns about 331 Cal/h. If the brisk walk were done at 3.0 mi/h, how far would a person have to walk
to burn off 1 lb of body fat? (A pound of body fat stores an amount of chemical energy equivalent to 3,500 Cal.)
mi?​

Answers

Answer:

32mi

Explanation:

If 1lb contains 3,500 Cal

It means the number of hours required to burn 3500cal would be;

3500/331 = 10.57hours

But a brisk walk is 3.0 mi/h,

It means a distance of 3.0 × 10.57 mi would be covered = 31.71 miles

32miles{ approximated to the nearest whole}

Note Distance = speed × time

Plz solve this question..

Plz solve this question..

Answers

Answer:

Explanation:

Voltage = 12 (the two batteries are in series and the voltage adds).

Resistance = 3 ohms

I = V / R

I = 12/3

I = 4 amperes.

None of the answers are the right ones. If there is a fifth one that reads 4 amperes then it is the correct answer.

What happens to an object's kinetic energy as it falls from some height?

Answers

Answer:

The objects kinetic energy increases as it falls from some height.

The following table shows the distance from the sun of some unknown planets of equal mass.

Distance from Sun

Planet Distance from Sun
W 1.5 AU
X 0.723 AU


Which of the following best explains which planet revolves at a faster speed?
Planet X, because the sun pulls it with a greater force
Planet W, because the sun pulls it with a greater force
Planet W, because the gravitational force is weakened by distance
Planet X, because the gravitational force is strengthened by distance


(D was wrong, I'm taking the test again)

Answers

The correct answer is : Planet X, because the sun pulls it with a greater force

The speed at which a planet revolves around the sun is determined by its distance from the sun and the gravitational force between the planet and the sun. The closer a planet is to the sun, the stronger the gravitational force, and the faster it will orbit. Therefore, Planet X, which is closer to the sun than Planet W, will revolve around the sun at a faster speed, assuming that both planets have equal masses. Thus, the correct answer is "Planet X, because the gravitational force is strengthened by distance." The farther a planet is from the sun, the weaker the gravitational force, but this would result in a slower orbital speed, not a faster one.

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Answer: A A A !!!!  

Explanation: just did the test, got it right thx thx!!!

A ball is thrown upwards at 19.50m/s from a window 58.52m above the ground. When does it strike the ground?​

Answers

The ball will strike the ground after 8.04 seconds.

Kinematic motion problem

Using the kinematic equation for displacement:

y = y0 + v0t - 1/2g*t^2

where:

y = final displacement (ground level), y = 0 my0 = initial displacement (window), y0 = 58.52 mv0 = initial velocity, v0 = 19.50 m/s (upwards)g = acceleration due to gravity, g = 9.81 m/s^2 (downwards)

We want to findt, let's substitute the values:

0 = 58.52 + 19.50t - 1/2(9.81)*t^2

4.905t^2 - 19.50t - 58.52 = 0

Using the quadratic formula:

t = (-b ± sqrt(b^2 - 4ac)) / 2a

where:

a = 4.905b = -19.50c = -58.52

t = (-(-19.50) ± sqrt((-19.50)^2 - 4(4.905)(-58.52))) / 2(4.905)

t = (19.50 ± 31.37) / 9.81

The two possible solutions are:

t1 = 5.61 s (ball on the way up)

t2 = 8.04 s (ball on the way down)

Since the question is asking for when the ball strikes the ground, we take the larger solution, which is:

t = 8.04 s

In other words, the ball will strike the ground after 8.04 seconds.

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proof(how this formula comes )
vector
u.v=|u||v|cosβ

Answers

The formula you mentioned is known as the dot product formula or the scalar product formula. It is used to find the angle between two vectors u and v.

Let's start by defining the vectors u and v. Suppose we have two vectors u and v in a two-dimensional space.

u = (u1, u2)

v = (v1, v2)

The dot product of these vectors is defined as:

u . v = |u| |v| cos(β)

where |u| and |v| are the magnitudes of the vectors u and v respectively, and β is the angle between the vectors u and v.

Now, let's derive this formula. The dot product of two vectors u and v is given by:

u . v = (u1 × v1) + (u2 × v2)

The magnitude of a vector is given by:

|u| = sqrt(u1² + u2²)

|v| = sqrt(v1² + v2²)

We can use the dot product and magnitude equations to obtain:

cos(β) = (u . v) / (|u| × |v|)

Multiplying both sides by |u| × |v| gives us:

|u| × |v| × cos(β) = u . v

Therefore, we have derived the dot product formula:

u . v = |u| × |v| × cos(β)

This formula can be used to find the angle between two vectors u and v in any two-dimensional or three-dimensional space.

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The complete question is-

Write the proof of the formula

u.v=|u||v|cosβ

The passenger side of your car has a side-view mirror with a convex sphericalmirror. When you pass a car, you see its reflection. If the image is 9.0 cm tall andthe car is 1.5 m tall, what is the mirror’s magnification? If the car is 3 m from themirror, what is the focal length of the mirror? What is the mirror’s radius ofcurvature?

Answers

ANSWER:

The mirror’s magnification is 0.06

The focal length is equal to 19.15 cm.

The mirror's radius of curvature is 38.3 cm

STEP-BY-STEP EXPLANATION:

Given:

height image = 9 cm

height object = 1.5 m = 150 cm

The mirror's magnification is calculated using the following formula:

\(m=\frac{h_i}{h_o}=\frac{9}{150}=0.06\)

The mirror’s magnification is 0.06

Since we know the distance of the object which is -3 m (-300 cm) and the mirror's magnification we can calculate the distance of the image, just like this:

\(\begin{gathered} m=\frac{-d_i}{d_o} \\ \\ 0.06=\frac{-d_i}{-300} \\ \\ d_i=300\cdot0.06 \\ \\ d_i=18\text{ cm} \end{gathered}\)

We calculate the focal length using the following formula:

\(\begin{gathered} \frac{1}{f}=\frac{1}{d_i}+\frac{1}{d_o} \\ \\ \frac{1}{f}=\frac{1}{18}+\frac{1}{-300} \\ \\ \frac{1}{f}=\frac{18-300}{-5400} \\ \\ f=\frac{-5400}{-282} \\ \\ f=\:19.15\text{ cm} \end{gathered}\)

The focal length is equal to 19.15 cm.

Finally we calculate the mirror's radius of curvature knowing that twice the focal length, therefore:

\(\begin{gathered} r=2f=19.15\cdot2 \\ \\ r=38.3\text{ cm} \end{gathered}\)

The mirror's radius of curvature is 38.3 cm

Explain why a ping pong ball and bouncy ball of the same size have different weights

Answers

Answer:

the material

Explanation:

weight is defined as the amount of force on the object because of gravity. ping pong balls and bouncy balls are made out of different materials that are different weights. most bouncy balls are also not hollow, unlike ping pong balls. these factors affect the weight of these objects.

A negatively charged particle accelerates from East to West in a uniform electric field. What are the direction and the value of the electric field if the particle has charge q-3mC, mass m=1mg, the value of its acceleration is 3mm/s²? and if the value of its acceleration is 3mm/s²?​

Answers

Answer: 9 N/C.

Explanation: The direction of the electric field is from West to East.

We can use the equation for the acceleration of a charged particle in an electric field:

a = (q/m)E

where a is the acceleration of the particle, q is the charge on the particle, m is the mass of the particle, and E is the electric field.

Plugging in the given values, we have:

3 mm/s^2 = (-3 mC / 1 mg) * E

Simplifying and converting units, we get:

E = 9 N/C

Therefore, the direction and value of the electric field is from West to East with a magnitude of 9 N/C.

If the air inside a balloon exerts a force of 1 N on an area of 0.5 m^2 what is the pressure inside the balloon

Answers

Answer:

2 Pascal (Pa)

Explanation:

Pressure is defined as the force acting per unit area. Mathematically, it is expressed as:

Pressure (P) = Force (F) / Area (A)

Given:

Force exerted by the air inside the balloon (F) = 1 N

Area of the balloon (A) = 0.5 m^2

Plugging in the given values into the formula for pressure, we get:

P = F / A

P = 1 N / 0.5 m^2

Using basic arithmetic, we can calculate the pressure inside the balloon:

P = 2 N/m^2

So, the pressure inside the balloon is 2 N/m^2, which is also commonly referred to as 2 Pascal (Pa) since 1 Pascal is equal to 1 N/m^2.

A plane wave in a nonmagnetic medium has E = 50 sin (10^8 + 2*z) ay V/m. Find (a) The direction of wave propagation (b) λ, f, and Er (c) H​

Answers

(a) The direction of wave propagation is along the negative z-axis.

(b) The wavelength (λ) is π m, the frequency (f) is approximately 1.59 × \(10^{7}\) Hz, and the wave impedance (Er) is approximately 0.1667 sin (\(10^{8}\) + 2z) ohms.

(c) The magnetic field (H) is (50 sin (\(10^{8}\) + 2z)) / (3 × \(10^{8}\)) ay A/m.

If the direction of wave propagation is specified as along the negative z-axis, we can conclude that the wave is traveling in the opposite direction to the positive z-axis. In the given expression: E = 50 sin(10^8 + 2z) ay V/m

Since the wave is traveling along the negative z-axis, it means that as z increases (in the positive direction), the wave is propagating in the opposite direction.

Hence, the direction of wave propagation for the given wave is along the negative z-axis.

To find the wavelength (λ), frequency (f), and wave impedance (Er), we can relate the electric field (E) and magnetic field (H) components using the wave equation in a nonmagnetic medium:

E = c * H,

where c is the speed of light in the medium, which can be approximated as 3 × \(10^{8}\) m/s in free space.

(a) Direction of wave propagation: Along the positive z-axis.

(b) Calculating λ, f, and Er:

Since the electric field (E) is given as E = 50 sin (\(10^{8}\) + 2z) ay V/m, we can see that the angular frequency (ω) is \(10^{8}\) rad/s and the wave number (k) is 2.

The relationship between wave parameters is given by: c = λ * f, where c is the speed of light.

Using the relation c = ω/k, we can solve for λ and f:

λ = 2π/k = 2π/2 = π m (meters)

f = ω/2π = \(10^{8}\)/2π ≈ 1.59 × \(10^{7}\) Hz (Hertz)

To find the wave impedance (Er), we can use the equation Er = E/H:

Er = E/c = (50 sin (\(10^{8}\) + 2z)) / (3 × \(10^{8}\)) ≈ 0.1667 sin (\(10^{8}\) + 2z) ohms.

(c) The magnetic field (H) can be calculated using the relationship H = E/c:

H = (E/c) = (50 sin (\(10^{8}\) + 2z)) / (3 × \(10^{8}\)) ay A/m.

The direction of wave propagation is along the negative z-axis. (b) The wavelength (λ) is π m, the frequency (f) is approximately 1.59 × \(10^{7}\) Hz, and the wave impedance (Er) is approximately 0.1667 sin (\(10^{8}\) + 2z) ohms. The magnetic field (H) is (50 sin (\(10^{8}\) + 2z)) / (3 × \(10^{8}\)) ay A/m.

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How do we sip water from glass using straw?can we sip water with straw on moon?

Answers

Answer:To sip water from a glass using a straw, you would simply place the straw into the glass and tilt the glass towards your mouth. You would then use your lips to create a seal around the straw and take a small sip of the water.As for sipping water with a straw on the moon, it is possible, but it would require some modification to the traditional method of using a straw. On the moon, there is no atmospheric pressure, so the water would not be held in place by gravity. Instead, you would have to use a specialized straw that is designed to work in a vacuum, such as those used by astronauts on the International Space Station. These straws have a valve at the top that allows the water to flow into your mouth when you suck on the straw, but prevents it from spilling out when you release your lips. So, in order to sip water with a straw on the moon, you would have to use one of these specialized straws and follow the same basic technique as you would on Earth, but you would have to be careful not to spill any water in the low gravity environment.

Rough Surface with: Ms = 0.8 HK = 0.4

(a) Find the magnitude of the

force F needed to prevent the

book from sliding down the

rough wall.

F

M = 1.5 kg

600

(b) Find the minimum force F

needed to set the book in

motion up the rough wall with

constant velocity

Answers

Answer:

a)    F = 18.375N, b) F = 24.5 N

Explanation:

This exercise can be solved using the translational equilibrium equations.

Let's start by fixing a reference system with the horizontal x axis and the vertical y axis, from the statement of the exercise I understand that the wall is vertical and the book is supported on it, therefore the applied force is in the direction towards the wall

a) In this part the force that does not allow the movement of the book is requested, therefore the static friction coefficient must be used (μ_s = 0.8)

X axis  

       F - N = 0

       N = F

Y axis

       fr - W = 0

       W = fr

where W is the weight of the book.

The friction force has the formula

       fr = μ_s N

we substitute

       mg = μ_s F

       F = \(\frac{mg}{\mu_s }\)

let's calculate

       F = 1.5 9.8 / 0.8

       F = 18.375N

b) In this case the book is moving so the friction coefficient to use is kinetic (   μ_K = 0.6)

   

       F = \(\frac{mg}{\mu_K }\)

       

we calculate

        F = 1.5 9.8 / 0.6

        F = 24.5 N

Your friend's Frisbee has become stuck 19 m above the ground in a tree. You want to dislodge the Frisbee by throwing a rock at it. The Frisbee is stuck pretty tight, so you figure the rock needs to be traveling at least 4.1 m/s when it hits the Frisbee.

If you release the rock 1.8 m above the ground, with what minimum speed must you throw it?

Answers

Answer:

18.36 m/s

Explanation:

We can solve this using conservation of energy. The energy in the system will be conserved since there are no outside forces acting upon it so the potential energy and kinetic energy will be equal. Giving us this formula to start:

1/2mv^2=mgh

m=mass

g=gravity

h=height

v=velocity

We can start by figuring out the total height the rock travels which we can do by subtracting the height of the frisbee by the height the rock started at.

19m-1.8m=17.2m

Now we can plug in our variables to solve for velocity.

First we negate mass since its on both sides and cancels out leaving us with.

1/2v^2=gh

Plug in.

1/2v^2=(9.8)(17.2)

1/2v^2=168.56

v^2=337.12

v=18.36m/s

Which object exerts the action force?
Which object exerts the reaction force?
In what direction does the action force push?
In what direction does the reaction force push?

Answers

For answering this question,let us assume that a person is pushing against the walls,so now:

Which object exerts the action force?

Person

Which object exerts the reaction force?

Wall

In what direction does the action force push?

Backward

In what direction does the reaction force push?

Forward

The answer varies from different scenarios.

Answer:

diver, diving board, down, and up.

Explanation:

A 1.40-kg block is on a frictionless, 30 ∘ inclined plane. The block is attached to a spring (k = 40.0 N/m ) that is fixed to a wall at the bottom of the incline. A light string attached to the block runs over a frictionless pulley to a 60.0-g suspended mass. The suspended mass is given an initial downward speed of 1.60 m/s .
How far does it drop before coming to rest? (Assume the spring is unlimited in how far it can stretch.)
Express your answer using two significant figures.

Answers

Answer:

0.5

Explanation:

because the block is attached to the pulley of the string

A sample of 0.500 kg of ice is held at a temperature of 0°C. How much energy
must be added to completely turn the ice into liquid water? (The latent heat of
vaporization for water is 2260 kJ/kg; the latent heat of fusion for water is 333
kJ/kg.)
A. 1130 kJ
B. 666 kJ
C. 167 kJ
D. 4520 kJ

Answers

Answer:

C. 167 kJ

Explanation:

The minimum amount of heat require to complete turn the ice into liquid water is equal to the latent heat of the ice, that is, the amount of heat needed by the ice to turn into water. This amount is calculated by:

\(Q = m\cdot h_{f}\) (1)

Where:

\(m\) - Mass of ice, measured in kilograms.

\(h_{f}\) - Latent heat of fusion, measured in kilojoules per kilogram.

\(Q\) - Latent heat, measured in kilojoules.

If we know that \(m = 0.500\,kg\) and \(h_{f} = 333\,\frac{kJ}{kg}\), the latent heat of ice is:

\(Q = (0.500\,kg)\cdot \left(333\,\frac{kJ}{kg} \right)\)

\(Q = 166.5\,kJ\)

Therefore, the correct answer is C.

A container holds 192 g of oxygen gas at a pressure of 8.00 atm.
How much heat Q is required to increase the temperature by
145 °C at constant volume?

Answers

The quantity of heat (Q) that is required to increase the temperature at constant volume is 18,082.95 Joules.

Given the following data:

Mass of oxygen gas = 192 gPressure = 8.00 atmTemperature = 145°C

Scientific data:

Ideal gas constant, R = 8.314 J/molKMolar mass of oxygen gas = 32 g/mol.

To determine the quantity of heat (Q) that is required to increase the temperature at constant volume:

First of all, we would find the number of moles of oxygen gas.

\(Number\;of\;moles = \frac{mass}{molar\;mass}\\\\Number\;of\;moles = \frac{192}{32}\)

Number of moles = 6 moles.

At constant volume, the heat capacity for a diatomic gas is given by:

\(C_v = \frac{5}{2} R\\\\C_v =\frac{5}{2} \times 8.314\)

Heat capacity = 20.785 J/molK.

At constant volume, the quantity of heat (Q) is given by this formula:

\(Q = nC_v \Delta T\\\\Q=6 \times 20.785 \times 145\)

Quantity of heat (Q) = 18,082.95 Joules

Note: \(\Delta T\) = 145°C = 145 K (since the difference is the same).

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what happens to the reflection when it hits the triangular prisms? the reflection is from air to glass. critical angle=42° please help me i need it right now:( ​

what happens to the reflection when it hits the triangular prisms? the reflection is from air to glass.

Answers

Answer: TIR (total internal reflection) occurs

Explanation: TIR occurs because the angle of refraction reaches a 90-degree angle before the angle of incidence reaches a 90-degree angle. The only way for the angle of refraction to be greater than the angle of incidence is for light to bend away from the normal. Since light only bends away from the normal when passing from a more dense medium into a less dense medium, then this would be a necessary condition for total internal reflection.

I agree with this tip comment I have solved this equation and I have gotten what the top comment says

you made $100,000 this year. you have $0 in adjustments, $11,500 in deductions and $7,300 in exemptions. What is your taxable increase?

Answers

The tax rate you will pay is displayed in tax brackets for each category of taxable income.

Thus, For instance, in 2022, the first $10,275 of your taxable income is subject to the lowest tax rate of 10% if you are single.

Up until the maximum amount of your taxable income, the following portion of your income is taxed at a rate of 12%.

As taxable income rises, the tax rate rises under the progressive tax system. Overall, this has the result that taxpayers with higher incomes often pay a greater rate of income tax than taxpayers with lower incomes.

Thus, The tax rate you will pay is displayed in tax brackets for each category of taxable income.

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How did earth change about 2.5 billion years ago when many organisms began using photosynthesis to make food

A. The amount of oxygen in the atmosphere increased

B. Mass extinctions occurred

C. The oceans became larger

D. Rainfall increased

Answers

The amount of oxygen in the air was increased

Complete each of the statements

A. Lines of force are lines used to represent ________ an ________ electric field


B. The intensity of an electric field is the coefficient between the _________ that in the field exerts on a test ___________ located at that point and the value of said charge

C. The electric field is uniform if at any point in the field its _________ and ________ is the same

D. The van der graff generator is a _________ machine which has two __________ that are driven by a _________ that generates a rotation

Answers

Answer:

A:  magnitude and direction

B: Force that the field exerts on a test charge

C: its magnitude and direction is the same.

D: electrostatic machine

two rollers that are driven by a motor that generates a rotation

Explanation:

An electron traveling with initial velocity 4000 m/s, enters aregion of uniform electric field 1 × 10−8 N/C. After 3 sec, what is thespeed of the electron () in m/s?

Answers

Given data

*The given initial velocity is v = 4000 m/s

*The given uniform electric field is E = 1 × 10^-8 N/C

*The given time is t = 3 s

The formula for the acceleration of the electron in the electric field is given as

\(a=\frac{qE}{m}\)

Substitute the known values in the above expression as

\(\begin{gathered} a=\frac{(1.6\times10^{-19})(1\times10^{-8})}{(9.11\times10^{-31})} \\ =1.75\times10^3m/s^2 \end{gathered}\)

The formula for the speed of the electron in m/s is given as

\(v_r=u+at\)

Substitute the known values in the above expression as

\(\begin{gathered} v_r=(4000)+(1.75\times10^3)(3) \\ =9250\text{ m/s} \\ \approx9300\text{ m/s} \end{gathered}\)

What is the average time for the toy car to move 1.0 m on tile? 20.2 s 24.4 s 28.1 s 60.7 s

Answers

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