10(x+12)=15x solve for x with how ?

The given Hoare partition algorithm is a method used to partition the given array A[p..r] into two parts based on a pivot element x in O(n) time complexity and O(1) space complexity.Algorithm: Hoare-Partition (A, p, r)1. x = A[p]2. i = p-1, j = r+13. while True do4. repeat j = j-1 until A[j] <= x5. repeat i = i+1 until A[i] >= x6. if i < j then exchange A[i] with A[j]7. else return jThe above algorithm is a recursive approach to quicksort, which is a widely used sorting algorithm.

The algorithm partitions the given array A[p..r] into two sections, each of which contains elements smaller than or equal to the pivot element x in the left section and elements larger than or equal to the pivot element x in the right section. The index j returned by the algorithm is used to partition the array further into subarrays, each of which is sorted recursively using the Hoare partition algorithm.

Here, the partitioning takes place using two indices, i and j, which move in opposite directions, eventually ending at the partition element. The algorithm runs an outer loop that runs indefinitely until the inner loops stop swapping the elements. The inner loops run until they find elements to swap to the other side of the partition.Here, i is incremented until it points to an element that is greater than or equal to the partition element. Similarly, j is decremented until it points to an element that is less than or equal to the partition element. If i is less than j, then the elements are swapped, and the loop continues until it stops swapping elements.Finally, the partition index j is returned, and the partitioned array is recursively sorted.

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The 95% confidence interval for the mean birth weight of girls, based on a sample of 12 observations, is estimated to be approximately 29.627hg to 32.707hg.

A confidence interval provides an estimate of the range within which the true population parameter (in this case, the mean birth weight of girls) is likely to fall. To construct a 95% confidence interval, we can use the formula:

Confidence interval = sample mean ± (critical value) × (standard deviation / square root of sample size)

Given the sample statistics, n = 12, = 31.167hg, and s = 3.157hg, we can compute the standard error by dividing the standard deviation by the square root of the sample size: s / sqrt(n) = 3.157 / sqrt(12) = 0.910hg.

To find the critical value corresponding to a 95% confidence level, we need to determine the degrees of freedom (n-1) and refer to the t-distribution table or use statistical software. Assuming a t-distribution with 11 degrees of freedom, the critical value for a 95% confidence level is approximately 2.201.

Substituting the values into the confidence interval formula, we have:

Confidence interval = 31.167 ± (2.201) × (0.910) = 31.167 ± 2.004 = (29.627hg, 32.707hg).

Therefore, we can be 95% confident that the true mean birth weight of girls lies within the range of approximately 29.627hg to 32.707hg, based on the given sample data.

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Answer:

The African Elephant is 2.27 times heavier than a African Lion.

Step-by-step explanation:

9 × 103 pounds = 927E.

4 × 102 pounds = 408L.

Answer:

for people who use time4learning:

the answer is (a) 22.5 x 10^1

Step-by-step explanation:

9 x 10^3 / 4 x 10^2 = 22.5

2.25 x 10^1 = 22.5

The cost of one sandwich is $5.7

The given parameters are:

Order = 3

Tax = 8% off

Total cost = $20.66

Tip = $5

The cost of one sandwich is calculated as:

Total cost = Order * Cost of One (x) * (1 - tax) + Tip

This gives

20.66 = 3 * x * (1 - 8%) + 5

Subtract 5 from both sides

15.66 = 3 * x * (1 - 8%)

Make x the subject

x = 15.66/[3 * (1 - 8%)]

Evaluate

x = 5.7

Hence, the cost of one sandwich is $5.7

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Answer:

\(\boxed {x < -4}\) (Choice D)

Step-by-step explanation:

You first need to solve the following inequality in order to get the actual answer and find the actual graph:

\(1 + 2x < -7\)

-Subtract \(1\) to both sides:

\(1 - 1 + 2x < -7 - 1\)

\(2x < -8\)

-Divide both sides by \(2\):

\(\frac{2x}{2} < \frac{-8}{2}\)

\(\boxed {x < -4}\)

The number line graphed:

The capacity to overcome opposition or hesitancy to accept is referred to as convincing.

Convincing can also be described by other words like cogent, sound, telling, and valid.

Despite the fact that all of these words have the same meaning—"having such force as to compel serious attention and typically acceptance”—convincing denotes the ability to go over resistance or hesitation to accept.

When you say that someone or something is compelling, you indicate that they persuade you that something is real, accurate, or true.

Three fundamental strategies for persuading a listener to agree with you are ethos, logos, and pathos.

A more appropriate translation today may be "picture."

The audience's perception of the speaker's character, according to Aristotle, is referred to as ethos.

Therefore, the capacity to overcome opposition or hesitancy to accept is referred to as convincing.

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\(( ~~ \csc(\theta )-\cot(\theta ) ~~ )^2=\cfrac{1-\cos(\theta )}{1+\cos(\theta )} \\\\[-0.35em] ~\dotfill\\\\ ( ~~ \csc(\theta )-\cot(\theta ) ~~ )^2\implies \csc^2(\theta )-2\csc(\theta )\cot(\theta )+\cot^2(\theta ) \\\\\\ \cfrac{1^2}{\sin^2(\theta )}-2\cdot \cfrac{1}{\sin(\theta )}\cdot \cfrac{\cos(\theta )}{\sin(\theta )}+\cfrac{\cos^2(\theta )}{\sin^2(\theta )}\implies \cfrac{1}{\sin^2(\theta )}-\cfrac{2\cos(\theta )}{\sin^2(\theta )}+\cfrac{\cos^2(\theta )}{\sin^2(\theta )}\)

\(\cfrac{\cos^2(\theta )-2\cos(\theta )+1}{\sin^2(\theta )}\implies \cfrac{[\cos(\theta )-1][\cos(\theta )-1]}{\sin^2(\theta )} \\\\\\ \cfrac{[\cos(\theta )-1][\cos(\theta )-1]}{1-\cos^2(\theta )}\implies \cfrac{[\cos(\theta )-1][\cos(\theta )-1]}{-[\cos^2(\theta )-1]}\)

\(\cfrac{[\cos(\theta )-1][\cos(\theta )-1]}{-[\cos^2(\theta )-1^2]}\implies \cfrac{[\cos(\theta )-1][\cos(\theta )-1]}{-[\cos(\theta )-1][\cos(\theta )+1]} \\\\\\ \cfrac{\cos(\theta )-1}{-[\cos(\theta )+1]}\implies \cfrac{-[\cos(\theta )-1]}{\cos(\theta )+1}\implies \cfrac{1-\cos(\theta )}{1+\cos(\theta )}\)

To find the optimal solution, we need to determine the feasible region by graphing the given constraints and identify the corner points where the constraints intersect. However, to provide a numerical solution, we can use a linear programming solver.

Using a linear programming solver, we can input the objective function C = 7x + 9y and the constraints 6x + 8y ≤ 15 and 9x + 8y ≤ 19, along with the non-negativity constraints x ≥ 0 and y ≥ 0. The solver will then calculate the optimal values of x and y that maximize the objective function C.

The optimal values of x and y will depend on the specific values of the constraints, and the resulting values may not be whole numbers. Therefore, rounding the answers to three decimal places will provide the desired level of precision. The linear programming solver will provide the optimal values of x and y that maximize the objective function C.

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When slave starting a disabled vehicle, the term that serves an important safety consideration is c. The slaving vehicle engine must be running while connecting the slave cable

The dead car is started while the live vehicle's engine is running by inserting a slave cable into the receptacle on each vehicle.

Vehicles with manual transmissions rely heavily on the clutch slave cylinder. When the pedal is depressed, the clutch is disengaged and the transmission is shifted thanks to the slave and clutch master cylinders.

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Answer:

Option (B)

Step-by-step explanation:

From the graph attached,

x-intercepts of the graphed function are,

x = -3 and x = 4

Therefore, zero factors of the function will be,

(x + 3) and (x - 4)

So the quadratic function given in the graph will be in the form of,

f(x) = (x + 3)(x - 4)

Option (B) will be the correct option.

The value of n is A. -1/2

The inequality that does not represent the position of 2 numbers on a number line is A. 4 1/2 > 25/4

A number line is a horizontal representation of number parts with equal intervals

The numbers in a number line is arranged to be increasing from left to right , hence drawing a number line will have the smaller values to the left of the bigger values

n is the negative side of the line and it is half (1/2) way between 0 and -1 hence should be -1/2

for the inequality, 4 1/2 > 25/4

4 1/2 = 4.5

25/4 = 6.25

4.5 should less than 6.25, and hence do not represent the correct position of two numbers

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Answer:

The number of hours Moran wold have driven before Andre catches up with him is 14 hours

Step-by-step explanation:

The given information are;

The speed with which Andre will drive = 70 miles per hour

The speed with which Morgan will drive = 55 miles per hour

The time of departure of Morgan = 3 hours before Andre departs

Let the time at which Andre catches up with Morgan be, t

We have, from the definition of distance traveled;

Distance traveled =Speed × Time

The distance Morgan would have driven in t hours = 55 × t

Given that to catch up with Morgan, Andre has to travel the same distance, and that Andre starts 3 hours late, we have;

The distance Andre would  drive when Morgan has driven for t hours = 70 × (t - 3)

Therefore, since the distance at the point they meet is the same distance for them both, we have;

55 × t = 70 × (t - 3)

55 × t = 70 × t - 210

210 = 70 × t - 55 × t  = 15 × t

t = 210/15 = 14 hours

Therefore, Morgan would have driven for 14 hours before Andre catches uo with him.

Answer:

Morgan walks 2 miles per hour.

Step-by-step explanation:

took the test. ;)

If the cost for 10 ounce of organic blueberry is $2. 70, the cost of 30 ounce of organic blueberry is represented by the equation x = 20y + 2.70 where y is the cost in dollars for one ounce of organic blueberry.

As x is the cost in dollar for 30 ounce of organic blueberry. For y is the cost in dollars for one ounce of organic blueberry, then

x = 30y + c

where c is the fixed cost

We know for 10 ounce of organic blueberry it costs $2.70. That is

2.70 = 10y + c

c = 2.70 - 10y

So x = 30y + 2.70 - 10y

x = 20y + 2.70

-- The question is incomplete, the complete question is as follows--

"The cost for 10 ounce of organic blueberry is $2. 70 which equation can be used to determine x the cost in dollars, for 30 ounces of organic blueberries.?"

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Answer:

1024

Step-by-step explanation:

4x4= 16

8x8= 64

sqrt4 x sqrt8

The square root of 4 is 2.

The square root of 8 is 2.83.

2x2.83=5.66

hope it helps!

A computation time expression ~ n, of means that the computation time increases in proportion to the size of the input.

This presents a computational complexity of O(n). Here 'O' stands for 'Big O Notation' and is used to denote an upper bound on the computational complexity of the algorithm.

That's, the algorithm's computational complexity is straightforwardly corresponding to the measure of the input information.

This shows that as the input estimate increments, the computational time will increment at the same rate.

 Linear time complexity is considered to be very efficient, and many algorithms aim to achieve this level of complexity. This is a relatively efficient computational complexity and is common in algorithms that require only one pass through the input data. 

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Answer: The answer is D.

The solution for the expression will be \(X = \dfrac{5\pm\sqrt{15}i}{4}\). The correct option is D.

A quadratic equation is a polynomial with a degree of 2 or the maximum power of the variable is 2 in quadratic equations. It has two solutions as its maximum power is 2.

Given that the quadratic equation is 2x² - 5x + 5 = 0. The equation can be solved as below,

\(X = \dfrac{-b\pm\sqrt{b^2-4ac}}{4a}\)

Substitute the values in the equation above,

\(X = \dfrac{-b\pm\sqrt{b^2-4ac}}{4a}\)

\(X = \dfrac{-(-5)\pm\sqrt{(-5)^2-4\times2 \times4}}{4\times4}\)

\(X = \dfrac{5\pm\sqrt{15}i}{4}\)

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Answer: To subtract mixed fractions with different denominators, you need to convert the mixed fractions to equivalent fractions with a common denominator. Once the fractions have a common denominator, you can simply subtract the numerators and keep the denominator the same.

Example:

the difference of 2 1/3 and 1 3/4 is 5/12.

Step-by-step explanation:

First, convert 2 1/3 to an improper fraction: 2 1/3 = 7/3

Next, convert 1 3/4 to an improper fraction: 1 3/4 = 7/4

Now, both fractions have the same denominator, 3. So, you can subtract the numerators:

7/3 - 7/4 = (7 * 4 - 7 * 3) / (3 * 4) = 28/12 - 21/12 = 7/12

Finally, convert the answer back to a mixed fraction: 7/12 = 7 ÷ 12 =  5/12.

Answer:

$550 was invested in the 4% account while $700 was invested in the 7% account

Step-by-step explanation:

Let the amount invested in each account be $x and $y respectively

The sum of these two is $1,250

Mathematically;

x + y = 1250 •••••(i)

Now, let’s work with the interest rate;

4% of x + 7% of y = 71

4x/100 + 7y/100 = 71

Multiply through by 100

4x + 7y = 7100 •••••(ii)

From i;

x = 1250-y

Substitute this into ii

4(1250-y) + 7y = 7100

5000 - 4y + 7y = 7100

3y = 7100-5000

3y = 2100

y = 2100/3

y = 700

Recall;

x + y = 1250

700 + x = 1250

x = 1250 - 700

x = 550

If it is the two ordered pairs that are given then use the following slope formula.

\(m = \frac{y_2-y_1}{x_2-x_1}\)

also known as m = rise / run

Step-by-step explanation:

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Answer:

4x12= 48. So what option gives you 48?

Step-by-step explanation:

Give the options

The difference between  the numbers 9.1 x 10⁹ and 7.8 x 10⁸ is 8.32 x 10⁹.

Given numbers are 9.1 x 10⁹ and 7.8 x 10⁸

Let's align the exponents by moving the decimal point to the right in the number with the smaller exponent, while incrementing the exponent accordingly.

We need to move the decimal point and increment the exponent of 7.8 x 10⁸ to match the exponent of 9.1 x 10⁹

7.8 x 10⁸ can be rewritten as 0.78 x 10⁹

Now that the exponents are aligned, we can subtract the coefficients:

9.1 x 10⁹ - 0.78 x 10⁹

= (9.1 - 0.78) x 10⁹

= 8.32 x 10⁹

Therefore, the difference between 9.1 x 10⁹ and 7.8 x 10⁸ is 8.32 x 10⁹.

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The solution to this given question should be -3/14. We can find it in the following manner.

−(14w+8)+8=3

-14w - 8 + 8 = 3

-14w = 3 (+8 and -8 get cancelled)

w = -3/14

This is how one can simplify the equation and solve for w.

None of the given options match the solution we obtained. Therefore, there may have been an error in the question or the answer choices.

To simplify simply means to make anything easier. In mathematics, simplifying an equation, fraction, or problem means taking it and making it simpler. Calculations and problem-solving techniques simplify the issue.

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Answer:

{u,v} = {4,1}

Step-by-step explanation:

Use analytic methods,

(a) The local extrema,

1) If f'(x) > 0 for all x on (a , c) and f'(x)<0 for all x on (c , b), then f(c) is a local maximum value.

2) If f'(x) < 0 for all x on (a , c) and f'(x)>0 for all x on (c , b), then f(c) is a local maximum value.

(b) The intervals on which the function is increasing

Write properties of function :

Increasing interval : ( - ∞ , 0 )

(c) The intervals on which the function is decreasing

Write properties of function :

Decreasing interval : ( 0 , ∞ )

Given that,

Use analytic methods (a) the local extrema, (b) the intervals on which the function is increasing, and (c) the intervals, then the function is,

A function's growing (or decreasing) periods match the periods when its derivative is positive (or negative). As a result, we can easily determine the intervals where a function increases or decreases by taking its derivative and analyzing it to determine if it is positive or negative.

Let f be continuous on an open interval (a , b) that contains a critical x-value.

1) If f'(x) > 0 for all x on (a , c) and f'(x)<0 for all x on (c , b), then f(c) is a local maximum value.

2) If f'(x) < 0 for all x on (a , c) and f'(x)>0 for all x on (c , b), then f(c) is a local maximum value.

(b) The intervals on which the function is increasing

Write properties of function :

Increasing interval : ( - ∞ , 0 )

(c) The intervals on which the function is decreasing

Write properties of function :

Decreasing interval : ( 0 , ∞ )

Therefore,

Use analytic methods,

(a) The local extrema,

1) If f'(x) > 0 for all x on (a , c) and f'(x)<0 for all x on (c , b), then f(c) is a local maximum value.

2) If f'(x) < 0 for all x on (a , c) and f'(x)>0 for all x on (c , b), then f(c) is a local maximum value.

(b) The intervals on which the function is increasing

Write properties of function :

Increasing interval : ( - ∞ , 0 )

(c) The intervals on which the function is decreasing

Write properties of function :

Decreasing interval : ( 0 , ∞ )

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