100.0 ml of a 0.530 m solution of kbr is diluted to 500.0 ml. what is the new concentration of the solution?

From the solubility table given, we can see that the solute that dissolves in 50 g of water at 20 °C is NaNO3, which has a solubility of 80 g/100 g H2O at 20 °C.

The more solute does not dissolve, which means that the solution is earlier saturated with NaNO3. Hence, any additional solute must be NaNO3 itself.

We can use the mass balance equation to get how much NaNO3 has been added to the solution before it became saturated:

total mass of NaNO3 added = total mass of saturated solution - mass of water - mass of initial NaNO3 = (50 g + 70 g) - 50 g - 70 g = 0 g

This means that 70 g of NaNO3 was basically added to the 50 g of water, and no additional NaNO3 can dissolve in the solution. Hence, the solute is NaNO3.

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Specific heat capacity of the metal  by the given values is 5.389 J/ g°C  

Mass of water = 140.0 g

Initial temperature of water = 20.0°C

Mass of a certain metal = 100.0 g

Initial temperature of metal = 100.0°C

Final temperature of water and metal = 95.0°C

Since the metal is at a higher initial temperature it will lose heat and the water having a lower initial temperature will gain heat.  

Thus, heat lost by metal = Heat gained by water  

formula: (mass metal )(initialT - finalT)( Cp metal ) = ( mass water )(finalT- initalT)( Cp water)  

After plugging in the given data we get,  

(100.0 g )(100.0 °C -95.0°C)( Cp metal) = (140.0g )(24.6°C-20.0°C) (4.184 J/g°C)  

(100.0g )(5.0C)( Cp metal )=(140.0g )(4.6°C)(4.184 J/g°C)  

(500 g°C) (Cp metal) = 2694.5 J  

(Cp metal) =5.389 J/ g°C  

Thus, specific heat capacity(Cp) of metal = 5.389 J/ g°C

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Answer:

This question lacks options, the options are;

A. Absorption of heat

B. A chemical change

C. A physical change

D. Formation of a new compound

The answer is C. A physical change

Explanation:

A physical change is a type of change that does not involve the chemical composition of the substance(s) involved. Physical changes affect the form but not the chemical content of a substance. Examples of physical changes are freezing, change of state, boiling etc.

In this question, a liquid is cooled during an investigation causing it to solidify. The cooling of this liquid represents a PHYSICAL CHANGE because the liquid state of the substance is only changed to a solid state but does not involve changing the chemical composition of the substance.

A liquid is cooled during an investigation physical change causing it to solidify.

Physical change occurs whenever there is difference in the appearance of any object observed.

In the question it is given that during an investigation a liquid is cooled down which results in the solidification of that liquid. During that change state of material changes from liquid state to the solid state, which is an example of a physical change.

Hence, in the question physical change occurs.

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The opinions of Aristotle and Democritus are not considered scientific theories because they were not empirical.

Science is empirical in nature. It depends on evidences obtained from rigorous experiments.

However, Aristotle and Democritus and were philosophers whose opinions were based on reasoning rather than empiricism.

Since their opinions were not empirical, they are not considered scientific theories.

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The strongest type of intermolecular force between solute and solvent in the solution of CH\(_{3}\)Cl (g) in CH\(_{3}\)OCH\(_{3}\) (g) is dipole-dipole interaction.

In  CH\(_{3}\)Cl, the molecule has a polar covalent bond between carbon and chlorine atoms. Chlorine is more electronegative than carbon, resulting in a partial negative charge on chlorine and a partial positive charge on carbon. In  CH\(_{3}\)OCH\(_{3}\) , the molecule is also polar due to the oxygen atom's higher electronegativity compared to carbon and hydrogen. This creates a dipole moment in both molecules.

In the solution, the positive end of the  CH\(_{3}\)Cl molecule interacts with the negative end of the  CH\(_{3}\)OCH\(_{3}\) molecule, forming dipole-dipole interactions. These intermolecular forces are stronger than London dispersion forces, which are present in all molecules but are typically weaker. Therefore, the strongest intermolecular force in this solution is dipole-dipole interaction.

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Answer:

The molar mass of \(NI_{3}\) is 394.719 g/mol.

Explanation:

This was on my periodic table.

The value of the expression 22 - 80% for one month can be calculated as follows:22 - 0.8 * 22 = 22 - 17.6 = 4.4Rounding off 4.4 to two decimal places gives 4.40.So, the answer to the expression 22 - 80% rounded to two decimal places is 4.40

.The value of the expression 2212% for one month can be calculated as follows:2212/100 = 2.64Rounding off 2.64 to two decimal places gives 2.64.

So, the answer to the expression 2212% rounded to two decimal places is 2.64.The value of the expression 95.00% for one month can be calculated as follows:95.00/100 = 0.95Rounding off 0.95 to two decimal places gives 0.95.So, the answer to the expression 95.00% rounded to two decimal places is 0.95.

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The acid-dissociation constants of phosphoric acid . The pH of a 2.5 M aqueous solution of phosphoric acid will be 0.5.

concentration of the first dissociation:

                           [H⁺] =√7.5x10⁻³ x 2.5 = 0.1369

concentration of the second dissociation:

                                             [H⁺] =√6.2x10⁻⁸ x 0.1369 = 9.21x10⁻⁵

concentration of the third dissociation:

                           [H⁺] =√4.2x10⁻¹³ x 9.21x10⁻⁵

                                        = 6.22x10⁻⁹

Total    [H⁺] = 0.3168

pH = -log₁₀( 0.3168 ) = 0.5

Strong and weak acids are distinguished by the acid dissociation constant (Ka). The corrosive separates more as the Ka increments. Solid acids should subsequently separate more in water. However, a weak acid is less likely to ionize and produce a hydrogen ion, resulting in a solution that is less acidic.

The corrosive separation consistent is an immediate consequence of the separation response's fundamental thermodynamics; the pKa esteem is corresponding to the standard Gibbs free energy change for the response.

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The equation that represent the given reaction is precipitation reaction. The correct option is 2.

When ammonium phosphate reacts with barium nitrate, it produces ammonium nitrate and barium phosphate that's a precipitate. Precipitation reactions are an instance of a double-displacement reaction. In a double substitute reaction, which also can be known as a double displacement reaction, both the cationic or the anionic quantities of compounds change their relative positions.

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Complete question-

the reaction of solutions of ammonium phosphate and barium nitrate forms a precipitate. this reaction is:

Option B is correct answer, when TΔS is 3 KJ the reaction is spontaneous reaction.

What is spontaneous reaction?

A spontaneous process in thermodynamics is one that happens without the system receiving any outside input. The time-evolution of a system in which it releases free energy and transitions to a lower, more thermodynamically stable energy state is a more technical definition (closer to thermodynamic equilibrium). Following the general convention for thermodynamic measurements, the sign convention for changes in free energy is as follows: a release of free energy from the system corresponds to a negative change in the system's free energy and a positive change in the surrounding free energy.

The reaction's spontaneity is determined by the Gibbs Free Energy (ΔG) value.

This value is calculated using the following equation, which depicts the link between temperature, entropy (ΔS), enthalpy (ΔH), and the Gibbs free energy (ΔG):

ΔG = ΔH - T(ΔS)

A positive ΔG value represents a non-spontaneous reaction,

A negative ΔG value  represents a spontaneous reaction.

Given ΔH = 2 KJ,

We get ΔG negative only when TΔS is 3 KJ.

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The microbiologist needs to combine 9.39 mL of equimolar K2HPO4 and 690.61 mL of equimolar KH2PO4 to make 700.0 mL of pH 7.00 buffer.

To set up the pH 7.00 cushion, the microbiologist needs to consolidate equimolar measures of the corrosive (H2PO4-) and its form base (HPO42-), which can be accomplished utilizing the Henderson-Hasselbalch condition:

pH = pKa + log([A-]/[HA])

Where pH is the ideal pH of the cradle, pKa is the corrosive separation steady of the corrosive, and [A-]/[HA] is the proportion of the centralizations of the form base to the corrosive.

For this situation, the pKa1 an incentive for phosphoric corrosive is 2.15. Since the cushion should be arranged utilizing equimolar measures of K2HPO4 and KH2PO4, the [A-]/[HA] proportion is 1. Consequently, we can rework the Henderson-Hasselbalch condition to address for the proportion of the volumes of the two arrangements:

[V(HPO42-)/V(H2PO4-)] = [A-]/[HA] = 1

Subbing the pKa worth and settling for the proportion, we get:

[V(HPO42-)/V(H2PO4-)] = \(10^(pH-pKa)\) = \(10^(7.00-2.15)\) = 73.5

Since the volumes of the two arrangements should amount to 700.0 mL, we can communicate the volume of one arrangement as far as the other:

V(H2PO4-) = 700.0 mL/(1 + 73.5) = 9.39 mL

V(HPO42-) = 700.0 mL - V(H2PO4-) = 690.61 mL

Thusly, the microbiologist needs to consolidate 9.39 mL of the equimolar K2HPO4 arrangement with 690.61 mL of the equimolar KH2PO4 answer for get ready 700.0 mL of the pH 7.00 cradle.

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The complete question is:

A microbiologist is preparing a medium on which to culture E. coli bacteria. She buffers the medium at pH 7.00 to minimize the effect of acid-producing fermentation. What volumes of equimolar aqueous solutions of K_2HPO_4 and KH_2PO_4 must she combine to make 250.0 mL of the pH 7.00 buffer? K_a values for phosphoric acid: K_a_1 = 7.2 times 10^-3 K_a_2 = 6.3 times 10^-8 K_a_3 = 4.2 times 10^-13 Volume H_2PO_4^- = mL Volume HPO_4^2- = mL

Answer:

O 9 carbon atoms, only

Explanation:

Prefix: non- simply means 9.

Suffix: -ene means double bond, -yne means triple bond, and -ane means single bonded carbons.

The pH of a 0.5 M solution of sodium bisulfate (\(NAHSO_{4}\)) is approximately 1.

pH is a measure of the acidity or basicity of a solution, with a pH of 7 considered neutral, a pH less than 7 considered acidic, and a pH greater than 7 considered basic. The pH is determined by the concentration of hydrogen ions (H+) in the solution.

Sodium bisulfate (\(NAHSO_{4}\)) is a strong acid, meaning that it dissociates completely in water to form hydrogen ions (H+) and sulfate ions (\(SO_{4} ^{2-}\)). The concentration of hydrogen ions in a 0.5 M solution of sodium bisulfate is equal to the concentration of the bisulfate ions, meaning that the pH of the solution would be around 1.

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Answer:

D

Explanation:

I took the test

Answer:

D took the test

Explanation:

The reaction flask contains the mass of 1000.176 g. This calculated using the concept of Mole.

CaCO3 + 2HCl ----->  CaCl2 + CO2 + H2O.

For 1 mole of CaCO3 require 2 moles of HCL to form 1 mole CaCL2 and 1 mole of CO2.

The Molar mass of CaCO3  is 100.0869 g /mole.

The Molar mass of HCL is 36.46 g/mole

The Molar mass of CO2 is 44.01 g/mole.

As 0.21 g of carbon dioxide is given off,

The Moles of CO2 given off =0.21/44.01

The Moles of CO2 given off = 0.00477 moles.

The ratio of Moles of CaCO3 : HCL : CO2 is 1: 2 : 1.

As 0.00477 moles of CO2 is given off, that means 0.00477 moles of CaCO3 and 0.00952 moles of Hydrochloric acid is reacted.

So, the moles = mass of solute /molar mass

For calcium carbonate,

0.00477 moles of calcium carbonate =mass of CaCO3 /100.0869

Mass of CaCO3 becomes 0.477 g

So , 0.477 g of calcium carbonate is reacted to form 0.21 g  of CO2.

The unreacted mass of calcium carbonate =1 - 0.477 = 0.523 g

For, Hydrochloric acid,

Moles = mass of HCL / molar mass of HCL

0.00952 = mass of HCL /36.46

Mass of HCL = 0.347 g.

Mass of Hydrochloric acid reacted = 0.347 g form 0.21 g CO2.

The unreacted mass of hydrochloric acid = 1000 - 0.347

The unreacted mass of HCL= 999.653 g

Total left mass in reaction  flask= unreacted mass of CaCO3 + unreacted mass of Hydrochloric acid

Total left mass in reaction flask is,

                    = 0.523 +999.653

Total left mass in reaction flask is 1000.176 g.

So The reaction flask contains 1000.176 g.

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To accurately classify the changes in the PhET simulation's effect on the wavelength, a description of the available changes and their respective bins is necessary In general, changes that can affect the wavelength in a wave simulation include adjusting the frequency, amplitude, speed, or medium properties.

Each of these changes can have a specific effect on the wavelength of the wave. For example, increasing the frequency generally results in a shorter wavelength, while decreasing the frequency leads to a longer wavelength. Similarly, altering the amplitude may not directly affect the wavelength but can impact the intensity or energy of the wave.

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Answer:

CO32−

Explanation:

We have to consider the valencies of the polyatomic ions involved. Recall that it is only a polyatomic ion with a valency of -2 that can form a compound which requires two sodium ions.

When we look closely at the options, we will realize that among all the options, only CO32− has a valency of -2, hence it must be the required answer. In order to be double sure, we put down the ionic reaction equation as follows;

2Na^+(aq) + CO3^2-(aq) ---------> Na2CO3(aq)

Answer:

A).  CO32−

Explanation:

Technetium-99m is a radioisotope that is widely used in nuclear medicine for various imaging studies. It is usually produced through a process called generator system from the decay of its parent isotope, Molybdenum-99 (Mo-99).

How technetium-99m is generated:Technetium-99m is generated by a process called a generator system from the decay of its parent isotope, Molybdenum-99 (Mo-99). This generator system is essentially a column packed with a gel-like substance, which is usually made of alumina, silica, or another material. The column contains Mo-99, which is produced in a nuclear reactor, and its daughter isotope Technetium-99m (Tc-99m).The Mo-99 decays into Tc-99m by beta decay, emitting a beta particle and a neutrino.

As a result, Tc-99m is separated from Mo-99 by using a saline solution or another eluant to flush the column. The Tc-99m-containing eluant is then used for imaging studies.There are several advantages to using Tc-99m for imaging studies. It has a short half-life of only six hours, which means that it does not stay in the body for a long time and is eliminated quickly. This makes it safer for patients than isotopes with longer half-lives. Additionally, Tc-99m emits gamma rays, which can be detected by imaging equipment such as gamma cameras. This allows for high-quality imaging studies that can help diagnose a wide range of medical conditions.

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The Iupac Name of given three compounds are 3,4,5-trimethylheptane, 2,2,3,3-tetramethylpentane and 2,2- dimethyl-3-ethylpentane.

For (1),

The longest straight chain have 7 carbon compound and having single bond, suffix of this compound is Heptane. Now there are three functional group of methyl there for prefix is trimethyl. Overall the name of compound is 3,4,5-trimethylheptane.

The longest straight chain have 5 carbon compound and having single bond, suffix of this compound is pentane. Now there are four functional group of methyl there for prefix is tetramethyl. Overall the name of compound is 2,2,3,3-tetramethylpentane.

The longest straight chain have 5 carbon compound and having single bond, suffix of this compound is pentane. Now there are three functional group of methyl and ethyl so they write according to alphabetic order. Overall the name of compound is 2,2- dimethyl-3-ethylpentane.

Thus, we concluded that the The Iupac Name of given three compounds are 3,4,5-trimethylheptane, 2,2,3,3-tetramethylpentane and 2,2- dimethyl-3-ethylpentane.

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Answer:

relating to the periodic table of the elements or the pattern of chemical properties that underlies it.

Explanation:

Answer:

Periodic refers to properties that repeat at certain intervals. Explanation: The elements on the periodic table repeat at intervals called periods.

Explanation:

a) The acetate ion concentration is computed as follows:

[Acetate] = C1 * V1 + V2 = 0.5 M * 8 + 10 = 0.4 M

b) The buffer components' molar ratio is computed as follows:

Salt / acid is equal to 10 (pH - pKa) = 10 (3.6 - 3.75) = 0.7.

It has:

I) n Acid = 0; n Salt = -0.7;

ii) M*V = 0.03 M*0.25 L = 0.015 Salt + Acid

When a system of equations is used, you get:

Format n = 0.006 moles

Acid equals 0.009 mol.

There is a need for 0.009 mol of formic acid.

The sodium salt of acetic acid is called sodium acetate, commonly known as NaOAc or CH3COONa. There are numerous applications for this tasteless, deliquescent salt.

It is feasible to add sodium acetate to goods like heating pads, food, businesses, and concrete. As an electrolyte replenisher when given intravenously, sodium acetate is essential in medicine. The majority of the time, treating sodium levels in hyponatremic patients is advised.

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Based on the recipe for preparing the food, the limiting ingredient is the 2 cans of tomatoes.

The recipe for the food is given below:

Hence, 2 cans of diced tomatoes require 1 cup of green beans, 1/2 cup of pasta, 1 can of beans, and 4 of cups broth.

Hence, after, the 2 cans of diced tomatoes are used up, no more food can be prepared.

A limiting reagent or limiting ingredient is used up when cooking, hence, the 2 cans of tomatoes are the limiting ingredient.

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3.10 moles of iron will produce 4.65 moles of iron (III) oxide  are produced.

What is oxide  ?

Oxide is a compound formed when an element combines with oxygen. It usually has the form of a solid and is often found naturally in the environment. Oxides can be either ionic or covalent in nature, depending on the elements involved.

Examples of oxides are iron oxide, carbon dioxide, and sulfur dioxide. Oxides can also be created synthetically in laboratories. Oxides have many uses in industry, including as catalysts, pigments, and in the production of ceramics.

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Answer:

\(\boxed {\boxed {\sf molarity \approx 0.722 \ M \ HCl}}\)

Explanation:

Molarity is the concentration measurement equal to moles per liter.

\(molarity=\frac{moles}{liters}\)

We have 26.0 grams of HCl and 1.00 liters of water. We must convert grams of HCl to moles.

To convert from grams to moles, the molar mass is used. Usually we find these values on the Periodic Table, but they are already provided. The molar mass of hydrochloric acid is 36.0 grams per mole. Use this number as a ratio.

\(\frac {36.0 \ g \ HCl}{ 1 \ mol \ HCl}\)

Multiply by the given number of grams: 26.0

\(26.0 \ g \ HCl *\frac {36.0 \ g \ HCl}{ 1 \ mol \ HCl}\)

Flip the ratio so the grams of hydrochloric acid cancel.

\(26.0 \ g \ HCl *\frac {1 \ mol \ HCl}{ 36.0 \ g \ HCl}\)

\(26.0 *\frac {1 \ mol \ HCl}{ 36.0 }\)

\(\frac {26.0}{ 36.0 } \ mol \ HCl = 0.72222222222 \ mol \ HCl\)

Now we know the moles and liters.

Substitute these values into the molarity formula.

\(molarity = \frac {0.72222222222 \ mol \ HCl}{1.00 \ L }\)

\(molarity = 0.72222222222 \ mol \ HCl/L\)

The original measurements of grams and liters have 3 significant figures, so our answer must have the same. For the number we calculated, that is the thousandth place.

The 2 tells us to leave the 2 in the thousandth place.

\(molarity \approx 0.722 \ mol \ HCl/ L\)

1 mole per liter is equal to 1 molar, or M. Change the units.

\(molarity \approx 0.722 \ M \ HCl\)

The molarity of this solution is approximately 0.722 M HCl

Answer:

A heterogeneous mixture is simply any mixture that is not uniform in composition - it's a non-uniform mixture of smaller constituent parts. By contrast, a mixture that is uniform in composition is a homogeneous mixture.

Answer:

Tbe reddish brown substance might be the rust that formed overtime in a iron tap and over the course of time mixed with other dust and particles it might have formed another substance .

The reddish brown substance is iron oxide which is formed by the reaction of iron materials with water and air. This oxide layer above the surface of metallic parts is called rust.

The Fe is a reddish metal more reactive towards the air and water as well. Fe is a very common in the manufacturing of many household materials. However, by the action of air and water these metallic parts undergo corrosion.

Corrosion is a chemical change involving the formation of oxide layer over the metallic surface which eventually corrode the substance and make it unusable.

Fe reacts with oxygen of water or air forming the reddish brown iron oxide Fe₂O₃ that is what called the rust. Rust can be seen in needles, vehicle parts made of iron etc.

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There are 24 valance electrons in the compound.

We know that the valence electrons are those that are found on the valence shell of an atom. There are four atoms that can be seen in the compound that is under consideration. The atoms are selenium, bromine (2 atoms) and oxygen.

Given that there are seven valence electrons in bromine and six valence electrons in oxygen and selenium. We have;

2(7 electrons of bromine) + 6 electrons of oxygen + 4 electrons of Se

= 24 electrons

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Answer:

it is D

Explanation

Electrons are a type of subatomic particle with a negative charge. ... Protons and neutrons have approximately the same mass, but they are both much more massive than electrons (approximately 2,000 times as massive as an electron).

Without ampicillin in the agar, any bacteria that are sensitive to ampicillin will be able to grow on the agar.

This means that both the desired bacteria (if you were using ampicillin resistance as a selection marker) and any unwanted contaminants or bacteria that may have been present in the sample will grow. In other words, the specificity of the agar will be lost and it will be harder to isolate and identify the specific bacteria of interest.

                              Ampicillin is an antibiotic that specifically inhibits the growth of bacteria that have not acquired resistance to it. Without ampicillin in the agar, any bacteria that are sensitive to ampicillin will be able to grow and replicate, including potential contaminants or unwanted bacteria. This could lead to false positives or inaccurate results in experiments that require selective growth of specific bacteria.

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