100 POINTS +BRAINLIEST PLZ ANSWER ASAP

Eduardo looks at stars through his telescope. He says that the star Sirius is brighter than the star Rigel. In reality, Rigel has a greater absolute brightness than Sirius. What can explain Eduardo's observation?

A. Sirius is much closer to Earth than Rigel
B. Rigel is much closer to Earth than Sirius
C. Sirius is a hotter star than Rigel.
D. Rigel is a hotter star than Sirius,p​

2.592e+9. I looked it up on

Answer:

2592000000 Milliseconds

Explanation:

To calculate 30 Days to the corresponding value in Milliseconds, multiply the quantity in Days by 86400000 (conversion factor). In this case we should multiply 30 Days by 86400000 to get the equivalent result in Milliseconds:

30 Days x 86400000 = 2592000000 Milliseconds

I took it from https://whatisconvert.com/30-days-in-milliseconds

Answer:

A Full Moon

Explanation:

If it is the same image I had it would be a full moon since there are no shadows on the moon. This means the moon gets full sunlight

In the case of the equilibrium reaction provided, if the concentration of Co(H2O)2+ is increased, the reaction will shift to the right in order to consume the excess Co(H2O)2+ and produce more CoCl2 and H2O.

Conversely, if the concentration of CoCl2 is increased, the reaction will shift to the left in order to consume the excess CoCl2 and produce more Co(H2O)2+ and Cl- ions.

According to Le Chatelier's principle, a change in concentration of one or more of the reactants or products of a chemical reaction at equilibrium will cause a shift in the equilibrium position to counteract the change and re-establish equilibrium.

Specifically, if the concentration of one of the reactants is increased, the reaction will shift in the direction that consumes that reactant in order to restore equilibrium.

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Answer:

element A has a mass of 2 units, while an atom of element B

has a mass of 5 units, what would be the mass of the

compound A3 B2

Explanation:

The two components of the mixture of the liquids hexane and octane, which are miscible in all ratios, would be best separated using the distillation process.

Hexane and octane mixture is added to and heated in a distillation flask. Hexane vapours flow through and condense in the condenser due to its lower boiling point (69°C) than octane. However, octane, which has a higher boiling point than hexane (126°C), condenses and runs back into the condenser flask. The technique of selectively boiling and condensing to remove the constituents or chemicals from a liquid mixture is known as distillation, or classical distillation. Heating solid materials to create gaseous products is known as dry distillation.

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Answer: argon

What must happen to a sulfur atom in order for it to have an electron arrangement similar to that of a noble gas? Answer: The noble gas closest to sulfur is argon. A sulfur atom gains two electrons to have an electron arrangement similar to that of argon.

Explanation:

1.  the final concentration of NaOH after adding 125 mL of water to 45.3 mL of 0.71 M NaOH solution is approximately 0.189 M.

2.  the final concentration of KOH after adding 550 mL of water to 125 mL of 3.01 M KOH solution is approximately 0.557 M.

1.) If 125 mL of water is added to 45.3 mL of a 0.71 M NaOH solution, the resulting solution will be a diluted NaOH solution. The addition of water will increase the total volume while reducing the concentration of NaOH. To determine the final concentration of NaOH, we need to consider the conservation of moles.

First, let's calculate the moles of NaOH in the initial solution:

moles of NaOH = volume (in L) × concentration (in M)

moles of NaOH = 0.0453 L × 0.71 M = 0.0321433 moles

After adding 125 mL (0.125 L) of water, the total volume of the solution becomes 0.0453 L + 0.125 L = 0.1703 L.

To find the final concentration, we divide the moles of NaOH by the total volume:

final concentration of NaOH = moles of NaOH / total volume

final concentration of NaOH = 0.0321433 moles / 0.1703 L ≈ 0.189 M

Therefore, the final concentration of NaOH after adding 125 mL of water to 45.3 mL of 0.71 M NaOH solution is approximately 0.189 M.

2.) If 550 mL of water is added to 125 mL of a 3.01 M KOH solution, the resulting solution will also be a diluted solution. Again, we will apply the conservation of moles to determine the final concentration of KOH.

First, calculate the moles of KOH in the initial solution:

moles of KOH = volume (in L) × concentration (in M)

moles of KOH = 0.125 L × 3.01 M = 0.37625 moles

After adding 550 mL (0.55 L) of water, the total volume of the solution becomes 0.125 L + 0.55 L = 0.675 L.

To find the final concentration, divide the moles of KOH by the total volume:

final concentration of KOH = moles of KOH / total volume

final concentration of KOH = 0.37625 moles / 0.675 L ≈ 0.557 M

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The amino acid that is not glucogenic among the options provided is leucine (option e). Leucine is one of the branched-chain amino acids (BCAAs) and is primarily ketogenic, meaning it is metabolized to produce ketone bodies rather than glucose.

The remaining options (alanine, aspartate, glutamate, and glycine) are all glucogenic amino acids, meaning they can be converted into intermediates of glucose metabolism.

Among the amino acids you listed, leucine (option e) is the only one that is not glucogenic. Leucine is a branched-chain amino acid (BCAA) that undergoes primarily ketogenic metabolism, meaning it is primarily converted into acetyl-CoA and acetoacetate, leading to the production of ketone bodies. It does not contribute significantly to glucose production.

On the other hand, alanine (option a), aspartate (option b), glutamate (option c), and glycine (option d) are all glucogenic amino acids. They can be converted into intermediates of glucose metabolism, such as pyruvate, oxaloacetate, and glyceraldehyde-3-phosphate, which can enter the gluconeogenic pathway to produce glucose.

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According to the question the maximum amount of phosphate remaining in solution is 5.6016 mol.

Phosphate is an inorganic chemical compound that contains phosphorus, oxygen and other elements. It is a key component of DNA and RNA, and serves as an important energy source for cells and organisms.

To calculate the maximum amount of phosphate remaining in solution, we need to first determine the amount of barium iodide needed to reach the desired concentration of barium ion.
Using the equation:
Concentration of Barium Ion = Amount of Barium Iodide/Volume of Solution
We can calculate that the amount of barium iodide required is 0.0576 mol.
Next, we need to calculate the amount of phosphate that is consumed when the barium iodide is added. According to the solubility product of barium phosphate, the amount of phosphate that is consumed is equal to the amount of barium iodide added, 0.0576 mol.

Therefore, the maximum amount of phosphate remaining in solution is
125 ml x 0.0463 mol/L - 0.0576 mol
= 5.6016 mol.

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We don't have to find the volume .We have to write the formula to find

\(\\ \bull\tt\longmapsto PV=nRT\)

\(\\ \bull\tt\longmapsto V=\dfrac{nRT}{P}\)

Answer:

The oxygen we breathe is not in atomic form. It is in its molecular form, which is two oxygen atoms joined together by bonds, and between its two atoms, this molecule has 16 protons, 16 electrons, and most commonly 16 neutrons. Answer 5: An oxygen atom contains eight protons.

Answer:

The acid mist is known as laze - a term combining the words lava and haze - when laze and sea water combine. Laze is potentially deadly if inhaled and can be hot and corrosive. If anyone goes near it, they can experience breathing difficulties and irritation of their eyes and skin.

Explanation:

hope it helps :)

Answer:

Cytokinesis

Explanation:

The heat of fusion is the amount of heat energy needed to turn anything solid into a liquid. There is a formula, Q = mHf. Because matter doesn't affect temperature, the temperature is not a factor.

There is no increase in the kinetic energies of the particles, and hence no rise in temperature, because the energy required for phase shifts is employed to break bonds. Similarly, energy is required to evaporate a liquid to defeat the attraction forces between the liquid's particles.

The energy that is given during a change in the state of matter is used to alter the binding energies rather than boost the kinetic energy of the molecules. As a result, the temperature doesn't change.

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The empirical formula for the compound is C2H4O3.

The empirical formula of the compound can be determined by analyzing the mass of the elements present in the combustion products. In this case, the mass of carbon, hydrogen, and oxygen can be calculated as follows:

Mass of carbon = Mass of CO2 = 33.31 g

Mass of hydrogen = Mass of H2O = 13.64 g

Mass of oxygen = Mass of the compound - (Mass of carbon + Mass of hydrogen) = 28.78 g - (33.31 g + 13.64 g)

By dividing the masses of each element by their respective molar masses, we can determine the moles of each element. Then, we divide the moles by the smallest mole value to obtain the empirical formula.

From the calculations, the empirical formula for the compound is C2H4O3.

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3.99 teaspoons should be administered to a person weighing 220 pounds

The adult dose of a solution is 0.2 mL/kg of body weight to be administered once daily.

If a person weighs 220 pounds, you have to first convert their weight from pounds to kilograms before you can calculate the dosage.

You should be given the conversion factor of 1 teaspoon = 5 milliliters (mL) or 1 mL

= 0.2 teaspoons (tsp).

Using the conversion factor of pounds to kilograms,1 pound = 0.453592 kilograms

220 pounds = 99.7913 kilograms

Dose = 0.2 mL/kg x 99.7913 kg = 19.95826 mL

To convert the dose from milliliters to teaspoons, use the conversion factor of 1 teaspoon = 5 milliliters.

19.95826 mL × 1 tsp / 5 mL = 3.991652 tsp

Therefore, 3.99 teaspoons should be administered to a person weighing 220 pounds, given the adult dose of 0.2 mL/kg of body weight to be administered once daily.

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Dimensional analysis can only be used for time, distance, mass, speed, volume, and chemical quantities: False.

A dimensional analysis can be defined as an analysis of the relationships that exist between different physical quantities by identifying their fundamental (base) quantities, especially for the purpose of inferences.

Dimensional analysis is also referred to as unit-factor method or factor-label method and it is typically used to convert a different type of unit to another.

Generally, dimensional analysis can only be used for the following physical quantities:

In conclusion, a dimensional analysis cannot be used for chemical quantities such as a mole i.e it has no dimensional formula.

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Answer:

\(\lambda=6.56x10^{-7}m\)

Explanation:

Hello there!

In this case, it possible to use the Rydberg equation in order to calculate the wavelength for this transition from n=3 to n=2 as shown below:

\(\frac{1}{\lambda} =R_H(\frac{1}{n_f^2}-\frac{1}{n_i^2} )\)

Thus, we plug in the corresponding energy levels and the Rydberg constant to obtain:

\(\frac{1}{\lambda} =10973731.6m^{-1}(\frac{1}{2^2}-\frac{1}{3^2} )\\\\\frac{1}{\lambda} =1524129.4m^{-1}\\\\\lambda=\frac{1}{1524129.4m^{-1}} \\\\\lambda=6.56x10^{-7}m\)

Best regards!

By the process of natural selection, individuals in Finch 1 will evolve over time to resemble individuals in Finch 2.

Natural selection is the process by which individuals who possess certain features or structures that make them better suited to their environment are able to survive and reproduce in their environment while those who do not have such features die off.

Since the preferred food for Finch 1 has become scarce due to drought, individuals in Finch 1 who have features that enable them eat larger seed will be naturally selected for survival , most population in Finch will be composed of such individuals.

Therefore, natural selection will cause individuals in Finch 1 to evolve over time to resemble individuals in Finch 2.

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To calculate the mass percent of the acid in the original solution, you must first calculate the moles of acid used in the reaction. Since oxalic acid has a molar mass of 90.03 g/mol, 13.1 g of the acid is equivalent to 0.145 moles of acid.

Then, you can use the moles of acid to calculate the moles of base required to neutralize it. Since 28.05 ml of 0.103 M base was used, this is equivalent to 0.0288 moles of base. Since the reaction involves a 1:2 mole ratio of acid to base, the moles of acid used was twice the moles of base, or 0.145 moles.

Finally, you can calculate the mass percent of the acid in the original solution by dividing the mass of the acid used (13.1 g) by the total mass of the solution (13.1 g + 28.05 ml of 0.103 M base). This gives a mass percent of 32.2%.

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Answer:

Increasing the H+/H3O+ will decrease the pH, while increasing the OH- ions will increase the pH

Explanation:

so pH=-log(H), which means that the smaller H gets to 0, the more the pH rises. The larger the H+ gets, the smaller the pH
if H is 1, then pH is 0
if H is 0.1, then pH is 1
if H is 0.01, then pH is 2
and so on
if H is 0.00000000000001, then the pH is 14
When OH goes up, H goes down, so
if OH is 0.00000000000001, then the ph is 0
if OH is 0.0000000000001, then the pH is 1
and so on
If the OH is 1, then the pH is 14

Answer:

A diffraction.

Explanation:

Diffraction takes place with sound; with electromagnetic radiation, such as light, X-rays, and gamma rays; and with very small moving particles such as atoms, neutrons, and electrons, which show wavelike properties.

After one day, approximately 8.67mg of the sample will be remaininga) The function that models the sample of Technetium-99 is given by

f(t) = P₀e^(-kt)

Where,P₀ = initial quantity = 100mgk = decay constantt = timef(t) = remaining quantity after t time.

A half-life of 6 hours is given. The decay constant can be found using the half-life formula:

T½ = (ln 2)/k6

= (ln 2)/kk

= (ln 2)/6f(t)

= P₀e^(-kt)f(t)

= 100e^(-0.1155t)mg

b) After one day, 24 hours = 4 half-lives Remaining amount,

f(t) = P₀e^(-kt)f(24)

= 100e^(-0.1155 × 24)

= 100e^(-2.772)

≈ 8.67mg

After one day, approximately 8.67mg of the sample will be remaining. The function that models the sample is

f(t) = 100e^(-0.1155t), where t is time in hours and f(t) is the remaining quantity in milligrams.

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After one day, approximately 8.67mg of the sample will be remaininga) The function that models the sample of Technetium-99 is given by

f(t) = P₀e^(-kt)

Where,P₀ = initial quantity = 100mgk = decay constantt = timef(t) = remaining quantity after t time.

A half-life of 6 hours is given. The decay constant can be found using the half-life formula:

T½ = (ln 2)/k6

= (ln 2)/kk

= (ln 2)/6f(t)

= P₀e^(-kt)f(t)

= 100e^(-0.1155t)mg

b) After one day, 24 hours = 4 half-lives Remaining amount,

f(t) = P₀e^(-kt)f(24)

= 100e^(-0.1155 × 24)

= 100e^(-2.772)

≈ 8.67mg

After one day, approximately 8.67mg of the sample will be remaining. The function that models the sample is

f(t) = 100e^(-0.1155t), where t is time in hours and f(t) is the remaining quantity in milligrams.

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Given :

Volume of water , V = 63 ml .

To Find :

The volume of the water in \(dm^3\) .

Solution :

We know , 1 ml of water is equal to \(1 \ cm^3\) .

So , 63 ml of water is :

\(V=63 \ cm^3\)     .... equation 1 .

Now , 1 cm = 0.1 dm

Putting value of 1 cm in equation 1 .

We get ,

\(V=63\times (0.1\ dm)^3\\V=63\times 10^{-3}\ dm^3\\V=6.3\times 10^{-2}\ dm^3\)

Therefore , the volume of 63 ml water in \(dm^3\) is \(6.3\times 10^{-2}\ dm^3\) .

Hence , this is the required solution .

Answer:

380 mL

Explanation:

A chemist must prepare 925 mL of 325 mM aqueous copper(II) sulfate working solution. He'll do this by pouring out some 0.792 M aqueous copper(II) sulfate stock solution into a graduated cylinder and diluting it with distilled water. Calculate the volume in mL of the copper(II) sulfate stock solution that the chemist should pour out. Be sure your answer has the correct number of significant digits.

Step 1: Given data

Step 2: Convert "C₂" to M

We will use the conversion factor 1 M = 1000 mM.

325 mM × (1 M/1000 mM) = 0.325 M

Step 3: Calculate the inital volume

We will use the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂/C₁

V₁ = 0.325 M × 925 mL/0.792 M

V₁ = 380 mL

Answer: D is ur answer

Hope it helps chu!

Have a good day, My fellow bean UwU

Answer:

Atom 1 after gaing 2 electrons have -2 charge

And atom 2 after donating 2 electrons have +2 charge

Explanation:

An imbalance in the lonization energy leads to the distribution of charge in molecules. A polar molecule is one that has an unequal distribution of charges, causing it to have a positive end and a negative end.

In the case of an uneven distribution of charges, which molecules are present?

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