100 POINTS AND BRAINLIST!




Question
Why does the sun appear so much larger and brighter than the other stars that are seen from Earth?
Responses

The sun is much larger than other stars. [A]

The sun appears only during the daytime. [B]

The sun is closer to Earth than other stars. [C]

The sun burns more brightly than other stars. [D]

When the air around you is densely packed, it means the pressure is high.

The atmospheric pressure is directly proportional to air density.

When the air around a place is densely packed, it is an indication of high atmospheric pressure.

On the other hand, if the air around is loosely packed, it means the atmospheric pressure is also low.

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306.178 liters is the volume of O2 at STP, required for the complete combustion of 125g octane (\(C_{8}H_{18}\)) to \(CO_{2}\) and H20

To calculate the volume of \(O_{2}\) required for the complete combustion of octane (\(C_{8}H_{18}\)) to \(CO_{2}\) and \(H_{2}O\) at STP (Standard Temperature and Pressure), we need to consider the stoichiometry of the balanced chemical equation.

The balanced equation for the combustion of octane is:

\(C_{8}H_{18}\) + 12.5\(O_{2}\) -> 8\(CO_{2}\) + 9\(H_{2}O\)

From the equation, we can see that 1 mole of octane requires 12.5 moles of \(O_{2}\) to completely combust. The molar mass of octane (\(C_{3}H_{18}\)) is approximately 114.22 g/mol.

To calculate the moles of octane, we divide the given mass by the molar mass:

Moles of octane = 125 g / 114.22 g/mol ≈ 1.093 mol

Since the molar ratio between octane and \(O_{2}\) is 1:12.5, the moles of \(O_{2}\)required can be calculated as:

Moles of \(O_{2}\) = 1.093 mol * 12.5 ≈ 13.663 mol

Now, we can use the ideal gas law, PV = nRT, to calculate the volume of \(O_{2}\) at STP. At STP, the temperature is 273 K, and the pressure is 1 atm.

Using the molar volume of an ideal gas at STP (22.4 L/mol), the volume of \(O_{2}\) required is:

Volume of \(O_{2}\) = Moles of \(O_{2}\) * Molar volume = 13.663 mol * 22.4 L/mol ≈ 306.178 L

Therefore, approximately 306.178 liters of \(O_{2}\) at STP would be required for the complete combustion of 125 grams of octane (\(C_{8}H_{18}\)) to \(CO_{2}\) and \(H_{2}O\)

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The boiling point of liquid octane when the external pressure is 0.727 atm is 388.9 K.

What do you mean by boiling point?

Boiling point is the temperature at which the vapor pressure of a liquid equals the external pressure acting on the surface of the liquid, and the liquid starts to boil and transform into a gas. At the boiling point, the molecules in the liquid gain enough kinetic energy to overcome the intermolecular forces holding them together, and they escape from the surface of the liquid as gas molecules. The boiling point of a substance is a physical property that is influenced by the strength of the intermolecular forces, as well as external factors such as pressure and atmospheric conditions. The boiling point can be used to identify and characterize different substances.

We can use the Clausius-Clapeyron equation to solve this problem:

ln(P2/P1) = (-ΔHvap/R) x (1/T2 - 1/T1)

where P1 and T1 are the normal boiling point conditions (1 atm and 399 K), P2 is the external pressure (0.727 atm), ΔHvap is the molar heat of vaporization (36.5 kJ/mol), R is the gas constant (8.31 J/mol·K), and we need to solve for T2.

First, let's convert the molar heat of vaporization to J/mol:

ΔHvap = 36.5 kJ/mol = 36,500 J/mol

Now we can plug in the values and solve for T2:

ln(0.727/1) = (-36,500/R) x (1/T2 - 1/399)

ln(0.727) = (-36,500/8.31) x (1/T2 - 1/399)

-0.3176 = -4396.4 x (1/T2 - 0.0025)

1/T2 - 0.0025 = 0.0000723

1/T2 = 0.0025723

T2 = 388.9 K

Therefore, the boiling point of liquid octane when the external pressure is 0.727 atm is 388.9 K.

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Hey there!

Mass = ?

volume = 105 mL

Density = 2.26 g/mL

Therefore:

D = m / V

2.26 = m / 105

m = 2.26 * 105

m = 237.3 g

Hope this helps!

Answer:

2.5 % butane, 42.2 % pentane and 55.3 % hexane

Explanation:

Hello,

In this case, the mass balance for each substance is given by:

\(Butane:z_bF=y_bD+x_bB\\\\Pentane: z_pF=y_pD+x_pB\\\\Hexane: z_hF=y_hD+x_hB\)

Whereas \(y\) accounts for the fractions at the outlet distillate and \(x\) for the fractions at the outlet bottoms. Moreover, with the 90 % recovery of butane, we can write:

\(0.9=\frac{y_bD}{z_bF}\)

So we can compute the product of the molar fraction of butane at the distillate by total distillate flow by assuming a 100-mol feed:

\(y_bD=0.9*z_bF=0.9*0.2*100mol=18mol\)

The total distillate flow:

\(y_bD=18mol\\\\D=\frac{18mol}{0.95} =18.95mol\)

And the total bottoms flow:

\(F=D+B\\\\B=F-D=100mol-18.95mol=81.05mol\)

Next, by using the mass balance of butane, we compute the molar fraction of butane at the bottoms:

\(x_b=\frac{z_bF-y_bD}{B} =\frac{0.2*100mol-18mol}{81.05} =0.025\)

Then, the molar fraction of pentane and hexane:

\(x_p=\frac{z_pF-y_pD}{B} =\frac{0.35*100mol-0.04*18.95mol}{81.05} =0.422\)

\(x_h=\frac{z_hF-y_hD}{B} =\frac{(1-0.2-0.35)*100mol-(1-0.95-0.04)*18.95mol}{81.05} =0.553\)

Therefore, the molar composition of the bottom product is 2.5 % butane, 42.2 % pentane and 55.3 % hexane.

NOTE: notice the result is independent of the value of the assumed feed, it means that no matter the basis, the compositions will be the same for the same recovery of butane at the feed, only the flows will change.

Regards.

Answer:

The percentage composition of the Bottoms is

- 2.46% Butane.

- 42.25% Pentane.

- 55 29% Hexane.

Explanation:

The feed is eventually separated into distillate and bottoms at the end of the day.

If the total number of moles in the feed = F, and we assume an initial basis of 100 mol

Total number of moles in the distillate = D

Total number of moles in the bottoms = B

Since distillation is a physical separation technique, with no chemical reaction expected,

The overall balance of the system,

F = 100 = B + D (eqn 1)

In the feed, there is 20 mole% of butane, 35 mole% of pentane and the rest, that is, 45 mole% of hexane.

Butane = 0.20F moles = 0 2×100 = 20 moles

Pentane = 0.35F moles = 0.35×100 = 35 moles

Hexane = 0.45F moles = 0.45×100 = 45 moles

In the distillate, there is 95 mole% of butane, 4 mole% of pentane and the rest, that is, 1 mole% is hexane

Butane = 0.95D moles

Pentane = 0.04D moles

Hexane = 0.01D moles

The composition of the Bottoms isn't known.

But, it is given that the distillate is expected to contain 90% of the butane in the feed

Component balance for butane, based on this information

Butane in the distillate = 90% of butane in feed

0.95D = 90% × 0.20F = 0.18F

Butane in the distillate = 0.95D = 0.18F

D = 0.1895F = 0.1895 × 100 = 18.95 moles

The composition of the distillate can then be rewritten as

Butane = 0.95D moles = 0.95×18.95 = 18 0025 moles

Pentane = 0.04D moles = 0.04×18.95 = 0.758 moles

Hexane = 0.01D moles = 0.01×18.95 = 0.1895 moles

From the overall balance,

100 = B + D

B = 100 - D = 100 - 18.95 = 81.05 moles

Hence, the amount of each component in the Bottoms now will be the amount in the feed minus the amount in the distillate

Butane

20 - 18.0025 = 1.9975 moles

Percent compositon = (1.9975/81.05) = 0.0246 = 2.46%

Pentane

35 - 0.758 = 34.242 moles

Percent composition = (34.242/81.05) = 0.4225 = 42.25%

Hexane

45 - 0.1895 = 44.8105 moles

Percent composition = (44.8105/81.05) = 0.5529 = 55.29%

Please note that, irrespective of the assumed basis for the total number of moles in the feed, the molar composition of the bottoms obtained, remains the same.

Hope this Helps!

The volume of methanol is 54.72 ml, m/m% of solution is 29% and mass of NaCl present is 73.76g

The mole is an amount unit similar to familiar units like pair, dozen, gross, etc. It provides a specific measure of the number of atoms or molecules in a bulk sample of matter.

A mole is defined as the amount of substance containing the same number of atoms, molecules, ions, etc. as the number of atoms in a sample of pure 12C weighing exactly 12 g.

Given,

1. v/v% = 17.1 %

This means that 17.1 ml of methanol is present in 100 ml of water.

so, 320 ml of water has 0.171 × 320 = 54.72 ml

2. Mass of NaCl = 8.5 lbs

Mass of water = 29.3 lbs

mass of NaCl in 1 lbs = 8.5 / 29.3 = 0.29 lbs

m/m% = 29%

3. Volume of NaCl = 194 ml

Concentration of NaCl = 6.5 M

Moles of NaCl = 0.194 × 6.5 = 1.261 moles

Mass of NaCl = 1.261 × 58.5 = 73.76g

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Answer:

Kauai

Explanation:

I look this up when I am doing math

The resistance of the wire is dependent on temperature, diameter and nature of the material.

The term resistance refers to the opposition offered to the flow of current in a circuit. The resistance is obtained form Ohm's law which states that;

V = IR

Where;

V = voltage

I = current

R = resistance

Hence, the resistance is dependent on;

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The mass of water that can be obtained is 2.2 g of water.

We know that in the case that we have here, we are going to depend on the stoichiometry of the reaction and this is very important in the determination of the amount of the water that can be formed.

Now we can see that the reaction equation can be written from the fact that; \(2H_{2} (g) + O_{2} (g) ---- > 2H_{2} O(g)\). Then we can see that in this kind of chemical reaction we have to apply the stoichiometry.

Number of moles of the hydrogen = 14.8g/2 g/mol = 7.4 moles

Number of moles of oxygen = 34.8 g/32 g/mol = 1.1 moles

Given that 2 moles of hydrogen reacts with 1 mole of oxygen

7.4 moles of hydrogen reacts with 7.4 * 1/2

= 3.7 moles

Hence oxygen is the limiting reactant.

1 mole of oxygen produces 2 moles of water

1.1 moles of oxygen would produce 1.1 * 2/1

= 2.2 moles of water

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The buffer solution has a pH of 5.36.

To find the pH of this buffer solution, use the Henderson-Hasselbalch equation:

pH = pKa + log([A⁻]/[HA])

where pKa = dissociation constant of acetic acid, [A⁻] = concentration of acetate ions, and [HA] = concentration of acetic acid.

Calculate the concentrations of acetate ions and acetic acid in the solution.

The initial moles of acetic acid are:

moles of acetic acid = volume of acetic acid x concentration of acetic acid

moles of acetic acid = 0.020 L x 0.10 mol/L

moles of acetic acid = 0.002 mol

After mixing with sodium acetate, the total volume of the solution is 50 mL, so the concentration of acetic acid and acetate ions are:

[HA] = moles of acetic acid / total volume of solution

[HA] = 0.002 mol / 0.050 L

[HA] = 0.040 M

[A⁻] = concentration of sodium acetate

[A⁻] = 0.10 M

The dissociation constant of acetic acid is pKa = 4.76.

Now, substitute these values into the Henderson-Hasselbalch equation:

pH = pKa + log([A⁻]/[HA])

pH = 4.76 + log(0.10/0.040)

pH = 4.76 + 0.60

pH = 5.36

Therefore, the pH of the buffer solution is 5.36.

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Percent of gold and copper are 88.2 and 11.8

Red gold is a gold-copper alloy used to make jewelry .

Let the mass  of gold be m1

Let the mass of copper be m2

We are given that m1+m2 =8.97 g

We know that volume is the ratio of mass to density

Thus

m1/d1  + m2/d2 = 0.528 cm3

where d1 and d2 is the density of gold and copper

m1/19.3 + m2/8.96 = 0.528

8.96m1 +19.3 m2 = 0.528 x 19.3 x 8.96 = 91.305

putting m1 = 8.97 - m2

8.96 ( 8.97 - m2 ) + 19.3 m2 = 91.305

80.3712 - 8.96m2 + 19.3 m2 =91.305

10.34 m2 = 91.305-80.3712

m2 = 10.9338 /10.34

      =1.0537gm

m1=8.97-1.0537

    =7.91gm

Therefore, percent of gold = 7.91/8.97 x 100 =88.20%

                 percent of copper = 100-88.2=11.8%

Therefore, percent of gold and copper are 88.2 and 11.8

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\(H_3PO_4\) ionizes during dissociation and  \(Ba(OH)_2\) is dissolved in \(H_2O\) (water) it will dissociate (dissolve) into \(Ba^+2\) and \(OH^-\) ions.

Dissociation, in chemistry is the breaking up of a compound into simpler constituents that are usually capable of recombining under other conditions.

Phosphoric acid is a weak acid which only partially ionizes during dissociation. \(H_3PO_4\) can donate three protons during dissociation reaction \(H_3PO_4\) has three steps of dissociation.

The three equations for the dissociation of \(H_3PO_4\) into ions is listed below:

\(H_3PO_4 + H_2O\)   ⇌  \(H+ + H_2PO_4 ^{-}\)

\(H_2PO_4^{-} + H_2O\)   ⇌  \(H^+ + HPO_4 ^{-}\)

\(HPO_4^{2-} + H_2O\)   ⇌  \(H^{+} + PO_4 ^{3-}\)

When \(Ba(OH)_2\) is dissolved in \(H_2O\) (water) it will dissociate (dissolve) into \(Ba^+2\) and \(OH^-\) ions.

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Answer:

the relationship between the relative quantities of substances taking part in a reaction or forming a compound, typically a ratio of whole integers.

Explanation:

G o o g l e

Explanation:

Stoichiometry is the calculation of reactants and products in chemical reactions in chemistry.

Answer:

0.75moles of  H₄SiO₄

Explanation:

Given parameters:

Number of moles of H₂O  = 1.5moles

Unknown:

Number of moles of H₄SiO₄  = ?

Solution:

To solve this problem, we need to write the reaction equation first;

            SiO₂  +  2H₂O  →   H₄SiO₄

From the balanced reaction equation:

             2 moles of water will produce 1 mole of  H₄SiO₄

    So     1.5 moles of water will produce \(\frac{1.5}{2}\)   = 0.75moles of  H₄SiO₄

114.5 g is the total mass of the beaker .

Total mass of beaker=53.10g+5.348g+ 56.1g

Total mass=114.5 g

Mass is used in physics to specific inertia, a fundamental function of all remember. basically, it's far a mass of rely's resistance to changing its course or pace in response to the software of a force.

The exchange that an applied force produces is smaller the extra mass a body has. The kilogram, the unit of mass within the international machine of gadgets, corresponds to 6.62607015 1034 joule seconds using Planck's consistent (SI). One joule is produced by way of multiplying one kilogram by means of one rectangular meter per 2d.

The kilogram is decided by genuine measurements of Planck's regular on account that the second one and the meter have formerly been described in phrases of other bodily constants.

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Ammonia (\(NH_3\)) and ammonium chloride (\(NH_4Cl\)) mixture could be a useful buffer in a solution. Option C

A buffer is a solution that can resist changes in pH when small amounts of acid or base are added. It consists of a weak acid and its conjugate base or a weak base and its conjugate acid. The buffer system works by the principle of Le Chatelier's principle, where the equilibrium is shifted to counteract the changes caused by the addition of an acid or a base.

In option A, acetic acid (\(CH_3CO_2H\)) is a weak acid, but hydrochloric acid (HCl) is a strong acid. This combination does not form a buffer because HCl is completely dissociated in water and cannot provide a significant concentration of its conjugate base.

Option B consists of sodium hydroxide (NaOH), which is a strong base, and elemental sodium (Na), which is a metal. This combination does not form a buffer as there is no weak acid-base pair involved.

Option D contains acetic acid (\(CH_3CO_2H\)), a weak acid, and ammonia (\(NH_3\)), a weak base. Although they are weak acid and base, they do not form a buffer system together as they are both weak acids or bases and lack the required conjugate acid-base pair.

Option C, ammonia (\(NH_3\)), is a weak base, and ammonium chloride (\(NH_4Cl\)) is its conjugate acid. This combination can form a buffer system. When ammonia reacts with water, it forms ammonium ions (NH4+) and hydroxide ions (OH-).

The ammonium ions act as the weak acid, while the ammonia acts as the weak base. The addition of a small amount of acid will be counteracted by the ammonium ions, and the addition of a small amount of base will be counteracted by the ammonia, thus maintaining the pH of the solution relatively stable.

Therefore, option C, consisting of ammonia (\(NH_3\)) and ammonium chloride (\(NH_4Cl\)), is the suitable mixture that could be a useful buffer in a solution.

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The amount of heat energy absorbed when 200 grams of water are heated from 20 C to 60 C is 33,440 Joules.

To find the amount of heat energy absorbed when 200 grams of water are heated from 20 C to 60 C, we can use the equation Q = mcAT.
First, we need to find the value of m, which is the mass of the water in grams. In this case, it is given as 200 grams.
Next, we need to find the value of AT, which is the change in temperature in degrees Celsius.

This can be calculated by subtracting the initial temperature from the final temperature, which gives us 60 C - 20 C = 40 C.
The specific heat capacity of water, C, is given as 4.18 Joules per gram per degree Celsius.
Now we can plug in the values into the equation:
Q = mcAT
Q = (200 g) x (4.18 J/g°C) x (40°C)
Q = 33,440 J
Therefore, the amount of heat energy absorbed when 200 grams of water are heated from 20 C to 60 C is 33,440 Joules.

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The structure illustrated here is butanone

Butanone, also known as methyl ethyl ketone (MEK), is a solvent that is commonly used in industrial applications such as in the manufacture of plastics, textiles, and paints. It is also used as a solvent in the production of adhesives, and as a cleaning agent for electronic components.

Butanone's importance lies in its versatile properties as a solvent, which make it essential in the production of many consumer goods and industrial products. Its high solvency power and fast evaporation rate make it particularly useful in applications where rapid drying and bonding are required.

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Answer:

The first one is Butanone and the second one is Propenal

Explanation:

Just did it on Edge2023!

Answer:

When equation for neutralization of HBr by Ca(OH)₂ is correctly balanced, 1.2046*10²⁴ molecules of water will be formed

Explanation:

A neutralization reaction is one in which an acid (or acidic oxide) reacts with a base (or basic oxide). In the reaction a salt is formed and in most cases water is formed. A Salt is an ionic compound formed by the union of ions and cations through ionic bonds.

In the reactions of a strong acid (those substances that completely dissociate) with a strong base (they dissociate completely, giving up all their OH-), the complete neutralization of the species is carried out:

2 HBr (aq) + Ca(OH)₂ (s) → CaBr₂ (aq) + 2 H₂O (l)

The reaction is already balanced, complying with the law of conservation of matter. This law states that since no atom can be created or destroyed in a chemical reaction, the number of atoms that are present in the reactants must be equal to the number of atoms present in the products.

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), 2 moles of water H₂O are formed.

On the other hand, Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023 * 10²³ particles per mole. Avogadro's number applies to any substance.

Then you can apply the following rule of three: if 1 mole of H₂O contains 6.023*10²³ molecules, 2 moles of H₂O, how many molecules does it contain?

\(amount of molecules=\frac{2moles*6.023*10^{23}molecules }{1 mole}\)

amount of molecules= 1.2046*10²⁴ molecules

When equation for neutralization of HBr by Ca(OH)₂ is correctly balanced, 1.2046*10²⁴ molecules of water will be formed

Answer: metal turn orange and weaker as it gets oxidised

Explanation:

The highest electric force exerted by charges -4 ×10⁻⁵ C and 3 ×10⁻⁵ C  placed 0.5 m apart is equal to 43.15 N.

The lowest electric force exerted by charges 3 ×10⁻⁵ C and 3 ×10⁻⁵ C  placed 1 m apart is equal to 8.10 N.

According to Coulomb’s law, the force of attraction between two charges is equal to the product of their charges and is inversely proportional to the square of the distance. This electric force applies along the line joining the two charges.

The magnitude of the electric force can be written as follows:

\(\displaystyle F = k\frac{q_1q_2}{r^2}\)

where k is constant proportionality = 8.99 × 10⁹ N.m²/C².

Given the charge on one point charge, q₁ =  4 ×10⁻⁵ C

The charge on the other point charge, q₂ = - 3 × 10⁻⁵C

The distance between these two charges, r = 0.5 m

The magnitude of electric force between the charges  will be:

\(\displaystyle F = 8.99\times 10^{9}\times \frac{4\times 10^{-5}\times 3\times 10^{-5}}{(0.5)^2}\)

F = 43.15 N

Given the charge on one point charge, q₁ =  3 ×10⁻⁵ C

The charge on the other point charge, q₂ = 3 × 10⁻⁵C

The distance between these two charges, r = 1 m

The magnitude of force between the charges will be:

\(\displaystyle F = 8.99\times 10^{9}\times \frac{3\times 10^{-5}\times 3\times 10^{-5}}{(1)^2}\)

F = 8.1 N

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Answer:

I choose my table

Types of luminous flames:

1. Yellow Luminous Flame

2. Smoky Luminous Flame

3. Orange Luminous Flame

4. Blue Luminous Flame

Luminous flames are characterized by their visible glow, which is caused by the incomplete combustion of fuel. The presence of soot particles in the flame causes the emission of light. There are different types of luminous flames, which can be classified based on their fuel composition and burning conditions. Here are some common types of luminous flames:

1. Yellow Luminous Flame: This is the most common type of luminous flame, often seen in open fires, candles, and gas stoves. It appears yellow due to the presence of soot particles in the flame. Yellow flames indicate incomplete combustion of hydrocarbon fuels, such as methane, propane, or natural gas. The high carbon content in these fuels leads to the formation of soot, which emits visible light.

2. Smoky Luminous Flame: This type of flame is characterized by a significant amount of black smoke and soot production. It is commonly observed in poorly adjusted or malfunctioning burners or engines. The excessive presence of unburned fuel in the flame results in incomplete combustion and the emission of dark smoke particles.

3. Orange Luminous Flame: An orange flame indicates a higher combustion temperature compared to a yellow flame. It is often seen in more efficient burners or when burning fuels with a higher carbon content, such as oil or diesel. The higher temperature helps in burning more of the carbon particles, reducing the amount of soot and making the flame appear less yellow.

4. Blue Luminous Flame: A blue flame is typically associated with complete combustion. It indicates efficient burning of fuel, resulting in minimal soot formation. Blue flames are commonly observed in gas burners or Bunsen burners. The blue color is a result of the combustion of gases, such as methane, in the presence of sufficient oxygen.

It's important to note that the luminosity of a flame can vary depending on factors such as fuel-air mixture, combustion temperature, and the presence of impurities. Achieving complete combustion and minimizing the production of soot is desirable for efficient and cleaner burning processes.

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Answer:

The answer is

Explanation:

To find the density of a substance when given the mass and volume we use the formula

From the question

mass = 15 g

volume of rock = 5 cm³

The density of the substance is

\(density = \frac{15}{5} \)

We have the final answer as

Hope this helps you

The answer responses to  the structures shown in the diagram are:

A. chromosomes

C. They would be the same.

B. They are in pairs because each one comes from a different parent.

The chromosomes are in pairs because humans have a diploid number of chromosomes, meaning they have two sets of chromosomes, one inherited from each parent.

The nucleus is important in eukaryotic cells and has many important parts that help the cell work properly. There are some parts inside cells called the nuclear membrane, nucleoplasm, nucleolus, and chromatin. Chromatin is made up of DNA and other proteins.

Every part of a person's body has the same genes, but the way they are organized can be different in different types of cells. The chromosomes in our skin cells might not be the same as the chromosomes in our muscle cells, even if they come from the same person.

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Identify the structures shown.

A. chromosomes

B. mitochondria

C. nuclei

D. vacuoles

C

Describe how the structures from this cell would compare to the structures in the nucleus of another body cell from the same person.

A. There would be longer.

B. They would be shorter.

C. They would be the same.

D. They would be different.

Describe how the structures from this cell would compare to the structures in the nucleus of another body cell from the same person.

A. There would be longer.

B. They would be shorter.

C. They would be the same.

D. They would be different.

Explain why the structures are in pairs.

A. They aren't in pairs.

B. They are in pairs because each one comes from a different parent.

C. This cell is making a copy of itself.

D. The cell always has 2 copies in case 1 is damaged.

Answer:

A straight-chain alkane that has five carbon atoms, also known as pentane, differs from a cycloalkane that has five carbon atoms, also known as cyclopentane, in terms of their molecular structure and properties. Pentane has a linear, straight-chain structure, while cyclopentane has a ring-shaped structure. This difference in structure affects their physical and chemical properties. For example, pentane has a higher boiling point and lower melting point than cyclopentane due to the differences in the strength of the intermolecular forces between their molecules

Explanation: