10. The figures below are similar.
State the ratio of similarity and then use it
to find the value of x. (2 points)

Answer:

Equilateral acute

Step-by-step explanation:

Equilateral acute

Answer:

The one above the orange answer in the picture

Step-by-step explanation:

85% of 20 is 17 every thing else is not 85%

The correct answer would be the one on top left

Answer:

30cm^2

Step-by-step explanation:

Answer:

Dear user,

Answer to your query is provided below

Water left in the tank is 158 m^3

Step-by-step explanation:

Volume of Rectangular tank = 4.5 x 6 x 8 = 216m^3

Water used = 58m^3

Water left = 216 - 58 = 158m^3

Answer:

Making money

Step-by-step explanation:

selling motorcycle for 2,535

After 2 years the motorcycle is worth:

y = 4721(0.65)^2

= 1994.6

2535> 1994.6

Answer:

Joel is selling a motorcycle for $2,535. He bought the

motorcycle two years ago and paid $4,721 for it. It depreciated

35% during the two years. Is he losing money or making money

on this sale

Amount of $150,000 represents 42.86% of $350,000.

Equation modelling is the process of writing a mathematical verbal expression in the form of a mathematical expression for correct analysis, observations and results of the given problem.

We have Danny’s home cost $350,000. The federal government program for flood damage insurance covers only $150,000.

Assume that it represents [x%] percent of the total value. Then, we can write -

x = (150000/350000) x 100

x = 42.86%

Therefore, $150,000 represents 42.86% of $350,000.

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The expansion will be 64d^6 + 1152d^5 + 9720d^4 + 43740d^3 + 98415d^2 + 145458d + 729

We can expand (2d+3)^6 using the binomial theorem, which states that:

(a + b)^n = nC0 * a^n * b^0 + nC1 * a^(n-1) * b^1 + nC2 * a^(n-2) * b^2 + ... + nCn-1 * a^1 * b^(n-1) + nCn * a^0 * b^n

where nCk is the binomial coefficient, given by:

nCk = n! / (k! * (n-k)!)

Expanding (2d+3)^6 using this formula, we get:

(2d+3)^6 = 6C0 * (2d)^6 * 3^0 + 6C1 * (2d)^5 * 3^1 + 6C2 * (2d)^4 * 3^2 + 6C3 * (2d)^3 * 3^3 + 6C4 * (2d)^2 * 3^4 + 6C5 * (2d)^1 * 3^5 + 6C6 * (2d)^0 * 3^6

Simplifying each term using the binomial coefficient formula, we get:

(2d+3)^6 = 1 * 64d^6 * 1 + 6 * 32d^5 * 3 + 15 * 16d^4 * 9 + 20 * 8d^3 * 27 + 15 * 4d^2 * 81 + 6 * 2d * 243 + 1 * 1 * 729

Simplifying each term further, we get:

(2d+3)^6 = 64d^6 + 1152d^5 + 9720d^4 + 43740d^3 + 98415d^2 + 145458d + 729

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Answer:

14- 1/5

15- 9/20

16- 11/20

Step-by-step explanation:

Answer:

n = 70

Step-by-step explanation:

-8 + n = 62

      n = 70

The cotangent of the angle is -√570/30

From the question, we have the following parameters that can be used in our computation:

(√30/7,-√19/7)

This means that

(x, y) = (√30/7,-√19/7)

The cot(θ) is calculated as

cot(θ) = y/x

Substitute the known values in the above equation, so, we have the following representation

cot(θ) = (-√19/7)/(√30/7)

Evaluate

cot(θ) = -√19/√30

Rationalize

cot(θ) = -√570/30

Hence, the value of cot(θ) is -√570/30

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Answer:

83.29% probability that at least 2 flights arrive late.

Step-by-step explanation:

For each flight, there are only two possible outcomes. Either they arrive late, or they do not. The probability of a flight arriving late is independent of other flights. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

\(P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}\)

In which \(C_{n,x}\) is the number of different combinations of x objects from a set of n elements, given by the following formula.

\(C_{n,x} = \frac{n!}{x!(n-x)!}\)

And p is the probability of X happening.

80 % of its flights arriving on time.

This means that 100-80 = 20% arrive late, so \(p = 0.2\)

A test is conducted by randomly selecting 15 Southwest flights and observing whether they arrive on time.

This means that \(n = 15\)

Find the probability that at least 2 flights arrive late.

Either less than 2 arrive late, or at least 2 does. The sum of the probabilities of these events is decimal 1. So

\(P(X < 2) + P(X \geq 2) = 1\)

We want \(P(X \geq 2)\). Then

\(P(X \geq 2) = 1 - P(X < 2)\)

In which

\(P(X = 2) = P(X = 0) + P(X = 1)\)

So

\(P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}\)

\(P(X = 0) = C_{15,0}.(0.2)^{0}.(0.8)^{15} = 0.0352\)

\(P(X = 1) = C_{15,1}.(0.2)^{1}.(0.8)^{14} = 0.1319\)

\(P(X = 2) = P(X = 0) + P(X = 1) = 0.0352 + 0.1319 = 0.1671\)

\(P(X \geq 2) = 1 - P(X < 2) = 1 - 0.1671 = 0.8329\)

83.29% probability that at least 2 flights arrive late.

QUESTION:- WHICH FRACTION IS THE RECIPROCAL OF \( \frac{4}{3}\)

\(RECIPROCAL = \frac{3}{4} \)

Answer:

1/-6

Step-by-step explanation:

1)Gross Yearly Income = Hourly Wage × Hours per Week × Weeks in a Year

Gross Yearly Income = $15/hour × 40 hours/week × 52 weeks/year

Gross Yearly Income = $31,200

2)Gross Monthly Income = Gross Yearly Income / Months in a Year

Gross Monthly Income = $31,200 / 12 months

Gross Monthly Income ≈ $2,600

The simplified form of the given expression as a fraction is 7x/x-7

Fractions  are written as a ratio of two integers. For instance a/b is a fraction where a and b are integers.

Given the expression below;

(1/7+1/x)/(1/49+1/x²)

Find the LCM to have:

(x+7/7x)/(x²-49)/49x²

Divide to have:

x+7/7x * 49x²/(x²-49)

(x+7) * 7x/(x+7)(x-7)

Cancel out the like terms to have:

1 * 7x/x-7

= 7x/x-7

Hence the simplified form of the given expression as a fraction is 7x/x-7

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The probability that a mouse leaves first and then a bat is given as follows:

14/55.

The parameters that are needed to calculate a probability are listed as follows:

Then the probability is calculated as the division of the number of desired outcomes by the number of total outcomes.

As the animal is not replaced, the probabilities for this problem are given as follows:

Hence the probability is given as follows:

4/11 x 7/10 = 2/11 x 7/5 = 14/55.

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Answer:

In exponential form

3.2615 X 10¹

The probability of getting exactly 9 of them major in STEM is 0.139 or 13.9%.

The probability of getting at most 11 of them major in STEM is approximately 0.898 or 89.8%.

The probability of getting at least 11 of them major in STEM is approximately 0.318 or 31.8%.

a. Exactly 9 of them major in STEM.

In this case, the probability of success (a student majoring in STEM) is 0.27, and the number of trials is 35. The probability of exactly 9 students majoring in STEM is then given by the formula:

P(X = 9) = (35 choose 9) x (0.27)⁹ x (0.73)²⁶

where (35 choose 9) is the number of ways to choose 9 students out of 35, and (0.27)⁹ x (0.73)²⁶ is the probability of 9 successes and 26 failures. Evaluating this expression gives a probability of approximately 0.139 or 13.9%.

b. At most 11 of them major in STEM.

To calculate the probability that at most 11 students out of 35 major in STEM, we can use the cumulative binomial probability distribution. This distribution calculates the probability of at most X successes, where X is any number from 0 to the total number of trials.

The probability of at most 11 students majoring in STEM can be calculated as follows:

P(X <= 11) = P(X = 0) + P(X = 1) + ... + P(X = 11) = 0.898 or 89.8%.

c. At least 11 of them major in STEM.

The probability of less than 11 students majoring in STEM can be calculated using the cumulative binomial probability distribution, as in part (b). Specifically:

P(X < 11) = P(X = 0) + P(X = 1) + ... + P(X = 10)

Subtracting this probability from 1 gives the probability of at least 11 students majoring in STEM:

P(X >= 11) = 1 - P(X < 11) = 31.8%

Again, we can use the binomial distribution formula from part (a), or a binomial probability calculator or statistical software package to calculate this probability.

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A regression through the origin is a linear regression model where the intercept time period is assumed to be 0, meaning the regression line passes through the starting place.

This version is also referred to as zero-intercept regression or homogeneous regression.

It's far frequently used whilst there's a theoretical foundation to agree with that the relationship among the dependent and unbiased variable passes via the foundation or whilst the information propose that the intercept ought to be 0.

The slope coefficient represents the change within the structured variable for a one-unit increase inside the unbiased variable.

However, this kind of regression may not be appropriate in all cases, and a general linear regression version with an intercept term can be greater suitable.

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Answer:

0.08

Step-by-step explanation:

Answer:

0.825 bags of oranges

Step-by-step explanation:

1/3 is 0.33 and 2/5 is 0.4 so 0.33/0.4 is 0.825

Answer:

n = 12

Step-by-step explanation:

Given expression:

\(\dfrac{a^n}{a^3} = a^9\)

multiply both sides by a³

\(\dfrac{a^n}{a^3} \times a^3 = a^9 \times a^3\)

simplify following

\(a^n = a^9 \times a^3\)

apply indices law

\(a^n = a^{9+3}\)

simplify

\(a^n = a^{12}\)

compare powers

\(n = 12\)

Answer:

n = 12

Step-by-step explanation:

Given function:

\(\dfrac{a^n}{a^3}=a^9\)

\(\textsf{Apply exponent rule} \quad \dfrac{a^b}{a^c}=a^{b-c}:\)

\(\implies a^{n-3}=a^9\)

\(\textsf{Apply exponent rule} \quad a^{f(x)}=a^{g(x)} \implies f(x)=g(x):\)

\(\implies n-3=9\)

Add 3 to both sides:

\(\implies n-3+3=9+3\)

\(\implies n=12\)

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The difference between the median is 0.5. option D

Getting the sets of values that we have in order, we can see that we have;

12, 15, 33, 45, 46, 51, 52, 93

We can find the median between  4th and 5th numbers this is now going to give us that;  (45+46)/2 =  45.5

Median value  = 45.5

We can see that 93 is the outlier in the data set so if we remove it we would have;

12, 15, 33, 45, 46, 51, 52

The median of the data set in this case is 45.

The difference is;

45.5 - 45 = 0.5

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Missing parts;

The number of lattes sold daily for two coffee shops is shown in the table:

Lattes

12

52

93

33

51

15

46

45

Based on the data, what is the difference between the median of the data, including the outlier and excluding the outlier?

A.46

B.45.5

C.45

D.0.5

Answer:

No

Step-by-step explanation:

10 is not less than 6, so 10 < r when r=6 is not true.

The total surface area of the pyramid from the net is 286 square cm

To calculate the total surface area of a pyramid from its net, you need to add up the areas of all its faces.

The net of a pyramid is a two-dimensional representation of the pyramid, where the edges of the net represent the edges of the pyramid.

In this case, the nets are

Using the above as a guide, we have the following:

Area = 10 * 7 + 2 * (1/2 * 10 * 12.5 + 1/2 * 7 * 13)

Evaluate

Area = 286

Hence, the surface area is 286 square cm

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Answer:

4x+12

I think that's it............

The profit function is P(x) = -500.523x^2 + 600x - 200.

To find the profit function, P(x), we need to subtract the cost function, C(a), from the revenue function, R(x).

Given:

Cost function: C(a) = 500x^2 + 300

Revenue function: R(x) = -0.523x^2 + 600x - 200 + 300

Profit function, P(x), is obtained by subtracting the cost function from the revenue function:

P(x) = R(x) - C(a)

P(x) = (-0.523x^2 + 600x - 200 + 300) - (500x^2 + 300)

Simplifying the expression:

P(x) = -0.523x^2 + 600x - 200 + 300 - 500x^2 - 300

P(x) = -500x^2 - 0.523x^2 + 600x + 300 - 200 - 300

P(x) = -500x^2 - 0.523x^2 + 600x - 200

Combining like terms:

P(x) = (-500 - 0.523)x^2 + 600x - 200

Simplifying further:

P(x) = -500.523x^2 + 600x - 200

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Answer:

Subscribe Single-3 FF on yt