Answer: The molecular formula will be \(C_2H_4O_2\)
Explanation:
If percentage are given then we are taking total mass is 100 grams.
So, the mass of each element is equal to the percentage given.
Mass of C = 40.0 g
Mass of O = 53.3 g
Mass of H = 6.66 g
Step 1 : convert given masses into moles.
Moles of C =\(\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{40.0g}{12g/mole}=3.33moles\)
Moles of O =\(\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{53.3g}{16g/mole}=3.33moles\)
Moles of H =\(\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{6.66g}{1g/mole}=6.66moles\)
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C = \(\frac{3.33}{3.33}=1\)
For O =\(\frac{3.33}{3.33}=1\)
For H = \(\frac{6.66}{3.33}=2\)
The ratio of C : O : H = 1: 1: 2
Hence the empirical formula is \(COH_2\)
The empirical weight of \(COH_2\) = 1(12)+1(16)+2(1)= 30g.
The molecular weight = 60 g/mole
Now we have to calculate the molecular formula.
\(n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{60}{30}=2\)
The molecular formula will be=\(2\times CH_2O=C_2H_4O_2\)
which macromolecules has a nitrogen base and phosphate found in its structure?
Answer:
A nucleic acid
Explanation: A nucleic acid is a polymeric macromolecule made up of repeated units of monomeric 'nucleotides' composed of a nitrogenous heterocyclic base which is either a purine or pyrimidine, a pentose five-carbon sugar either ribose or 2′-deoxyribose, and one to three phosphate groups.
What organelle is sac like and stores different materials?
Group of answer choices
endoplasmic reticulum
vacuoles
ribosomes
Golgi Body
What drugs are calcium channel blockers?
Answer:
Examples of calcium channel blockers include:
Amlodipine (Norvasc)
Diltiazem (Cardizem, Tiazac, others)
Felodipine.
Isradipine.
Nicardipine.
Nifedipine (Procardia)
Nisoldipine (Sular)
Verapamil (Calan SR, Verelan)
What do you notice about the dipole moment vector and the hydrogen bond? think about why the direction of the dipole vector makes sense in terms of the idea of hydrogen bond donor vs. acceptor.
The oxygen atom is next to the negative terminal of the dipole vector. This occurs as a result of the atom's electronegative nature and abundance of lone electron pairs. Because it trades up its lone pair electrons to create a hydrogen bond, such oxygen is called the hydrogen bonding donor.
Hydrogen-bonded compounds exhibit abnormally high melting and boiling points. According to the additional energy required to break these bonds, the molecule with hydrogen bonds has a high melting or boiling point.
The dipole moment increases with the difference in electronegativity. Another element affecting the size of the dipole moment was the spacing between the charge separations. The polarity of the molecule is determined by the dipole moment.
Therefore, the oxygen atom is next to the negative terminal of the dipole vector. This occurs as a result of the atom's electronegative nature and abundance of lone electron pairs.
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The cultures of prehistoric humans are known mostly through the excavation of stone tools and other relatively imperishable artifacts. The early tool making traditions are often referred to as being paleolithic (literally "Old Stone Age). The Oldowan and Acheulian tool traditions of the first humans were the simplest applied research basic research Scientihe thought O philosophies technologies
The cultures of prehistoric humans are primarily known through the excavation of stone tools and other durable artifacts, such as the Oldowan and Acheulian tool traditions.
Stone tools and imperishable artifacts serve as key archaeological evidence for understanding prehistoric cultures. Through meticulous excavation and analysis, archaeologists have been able to piece together the lifestyles, technological advancements, and social behaviors of early human societies. The term "paleolithic" refers to the Old Stone Age, a time when humans relied on stone tools as their primary implements.
The Oldowan tool tradition is considered the earliest stone tool industry, dating back around 2.6 million years ago. It is characterized by simple tools, such as choppers and scrapers, which were crafted by flaking off pieces from larger stones. These tools were primarily used for basic activities like butchering and processing animal carcasses.
Later, the Acheulian tool tradition emerged around 1.76 million years ago, representing an advancement in stone tool technology. Acheulian tools, such as handaxes and cleavers, were more refined and standardized, showcasing an increased level of sophistication in tool-making techniques. These tools served a wide range of purposes, including hunting, woodworking, and shaping raw materials.
By studying the Oldowan and Acheulian tool traditions, researchers gain valuable insights into the cognitive abilities, cultural development, and technological progress of early humans. The examination of these artifacts provides evidence of their adaptability, problem-solving skills, and the gradual refinement of their tool-making techniques over time.
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how does the number of atoms in a 27.5-gram gold ring compare to the number in a chromium ring of the same mass?
The 0.322335 number of atoms in a 27.5-gram gold ring compare to the number in a chromium ring of the same mass.
no of atoms = 27.5 /197 *N
no of atoms of copper = 27.5 /63.5 *N
ratio = 0.3223
N gold = no. of moles * 6.022*10^23 = (27.5/196.96 ) *6.022*10^23
N Copper = no. of moles * 6.022*10^23 = (27.5/63.54 ) *6.022*10^23
=> N gold/N copper =63.54/196.96 = 0.322
no. of moles of gold = 27.5/197
no. of moles of copper = 27.5/63.5
Now, no, of atoms = no. of moles * Avagadro's no.
where Avagadros no. = 6.022*10^23
N(gold)=27.5/197 * Avagadros no.
N(copper) = 27.5/63.5 * avagadros no.
So, N(gold)/N(copper) = (27.5/197 * Avagadros no.)/(27.5/63.5 * avagadros no.)
= 63.5/197
= 0.322335
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hydrogen can react explosively with oxygen to form water how many liters of hydrogen are required to combine 18 grams of oxygen at standard conditions
50.1 liters of hydrogen to combine with 18 grams of oxygen to form water at standard conditions. The balanced chemical equation for the reaction between hydrogen and oxygen is:
2H2 + O2 → 2H2O
To calculate the amount of hydrogen needed to combine with 18 grams of oxygen to form water, we need to use the balanced chemical equation for the reaction between hydrogen and oxygen:
2H2 + O2 → 2H2O
From this equation, we can see that two molecules of hydrogen react with one molecule of oxygen to form two molecules of water.
To calculate the amount of hydrogen needed, we first need to convert the 18 grams of oxygen to moles. The molar mass of oxygen is 16 g/mol, so:
18 g O2 × (1 mol O2/16 g O2) = 1.125 mol O2
From the balanced equation, we know that 1 mole of oxygen reacts with 2 moles of hydrogen. Therefore, we need:
1.125 mol O2 × (2 mol H2/1 mol O2) = 2.25 mol H2
To convert from moles to liters, we need to use the ideal gas law:
PV = nRT
where P is the pressure (which we can assume is standard pressure, 1 atm), V is the volume, n is the number of moles, R is the gas constant (0.0821 L·atm/mol·K), and T is the temperature (which we can assume is standard temperature, 273 K).
Solving for V:
V = nRT/P
V = (2.25 mol) × (0.0821 L·atm/mol·K) × (273 K) / (1 atm)
V = 50.1 L
Therefore, we need 50.1 liters of hydrogen to combine with 18 grams of oxygen to form water at standard conditions.
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25 ml of a 0. 10 m solution of magnesium chloride reacts with 25 ml of potassium hydroxide to form a magnesium hydroxide precipitate. What is the minimum concentration of potassium hydroxide necessary to completely precipitate all of the magnesium?.
Magnesium chloride, often known as MgCl2, can be produced chemically by extracting it from brine or seawater.
Magnesium chloride+ potassium hydroxide (25 ml )------>magnesium hydroxide
Magnesium chloride: what is it?
One magnesium (Mg) and two chloride ions make up magnesium chloride, also known as magnesium dichloride, magnesium (II) chloride, or chloromagnesite (Cl-).
Ionic halides, such as magnesium dichloride and related salts, have the appearance of fine, white to grey granules.
It has no smell and is very water soluble.It is frequently employed as medication for numerous cellular processes.Uses of MgCl2 (Magnesium Chloride)
Magnesium metals are produced using magnesium chloride as a precursor.utilised for soil stabilisation, dust management, and wind erosion.Fire extinguishers use this.used as an additive in food.utilised in the production of paper.is a component of disinfectants.a flocculating agent is used.To learn more about Magnesium hydroxide reaction, visit
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Express the rate of reaction in terms of the change in concentration of each of the reactants and products: 2D(g) + 3E(g) + F(g) → 2G(g) + H(g) Rate = − 2 Δ[D] Δt = − 3 Δ[E] Δt = − Δ[F] Δt = 2 Δ[G] Δt = Δ[H] Δt Rate = 1 2 Δ[D] Δt = 1 3 Δ[E] Δt = 2 3 Δ[F] Δt = − 1 2 Δ[G] Δt = − Δ[H] Δt Rate = − 1 2 Δ[D] Δt = − 1 3 Δ[E] Δt = − Δ[F] Δt = 1 2 Δ[G] Δt = Δ[H] Δt When [D] is decreasing at 0. 74 mol/L·s, how fast is [H] increasing?
The rate of the reaction is correlated with the variation in concentration of each reactant and product, as can be seen from the rate expressions provided.
Express the rate of reaction in terms of the change in concentration of each of the reactants and products:Rate = 1/2 [D] / [H] / [T]
This demonstrates that the reaction's rate and [H] concentration change are directly inversely related. Given that [D] is vanishing at a rate of 0.74 mol/L/s, the following conclusions can be drawn:
[D]/[t] = -0.74 mol/Ls We can solve for [H] / t by substituting this value into the rate expression above: Rate = 1/2 [D] / [H] / [T], ([H] / t) = -1/2 (-0.74 mol/Ls), [H]/[t] = 2(0.74 mol/L s) = 1.48 mol/L s With [D] decreasing at a rate of 0.74 mol/L, [H] is therefore increasing at a rate of 1.48 mol/L/s.
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A box of paperclips contains 2.21x10 24 atoms of aluminum. How many moles are in the box of paperclips? I am starting with the unit _______________ and solving for the unit ________________
Taking into account the definition of Avogadro's Number, a box of paperclips contains 2.21×10²⁴ atoms of aluminum and 3.67 moles of aluminum.
Definition of Avogadro's NumberAvogadro's number is a number that defines the amount of elements (which can be electrons, atoms, ions, molecules) found in one mole of a substance.
Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.
Amount of moles in the box of paperclipsThen you can apply the following rule of three: if 6.023×10²³ atoms are contained in 1 mole of aluminum, then 2.21×10²⁴ atoms are contained in how many moles of aluminum?
amount of moles of aluminum= (2.21×10²⁴ atoms × 1 mole)÷ 6.023×10²³ atoms
amount of moles of aluminum= 3.67 moles
Finally, 3.67 moles of aluminum are present.
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which of the following is a compound?
Answer:
option D and option B
Explanation:
water and bromine both belongs to inorganic compund..
3H2 + blank, reaction arrow, 2NH3
How to complete the equation so that it is a Synthesis reaction
The complete equation representing the synthesis reaction for the formation of ammonia is: 3 H₂ + N₂ ⇒ 2 NH₃
What is a synthesis reaction?It is a reaction in which 2 or more substances combine to form 1 product.
Let's consider the following incomplete synthesis reaction.
3 H₂ + ____ ⇒ 2 NH₃
According to Lavoisier's law, the mass and the elements must be conserved in a chemical reaction. So, since there is nitrogen to the right, the missing element to the left must be nitrogen. Molecular nitrogen is diatomic.
The complete reaction is:
3 H₂ + N₂ ⇒ 2 NH₃
The complete equation representing the synthesis reaction for the formation of ammonia is: 3 H₂ + N₂ ⇒ 2 NH₃
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3. A saturated-liquid mixture of benzene and toluene is fed at a rate of 350 mol/h into a distillation column. The feed consists of 154 mol/h of benzene. It is desired to obtain 97.4 mol% of benzene at the top and 97.6 mol % of toluene at the bottom. L/V at the top of the column is kept constant at 0.778. (a) What are the flow rates of distillate and bottoms products? (b) What is the reflux ratio, R of this column? (c) What is the ratio of reflux to minimum reflux? (d) Determine the number of theoretical stages needed using McCabe-Thiele method. (Equilibrium curve for benzene-toluene system is given below)
The flow rate of distillate and bottoms products can be determined by applying material balance equations to the given saturated-liquid mixture of benzene and toluene in the distillation column.
What is the desired composition of benzene at the top and toluene at the bottom in the distillation column for the given saturated-liquid mixture?(a) The flow rates of distillate and bottoms products are determined by the material balance equations and the given information about the feed and desired product compositions.
(b) The reflux ratio (R) of the column is the ratio of liquid returning as reflux to the distillate flow rate.
(c) The ratio of reflux to minimum reflux (R/Rmin) can be calculated by comparing the reflux ratio to the minimum reflux ratio required for achieving the desired separation.
(d) The number of theoretical stages needed can be determined by constructing the McCabe-Thiele diagram and counting the number of equilibrium stages intersected by the operating line.
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Green energy may also be referred to as renewable or clean energy.
True
False
Aditya Birla Cement Manutacturing Company manufactures cement for use in construction of stone builelings. Beginning work in process inclustes 400 urvits that are 20% compiete with respect to conversion and 30% complete with respect to materials. Ensing work in process inclades 200 units that are 40% complete with respect to corversion and 50 E complete with respect to materials, 2,000 units were stated duting the perlod. Also, assume that $9,900 of material costs and $14,880 of cortversion costs were in the beginning inventory and $180,080 of materials and $409,200 of conversion costs were added to paoduction duing the period. What is the total cost pet equivalent unit using the weighted average method? Multiple Choice $26860 $26785 578000 $26500
The correct option is $26785.To calculate the total cost per equivalent unit using the weighted average method, we need to consider the costs incurred in both the beginning work in process and the units added during the period.
First, let's calculate the equivalent units of production for both conversion and materials:
Conversion costs:
Beginning work in process: 400 units × 20% complete = 80 equivalent units
Units added during the period: 2,000 units × 40% complete = 800 equivalent units
Total equivalent units for conversion = 80 + 800 = 880 equivalent units
Material costs:
Beginning work in process: 400 units × 30% complete = 120 equivalent units
Units added during the period: 2,000 units × 50% complete = 1,000 equivalent units
Total equivalent units for materials = 120 + 1,000 = 1,120 equivalent units
Next, let's calculate the total costs incurred:
Conversion costs:
Beginning work in process cost: $14,880
Costs added during the period: $409,200
Total conversion costs = $14,880 + $409,200 = $424,080
Material costs:
Beginning work in process cost: $9,900
Costs added during the period: $180,080
Total material costs = $9,900 + $180,080 = $189,980
Now, we can calculate the total cost per equivalent unit:
Total cost per equivalent unit = (Total conversion costs + Total material costs) / (Total equivalent units for conversion + Total equivalent units for materials)
Total cost per equivalent unit = ($424,080 + $189,980) / (880 + 1,120)
Total cost per equivalent unit ≈ $267.85
Therefore, the correct option is $26785.
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the variable part of an amino acid, which is the unique chemical structure that distinguishes one amino acid from another, is the . a. amino group b. acid group c. side chain d. carbon bond
Answer:
c. side chain
Explanation:
c. side chain. The variable part of an amino acid, which is the unique chemical structure that distinguishes one amino acid from another, is the side chain (also known as R-group).
The side chain, commonly referred to as the R-group, is the variable component of an amino acid and the particular chemical structure that sets one amino acid apart from the others. Each amino acid shares the same fundamental structure, which consists of a core alpha carbon atom bound to a hydrogen atom, an amino group (NH₂), an acid group (COOH), and an amino group (NH₂). The particular collection of atoms connected to the core carbon is known as the side chain, and it differs amongst various amino acids. The amino acid's distinct characteristics and roles in protein synthesis and biological processes are determined by the side chain's make-up and structure.
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When a small piece of copper metal is added to a silver nitrate solution, the following reaction occurs: 2Ag+NO3+Cu → Cu (NO3)2+2Ag
This equation represents both a single replacement reaction AND a(n) ______________________ reaction.
Question 4 options:
A. oxidation - reduction
B. neutralization
C. combustion
D. decomposition
Answer:
A. Oxidation-reduction
Explanation:
I assume you mean the reaction is:
Ag2NO3(aq) + Cu(s) -> 2Ag(s) + Cu(NO3)2(aq)
Either way:
Solids have the oxidation number of 0. So in the beginning of the reaction Cu(s) has the oxidation number 0, and at the end it has a oxidation number of +2. So it was oxidized.
Ag in the beginning of the reaction has the oxidation number of +1, and ends with the oxidation number of 0. It was reduced.
So its an oxidation reduction.
PLEASE HELP GIVING POINTS!
Answer is 6m
because you can see the line for a to b. it's was key answer by 6m
This is for chemistry
I need help for this question
Answer:
what is the quetion.......
Explanation:
What is the name for the compound li2so4
Answer:
Explanation:
Lithium Sulphate
Answer:
Lithium sulfate is a white inorganic salt with the formula Li2SO4. It is the lithium salt of sulfuric acid.
Metallic magnesium reacts with steam to produce magnesium hydroxide and hydrogen gas. If 16.2 g Mg is heated with 12.0 g H2O, How many grams of each product are formed?
When 12.0 g \(H_2O\) and 16.2 g Mg are heat,then 38.9 g \(Mg(OH)_2\) and 2.67 g \(H_2\) are produced.
The balanced equation for the reaction is
\(Mg(s) + 2H_2O(g) \rightarrow Mg(OH)_2(s) + H_2(g)\)
To determine the amount of each product formed, we first need to calculate the number of moles of each reactant.
Moles of Mg = \(\frac{16.2 g }{ 24.305 g/mol }= 0.665 mol\)
Moles of H2O = \(\frac{ 12.0 g }{18.015 g/mol }= 0.666 mol\)
Because the reaction involves two moles of water for every mole of magnesium, the moles of magnesium and water are equal.
Next, we use the mole ratio from the balanced equation to calculate the moles of each product formed.
Moles of \(Mg(OH)_2\) =
\(0.665 mol Mg * (\frac{1 mol Mg(OH)_2 }{ 1 mol Mg})\\\\ = 0.665 mol Mg(OH)_2\)
Moles of \(H_2\) = \(0.665 mol Mg * (\frac{2 mol H_2 }{ 1 mol Mg}) = 1.33 mol H_2\)
Finally, we use the molar masses of each product to calculate the mass of each product formed.
Mass of \(Mg(OH)_2\) = 0.665 mol\(Mg(OH)_2\) * 58.323 g/mol = 38.9 g \(Mg(OH)_2\)
Mass of \(H_2\) = 1.33 mol \(H_2\)* 2.016 g/mol = 2.67 g \(H_2\)
Therefore, if 16.2 g Mg is heated with 12.0 g \(H_2O\), 38.9 g \(Mg(OH)_2\) and 2.67 g \(H_2\) are formed.
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What is the main use of Cellulosic Ethanol?
Explanation:
Cellulosic ethanol is ethanol (ethyl alcohol) produced from cellulose (the stringy fiber of a plant) rather than from the plant's seeds or fruit. It can be produced from grasses, wood, algae, or other plants. It is generally discussed for use as a biofuel.
What is the name of the theory that proposes continents move over time due to the motion of the lithospheric plates?
Continental Slide
Convection Currents
Plate Drifting
Continental Drift
Answer:
plate drifting
Explanation:
Plate tectonics
Plate tectonics is the theory that Earth's land masses are in constant motion. The realization that Earth's land masses move was first proposed by Alfred Wegener, which he called continental drift.
Answer:
Plate drifting
Explanation:
Plate drifting is similar to plate tectonics.Earth's surface consists of different plates.These plates keep moving slowly all time .So slowly the continents have been formed by this tectonics (Still going on)white powder treated with diluted hcl acid dissolves quickly, and the reaction is featured with intensive bubbling. during a flame test of the resultant solution, the flame turns brick red in colour. from the chemical point of view, this white powder could be: a. na2co3 b. baco3 c. baso4 d. na2so4 e. caco3
Answer:
The bubbling and rapid dissolution of the white powder when treated with diluted HCl acid suggests that the powder is a carbonate. Among the options provided, only (a) Na2CO3 and (e) CaCO3 are carbonates.
To determine which of the two it is, we can look at the results of the flame test. The brick red color of the flame indicates the presence of sodium ions in the solution, which suggests that the white powder is (a) Na2CO3, since it is the only compound in the options given that contains sodium.
Therefore, the answer is (a) Na2CO3.
Explanation:
The white powder that dissolves quickly in diluted HCl acid and produces intensive bubbling is most likely a carbonate compound. The options provided are Na2CO3, BaCO3, and CaCO3. These three carbonates are all known to react with HCl acid, producing carbon dioxide gas, water, and the corresponding metal chloride salt. The reaction can be represented as:
MCO3 + 2HCl → CO2 + H2O + 2MCl
The reaction between Na2CO3 and HCl is particularly vigorous, producing a large amount of carbon dioxide gas, which leads to the intensive bubbling. The other carbonates, including BaCO3 and CaCO3, react more slowly, producing fewer bubbles.
The flame test of the resultant solution, where the flame turns brick red in color, indicates the presence of sodium ions. Sodium ions are known to produce a brick red flame color when exposed to heat. Therefore, the correct answer to this question is option (a) Na2CO3.
In summary, the white powder treated with diluted HCl acid that dissolves quickly and produces intensive bubbling is most likely a carbonate compound. The flame test of the resultant solution, where the flame turns brick red in color, indicates the presence of sodium ions. The correct answer to this question is Na2CO3.
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why can't grignard/organolithium compounds cannot be formed in the presence of o-h, n-h, s-h bonds or terminal alkyne
Grignard reagents and organolithium compounds are powerful nucleophiles that can react with a wide range of electrophiles, including carbonyl compounds and alkyl halides.
However, they are highly reactive and can react with a variety of functional groups, including O-H, N-H, and S-H bonds, as well as terminal alkynes.
The reason why Grignard/organolithium compounds cannot be formed in the presence of O-H, N-H, and S-H bonds is due to their acidic nature. The presence of an acidic proton in the same reaction vessel as the Grignard or organolithium reagent can lead to the protonation of the reagent, which would result in the loss of its nucleophilicity. This is because the acidic proton can react with the negatively charged carbon atom of the Grignard or organolithium reagent, leading to the formation of a less reactive alkane and a neutral magnesium or lithium compound.
In the case of terminal alkynes, the problem is different. Terminal alkynes are highly acidic and can easily deprotonate Grignard or organolithium reagents, resulting in the formation of a new carbon-carbon bond between the two compounds. This can lead to the formation of unwanted byproducts and decrease the yield of the desired product.
Therefore, to avoid these issues, it is important to use anhydrous conditions and to exclude any acidic protons or terminal alkynes from the reaction vessel when forming Grignard or organolithium compounds.
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Help me please ????
Answer:
I think it is more that one is correct, so sorry if I'm wrong, if it isn't, it is one of the electron bonding ones
List one use for each of the following minerals.
Chalcopyrite
Pyrolusite
Kyanite
Talc
Chalcopyrite's sole significant application is as a copper ore, yet the significance of this one use cannot be overstated. as a minor copper resource and as examples of minerals.
What distinguishing features does chalcopyrite possess?It is brassy to golden yellow in color and rates 3.5 to 4 on the Mohs scale for hardness. The streak clearly shows a greenish hue to it. Brass yellow with a potential for iridescent purplish tarnish. mainly the disphenoid, resembles a tetrahedron, is frequently large, and occasionally has a botryoidal shape.
Where is chalcopyrite most frequently discovered?Chalcopyrite is a copper and iron sulfide mineral that is the most prevalent copper mineral and a significant copper resource. In ore veins deposited at medium to high temperatures, such as those in Rio Tinto, it often occurs.
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What is the percent by mass (mv) of a solution with 1.56 g of benzene dissolved in gasoline to make 998.44 mL of solution? (density of gasoline = 0.7489 g/mL)
please I need help lol
Answer:
The percentage by mass of benzene in the solution is approximately 0.2%
Explanation:
The given parameters are;
The mass of the benzene solute dissolved in the gasoline solvent, m₁ = 1.56 g
The total volume of the benzene gasoline solution made, V = 998.44 mL
The density of gasoline, ρ = 0.7489 g/mL
Mass, m = Density, ρ × Volume, V
∴ The mass of gasoline in the 998.44 mL, solution = 0.7489 g/mL × 998.44 mL = 747.731716 g
The total mass of the solution = The mass of the benzene in the solution + The mass of the gasoline in the solution
∴ The total mass of the solution = 747.731716 g + 1.5 g = 749.231716 g
\(The \ percentage \ by \ mass = \dfrac{The \ mass \ of \ a \ fraction}{(The \ mass \ of \ the \ total \ solution)} \times 100\)
The percentage by mass of benzene in the solution = (1.5 g/749.231716 g)×100 ≈ 0.2% by mass.
What is the approximate energy of a photon having a frequency of 4 x 10^14 Hz? (h = 6.6 x 10^-34 Js)
A.
6.1 x 10^47 J
B.
4.0 x 10^14 J
C.
2.6 x 10^-19 J
D.
1.7 x 10^-48 J
Answer:
option c
Explanation:
E = hf
E= energy
h = Planck constant
f = frequency
E = 6.6 X 10^-34 X 4 X 10^14
E = 2.64 X 10^-19J
If you had 50 grams of Oxygen, how many grams of Aluminum Oxide could you make?
Explanation:
4Al(s) + 3O2(g) → 2Al2O3(s) A mixture of 82.49 g of aluminum (м = 26.98 g/mol) and 117.65 g of oxygen (м = 32.00 g/mol) react according to this equation.