10) Allen was curious about dog interaction at the dog park. He wondered if big dogs liked to play with big dogs and if little dogs liked to play with little dogs. After gathering information through research, he followed the scientific method by stating a ____________. This educated guess refers back to the original questions and is stated in such a manner that the results can be measured. A) experiment B) hypothesis C) problem D) procedure

The 35m would the Roche limit be for an earth-orbiting body with the same density as iron(8.0g/cm ^3).

What is density ?

How much material an object contains per unit volume is determined by the density of the substance. It is symbolized by the letter D, however it can also be represented by the symbol.  The density of a substance reveals how dense it is in a certain space. The definition of density is the mass of a substance per unit volume.

It is measured in meters per second in the SI (ms -1 ). A body is considered to be accelerating if there is a change in the magnitude or direction of its velocity.

Therefore, The 35m would the Roche limit be for an earth-orbiting body with the same density as iron(8.0g/cm ^3).

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Answer:

regenerating arms....

Answer:

Mass and distance.

Explanation:

The force of gravity is proportional to the masses of the two objects and inversely proportional to the square of the distance between them.

The magnitude of the force exerted on this object is 1.2 Newton.

Given the following data:

In Science, the impulse that is experienced by an object is always equal to the change in momentum of the object, due to the force acting on an object.

Mathematically, impulse is given by this formula:

\(Impulse = change\;in\;momentum\\\\Force \times time = m \Delta V\)

Substituting the given parameters into the formula, we have:

\(Force \times 10=12\\\\Force =\frac{12}{10}\)

Force = 1.2 Newton.

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1.12 MPa is the shear stress in the glued joint.

If you think of an object as a 2D object, its cross section area is one of its areas. Consider a perfectly spherical ball as an illustration. A circle with a radius equal to the ball can be seen if you view the ball as a 2D object. Consider a cone for another illustration.

The axial or normal stress, σ, in the glued joint can be calculated as:

σ = P/A

A = 2 × b × h

A = 2 × 75 mm × 150 mm = 22,500 mm²

Substituting the values of P and A, we get:

σ = 18 kN / 22,500 mm² = 0.8 MPa

So the normal stress in the glued joint is 0.8 MPa.

The shear stress, τ, in the glued joint can be calculated as:

τ = VQ/It

V = P/2 = 9 kN

The first moment of area, Q, can be calculated as:

Q = b×h2/4

When we change the values of b and h, we obtain:

Q = 75 mm × (150 mm)2 / 4 = 1,406,250 mm³

Calculating the second instant of area, I, is as follows:

I = b×h3/12

The result of substituting the values of b and h is:

I = 75 mm × (150 mm)3 / 12 = 1,054,687.5 mm⁴

Substituting the values of V, Q, I, and t, we get:

τ = 9 kN × 1,406,250 mm³/ (1,054,687.5 mm⁴ × 75 mm) = 1.12 MPa

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The bubbles show rainbow colors under the sun because the sun light refracts into the bubble, being separated in the rainbow colors.

When the white light enters the bubble, it is decomposed, and each different color will have a slightly different direction:

Answer:

Solid - molecules are packed together, and it keeps its shape.

Liquids - take the shape of the container.

Gases - spread out to fill the container.

Electric field lines are a powerful tool to understand and visualize electric fields. They help to represent the direction and magnitude of the electric field at various points around a charged object.

The following statements are true about electric field lines:

A. Electric field lines cannot cross: This is because at the point where two field lines cross, there would be two directions for the electric field, which is impossible. Hence, the lines do not cross, and this is one of the fundamental characteristics of electric field lines.

B. Lines of electric field only originate from positive charges: Electric field lines originate from positive charges and terminate at negative charges. This is because positive charges repel positive charges and attract negative charges. Therefore, the electric field lines originating from a positive charge terminate at a negative charge.

C. Field lines point in the direction of the force the electric field creates on an electron: Electric field lines point in the direction of the force that would be experienced by a positive charge placed at any point in the field. Electrons, being negatively charged, would experience a force in the opposite direction to the electric field.

D. The strength of the electric field is greater in regions where the field lines are closer together: The density of field lines indicates the strength of the electric field. The closer the lines are, the stronger the field at that point.

E. In an electric-field-line drawing with many point charges, the number of field lines originating or terminating on each charge is proportional to the charge. That is, bigger charges have proportionally more field lines: The number of field lines originating or terminating on each charge is directly proportional to the magnitude of the charge.

F. The true strength of an electric field at any point can be determined from an electric field representation: The strength of the electric field at a point can be determined by the density of electric field lines at that point. However, the actual strength of the field would require quantitative measurements using instruments such as a voltmeter or an electrometer.

In conclusion, electric field lines are an essential tool in understanding the behavior of electric fields. They provide a visual representation of the electric field, its direction, and its strength at various points in space.

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Answer:

18 kg * m/s

Explanation:

The equation for momentum is:

momentum = mass * velocity

And although the problem already gave velocity, you must calculate the mass from the graviational force.

Fg = 3.4N = mg = 9.8m

mass = 3.4 N / 9.8 m/s^2 = 0.3469 kg

Momentum = 52m/s * 0.3469 kg - 18.041 kg * m/s = 18

Let the tension in the string connect. A and B be 'T' and let friction the force acting on A be fA

Now, for B,

T- fB -T' = \(M_{B} a\)

but a = 0, since speed is constant.

∴ T- fB - T' = 0

FB = friction force on B = f = 10N.

∴ T - FB - T' = 0

given,

50N - 10N -T' = 0

or, T' = 40N

for 'A', acceleration a = 0

T' - FA = \(M_{A} A\) = 0

or, FA = T' = 40N

∴ friction force acting on A is 40N.

Velocity is constant if both magnitude and direction do not change over time. In other words, this is when the rate of change of an object's position remains the same over a period of time. An object must have a constant speed in a constant direction. A constant direction forces an object to move in a straight line, so constant velocity means moving at a constant speed in a straight line.

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Answer:

1km west

Explanation:

Because if the cyclist is going back 2km then its 3-2=1km

One in twelve males have color blindness whereas One in two-hundred females have color blindness. Thus, Option D is correct.

Color blindness is the ability to distinguish different colors. It is hard to differentiate the colors between the same color family. A person with color blindness can not able to see red and green, and can able to see grey, black, and white. It is often inherited.

A person with color blindness can not able to differentiate the colors between red and green. There are three types of color blindness they are Deuteranomaly (difficulty with red-green color blindness and it makes green look redder), Protanomaly(red look greener), Protanopia, and deuteranopia (difficulty in identifying red and green). It is cured by using proper contact lenses.

Thus, One in twelve males has color blindness. Hence, the ideal solution is option D.

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Option C. According to Einstein's theory, an increase in the number of photons in a beam of light  C. The brightness of the beam of light increases.

According to Einstein's theory, the number of photons in a beam of light does not directly affect the fundamental properties of light such as its wavelength, speed, or frequency.

These characteristics of light are determined by the source and the medium through which it travels.

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Answer: C.

The brightness of the beam of light increases.

Explanation: ed mentum or plato

The coefficient of thermal conductivity (k) is related to the rate of heat flow (Q), the cross-sectional area (A), the length (L), the temperature difference (ΔT), and the thermal resistance (Rth) by the following equation:

k = Q / (A * ΔT * L) = Rth * (A * ΔT)

Reorganizing this equation gives:

Rth = k / (A * ΔT)

The given information in the problem is:

Rate of heat flow (Q) = 14.0 watts

Thermal resistance (Rth) = (350 mm × 350 mm × 15 mm) / (14.0 watts) = 31.5 mm⁴/C

Temperature difference (ΔT) = 28°C

Substituting these values into the equation, we have:

k = Q / (A * ΔT) = 14.0 W / (0.35 m² * 28°C) = 1.94 W/mK

So the coefficient of thermal conductivity (k) for this wood is approximately 1.94 W/mK.

Answer:

Compared to the emitted frequency, the received frequency is higher during the approach, identical at the instant of passing by, and lower during the recession.

Explanation:

Videos can be streamed from the cloud to a computer with no loss in quality because Digital signals are used to transmit data to and from the cloud.

How do digital signals work?

An established or one that represents data as a step made up of discrete values is known as a digital signal. There is no noise produced by digital signals. Electronic signals sent as pulses are used to transmit digital signals to computers. These signals can be found in things like digital phones and computers.

Because digital signals are used to transport data to and from the cloud, it should be noted that videos are said to stream from the cloud to a computer without quality degradation.

Videos can be streamed from the cloud to a computer with no loss in quality because Digital signals are used to transmit data to and from the cloud.

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At its maximum height h, the football has zero vertical velocity, so if it was kicked with initial upward speed v, then

0² - v² = -2gh

Solve this for v :

v² = 2gh

v = √(2gh)

The height y of the football t seconds after being kicked is

y = vt - 1/2 gt²

Substitute v = √(2gh), replace y = h, and solve for h when t = 3.8 s :

h = √(2gh) t - 1/2 gt²

h = √(2gh) (3.8 s) - 1/2 g (3.8 s)²

h ≈ (16.8233 √m) √h - 70.756 m

(By √m, I mean "square root meters"; on its own this quantity doesn't make much physical sense, but we need this to be consistent with √h. h is measured in meters, so √h is measured in √m, too.)

h - (16.8233 √m) √h + 70.756 m = 0

Use the quadratic formula to solve for √h :

√h = ((16.8233 √m) ± √((16.8233 √m)² - 4 (70.756 m))) / 2

Both the positive and negative square roots result in the same solution,

√h ≈ 8.411 √m

Take the square of both sides to solve for h itself:

(√h)² ≈ (8.411 √m)²

⇒   h ≈ 70.756 m ≈ 71 m

(1) The tension in cable 2 is 34.83 N.

(2) The coefficient of friction between the block and the floor is 0.45.

The tension in the cable 2 is determined by resolving the forces into various component as shown below.

The vertical component of the forces on the picture is given as;

∑Fy = T₁ sin (65) + T₂ sin (32) - 20 N = 0

T₁ sin (65) + T₂ sin (32) - 20 N = 0

1.7 x sin (65) + 0.53T₂ - 20 = 0

1.54 + 0.53T₂ = 20

0.53T₂ = 18.46

T₂ = 18.46 / 0.53

T₂ = 34.83 N

The value of coefficient of friction is calculated by applying Newton's second law of motion as follows;

F (net) = ma

(F₁ + F₂) - Ff = ma

where;

Ff is the force friction

a is the acceleration of the block

m is the mass of the block

(F₁ + F₂) - μmg = ma

where;

When block moves at a constant velocity, the acceleration a = 0

(F₁ + F₂) - μmg = 0

μmg  = (F₁ + F₂)

μ = (F₁ + F₂) / mg

μ = ( 195 + 222 ) / ( 95 x 9.8 )

μ = 0.45

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The nature of the image formed by the convex lens is virtual, the position of the image is 30 cm away from the lens on the same side as the object, and the size of the image is twice the size of the object. The magnification is 2, meaning the image is magnified.

Given:

Object height (h) = 5 cm

Focal length of the convex lens (f) = 10 cm

Object distance (u) = 15 cm (positive since it's on the same side as the incident light)

To determine the nature, position, and size of the image, we can use the lens formula:

1/f = 1/v - 1/u

Substituting the given values:

1/10 = 1/v - 1/15

To simplify the equation, we find the common denominator:

3v - 2v = 2v/3

Simplifying further:

v = 30 cm

The image distance (v) is 30 cm. Since the image distance is positive, the image is formed on the opposite side of the lens from the object.

To find the magnification (M), we use the formula:

M = -v/u

Substituting the values:

M = -30 / 15 = -2

The magnification is -2, indicating that the image is inverted and twice the size of the object.

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The mass of a substance is not directly related to latent heat. Instead, latent heat is a parameter that describes the amount of energy required or released during a phase shift of a substance.

Latent heat can be thought of as hidden energy that is supplied or extracted to change the state of a substance without changing its temperature or pressure.

Latent heat is energy released or absorbed, by a body or a thermodynamic system, during a constant-temperature process—typically a first-order phase transition.

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Classical mechanics describes the motion of objects on a macroscopic scale, while quantum mechanics deals with the behavior of particles on a microscopic scale. Classical mechanics is deterministic, meaning that it predicts precise outcomes based on initial conditions, while quantum mechanics is probabilistic, providing probabilities of different outcomes. Classical mechanics follows the principle of causality, where every effect has a specific cause, whereas quantum mechanics introduces inherent uncertainty and wave-particle duality. Classical mechanics is well-suited for describing everyday objects, while quantum mechanics is necessary to explain the behavior of particles at the atomic and subatomic levels.

~~~Harsha~~~

The new angular velocity becomes  0.286 rev/s.

Given parameters:

Mass of the marry go round: M = 120 kg.

Radius of the marry go round: r = 1.80 m.

Mass of the boy: m = 27 kg.

Initial angular velocity of the marry go round: ω₁ = 0.350 rev/s.

Final angular velocity of the marry go round: ω₂ = ?

From the principle of conservation of angular momentum;

Initial angular momentum = final angular momentum

⇒ 1/2 Mr²ω₁ = 1/2( M+m)r²ω₂

⇒ ω₂ = Mω₁/(m+M)

= 120×0.35/(120+27) rev/s

= 0.286 rev/s.

So, final angular velocity of the marry go round: ω₂ = 0.286 rev/s.

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The hiker made it to a safe landing on the other side of the gap after travelling horizontally at 2.49 m.

The time taken for the hiker to fall from the given height is calculated as follows;

h = vt + ¹/₂gt²

where;

h = ¹/₂gt²

t = √(2h/g)

t = √[(2 x 0.6) / (9.8)]

t = 0.35 seconds

The horizontal velocity of the hiker during the period of acceleration is calculated as follows;

Vₓ = at

Vₓ = (5.92 m/s²) x (1.2 s)

Vₓ = 7.104 m/s

The horizontal distance travelled during the time period of 0.35 seconds;

X = Vₓt

X = 7.104 x 0.35

X = 2.49 m

Thus, the hiker made it to a safe landing on the other side of the gap which is 2.3 m wide and smaller to his horizontal displacement of 2.49 m.

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Answer: 0 m/s. that is your answer i hope this help sorry if i am wrong

Explanation:

What does the area under the curve on a velocity-versus-time graph represent? ... then slows down to travel the last 40 miles in three hours. ... 20. A bicyclist travels the first 700 m of a trip at an average speed of 8 m/s, travels the ... to complete the trip at an average speed, for the entire trip of 440 km/h. ... 125) v1= 0 m/s.

Answer:

force applied by red = 50 N

force applied by blue = - 63 N (since it is in the opposite direction)

net force = force by red + force by blue

net force = 50 + (- 63)

net force = - 13 N  

Pangea ends due to movements in the tectonic plates.

19.3 gcm3 19.3 g c m 3 is equivalent to 19300 kgm3 due to the decimal place shifting due to the conversion being in metric measurements.

The amount of objects, including people, animals, plants, and other living things, that are present in a region is known as the density. The number of objects is divided by the area to determine density. The number of inhabitants in a nation divided by its size, measured in square kilometers or miles, is the population density of that nation.

In reference to the amount of matter contained in a thing, density refers to how much volume the object or substance occupies.

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Answer:

The correct answer is option A: 3.00 × 10^(-11) m.

Explanation:

To find the wavelength of a gamma ray with a frequency of about 10^19 s^(-1), we can use the equation:

wavelength = speed of light / frequency

Given:

Speed of light (c) = 3.00 × 10^8 m/s

Frequency (f) = 10^19 s^(-1)

Substituting the values into the equation:

wavelength = (3.00 × 10^8 m/s) / (10^19 s^(-1))

To simplify the expression, we can rewrite the denominator as (1 / 10^(-19)) s:

wavelength = (3.00 × 10^8 m/s) / (1 / 10^(-19)) s

To divide by a fraction, we multiply by its reciprocal:

wavelength = (3.00 × 10^8 m/s) × (10^(-19) s)

Applying the properties of exponents, we can add the exponents when multiplying with the same base:

wavelength = 3.00 × 10^(-11) m

Therefore, the wavelength of the gamma ray is approximately 3.00 × 10^(-11) m.