1. Young's Double Slit Experiment with light proved that light was a wave from a reflection.
a. True
b. False
2. Sound waves speed up as they go farther down in the ocean because of multiple factors such as the ocean's waves' wavelengths being longer, pressure increasing, and salinity.
a. True
b. False
Answers
1. Young's Double Slit Experiment with light proved that light was a wave from a reflection. FALSE
2. Sound waves speed up as they go farther down in the ocean because of multiple factors such as the ocean's waves' wavelengths being longer, pressure increasing, and salinity. TRUE.
What is reflection of light?
The reflection of the light occurs when light hits a hard surface and falls back.
The Young's Double Slit Experiment with light did not prove that light was a wave from a reflection.
For question, 2;
Sound waves speed up as they go farther down in the ocean because of multiple factors such as the ocean's waves' wavelengths being longer, pressure increasing, and salinity.
The above statement is true, as speed of a wave increases with increase in its wavelength.
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Related Questions
Select the correct answer.
A boat moves 60 kilometers east from point A to point B. There, it reverses direction and travels another 45 kilometers toward point A. What are the total
distance and total displacement of the boat?
O A.
OB.
O C.
O D.
The total distance is 105 kilometers and the total displacement is 45 kilometers east.
The total distance is 60 kilometers and the total displacement is 60 kilometers east.
The total distance is 105 kilometers and the total displacement is 15 kilometers east.
The total distance is 60 kilometers and the total displacement is 45 kilometers east.
Answers
The total distance is 105 kilometers and the total displacement is 15 kilometers east. Option C
How to solve for the total distanceTo calculate the total distance, we add the distances traveled in each leg of the journey: 60 kilometers (from A to B) + 45 kilometers (from B back to A) = 105 kilometers.
However, displacement refers to the change in position of an object in a straight line from its starting point to its ending point. In this case, since the boat starts and ends at the same point (A), the total displacement is zero.
Hence The total distance is 105 kilometers and the total displacement is 15 kilometers east.
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Nowton's third law refers to 'action reaction forces*. These forces are
always:
Answers
equal in magnitude but opposite in direction
If a body travelled a distance 's' in 't'.
What is the distance travelled in 't'
Answers
Answer: Distance traveled in time t is s
Explanation: Self Explanatory
Newton’s law of gravitation says that gravity is a mutually attractive force. Explain the following observation: A small object is dropped on Earth and we see it fall toward Earth. However, we do not observe Earth moving toward the object.
Answers
Answer:
Explanation:
The explanation involves another Newton's law: his second law of motion says force is a product of mass and acceleration.
When a small object is dropped on Earth, gravity pulls the object down towards Earth. The same mutually attractive gravity force also pulls Earth towards the object. But as mass of Earth is much larger than that of the small object, the acceleration of Earth and hence its movement toward the object will be much smaller as to be not noticeable.
By what percentage does the drag force on a car increase as it goes from 61 km/h to 113 km/h?
Answers
Given,
The initial speed of the car, u=61 km/h
The final speed of the car, v=113 km/h
The drag force on an object is given by,
\(F=\frac{1}{2}\rho v^2C_DA\)Where:
• ρ is the density of the air.
,• v is the speed of the object.
,• C_D is the drag coefficient.
,• A is the area of cross-section of the object.
In the given problem, only the speed of the car changes. And density of the air, drag coefficient, and area of the cross section remains the same.
Thus, the initial drag force on the car is
\(F_i=\frac{1}{2}\rho u^2C_DA\)The final drag force is given by,
\(F_f=\frac{1}{2}\rho v^2C_DA\)The percentage increase in the drag force is given by,
\(P=\frac{F_f-F_i}{F_i}_{}\times100\)On substituting,
\(\begin{gathered} P=\frac{\frac{1}{2}\rho v^2C_DA-\frac{1}{2}\rho u^2C_DA}{\frac{1}{2}\rho u^2C_DA}\times100 \\ =\frac{\frac{1}{2}\rho C_DA(v^2-u^2)}{\frac{1}{2}\rho u^2C_DA}\times100 \\ =\frac{v^2-u^2}{u^2}\times100 \end{gathered}\)On substituting the values of v and u,
\(\begin{gathered} P=\frac{113^2-61^2}{61^2}\times100 \\ =243\% \end{gathered}\)Thus, the percentage increase in the drag force is 243%
The minute hand of a clock on a clock tower is 1 meter long. What is the tangential speed at the tip of that hand
Answers
Answer:
ω = θ / t
1 rev = 2 pi rad
t = 60 sec / min * 60 min / hr = 3600 sec / hr
v = ω R tangential speed
v = (2 pi m / hr) / (3600 sec / hr) = .00175 m/sec
As a check
s = 2 pi * 1 m = 6.28 meters around dial
It takes 3600 sec for 1 rotation of the minute hand
v = 6.28 / 3600 = .0017 m/s
The batter swings his bat 1.8 meters in 0.1 seconds. How fast is his bat speed in meters per second?
Answers
Answer:
18 m/s
Explanation:
1.8 meters / 0.1 seconds = 18 m/s
Using the same cost and time estimates, consider any trade-offs that Drehex Corporation may have to make to complete the project. Camilla John Nora Oracio Cost per Hour $40 $30 $20 $15 Time to Complete Job 20 hours 30 hours 40 hours 50 hours Ideally, the process of technological design should be cost-effective and time-effective. However, sometimes this is simply not possible and trade-offs are necessary. Explain the trade-offs Drehex Corporation may have to make to complete the project.
Answers
Drehex Corporation may need to make trade-offs between cost and time to complete the project, considering the hourly rates and time estimates of their team members.
Corporation may have to make several trade-offs to complete the project based on the cost and time estimates provided. Here are some possible trade-offs they may need to consider:
Cost vs. Time: The corporation may need to decide whether to prioritize completing the project quickly or keeping the costs low. If they want to minimize costs, they might opt for a longer completion time by choosing a team member with a lower cost per hour. Conversely, if time is crucial, they might choose a team member with a higher cost per hour to expedite the process.Expertise vs. Cost: The team members have different levels of expertise, as indicated by their respective costs per hour. Drehex Corporation may need to evaluate the trade-off between the level of expertise required for the project and the associated cost. They might decide to invest more in a highly skilled team member to ensure the quality and efficiency of the project, even if it means incurring higher costs.Resource Allocation: The corporation will need to allocate resources effectively among the team members to ensure a balanced workload. They may need to assign tasks and responsibilities based on individual strengths and expertise, considering the trade-off between utilizing the most capable team members and maintaining a fair distribution of work.Quality vs. Time/Cost: The trade-off between project quality and time/cost is a common consideration. If Drehex Corporation wants to deliver a high-quality output, they might need to allocate more time and resources to ensure thoroughness and attention to detail. Conversely, if time or cost constraints are significant factors, they may need to compromise on certain aspects of quality to meet project deadlines or budget limitations.Ultimately, the trade-offs Drehex Corporation makes will depend on their specific project goals, budget, timeline, and the importance they place on factors such as cost-effectiveness, timeliness, expertise, and quality. Balancing these trade-offs effectively is crucial for successful project completion.
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Answer:
Sample Response: Oracio is the most cost-effective choice because he would cost the least to complete the project. However, he would also take the longest amount of time. Camilla could complete the job the fastest, but she costs more than Oracio. Drehex Corporation will have to decide if it is more important to save money or complete the work quickly to meet the deadline.
Explanation:
What would most likely occur if an earthquake occurred near a dry, steep slope? Why?
Answers
Answer: There would probably be a land slide.
Explanation: The earthquake would break up the dry steep hill and then it would break up and cause a land slide.
This is my first answer! :)
When you take your 1900-kg car out for a spin, you go around a corner of radius 56 m with a speed of 14 m/s. The coefficient of static friction between the car and the road is 0.88. Part A Assuming your car doesn't skid, what is the force exerted on it by static friction
Answers
Answer:
6,650 newtons
Explanation:
The computation of the force exerted on it by static friction is shown below:
Data provided in the question
Mass of car = m = 1,900 kg
speed = v = 14 m/s
radius = r = 56 m
Let us assume friction force be f
And, the Coefficient of friction = \(\mu\)= 0.88
As we know that
\(f = \frac{mv^2}{r}\)
\(= \frac{1,900 \times 14^2}{56}\)
= 6,650 newtons
We simply applied the above formula so that the force exerted could come
(A star if you answer this question) A school bus is traveling at 11.1 m/s and has a
momentum of 152,625 kgm/s. What is the mass of the bus?
Answers
\(\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}\)
Actually Welcome to the Concept of the Kinematics in real world.
So, as given here, we have to find the Mass of the bus from the given momentum, so we get as,
P = m * V
momentum = mass * velocity
here, P= 152625 kgm/s and v= 11.1 m/s
so substituting we get as,
m = 152625 ÷ 11.1 => 13,750 kg
hence,the mass of the bus is 13,750 kg.
An ideal spring is fixed at one end. A variable force F pulls on the spring. When the magnitude of F reaches a value of 43.8 N, the spring is stretched by 15.5 cm from its equilibrium length. Calculate the additional work required by F to stretch the spring by an additional 10.4 cm from that position. (in J)
Answers
A force of 43.8 N is required to stretch the spring a distance of 15.5 cm = 0.155 m, so the spring constant k is
43.8 N = k (0.155 m) ==> k = (43.8 N) / (0.155 m) ≈ 283 N/m
The total work done on the spring to stretch it to 15.5 cm from equilibrium is
1/2 (283 N/m) (0.155 m)² ≈ 3.39 J
The total work needed to stretch the spring to 15.5 cm + 10.4 cm = 25.9 cm = 0.259 m from equilibrium would be
1/2 (283 N/m) (0.259 m)² ≈ 9.48 J
Then the additional work needed to stretch the spring 10.4 cm further is the difference, about 6.08 J.
A box puts a pressure of 50 N/m2 on an area of 0.25 m2. Find the force of the box on the floor.
Answers
A box puts a pressure of 50 N/\(m^{2}\) on an area of 0.25 \(m^{2}\). The force of the box on the floor is 12.5 Newton (N)
What is pressure and types?Pressure is defined as the physical force exerted on an object. The force applied is perpendicular to the surface of objects per unit area. The basic formula for pressure is \(\frac{F}{A}\) (Force per unit area). Unit of pressure is Pascals (Pa). Types of Pressures are Absolute, Atmospheric, Differential, and Gauge Pressure.
Using the formula Force = Pressure × Area
given Pressure = 50 N/\(m^{2}\)
area = 0.25 \(m^{2}\)
Substituting the values ,
Force = 12.5 Newton
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a fly wheel is rotating with an angular velocity of 2 rad/sec and acted by an acceleration of 1/π rad/s2 . how long will it take to complete three revolutions?
Answers
Explanation:
this is the answer for your question if you have any doubt you can join
An astronomy class is so excited by the discovery of planets around other stars that they decide to do a library exhibit on the subject so that everyone in the school can learn about it. In this exhibit they want to pay tribute to both the astronomers of today who have done the work AND some of the scientists of the past whose work was essential to making the discoveries possible (and directly related to the techniques involved). Which of the following scientists of the past should definitely be included in the exhibit?
a. George Herbigâ
b. Ejnar Hertzsprungâ
c. Ptolemyâ
d. Gerard Kuiperâ
e. Christian Dopplerâ
Answers
Answer: e. Christian Dopplerâ
Explanation:
Based on the information given, the scientist of the past that should definitely be included in the exhibit is Christian Dopplera.
He described how the frequency of sound waves and light is being affected by the relative speed of both the source and also the observer. This was referred to as the Doppler effect.
In this scenario, the Doppler effect can be used to show how the universe is expanding. Therefore, the correct option is E.
3. A 142 g baseball is thrown at a speed of 42.9 m/s. What is the kinetic energy of the baseball at this moment?
261 )
131 )
O 6090 )
505 )
Kinetic energy (KE) is defined by the equation KE = { mu?.
Point
0
11
4. Harriet is practicing archery. As she draws back an arrow, the arrow has 34.3 of elastic notretia
have when it is about to hit the ground?
Answers
=1/2(142*10^-3)(42.9)^2=130.6=131J
Answer: For question 1
131 is the correct answer
KE = 1/2 mv^2
Explanation:
A heavy storm leaves 1 cm of rain on a city 5 km wide and 8 km long on a 2 hour period. How many cm3 of water fell on the city?
Answers
Answer: wow that’s hard
Explanation:
Write a detall note on Modern Periodic Table
Answers
Answer:
In a modern periodic table,Elements are arranged in the order of their increasing atomic number.In modern periodic table,there are seven horizontal rows called periods and eighteen vertical columns(1-18) called groups.The arrangement of the periods and groups result in formation of boxes.
Hope it helps❤️
who discovered earth was like a big magnet
Answers
Identify two technologies that can be used to find the locations of objects. Identify the type or types of waves each
technology uses.
Answers
X-rays use electromagnetic waves
A 1.2 kg ball drops vertically onto a floor hitting with a speed of 15 m/s
Answers
The magnitude of the change in momentum is 36 kg m/s.
The momentum of an object is defined as the product of its mass and velocity.
The symbol for momentum is p. Its unit is kilogram meters per second (kg m/s). When a ball falls vertically onto a surface, the momentum is said to change.
The magnitude of the change in momentum can be found by calculating the difference between the initial momentum and the final momentum.
We can use the equation below to find the change in momentum.Δp = pf - pi
Where Δp is the change in momentum, pf is the final momentum, and pi is the initial momentum.The initial momentum of the ball can be found using the equation:
p = mv
where p is momentum, m is mass and v is velocity.
Therefore, the initial momentum of the ball is:
p = mv= 1.2 kg × 15 m/s= 18 kg m/s
The final momentum can be found using the same equation, but with a negative velocity since the ball is bouncing back with the same speed but opposite direction.
Therefore, the final momentum is:-18 kg m/s/
The change in momentum can now be calculated using the equation:
Δp = pf - piΔp = (-18 kg m/s) - (18 kg m/s)Δp = -36 kg m/s
Therefore, the magnitude of the change in momentum is 36 kg m/s.
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A compound has a molar mass of 123. 22 g/mol. What is the molecular formula of a substance that has this molar mass?.
Answers
If the given compound has a molar mass of 123.22 g/mol then, SrS is the molecular formula of a substance that has this molar mass. Therefore, option c is the correct answer according to the given information.
The molecular formula is defined as the number of atoms present in the molecules of a chemical compound when the two molecules of different substances are combined together. The molecular mass is the mass of a given molecule measured in daltons.
The molar mass of Strontium = 87.22g/mol
The molar mass of Sulfur = 32 g/mol.
The total molecular mass of these two combined compounds
= Strontium + Sulfur = SrS
SrS = 87.22 + 32 = 123.22g/mol.
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The complete question is-
A compound has a molar mass of 123.22 g/mol. what is the molecular formula of a substance that has this molar mass?
A. CoH4
B. PSF3
C. SrS
D. ZrO2
I want the answer and that’s all
Answers
Answer:
Cuboid?
Explanation:
Imagine you are riding on a yacht in the ocean and traveling at 20 mph. You then hit a golf ball at 100 mph from the deck of the yacht. You see the ball move away from you at 100mph, while a person standing on a nearby beach would observe your golf ball traveling at 120 mph (20 mph + 100 mph).
Now imagine you are aboard the Hermes spacecraft traveling at 0.1c (1/10 the speed of light) past Mars and shine a laser from the front of the ship. You would see the light traveling at c (the speed of light) away from your ship.
Answers
An observer on the spacecraft would see the light beam moving away from the ship at the speed of light, while an observer on Mars would also see the light beam moving away from the ship at the speed of light. This is because the speed of light is always constant, regardless of the motion of the observer or the light source.
When the ball is hit from the deck of the yacht at 100 mph, it is moving at a speed relative to the yacht.
Since the yacht is moving at 20 mph, the ball would appear to be moving away from the yacht at 100 mph.
This is because the speed of the ball relative to the yacht is 100 mph, while the speed of the yacht relative to the ground is 20 mph.
Therefore, the total speed of the ball relative to the ground would be the sum of the speed of the yacht and the speed of the ball relative to the yacht, which is 120 mph (20 mph + 100 mph).
Now let's consider the Hermes spacecraft traveling at 0.1c past Mars and shining a laser from the front of the ship.
According to the theory of relativity, the speed of light is always the same for all observers, regardless of their motion or the motion of the light source.
So, regardless of the speed of the spacecraft, the light beam would travel away from the ship at the speed of light, c.
An observer on the spacecraft would see the light beam moving away from the ship at the speed of light, while an observer on Mars would also see the light beam moving away from the ship at the speed of light.
This is because the speed of light is always constant, regardless of the motion of the observer or the light source.
In summary, the theory of relativity tells us that the speed of light is always the same for all observers, regardless of their motion or the motion of the light source.
This means that the speed of light is a fundamental constant of the universe, and it plays a crucial role in our understanding of the laws of physics.
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A ball is thrown upward from the ground with an initial speed of 20.6 m/s; at the same instant, another ball is dropped from a building 14 m high. After how long will the balls be at the same height above the ground?
Answers
Answer:
t= 0.68 s
Explanation:
Neglecting air resistance, both balls are only under the influence of gravity, so we can use the kinematic equation for vertical displacement for both balls.First of all, we define two perpendicular axes, coincidently with horizontal and vertical directions, that we denote as x-axis and y-axis respectively.Assuming that the upward direction is the positive one, g must be negative as it always points downward.Taking the ground as our zero reference for the vertical axis (y axis), the equation for the ball thrown upward can be written as follows:\(y = v_{o}* t -\frac{1}{2} * g * t^{2} (1)\)
As the second ball is dropped, its initial velocity is 0. Taking the height of the building as the initial vertical position (y₀), we can write the equation for the vertical displacement as follows:\(y = y_{o} - \frac{1}2}*g*t^{2} (2)\)
As the left sides of (1) and (2) are equal each other (the height of both balls above the ground must be the same), the time must be the same also.We can rearrange (2) as follows:\(y -y_{o} = -\frac{1}{2}*g* t^{2} (3)\)
Replacing the right side of (3) in (1), we get:\(y = v_{o}*t + (y- y_{o})\)
⇒ \(t =\frac{y_{o} }{v_{o} } =\frac{14 m}{20.6 m/s} = 0.68 s\)
⇒ t = 0.68s
A 0.1-kg meter stick is supported at both ends by strings, and there is a 200-g mass attached to it at the 70 cm mark. What is the force exerted by the string connected at the 0 cm mark, if the system is in static equilibrium
Answers
Answer:
The force exerted by the string connected at the 0 cm mark is 1.078 N
Explanation:
Given;
mass of the meter stick, m = 0.1 kg
weight of the meter stick, = 0.1 kg x 9.8 m/s² = 0.98 N
the weight attached at 70 cm mark = 0.2 kg x 9.8 m/s² = 1.96 N
0cm--------------------------50cm-----------70cm-------------100cm
↑ ↓ ↓ ↑
F₁ 0.98N 1.96N F₂
Take the moment about F₂: clockwise moment = anticlockwise moment
F₁(100 - 0) = 0.98(100 -50) + 1.96(100 -70)
100F₁ = 49 + 58.8
100F₁ = 107.8
F₁ = 107.8 / 100
F₁ = 1.078 N
Therefore, the force exerted by the string connected at the 0 cm mark is 1.078 N
three identical blocks, X, Y, and Z, hang up from identical strings, as shown in the figure. which of the following free-body diagrams could represent the forces exerted on block Y?
Answers
The free-body diagram that could represent the forces exerted on block Y is upward tension force due to block X and downward tension force due to block block Z and its own weight.
option D is the correct answer.
What is free body diagram?A free-body diagram is a sketch of all the forces acting on the given object with all the surrounding objects stripped away and all of the forces acting on the body shown in their respective direction.
For the three identical blocks, X, Y, and Z, hang up from identical strings, as shown in the figure, the following are the direction of the forces acting on the string.
weight of block X -----> acting downwards
weight of block Y ------> acting downwards
weight of block Z ------> acting downwards
According to Newton's third law of motion, acting and reaction are equal and opposite.
As the weight of the blocks are acting downwards, the tension in the rope supporting the weights will be acting upwards.
The total weights of the = downward force of gravity
The tension in the string = upward tension force
The free body diagram is sketched as;
↑ F (Tension Up)
Ф
↓ ↓ F (Gravity) + F (tension down)
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A 0.150-m-radius grinding wheel, starting at rest, develops an angular speed of 12.0 rad/s in a time interval of 4.00 s. What is the centripetal acceleration of a point 0.100 m from the center when the wheel is moving at an angular speed of 12.0 rad/s?
Answers
The centripetal acceleration of a point 0.100 m from the center when the wheel is moving at an angular speed of 12.0 rad/s is 1.44 m/s^2.
To find the centripetal acceleration of a point on the grinding wheel, we can use the formula:
a = rω^2
Where:
a is the centripetal acceleration,
r is the distance from the center of the wheel to the point, and
ω (omega) is the angular speed.
Given:
Radius of the grinding wheel, r = 0.150 m
Angular speed, ω = 12.0 rad/s
Distance from the center, r' = 0.100 m
First, we calculate the centripetal acceleration at the given angular speed:
a = (0.150 m)(12.0 rad/s)^2 = 21.6 m/s^2
Now, to find the centripetal acceleration at a distance of 0.100 m from the center, we substitute the new radius into the formula:
a' = (0.100 m)(12.0 rad/s)^2 = 1.44 m/s^2
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How can climate and temperature influence an individual's behavior?
a Climate and temperature can affect an individual's social interactions.
b. Climate and temperature can affect an individual's attitude toward survival.
Climate and temperature affect all aspect of an individual's behavior
d. Climate and temperature have no effect on an individual's behavior.
С.
Please select the best answer from the choices provided
OA
B
С
OD
Answers
Answer:
Its B. Climate and temperature can affect an individual's attitude toward survival.
Explanation:
Edge 2022 got it right
Which object(s) would accelerate the least if the ALL felt the same net force? A) A and D B) B and C
Answers
Answer:
A and D
Explanation:
By the second law of Newton, the force is equal to mass times acceleration. So:
\(F=m\cdot a\longrightarrow a=\frac{F}{m}\)Therefore, if all felt the same net force but the mass is greater, the acceleration will be less. So, the objects with the least acceleration will be the objects with the greater mass. Then, the answer is A and D because 4 kg is greater than 2 kg.