What is the constant of proportionality in the equation
Below
Answer:
k = 9/2
Step-by-step explanation:
Constant of proportionality, k = y/x
given: x/y = 2/9
since k = y/x, therefore, k value will now be inverse of 2/9, which is 9/2
Summer looked at the formula for the Pythagorean Theorem, a2 + b2 = c2, she said that it didn’t matter which sides of a right triangle were a, b, and c. Is she correct?
Answer:
Summer is incorrect
Step-by-step explanation:
It definitely matters which side is side "c". Side "c" must be the hypotenuse (the side across from the right angle).
The other two sides are the legs (sides touching the right angle), and either leg can be "a" or "b", but the hypotenuse must be "c".
Take the equation, a² + b² = c², and subtract c² from both sides:
\(a^{2} +b^{2} -c^{2} =0\)
It won't matter which leg is "a" or "b", because of the commutative property of addition. Note that "a²" and "b²" are added together, and due to the commutative property of addition, we can add in either order and get the same result.
However, since the c² term is connected by subtraction, and subtraction doesn't have a commutative property, it can't be subtracted in any order. Meaning which side it is is important.
HELP ME PLEASE I ONLY HAVE 5 MIN
Answer:
L = (-1.5, 2) U = (1.5, 2.5) V = (1, -0.5)
Step-by-step explanation:
Just divided everything by two.
Hi can you please help me
The probability that student chosen at random is 16 years is 0.28.
How to find the probability of the student chosen?The table shows the distribution of student by age in a high school with 1500 students. Therefore, the probability that randomly chosen student is 16 years can be found as follows:
Therefore,
probability = number of favourable outcome to age / total number of possible outcome
Hence,
probability that student chosen at random is 16 years = 420 / 150
probability that student chosen at random is 16 years = 0.28
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A landscaper has 10 2/5 cubic yards of peat moss in a truck. If he unloads 2 2/3 cubic yards at the first site and 2 1/4 cubic yards at the second site, how many cubic yards of peat moss remain for the third site?
Step-by-step explanation:
The problem bothers on fractions, here we are being presented with mixed fractions.
what we are going to do bascially is to subtract the sum of all the uloaded
peat moss in sites 1 and 2 to get from the peat moss to get the remaining for the third site
therefore
\(10\frac{2}{5}-(2\frac{2}{3}+ 2\frac{1}{4})\)
we then have to convert the mixed fraction to further simplify the problem we have
\(\frac{52}{5}-(\frac{8}{3}+ \frac{9}{4})\)
we then solve the fraction to the right of the negative symbol first
\(=\frac{52}{5}-(\frac{8}{3}+ \frac{9}{4})\\\\=\frac{52}{5}-\frac{32+27}{12} \\\\=\frac{52}{5}-\frac{59}{12} \\\\\=\frac{624-295}{60} \\\\=\frac{329}{60}\)
We can now convert to mixed fraction
\(=\frac{329}{60}\\\\ =5\frac{12}{25}\)
For the third site the remainder is 5 12/25
Builtrite has calculated the average cash flow to be $14,000 with a standard deviation of $5000. What is the probability of a cash flow being between than $16,000 and $19,000 ? (Assume a normal distribution.) 16.25% 18.13% 23.90% 2120%
The correct answer is that the probability of a cash flow being between $16,000 and $19,000 is approximately 18.59%.
To calculate the probability of a cash flow being between $16,000 and $19,000, we can use the standard deviation and assume a normal distribution.
We are given that the average cash flow is $14,000 with a standard deviation of $5,000. These values are necessary to calculate the probability.
The probability of a cash flow falling within a certain range can be determined by converting the values to z-scores, which represent the number of standard deviations away from the mean.
First, we calculate the z-score for $16,000 using the formula: z = (x - μ) / σ, where x is the cash flow value, μ is the mean, and σ is the standard deviation. Plugging in the values, we get z1 = (16,000 - 14,000) / 5,000.
z1 = 2,000 / 5,000 = 0.4.
Next, we calculate the z-score for $19,000: z2 = (19,000 - 14,000) / 5,000.
z2 = 5,000 / 5,000 = 1.
Now that we have the z-scores, we can use a standard normal distribution table or calculator to find the corresponding probabilities.
Subtracting the probability corresponding to the lower z-score from the probability corresponding to the higher z-score will give us the probability of the cash flow falling between $16,000 and $19,000.
Looking up the z-scores in a standard normal distribution table or using a calculator, we find the probability for z1 is 0.6554 and the probability for z2 is 0.8413.
Therefore, the probability of the cash flow being between $16,000 and $19,000 is 0.8413 - 0.6554 = 0.1859, which is approximately 18.59%.
So, the correct answer is that the probability of a cash flow being between $16,000 and $19,000 is approximately 18.59%.
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The probability of a cash flow between $16,000 and $19,000 is approximately 18.59%.
To calculate the probability of a cash flow being between $16,000 and $19,000, we can use the standard deviation and assume a normal distribution.
We are given that the average cash flow is $14,000 with a standard deviation of $5,000. These values are necessary to calculate the probability.
The probability of a cash flow falling within a certain range can be determined by converting the values to z-scores, which represent the number of standard deviations away from the mean.
First, we calculate the z-score for $16,000 using the formula: z = (x - μ) / σ, where x is the cash flow value, μ is the mean, and σ is the standard deviation. Plugging in the values, we get z1 = (16,000 - 14,000) / 5,000.
z1 = 2,000 / 5,000 = 0.4.
Next, we calculate the z-score for $19,000: z2 = (19,000 - 14,000) / 5,000.
z2 = 5,000 / 5,000 = 1.
Now that we have the z-scores, we can use a standard normal distribution table or calculator to find the corresponding probabilities.
Subtracting the probability corresponding to the lower z-score from the probability corresponding to the higher z-score will give us the probability of the cash flow falling between $16,000 and $19,000.
Looking up the z-scores in a standard normal distribution table or using a calculator, we find the probability for z1 is 0.6554 and the probability for z2 is 0.8413.
Therefore, the probability of the cash flow being between $16,000 and $19,000 is 0.8413 - 0.6554 = 0.1859, which is approximately 18.59%.
So, the correct answer is that the probability of a cash flow being between $16,000 and $19,000 is approximately 18.59%.
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Tell whether the sequence is arithmetic if it is identify the common difference. -7, -3, 1, 5
Step-by-step explanation:
If you take any number in the sequence then subtract it by the previous one, and the result is always the same or constant then it is an arithmetic sequence.
d=-7+3=-3-1=1-5=-4
so it is an arithmetic sequence
hope it helps
graph each function. label the axis of symmetry and the vertex.
Answer:
easy
Step-by-step explanation:
answer is
hiiiiiiiii
will give brainliest
Answer:180 degrees
Step-by-step explanation:
A box in the shape of a rectangular prism is shown below. The box is completely filled with 432 identical cubes. The edge length of each cube is inch long. What is the volume of the box?
The volume of the box is 432 cubic inches
Calculating the volume of the box?From the question, we have the following parameters that can be used in our computation:
Completely filled with 432 identical cubes. Edge length of each cube is 1 inch long.The volume of the box is calculated as
Volume = Number of cubes * Volume of each cube
Where
Volume of each cube = 1 * 1 * 1
Volume of each cube = 1
Substitute the known values in the above equation, so, we have the following representation
Volume = 432 * 1
Evaluate
Volume = 432
Hence, the volume of the box is 432 cubic inches
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Solve for x
x =
A
C
E
4
D
3
x
B
4
A
After solving the value of x = 1/2.
From the figure:
AB = 4 ,BD = 3,DE = 4
AD = AB + BD
= 4+3
= 7
ADE is a right angle triangle.
AE^2 = AD^2+DE^2
= 7^2 + 4^2
= 49 + 16
= 65
AE = \(\sqrt{65}\)
AC = AE/2
= \(\sqrt{65}\)/2
ABC is a right angle triangle.
AC^2 = AB^2+BC^2
\((\sqrt{65}/2)^2\)= 4^2+x^2
65/4 = 16 + x^2
65/4 - 16 = x^2
65 - 16*4 / 4 = x^2
1/4 = x^2
x = \(\sqrt{1/4}\)
x = 1/2
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I need help with this question pls
Answer:
yes
Step-by-step explanation:
yes it is because if 6ounces is $2.10 and the more ounces you add the higher the cost
btw just copy/paste :P
*PLEASE ANSWER, I DON"T GET IT*
Which compound inequalitiy represents the inequality |y – 3| − 4 ≤ −3?
a.) −1 ≤ y – 3 OR y – 3 ≤ 1
b.) y – 3 ≤ −1 AND y – 3 ≥ 1
c.) −1 ≤ y – 3 AND y – 3 ≤ 1
d.) y – 3 ≤ −1 OR y – 3 ≥ 1
The compound inequality represents the given inequality is y-3≤1 OR -1≤y-3. Therefore, option A is the correct answer.
The given inequality is |y – 3| − 4 ≤ −3.
What is compound inequality?A compound inequality is a sentence with two inequality statements joined either by the word “or” or by the word “and.” “And” indicates that both statements of the compound sentence are true at the same time. It is the overlap or intersection of the solution sets for the individual statements. “Or” indicates that, as long as either statement is true, the entire compound sentence is true. It is the combination or union of the solution sets for the individual statements.
Now, solve inequality |y – 3| − 4 ≤ −3.
Add 4 on both sides of the inequality.
That is, |y – 3| − 4+4 ≤ −3+4
y-3≤1 OR -1≤y-3
The compound inequality represents the given inequality is y-3≤1 OR -1≤y-3. Therefore, option A is the correct answer.
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Solve the right triangle. Round decimal answers to the nearest tenth.
A right triangle X Y Z with base X Y is drawn. The length of side Y Z is 18 units and length of side X Z is 25 units. Angle X Y Z is a right angle.
The length of the hypotenuse is approximately 30.8 units.
The angle at vertex X is approximately 36.9 degrees.
The angle at vertex Y is approximately 35.2 degrees.
In your problem, we have a right triangle XYZ, where the angle at vertex Y is the right angle. The length of leg YZ is given as 18 units, and the length of leg XZ is given as 25 units.
In this particular problem, we can use the sine ratio to solve for the length of leg XY. Specifically, we have:
sin(XYZ) = XY / XZ
Since we know that XYZ is a right angle (i.e., 90 degrees), we can substitute in the appropriate values to get:
sin(90) = XY / 25
Since the sine of 90 degrees is 1, we can simplify this to:
1 = XY / 25
Multiplying both sides by 25 gives us:
XY = 25
So the length of leg XY is 25 units.
To find the other angles in the triangle, we can use the inverse trigonometric functions (such as arcsine or arccosine). For example, we can use the cosine ratio to solve for the angle at vertex X:
cos(XYZ) = XZ / hypotenuse
cos(90) = 25 / hypotenuse
0 = 25 / hypotenuse
Since the cosine of 90 degrees is 0, we know that hypotenuse = 25 / 0 is undefined. However, we can use the Pythagorean theorem to find the length of the hypotenuse:
hypotenuse² = XY² + XZ²
hypotenuse² = 25² + 18²
hypotenuse² = 625 + 324
hypotenuse² = 949
Taking the square root of both sides gives us:
hypotenuse = √(949) ≈ 30.8
Now that we know the lengths of all three sides of the triangle, we can use the sine and cosine ratios to solve for the other angles. For example, to find the angle at vertex X, we can use the cosine ratio:
cos(X) = XZ / hypotenuse
cos(X) = 25 / 30.8
cos(X) ≈ 0.811
Taking the inverse cosine (or arccosine) of both sides gives us:
X ≈ 36.9 degrees
Similarly, we can use the sine ratio to find the angle at vertex Y:
sin(Y) = YZ / hypotenuse
sin(Y) = 18 / 30.8
sin(Y) ≈ 0.584
Taking the inverse sine (or arcsine) of both sides gives us:
Y ≈ 35.2 degrees
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Ms. Weeks spent$48.10 for 10 bags of jolly ranchers. How much did each bag cost?
Answer: Mr. Weeks spent $4.81 per bag.
Step-by-step explanation: I knew the answer, because 48.10 divided by 10 is 4.81. You could've used an calculator to help.
Can someone please help me
Answer:
It might be 2/3
Step-by-step explanation:
Step-by-step explanation:
Let the number be x.
4-4x= 2x
4= 2x+4x
4= 6x
6x=4
x= 4/6
x= 2/3
Hope it helps :)
I would really appreciate if someone could help and explain as well not just give me the answer
Answer:
1330.5 cm³
Step-by-step explanation:
To find the volume you want to find the area of the circle and then times this by 14 which is the length of the shape
Area of circle = πr²
11 = the diameter so 5.5 = radius
5.5² x π = 121/4 π
times this by 14 to get 1330.464489 cm³
to 1dp = 1330.5 cm³
Answer:
1330cm³ (rounded to 3 s.f.)
Step-by-step explanation:
The formula of finding the volume of a cylinder is: \(\pi\) × r² × h
r is the radius of the cylinder, which is also half of the diameter.
You know the diameter is 11cm and the height (h) is 14cm.
Volume of cylinder = \(\pi\) × (11÷2)² × 14
= \(\pi\) × 5.5² × 14
= \(\pi\) × 30.25 × 14
= 423.5\(\pi\)
= 1330cm³ (rounded to 3 s.f.)
solve 15 2x = 36. round to the nearest ten-thousandth.
To solve the equation 15 + 2x = 36, we can start by subtracting 15 from both sides of the equation to get 2x = 21. Then, we can divide both sides by 2 to get x = 10.5. Rounded to the nearest ten-thousandth, the solution is x = 10.5000.
Someone help me please.
Answer:
No solution.
Step-by-step explanation:
Two same things can't equal different things.
Rank the following functions by order of growth. That is, find an arrangement f1, f2, ... of the functions satisfying f1 € O(f2), f2 € Olf3), and so on. logn n2 n (log n)logn log n log n
The ranked list, from slowest to fastest growth: log n € O((log n)log n) € O(n) € O(n^2) € O(n^log n) € O(2^n)
The basic idea behind this is to use Big O notation, which provides an upper bound on how quickly a function can grow. That is if we say that f(n) € O(g(n)), we mean that there exists some constant c such that f(n) is always less than or equal to c times g(n), for sufficiently large n.
In general, logarithmic functions (like log n and (log n)log n) grow more slowly than polynomial functions (like n and n^2), which in turn grow more slowly than exponential functions (like 2^n).
By comparing the rates of growth of these functions, we can get a sense of which algorithms or data structures are likely to be more efficient for large input sizes.
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Solve the differential equation y′′+2y′+y=e−tlnt by variation of parameters.
The general solution of the differential equation is the sum of the homogeneous and particular solutions:
\(y = y_h + y_p = c1 e^(-t) + c2 t e^(-t) + (t + 2 t ln t - 2 t + C) e^(-t)\)
where c1, c2, and C are constants to be determined by initial conditions.
We start by finding the general solution of the homogeneous differential equation y'' + 2y' + y = 0, which has the characteristic equation \(r^2 + 2r + 1 = 0.\)
Factoring the left-hand side, we get\((r + 1)^2 = 0\) , which has a repeated root r = -1.
Therefore, the general solution of the homogeneous equation is \(y_h = c1\) \(e^(-t) + c2 t e^(-t)\) , where c1 and c2 are constants to be determined by initial conditions.
To find a particular solution of the nonhomogeneous equation y'' + 2y' + \(y = e^(-t ln t)\), we assume a solution of the form \(y_p = u(t) e^(-t)\),
where u(t) is an unknown function to be determined.
We differentiate this expression to get\(y'_p = (u'(t) - u(t)) e^(-t) and y''_p = (u''(t) - 2u'(t) + u(t)) e^(-t).\)
Substituting these expressions into the differential equation, we get:
\((u''(t) - 2u'(t) + u(t)) e^(-t) + 2(u'(t) - u(t)) e^(-t) + u(t) e^(-t) = e^(-t ln t)\)
Simplifying, we get:
\(u''(t) = e^(t ln t)\)
Integrating once, we get:
\(u'(t)\) = ∫ \(e^(t ln t) dt\)
Using the substitution \(u = t ln t, du/dt = ln t + 1,\) and \(dt = du/(ln t + 1),\) we can write this integral as:
\(u'(t) =\) ∫ \(e^u / (ln t + 1) du\)
Using partial fractions, we can write:
\(e^u / (ln t + 1) = A + B ln t\)
where A and B are constants to be determined.
Multiplying both sides by ln t + 1 and setting ln t = -1, we get:
1 = A - B
Multiplying both sides by ln t and setting ln t = 0, we get:
\(e^u = A.\)
Therefore, \(A = e^u = 1\) and B = 2.
Substituting these values into the expression for u'(t), we get:
\(u'(t) = 1 + 2 ln t.\)
Integrating again, we get:
\(u(t) = t + 2 t ln t - 2 t + C\)
where C is a constant of integration.
Therefore, the particular solution of the differential equation is:
\(y_p = u(t) e^(-t) = (t + 2 t ln t - 2 t + C) e^(-t).\)
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can someone help with this problem 19r+1=20 need help
Answer:
r = 1
Step-by-step explanation:
We need to isolate r, so first subtract 1 from both sides to get 19r = 19. Divide both sides by 19 to get r = 1
solve the equation. (find all the solutions of the equation in the interval [0,2pi). Enter your answer as a comma separated list. sin(4x)
The solutions of the equation sin(4x) in the interval [0,2pi) are x = 0, pi/4, pi/2, 3pi/4, pi.
To solve the equation sin(4x) in the interval [0,2pi), we need to find all the values of x that satisfy the equation.
The equation sin(4x) = 0 has solutions when 4x is equal to 0, pi, or any multiple of pi.
Solving for x, we get:
4x = 0, pi, 2pi, 3pi, 4pi, ...
Dividing each solution by 4, we find the corresponding values of x:
x = 0, pi/4, pi/2, 3pi/4, pi, ...
So, the solutions of the equation sin(4x) in the interval [0,2pi) are x = 0, pi/4, pi/2, 3pi/4, pi.
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Simply the following :--
SOMEONE PLEASE HELP HONEST AWNSERS! !
Answer:
D.
\(\frac{2d^{2}-2d-38 }{(d+5)(d+3)}\)
Step-by-step explanation:
Remove any grouping symbol such as brackets and parentheses by multiplying factors.
Use the exponent rule to remove grouping if the terms are containing exponents.
Combine the like terms by addition or subtraction.
Combine the constants.
f(x)=x/3 -2 and g(x)=2x^2+x-3 find (f+g)(x)
Answer:
(f+g)(x) = 2x^2 + 4x/3 -5
Step-by-step explanation:
so, (f+g)(x) be y
y = f(x) + g(x)
y = x/3 -2 + 2x^2 + x - 3 = 2x^2 + 4x/3 -5
ore time on the Internet: A researcher polled a sample of 1012 adults in the year 2010 , asking them how many hours per week they spent on the Internet. The sample mean was 10.01 with a standard deviation of 13.90. A second sample of adults was taken in the year . For this sample, the mean was with a standard deviation of . Assume these are simple random samples from populations of adults. Can you conclude that the mean number of hours per week spent on the Internet differs between and
Sample 1: Mean=10.01, Standard deviation=13.90 Sample 2: Mean
=11.43, Standard deviation
=14.10
Sample size of 1st year = n1
= 1012Mean of 1st year sample
= X1 = 10.01Standard deviation of 1st year sample
= s1
= 13.90Sample size of 2nd year
= n2
= 1012Mean of 2nd year sample
= X2
= 11.43
Standard deviation of 2nd year sample = s2
= 14.10 Let us assume a significance level of α = 0.05, which implies that the critical region consists of 2.5% in both tails (since it is a two-tailed test).
Therefore, we do not have sufficient evidence to conclude that the mean number of hours per week spent on the Internet differs between 2010 and another year.
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The height y of a ball (in feet) is given by the function
y= -1/12^2+2+4
and x is the horizontal distance traveled by the ball. How high is the ball when it leaves the child’s hand?
Answer:
assuming that the problem was actually
-1/12 x ^ 2 + 2x + 4
height = 16
(12,16)
forty feet (40) feet
vertex = -b/2a = -2/(-1/6) = 12
f(12) = - 144/ 12 + 24 + 4 = -12+ 24 + 4 = 16
Step-by-step explanation:
Please answer all of these
Answer:
1. -4
2. 2
(ill continue adding more)
In the following code, add another array declaration thatcreates an array of 5 doubles called prices and another array of 5Strings called names and corresponding System.out.printlncommands.public class Test1{public static void main(String[] args){// Array exampleint[] highScores = new int[10];// Add an array of 5 doubles called prices.// Add an array of 5 Strings called names.System.out.println("Array highScores declared with size " +highScores.length);// Print out the length of the new arrays}
In the following code, you can add another array declaration that creates an array of 5 doubles called prices and another array of 5 Strings called names and corresponding System.out.println commands.
public class Test1 {
public static void main(String[] args) {
// Array example
int[] highScores = new int[10];
// Add an array of 5 doubles called prices.
double[] prices = new double[5];
// Add an array of 5 Strings called names.
String[] names = new String[5];
System.out.println("Array highScores declared with size " + highScores.length);
// Print out the length of the new arrays.
System.out.println("Array prices declared with size " + prices.length);
System.out.println("Array names declared with size " + names.length);
}
}
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