1. Which, if any, of these people are nearsighted (myopic)?
List the first letter of all correct answers in alphabetical order. For example, if Avishka and Edouard are the only nearsighted ones, enter AE.
2.Which, if any, of these people require bifocals to correct their vision?
3.Which, if any, of these people's vision can be corrected using only converging lenses?
Please show work and units.The near point (the smallest distance at which an object can be seen clearly) and the far point (the largest distance at which an object can be seen clearly) are measured for six different people.

A galaxy in the local group  is most likely to be the oldest.

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Answer:

all of the above

Explanation:

they are in every cell

Answer:

all but Nucelus

Explanation:

nucieus is not it

Answer:

winter

Explanation:

winter because the sun is not reaching the nothern hemisphere directly so the season inthe nothern hemisphere is winter.

and also it cannot be autumn because autumn is a season for leaves falling.

and also it cannot be spring because spring is the season for growth.

and also it cannot be summer because sumer is the season for the sun rays reaching directly on the earth.

HOPE THIS HELPS.

Answer: The equation for calculating friction is fr=FR/N

Explanation:

Fr (retentive force : friction) divided by N (normal/perpendicular force) equals fr (friction)

Plosive sounds are a common feature of many languages, and are often used to distinguish between different words.

When someone completely closes off the vocal tract then releases the air pressure suddenly, they have produced a sound energy known as a plosive or stop consonant.

Plosive sounds are produced by a sudden release of air pressure that has been built up behind a complete closure of the vocal tract. This closure can occur at different places in the vocal tract depending on the specific sound being produced, but common locations include the lips (for sounds like /p/, /b/, and /m/), the teeth and alveolar ridge behind the teeth (for sounds like /t/, /d/, /n/, /s/, and /z/), and the velum (for sounds like /k/, /g/, and /ng/).

When the air pressure behind the closure is suddenly released, it creates a burst of sound energy that is perceived as the plosive consonant. The specific sound produced depends on the location of the closure in the vocal tract and the amount of pressure built up behind it.

Plosive sounds are a common feature of many languages, and are often used to distinguish between different words. For example, in English, the words "pat", "bat", and "mat" are distinguished by the plosive consonants /p/, /b/, and /m/.

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To determine the launch speed of the cube, we can use the principle of conservation of mechanical energy. The potential energy stored in the spring when it is compressed is converted into kinetic energy when the cube is released. if the spring is pulled back 24 cm instead of 12 cm, the launch speed of the cube would be approximately 11.5 m/s (option b).

Given that the spring was pulled back 24 cm (or 0.24 m) instead of 12 cm, the potential energy stored in the spring is doubled. Let's assume the mass of the cube is m. Potential energy of the spring when compressed: PE = (1/2)kx^2. Where: k is the spring constant. x is the displacement of the spring. Since the potential energy is proportional to the square of the displacement, doubling the displacement will result in four times the potential energy. So, the potential energy of the spring when pulled back 24 cm is four times the potential energy when pulled back 12 cm. The kinetic energy of the cube when launched is given by: KE = (1/2)mv^2. According to the conservation of mechanical energy, the potential energy when the spring is compressed is equal to the kinetic energy when the cube is released: (1/2)k(0.24^2) = (1/2)mv^2. Since the mass of the cube cancels out, we can write: k(0.24^2) = v^2. Now, if we double the potential energy by doubling the displacement, the launch speed of the cube will increase by the square root of 2. v = √(2 * launch speed when pulled back 12 cm). Let's calculate the launch speed when pulled back 12 cm: v = √(2 * (0.8^2 * 39.2)) ≈ 8.4 m/s. Therefore, if the spring is pulled back 24 cm instead of 12 cm, the launch speed of the cube would be approximately 11.5 m/s (option b).

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Answer:

A liquid is a nearly incompressible fluid that conforms to the shape of its container but retains a (nearly) constant volume independent of pressure. A liquid is made up of tiny vibrating particles of matter, such as atoms, held together by intermolecular bonds.

Answer:

2 or more atoms

Explanation:

yes yes yes yes yes yes yes yes

Answer:

Two or more

Explanation:

It's mostly two but unique structures might compose of more than 2

To solve this problem, you can use the equations of motion for rotational motion under constant acceleration:

ωf = ωi + αt --(1)

θ = ωit + 0.5αt^2 --(2)

where ωi is the initial angular velocity, ωf is the final angular velocity, α is the angular acceleration, t is the time elapsed, and θ is the angular displacement.

Using equation (1), we can find the angular acceleration of the wheel:

α = (ωf - ωi)/t

= (30.0 rad/s - 10.0 rad/s)/20.0 s

= 1.0 rad/s^2

Using equation (2), we can find the total angular displacement of the wheel during the 20.0 seconds:

θ = ωit + 0.5αt^2

= 10.0 rad/s × 20.0 s + 0.5 × 1.0 rad/s^2 × (20.0 s)^2

= 400.0 rad

To find the time at which the wheel has undergone half of this angular displacement, we can use equation (2) again:

θ/2 = ωit + 0.5αt^2

Rearranging and solving for t, we get:

t = [(-ωi) ± sqrt(ωi^2 + 2αθ)]/α

Since we are looking for a positive time, we take the positive root:

t = [(-10.0 rad/s) ± sqrt((10.0 rad/s)^2 + 2 × 1.0 rad/s^2 × 400.0 rad)]/1.0 rad/s^2

≈ 12.4 s

Therefore, the answer is B, 12.4 s.

The maximum speed of her brother as he swings is 5.04777 m/s.

Calculation:

conservation of energy

ΔPE = ΔKE

= mg (h₁-h₂) = 1/2= mv²

= v = √2g (h₁-h₂)

= V = √2x9·8 (0.34 - 1.08)

Vmax =  5.04777 m/s

Forces are influences that can change the movement of an object. A force can cause a mass to accelerate, thus changing its velocity. Forces can also be described intuitively by pushing or pulling. The word "force" has a precise meaning.

At this level, it is appropriate to describe the force as pushing or pulling. A force does not contain or have within an object. A force is applied from one object to another. The idea of ​​force is not limited to animate or inanimate objects.

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The maximum speed of her brother as he swings (her brother sits passively in the swing.) is 1.14 m/s

The gravitational potential energy of the brother increases as he is lifted to a higher height. This increase in gravitational potential energy is converted to kinetic energy (the energy of motion) as the brother swings back down and gains speed. The maximum speed will be reached when all of the gravitational potential energy has been converted to kinetic energy.

The change in gravitational potential energy can be calculated using the formula:

ΔE = mgh

where m is the mass of the brother, g is the acceleration due to gravity (9.8 m/s^2), and h is the change in height.

Plugging in the values, we get:

ΔE = mgh = (50 kg)(9.8 m/s^2)(1.08 m - 0.34 m) = 330.8 kg*m^2/s^2

The maximum kinetic energy of the brother can be calculated using the formula:

E = 1/2 * m * v^2

where m is the mass of the brother, and v is the velocity (speed).

To find the maximum speed, we set the kinetic energy equal to the change in gravitational potential energy and solve for v:

E = 330.8 kgm^2/s^2 = 1/2 * (50 kg) * v^2

v = √(2E/m)

= √(2(330.8 kgm^2/s^2)/(50 kg))

= √(66.16/50)

= √(1.3232)

= 1.14 m/s

Thus, the maximum speed of the brother as he swings is approximately 1.14 m/s.

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The intensity of light incident on the screen is 0.089 W/m^2.

The intensity of light incident on the screen can be calculated using the inverse square law, which states that the intensity of radiation decreases with the square of the distance from the source.

First, we need to calculate the total power radiated by the light bulb in all directions. As the bulb emits radiation uniformly in all directions, the total power is given by the wattage of the bulb, which is 40 W.

Next, we need to calculate the surface area of a sphere with a radius of 2.1 m (the distance from the bulb to the screen), which is given by 4πr^2 = 55.42 m^2.

The intensity of light incident on the screen is then given by the total power divided by the surface area of the sphere at that distance, which is 40 W / 55.42 m^2 = 0.72 W/m^2.

However, this is the intensity at a single point on the screen directly facing the bulb. As the bulb emits radiation uniformly in all directions, we need to calculate the total area of the screen that receives the radiation.

Assuming the screen is a flat surface perpendicular to the line connecting the bulb and the screen, the area of the screen is given by its width times its height.

If we assume a standard size for a screen of 1.5 m by 2 m, then the total area of the screen is 3 m^2. Dividing the total power by the total area of the screen gives us the intensity of light incident on the screen, which is 40 W / 3 m^2 = 13.33 W/m^2.

However, we need to convert this value to the intensity at a single point on the screen directly facing the bulb. To do this, we assume that the intensity of light is evenly distributed over the surface of the screen, which gives us an average intensity of 13.33 W/m^2 / 3 = 4.44 W/m^2 at any point on the screen.

Finally, we need to take into account the angle between the bulb and the screen. As the bulb emits radiation uniformly in all directions, only a fraction of the total power emitted by the bulb will actually reach the screen.

Assuming the bulb emits light uniformly in all directions, the fraction of the total power that reaches the screen is given by the solid angle subtended by the screen as seen from the bulb, which is given by the surface area of the screen divided by the distance from the bulb squared, times π.

Using the same values as before, we get a solid angle of π(1.5 m × 2 m) / (2.1 m)^2 = 0.089 sr. Multiplying the average intensity by the solid angle gives us the intensity of light incident on the screen, which is 4.44 W/m^2 × 0.089 sr = 0.089 W/m^2. Therefore, the intensity of light incident on the screen is 0.089 W/m^2.

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The average force exerted on the train is approximately 4,275,000 N.

The force is calculated by using the formula force = mass x acceleration. In this case, the mass of the train is known (4500 kg) and the acceleration can be calculated by using the final velocity (50 m/s) and distance traveled (80 meters).

To calculate the average force exerted on the train, we need to use the equation:

force = mass x acceleration

The acceleration of the train can be calculated by using the final velocity and distance traveled, which are 50 m/s and 80 meters respectively.

acceleration = (final velocity - initial velocity) / time

time = distance / final velocity

So, we can substitute the values in the equation and calculate the average force exerted on the train.

force = 4500 kg x (50 m/s - 0 m/s) / (80 m / 50 m/s)

It is important to note that the above calculations are based on assumptions that the train had no initial velocity and that there was no other forces acting on the train, and that the given distance is the distance of the ride.

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The security guard make the trip of 120 m of distance in a time of 250 s with a speed of: 0.48 m/s

The formula and procedure we will use to solve this exercise is:

v = x /t

Where:

Information about the problem:

Applying the velocity formula we have that:

v = x /t

v = 120 m /250 s

v = 0.48 m/s

It is a physical quantity that indicates the displacement of a mobile per unit of time, it is expressed in units of distance per time, for example (miles/h, km/h).

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Answer:

The mechanical advantage of a machine is 2. Mechanical advantage MA is the ratio of output (generated by the machine) force to input (applied to the machine) force. So MA = 2 means that for example if you apply 100 N then your machine will multiply that force and generate 200 N .

because mechanical advantage decreases due to the friction and weight of moving parts of the machine whereas the velocity ratio remains constant

hope it helps you

(a) Lenz's law is a fundamental law of electromagnetism that states that the direction of an induced current in a conductor is always such that it opposes the change that produced it. This means that if a magnetic field changes in strength or direction, or if a conductor moves in a magnetic field, an induced current will be generated in the conductor that opposes the change in the magnetic field or the motion of the conductor.

(b) When the bar moves to the left in a magnetic field, the magnetic flux through the bar changes. According to Lenz's law, this change in magnetic flux will induce an electric current in the bar that opposes the motion of the bar.

To determine the direction of the induced current, we can use the right-hand rule for electromagnetic induction. We place the right hand around the bar with the fingers pointing in the direction of the magnetic field, and the thumb pointing in the direction of the bar's motion. The direction in which the fingers curl gives the direction of the induced current.

In this case, when the bar moves to the left, the magnetic field lines are cutting the bar from right to left. Therefore, the induced current must flow in a direction that creates a magnetic field that opposes this change. According to the right-hand rule, the induced current will flow in a clockwise direction when viewed from the left end of the bar. This means that the induced current will produce a magnetic field that points to the right, and that opposes the motion of the bar to the left.

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Answer:

If it is a true mixture, the mixing enthalpy is negligible, and there is no reaction or phase change, then you can do this using exclusively the temperatures of the individual compounds and their heat capacities. Any other process that takes place needs to be taken into account separately.

The solution can be found by understanding that we’re only using state variables. You can design any complicated process that starts with the starting situation and ends up at the ending situation, and the state variables will be the same. And sometimes a complicated process is easier to calculate than the simple one-step process, like here when mixing multiple components.

One way that will work is to start by bringing all compounds to the lowest temperature of either of the compounds. All but one of the compounds must be cooled down for this; make sure to calculate for each of the components how much energy is released. Now, mix all the components together. In the simplest situation sketched above you can calculate the heat capacity of the mixture by adding all the heat capacities of the components. Use this total heat capacity to calculate how much you can heat up the mixture using the energy you saved in cooling down the components earlier. This will be your desired end situation.

In case there are any phase changes or other processes in between, you need to take the energy needed for those into account too but in very similar ways.

Answer:

1.2 A

Explanation:

From the diagram attached, The three resistors are parallel because the each ends of the resistors are connected together. Since they are in parallel, the voltage across each resistor is the same. The voltage source connected in parallel to the resistors is 60 V. Therefore the voltage across the 50 Ω resistor is 60 V. Using ohm law:

Voltage (V) = Current (I) × Resistance (R)

V = IR

I = V/R

I = 60 V/ 50 Ω

I = 1.2 A

The current in the 50 Ω resistor is 1.2 A

The time period is 0.3 s and frequency is 3 Hz

Step 1 :

Given:

No. of cycles N = 24

Total time take t = 8 s

Step 1 : Calculating the frequency:

The frequency of a wave or oscillation is defined as the number of cycles or completed alternations per unit time.

f = N/t

f = 24/8

f = 3 Hz

Step 2: Calculating the time period:

Frequency and time period are inversely proportional.

The amount of time it takes for something to complete one oscillation is called its time period.

Time period = 1/Frequency

Time period = 1/3 = 0.3 s

So, the time period is 0.3 s and frequency is 3 Hz.

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The initial potential energy of the swing is 0 J. The final potential energy of the swing is 345.35J. The change in potential energy of the swing is 345.35J. And the work done is 345.35J.

The initial potential energy of the swing is given by:

PE_i = mgh_i

PE_i = 35 kg * 9.81 m/s^2 * 0 m

PE_i = 0 J

where m is the mass of the tire, g is the acceleration due to gravity, and h_i is the initial height of the tire.

The final potential energy of the swing is given by:

PE_f = mgh_f

PE_f = 35 kg * 9.81 m/s^2 * 1.0 m

PE_f = 343.35 J

where h_f is the final height of the tire.

The change in potential energy is:

ΔPE = PE_f - PE_i

ΔPE = 343.35 J - 0 J

ΔPE = 343.35 J

Therefore, the work done on the tire is:

W = ΔPE

W = 343.35 J

So it would take 343.35 J of work to move the tire a vertical distance of 1.0 m at a constant speed of 1 m/s.

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The gravitational potential energy of the person standing on the roof of the 10-story building varies depending on the height above a reference point.

The formula to calculate gravitational potential energy is:

GPE = mgh

where m is the mass of the object, g is the acceleration due to gravity (9.81 m/s^2), and h is the height above a reference point.

(a) The gravitational potential energy of the 61.2 kg person standing on the roof of the 10-story building relative to the tenth floor would be:

GPE = (61.2 kg) x (9.81 m/s^2) x (7 x 2.50 m)

GPE = 10736.94 J

(b) The gravitational potential energy of the person relative to the sixth floor would be:

GPE = (61.2 kg) x (9.81 m/s^2) x (4 x 2.50 m)

GPE = 5328.36 J

(c) The gravitational potential energy of the person relative to the first floor would be:

GPE = (61.2 kg) x (9.81 m/s^2) x (9 x 2.50 m)

GPE = 14726.86 J

Therefore, the gravitational potential energy of the person standing on the roof of the 10-story building varies depending on the height above a reference point.

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The most recent view of the atom is the quantum mechanical model of the atom.

We know that the atom is smallest part of the substances that can take part ion a chemical reaction.

An atomic model is a theoretical construct that explains the properties and behavior of atoms, the basic building blocks of matter. The most widely accepted atomic model is the quantum mechanical model, which describes atoms as consisting of a nucleus of protons and neutrons, surrounded by a cloud of electrons.

The electrons occupy energy levels or orbitals, and their behavior is described by the principles of quantum mechanics. The earliest atomic model was proposed by John Dalton in the early 19th century, which was a classical mechanical model.

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Energy is an important concept that affects us in many ways. It is the ability to do work, and it can come in many forms. When it comes to a water balloon, it has several types of energy that explain its behaviour.

Types of Energy: The water balloon has potential energy, which is stored energy due to its position or shape. This potential energy is converted to kinetic energy when the balloon is thrown. Kinetic energy is the energy of motion, so as the balloon moves, it has kinetic energy.

The balloon also has thermal energy, which is energy that comes from the temperature of the water in the balloon. As the water inside the balloon heats up, the thermal energy increases and the balloon becomes more elastic.

Behaviour: The water balloon's behaviour can be explained by the energy it contains. The potential energy it has will cause it to move when it is released, resulting in its kinetic energy. The thermal energy can cause the balloon to expand and become more elastic, making it more likely to burst when hit by an object. The combination of these energies explains why the balloon behaves the way it does.

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Answer:

1. Farther

2. Longer

3. Longer

Explanation:

Answer:

well they make the siren go beacaus eyou are doing somthing wrong so what were you thinking

Explanation:

see this and you

try to understand

Kepler's third law of planetary motion helps you compare the velocities of different planets.

The orbits of planets around the Sun are described by Kepler's laws of planetary motion, which he published between 1609 and 1619.

The laws replaced the circular orbits and epicycles of Nicolaus Copernicus' heliocentric theory with elliptical trajectories and provided an explanation for the variation in planetary velocities. As per the three laws:

Hence, Kepler's third law of planetary motion helps you compare the velocities of different planets.

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