1- When designing a storm sewer, you should ensure the flow velocity will be less than 10-15 ft/s to prevent scouring. Scouring can cause erosion of the sewer pipe material and can eventually lead to pipe failure.
2- In order to prevent clogging and to facilitate maintenance, the minimum pipe diameter you should use for a storm sewer is typically 12 inches. This size allows for adequate flow and easier access for maintenance purposes.
The storm sewer is a system created to transport drainage and runoff from rainfall. Sewage or hazardous waste cannot be placed in it because of its architecture. Runoff is transported by subterranean pipelines or open ditches and dumped directly into nearby streams, rivers, and other bodies of surface water.
A preparation process for some textile fabrics is scouring. Oils, waxes, fats, vegetable matter, dirt, and other soluble and insoluble impurities present in textiles as well as natural, added, and accidental impurities are all removed by scouring.
Therefore the answers are scouring and 12 inches.
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In each of the scenarios, two spheres of the same size and shape hang from a common attachment point. Each sphere is electrically charged and is either perfectly conductive or perfectly insulating (gray is conductive, orange is insulating). The magnitude of charge Q is greater than the magnitude of charge q.
Each pair of spheres is allowed to swing freely and comes to rest in some equilibrium position. In each scenario, determine whether the spheres come to rest in contact, or separated by some distance. Assume that the weight of the spheres is small enough that electrostatic forces are significant.
Spheres come to rest in contact:
- both gray, charges -q and +q
- both orange, charges -q and +q
- both orange, charges +Q and -q
- gray, charge -Q, orange, chargef +q
Spheres come to rest separated
- both gray, +Q and +q
- both gray, -Q and +q
- both orange, -q and -Q
Spheres come to rest in contact:
- both gray, charges -q and +q
- both orange, charges -q and +q
- both orange, charges +Q and -q
- gray, charge -Q, orange, chargef +q
Spheres come to rest separated
- both gray, +Q and +q
- both gray, -Q and +q
- both orange, -q and -Q
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The weight of the spheres is small enough that electrostatic forces are significant. Spheres come to rest in contact:
- both gray, charges -q and +q
- both orange, charges -q and +q
- both orange, charges +Q and -q
- gray, charge -Q, orange, charge f +q
Spheres come to rest separated
- both gray, +Q and +q
- both gray, -Q and +q
- both orange, -q and -Q
Where can electrostatic force be found?The distance between two charges creates an electrostatic force. The distance between two charges and their respective magnitudes determine the magnitude of the electrostatic force. When two charges, either positive or negative, are brought together, they repel one another.
What is electrostatics?The phenomena and properties of electric charges that are either stationary or moving slowly are the focus of the physics branch known as electrostatics. Coulomb's law describes electrostatic phenomena, which are caused by the forces that electric charges exert on one another.
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Multiple intake and exhaust valves per cylinder,
A) Assist scavenging only
B) Assist air/fuel intake only
C) Increase volumetric efficiency
D) Increase thermal efficiency
Multiple intake and exhaust valves per cylinder, C) Increase volumetric efficiency
What is the function of the intake and exhaust valve?Exhaust valves open to allow the release of exhaust gases from the combustion process after ignition has taken place, whereas intake valves open to allow the entry of an air/fuel mixture into the engine's cylinders prior to compression and ignition.
Each cylinder has several intake and exhaust valves, which improves volumetric efficiency.
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an adiabatic compressor receives 1.5 meter cube per second of air at 30 degrees celsius and 101 kpa. The discharge pressure is 505 kpa and the power supplied is 325 kW, what is the discharge temperature
Answer:
The discharge temperature is 259.82 K
Explanation:
In this question, we are concerned with calculating the discharge temperature
Please check attachment for complete solution
An amplifier's input voltage is 12 mV, and its output voltage is 128 mV. Calculate voltage gain.
Answer:
Amplifier gain is equal to 10.67.
Explanation:
Voltage gain of an amplifier can be expressed as this equation:
A_v = (V_output) / (V_input)
Where A_v is the gain, V_output is the output voltage, and V_input is the input voltage.
For this we will solve:
A_v = 128 mV / 12 mV
A_v = 10.67
So the amplifier's gain is 10.67.
Cheers.
Cell phones require powerful batteries in orde to work effectively. Which activity is best described as an engineering endeavor related to cell phone batteries
An estimate of the amount of work accomplished is the:
variation
relative intensity
volume load
specificity
The estimate of the amount of work accomplished is called volume load.
Volume load refers to the total amount of weight lifted in a workout session. It takes into account the number of sets, the number of repetitions, and the weight used. Volume load can be used as a measure of the amount of work accomplished. Volume load is also used to monitor progress over time.
In conclusion, the estimate of the amount of work accomplished is called volume load. Volume load is a measure of the amount of work done in a workout session. It can be used to monitor progress over time.
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What are these tools called need help with it?
Answer:
those look like clamps
Explanation:
For polymer-polymer blend system (binary mixture), what type of phase separation do you expect to see? Use the keyword below to describe. Keyword: USCT, LCST, Spinodal, Binodal, Droplet, Bicontinuous, Macrophase-sepration
For a polymer-polymer blend system (binary mixture), the type of phase separation that can be expected depends on the interactions between the polymers and their miscibility. The following keywords can be used to describe different types of phase separation:
1. USCT (Upper Critical Solution Temperature): In this case, the blend exhibits phase separation upon heating above a specific temperature. Below the critical temperature, the polymers are miscible, but phase separation occurs as the temperature exceeds the USCT.
2. LCST (Lower Critical Solution Temperature): This refers to phase separation occurring upon cooling below a specific temperature. The blend is miscible above the critical temperature, but phase separation occurs as the temperature decreases below the LCST.
3. Spinodal: A spinodal phase separation occurs when the blend is thermodynamically unstable, leading to the spontaneous formation of separate phases without the presence of a distinct critical temperature. This type of phase separation results in the formation of a bicontinuous morphology.
4. Binodal: Binodal phase separation refers to the situation where phase separation occurs at a specific composition and temperature. Above or below this composition and temperature, the blend remains miscible.
5. Droplet: In a droplet phase separation, one polymer forms dispersed droplets within the continuous phase of the other polymer. This occurs when the two polymers have limited miscibility.
6. Bicontinuous: Bicontinuous phase separation results in the formation of interpenetrating and continuous networks of the two polymers. The blend exhibits interconnected phases without a clear distinction between the two.
7. Macrophase separation: Macrophase separation is characterized by the formation of large-scale phase separation, resulting in distinct and separate regions of each polymer. This type of phase separation is more pronounced and easily visible.
The specific type of phase separation observed in a polymer-polymer blend will depend on factors such as the polymer chemistry, molecular weight, interactions, and thermodynamic properties of the polymers involved.
For a polymer-polymer blend system (binary mixture), the type of phase separation that is expected to be observed depends on the specific polymers and their interaction parameters. Here are the descriptions of the keywords you provided:
USCT (Upper Critical Solution Temperature): In a USCT phase separation, the polymer blend remains miscible above a certain temperature but undergoes phase separation as the temperature is lowered below the critical temperature. This results in the formation of two distinct phases.
LCST (Lower Critical Solution Temperature): In an LCST phase separation, the polymer blend remains miscible below a certain temperature but undergoes phase separation as the temperature is increased above the critical temperature. This leads to the formation of two distinct phases.
Spinodal: In a spinodal phase separation, the polymer blend spontaneously undergoes phase separation without the presence of a distinct phase boundary. This results in the formation of a continuous network structure or a bicontinuous morphology.
Binodal: In a binodal phase separation, the polymer blend undergoes phase separation with the formation of distinct droplet-like regions dispersed in a continuous phase. The phase separation occurs along a specific composition range.
Droplet: In a droplet phase separation, the polymer blend forms distinct droplets or domains of one polymer dispersed in a continuous phase of the other polymer. This can occur when the blend has a limited miscibility or the interaction between the polymers is unfavorable.
Bicontinuous: In a bicontinuous phase separation, the polymer blend forms a network-like structure with two continuous phases interpenetrating each other. This can occur when the blend has a high degree of miscibility or when the polymers have a specific compatibility.
Macrophase separation: In a macrophase separation, the polymer blend undergoes phase separation on a larger scale, resulting in the formation of macroscopic regions or domains of each polymer. This can occur when the blend has a limited miscibility or when there are significant differences in the properties of the polymers.
The specific type of phase separation observed in a polymer-polymer blend system depends on factors such as polymer composition, molecular weight, interaction parameters, and processing conditions. Experimental characterization techniques, such as microscopy, scattering methods, and thermal analysis, are often used to determine the nature of phase separation in polymer blends.
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the coprocessor 0 in a mips processor has a set of registers used to store necessary information when an exception occurs: $8 badvaddr $12 status $13 cause $14 epc. when a mips processor executes the following instructions: address instruction 0x00401000 li $t0, 0x7fffff0c 0x00401004 sw $s0, 7($t0) 0x00401008 ... the contents of these registers are: $8: 0x[a] $13 : 0x[b] note: assuming all interrupt pending (ip) bits are 0, i.e. no interrupt pending. $14: 0x[c].
BadVaddr ($8) stores the memory address at which the exception occurs.
Hence, the exception occurs in store word instruction.
What is memory address?A memory address in computing is a designation of a particular memory location that is used by hardware and software at different levels. Memory addresses are fixed-length digit sequences that are typically represented as unsigned integers and used in operations.
Such a numerical semantic is based on CPU characteristics (such as the instruction pointer and incremental address registers) as well as on the use of memory as an array that is supported by different programming languages.
Numerous memory locations make up the main memory of a digital computer. Physical addresses—which are codes—are assigned to each memory location. To access the appropriate memory location, the CPU (or other device) can use the code.
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why was the Internet originally designed?
For each of the following systems, determine whether or not the system is (1) linear, (2) time-invariant, and (3) causal:
a. y[n]=x[n]cos(0.2πn) b. y[n]=x[n]−x[n−1] c. y[n]=∣x[n]∣ d. y[n]=Ax[n]+B, where A and B are nonzero constants.
According to the information the systems are: 1. Linear: No, Time-invariant: Yes, Causal: Yes, 2. Linear: Yes, Time-invariant: Yes, Causal: Yes, 3. Linear: No, Time-invariant: Yes, Causal: Yes, 4. Linear: Yes, Time-invariant: Yes, Causal: Yes
How to identify if the system is linear, time-invariant and causal?The system y[n] = x[n]cos(0.2πn) is not linear because of the presence of the non-linear function cos(0.2πn). However, it is time-invariant and causal.The system y[n] = x[n] - x[n-1] is linear because it satisfies the linearity property (it involves addition and scaling of the input). It is also time-invariant and causal.The system y[n] = |x[n]| is not linear because of the absolute value operation, which introduces non-linearity. However, it is time-invariant and causal.The system y[n] = Ax[n] + B, where A and B are nonzero constants, is linear because it satisfies the linearity property (it involves addition and scaling of the input). It is also time-invariant and causal.Learn more about systems in: https://brainly.com/question/19843453
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The maverick hybrid powertrain features a 2. 5l atkinson-cycle i-4 powertrain. With the gas engine and electric motor working together, what is the horsepower output of this hybrid powertrain?.
The maverick hybrid powertrain is an innovative system that combines a 2.5L Atkinson-cycle I-4 gasoline engine with an electric motor. When these two power sources work together, they can produce a considerable amount of power.
The gasoline engine in the maverick hybrid powertrain is designed using the Atkinson cycle, which is a thermodynamic cycle that improves fuel efficiency by reducing energy losses during combustion. This engine alone can produce up to 162 horsepower and 155 lb-ft of torque.
However, when the electric motor is added to the equation, the total power output of the hybrid powertrain increases significantly. The electric motor can provide up to 94 horsepower and 173 lb-ft of torque, which is a significant boost to the overall power output of the system.
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construction expertise (e.g., by the construction firm) is typically included latest in the planning process in which arrangement?
The most common applications for micro piles are structural foundation support, underpinning, wall support, and slope stabilization.
The master format is a common outline for organizing information about building materials and components. Its primary divisions include topics such as sitework, concrete, masonry, metals, wood, and plastics, among others.) Seismic retrofitting or strengthening is done to improve the structural capacities (strength, stiffness, ductility, stability, and integrity) of the structure so that the building's performance level can be raised to withstand the design earthquake consideration.
The mass concrete underpinning method is the traditional underpinning method that has been used for centuries. The method entails extending the old foundation to a stable stratum. The soil beneath the existing foundation is excavated in stages orpins in a controlled manner.
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from the adversary types given in the shape of a triangle in the powerpoint slides of the module, you can guess that the administrators and subject matter experts are
By organizing your PowerPoint slides into sections, you can sort them more quickly. Click the triangle next to the section names to collapse a segment.
How do I make an Equilateral Triangle in PowerPoint 2010 that is perfect?
Three of the sides of an equilateral triangle coincide. True equilateral triangles are easy to make with PowerPoint. Just remember to hold down the SHIFT key when you draw your right triangle. The triangle's sides will all remain the same as a result of this. Pick the Right Triangle under Insert -> Shapes. The SHIFT key will maintain the ratio of each side when you draw a triangle on the slide.
What additional triangles can we make in PowerPoint?
This question has a straightforward solution. The shape points are editable, and the characteristics that the intended triangle requires.
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In the figure below, block A weighs 20 lb , while block B weighs 10 lb . Friction between the surfaces of the two blocks may be assumed negligible, but there is friction between block A and its underlying surface, and between block B and its adjacent confining surface, both with a kinetic friction coefficient of 0.25. The angle that the inclined face of block A makes with the horizontal is θ= 75 ∘ . A vertical downward force, P= 8 lb is applied to block B .
What is the acceleration of block B?
What is the acceleration of block A?
Answer:
As P is continually increased, the block will now slip, with the friction force acting on the block being: f = muK*N, where muK is the coefficient of kinetic friction, with f remaining constant thereafter as P is increased.
The transition between the corrosion protection for the bond and free stressing lengths shall be designed to ensure
The transition between the corrosion protection for the bond and free stressing lengths is a crucial aspect of structural design, as it ensures the long-term durability and integrity of the structure. This transition involves carefully designing and implementing measures to protect the bond and free stressing lengths from corrosion, which can weaken the structural elements and ultimately compromise the safety and stability of the entire structure.
In order to ensure a seamless transition between these two protection measures, several factors must be considered during the design process. First, the materials used in the bond and free stressing lengths should be compatible, as they will be exposed to similar environmental conditions and potential sources of corrosion. The use of high-quality materials with proven corrosion resistance is essential to minimize the risk of corrosion-related issues.
Next, proper detailing and reinforcement placement should be incorporated into the design to maintain adequate cover and ensure the bond and free stressing lengths are well-protected from potential corrosion. This may involve using a combination of passive and active corrosion protection systems, such as the application of protective coatings, the use of galvanic anodes, or the implementation of cathodic protection.
Additionally, the construction process should be carefully planned and executed to maintain the integrity of the corrosion protection measures during installation. This includes the proper handling and storage of materials, strict adherence to construction standards, and thorough quality control measures to verify the effectiveness of the implemented protection systems.
By taking these factors into account and designing the transition between the corrosion protection for the bond and free stressing lengths with careful consideration, engineers can help ensure the long-term durability and performance of the structure.
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What cycle time would match capacity and demand if demand is 300 units a day, there are three shifts of 420 minutes each, and workers are given four half – hour breaks during each shift.
In a production line, the cycle time refers to the time needed to complete one process or a unit of the item being manufactured. For instance, if an assembly line manufactures 300 units per day, and they operate 3 shifts a day, then they must make sure that their cycle time aligns with the demand.
What cycle time would match capacity and demand if demand is 300 units a day, there are three shifts of 420 minutes each, and workers are given four half – hour breaks during each shift.To figure out the cycle time, the first step is to determine the total number of production minutes available in a day, which is:420 minutes per shift x 3 shifts = 1260 minutes per day There are 4 half-hour breaks, so in total, there is a 2-hour break, which is equivalent to 120 minutes:420 x 3 - 120 = 1240 minutes available for production. If the demand is 300 units, the production line must produce one unit every:1240/300 = 4.133 minutes or 4 minutes and 8 seconds In conclusion, the cycle time that would match capacity and demand if the demand is 300 units a day, there are three shifts of 420 minutes each, and workers are given four half – hour breaks during each shift is 4 minutes and 8 seconds.For more such question on equivalent
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Q4. Consider the skier on a slope shown in the figure below. Her mass including equipment is 60.0 kg.
(a) What is her acceleration if friction is negligible?
(b) What is her acceleration if friction is known to be 45.0 N?
Note that the Skier's acceleration if friction is near zero is 4.14m/s, while her acceleration if friction is 45.0N is 3.39m/s.
What is acceleration?In mechanics, acceleration is defined as the rate of change of an object's velocity with respect to time. Vector quantities are accelerations. The orientation of an object's acceleration is determined by the orientation of its net force.
The change in velocity (v) over the change in time (t) is expressed by the equation a = v/t. This enables you to calculate how quickly velocity varies in meters per second squared (m/s²).
To arrive at the above values, note that we are given:
Mass = 60Kg
Friction = 45N
The formula for acceleration used here is:
a = g x sinθ. where
a = acceleration
g = gravity constant and
Sinθ is the angle of incline.
This is because acceleration is directly proportional to the sine of the incline angle (θ), When sinθ is 1, the angle of the incline is 90°. Incline here accounts for the incline of the skier's body as she descends.
Hence:
a = 9.8 x sin25°
a = 9.8 x 0.422
a = 4.14m/s where friction is negligible.
B)
Where friction is 45.0N, we must use the following formula to account for same:
a = g x sinθ - (f/m);
Where f is friction (45.0N) and
m is mass (60kg)
substituting the values we have:
a = 9.8 x sin 25° - (45/60)
a = 9.8 x 0.422 - 0.75
a = 4.14 - 0.75
a = 3.39 (m/s)
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In a countersinking operation, once the tool reaches the proper depth, what should the operator do to ensure hole concentricity and a good surface finish?
1. Back the tool in and out of the bottom of the hole several times.
2. Increase the spindle speed one and a half times the normal rate.
3. Turn off the spindle to let the hole walls cool before continuing.
4. Let the tool run a few seconds before backing out of the hole.
There are different aspect of drilling operations. What the operator have to do to ensure hole concentricity and a good surface finish is to Increase the spindle speed one and a half times the normal rate.
Countersinking is often used to produce a conical hole linking the angled shape on the bottom side of a flat-head screw.
Research has shown that surface roughness is often affected by the spindle speed and feed rate. Note that surface roughness often increases with increased in feed rate and is known also to be higher at lower speeds and vice versa..There is a required spindle speed used for countersinking operation . The lead out rule is of 1/3 the speed of a drill of the same size often work for almost all countersinking and counterboring operations.
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one method of bending segment is to use select one: a. an elapsed time method to keep track of each bend b. a stress meter to monitor each bend c. a level to monitor each bend d. the amount of travel method to monitor each bend
The method of bending segment that can be used to monitor each bend is a. an elapsed time method.
Using an elapsed time method to monitor each bend is an effective approach in bending segments. This method involves measuring the time it takes to complete each bend. By tracking the elapsed time, it becomes easier to ensure consistency and accuracy in the bending process.
When utilizing an elapsed time method, the operator starts a timer at the beginning of each bend and stops it once the bend is completed. This allows for precise measurement of the time taken for each bend. By establishing a benchmark time for a specific bend, operators can monitor subsequent bends and compare their times to the benchmark.
Any significant deviation from the benchmark can indicate a potential issue in the bending process, allowing for adjustments or corrections to be made promptly.
The elapsed time method is particularly useful when multiple bends need to be made consistently, such as in manufacturing or construction applications. It provides a reliable and objective measure to ensure that each bend meets the required specifications. This method can help reduce errors and variations in the bending process, resulting in improved overall quality and efficiency.
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A vendor is proposing use of an engine that produces 120 Btu of heat energy to produce
65 Btu of useful work. In the design, you note the heat source operates at 175°F and
the heat sink requires a temperature of 45°F. Is this engine theoretically possible?
Since the efficiency of the given engine (0.542) is less than the Carnot efficiency (0.743), the engine is not theoretically possible. Therefore, the engine proposed by the vendor is not theoretically possible.
Formula used:Efficiency = W/Qh
Where, Efficiency = (65/120)
Qh = heat energy input
W = useful work done
Qh = 120 Btu (given)
Efficiency = (65/120)
Efficiency = 0.542
Hence, efficiency is 0.542.
Now,Carnot efficiency = (Th - Tl)/Th
Where,Th = temperature of the heat source
Tl = temperature of the heat sink
Tl = 45°F (given)
Th = 175°F (given)
Carnot efficiency = (Th - Tl)/Th
Carnot efficiency = (175 - 45)/175
Carnot efficiency = 0.743
Hence, the Carnot efficiency is 0.743.
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Which part of a machine control unit interacts with the machine tools through electric signals?=]
A machine control unit is the electronic hardware that stores information and controls the machine tools. This unit contains a data processing unit that stores and manipulates data, and a ___________ that interacts with the machine tools through electrical signals.
Answer:
control loop unit
Explanation:
Edmentum/Plato
Find the voltage gain v0/vs of the circuit given below, where R1 = 14 kΩ and R2 = 13 kΩ
Answer:
The voltage gain is 2.07.
Explanation:
Given that,
Resistance \(R_{1}=14\ k\Omega\)
Resistance \(R_{2}=13\ k\Omega\)
We need to calculate the voltage gain
Using formula of voltage source
\(V_{s}=\dfrac{V_{o}\times R_{2}}{R_{1}+R_{2}}\)
\(\dfrac{V_{o}}{V_{s}}=\dfrac{R_{1}+R_{2}}{R_{2}}\)
Where, \(R_{1}\) = first resistance
\(R_{2}\) =second resistance
\(V_{s}\) = source voltage
\(V_{o}\) = output voltage
Put the value into the formula
\(\dfrac{V_{o}}{V_{s}}=\dfrac{14+13}{13}\)
\(\dfrac{V_{o}}{V_{s}}=2.07\)
Hence, The voltage gain is 2.07
The flow between two infinitely flat parallel plates displays a parabolic profile, and is called plane Poiseulle flow.
a. True
b. False
Answer:
a. True
Explanation:
The study of fluids in a state of rest or in motion and the forces involved in it is called fluid mechanics. Fluid mechanics has a wide range of applications in the field of mechanical engineering as well as civil engineering.
When we study the flow of fluid between any two flat plates that is indefinitely flat and is parallel, the flow of the fluid is known as plane Poiseulle flow. The profile of a plane Poiseulle flow is parabolic.
The velocity profile of a plane Poiseulle flow is :
\($\frac{u(y)}{U_{max}}=1-\left(\frac{2y}{h}\right)^2$\)
Thus the answer is TRUE.
If a uniform solid body weighs 50N in air and 30N in water, its specific gravity is close to i. 0.5 ii. 2.0 ii. 1.85 iv. 2.5 v. 5.0 Answer specific gravity =
Specific gravity = 1.67.
The specific gravity of a substance is defined as the ratio of the density of that substance to the density of a reference substance, typically water. Since the weight of a submerged object is reduced by the weight of the fluid it displaces, we can use the difference in weight between the object in air and in water to calculate the volume of water displaced, and hence the density of the object. Dividing the density of the object by the density of water gives the specific gravity. In this case, the specific gravity is (50 N - 30 N) / (50 N - 30 N) = 1.67.
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a commercial refrigerator with r-134a as the working fluid is used to keep the refrigerated space at -35 c by rejecting waste heat to cooling water that enters the condenser at 18 c at a rate of 0.25 kg/s and leaves at 26 c. the refrigerant enters the condenser at 1.2 mpa and 50 c and leaves at the same pressure subcooled by 6 c. if the compressor consumes 3.3 kw of power , determine (a) the mass flow rate of the refrigerant, b) the refrigerant load, c) the cop, and d) the minimum power input to the compressor for the same refrigeration load.
At 1.2mpa pressure and 50c
What is pressure?
By pressing a knife against some fruit, one can see a straightforward illustration of pressure. The surface won't be cut if you press the flat part of the knife against the fruit. The force is dispersed over a wide area (low pressure).
a)Mass flow rate of the refrigerant
Therefore h1= condenser inlet enthalpy =278.28KJ/Kg
saturation temperature at 1.2mpa is 46.29C
Therefore the temperature of the condenser
T2 = 46.29C - 5
T2 = 41.29C
Now,
d)power consumed by compressor W = 3.3KW
Q4 = QL + w = Q4
QL = mR(h1-h2)-W
= 0.0498 x (278.26 - 110.19)-3.3
=5.074KW
Hence refrigerator load is 5.74Kg
(COP)r = 238/53
(Cop) = 4.490
Therefore the above values are the (a) mass flow rate of the refrigerant, b) the refrigerant load, c) the cop, and d) the minimum power input to the compressor for the same refrigeration load.
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All of these are true about GMA (MIG) welding EXCEPT that:
O both the base metal and electrode are melted.
O shielding gas protects the well, tiom contamination.
O heat is produced using a short electric arc.
the welding gun liner regulates the shielding gas.
Answer:
the welding gun liner regulates the shielding gas.
Explanation:
The purpose of the welding gun liner is to properly position the welding wire from the wire feeder till it gets to the nozzle or contact tip of the gun. Regulation of the shielding gas depends on factors such as the speed, current, and type of gas being used. In gas metal arc welding, an electric arc is used to generate heat which melts both the electrode and the workpiece or base metal.
The electric arc produced is shielded from contamination by the shielding gas. The heat generated by the short electric arc is low.
A circuit has two resistors in parallel, each resistor is 6 ohms. This circuit is connected to a single resistor of 6 ohms, to form a series-parallel circuit. What is the total resistance of the circuit?
The tatal resistance of the series-parallel circuit with two resistor connected in parallel which combination is connected in series to a single resistor is 9 ohms.
What is a resistance?
This can be defined as the opposition to current flow in a circuit.
To calculate the total resistance, first we need to find the total resistance of the parallel resistor.
For parallel,
R' = (R₁R₂)/(R₁+R₂)............Equation 1Where:
R' = Total resistance of the parallel resistor.
From the question,
Given:
R₁ = 6 ohmsR₂ = 6 ohmsSubstitute these values into equation 1
R' = (6×6)(6+6)R' = 3 ohms.Finally, we combine the effective parallel resistance in series to the single resistance to the the total resistance of the circuit.
Rt = R'+R₃.................. Equation 2Where:
Rt = Total resistance of the circuit.From the question,
R' = 3 ohmsR₃ = 6 ohmsSubstitute these values into equation 2
Rt = 3+6Rt = 9 ohms.Hence, the total resistance of the circuit is 9 ohms.
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True or false for the 4 questions?
Answer:
true, false, true, true
Explanation:
Para un intercambiador de calor encargado de precalentar pulpa de fruta, se utiliza agua caliente que entra a 180°C y sale a 78°C, mientras que la pulpa de fruta entra a 3°C y sube su temperatura hasta 55°C. Realizar los esquemas de perfil de temperaturas para un intercambiador de calor que funcione en paralelo y en contracorriente. Además, calcular LMTD.
Answer:
La diferencia media logarítimica de temperatura del intercambiador en paralelo es aproximadamente 75.466 ºC.
La diferencia media logarítmica de temperatura del intercambiador en contracorriente es aproximadamente 97.881 ºC.
Explanation:
De la teoría de Transferencia de Calor tenemos que un intercambiador de calor en paralelo presenta las siguientes dos características:
1) Tanto el fluido caliente como el fluido frío entran por el mismo lado.
2) Tanto el fluido caliente como el fluido frío salen por el mismo lado.
Mientras que el intercambiador de calor en contracorriente tiene que:
1) El fluido caliente y el fluido frío entran por lados opuestos.
2) El fluido caliente y el fluido frío salen por lados opuestos.
A continuación, anexamos los esquemas de perfil de cada intercambiador.
Ahora, la Diferencia Media Logarítimica de Temperatura (\(\Delta T_{lm}\)), medida en grados Celsius, queda definida como sigue:
\(\Delta T_{lm} = \frac{\Delta T_{1}-\Delta T_{2}}{\ln \frac{\Delta T_{1}}{\Delta T_{2}} }\) (Eq. 1)
Donde \(\Delta T_{1}\) y \(\Delta T_{2}\) son las diferencias de temperatura de los fluidos en cada extremo del intercambiador, medido en grados Celsius.
Procedemos a determinar esas diferencias y la Diferencia Media Logarítimica de Temperatura para cada configuración:
Intercambiador en paralelo
\(\Delta T_{1} = 180\,^{\circ}C-3\,^{\circ}C\)
\(\Delta T_{1} = 177\,^{\circ}C\)
\(\Delta T_{2} = 78\,^{\circ}C - 55\,^{\circ}C\)
\(\Delta T_{2} = 23\,^{\circ}C\)
\(\Delta T_{lm} = \frac{177\,^{\circ}C-23\,^{\circ}C}{\ln \frac{177\,^{\circ}C}{23\,^{\circ}C} }\)
\(\Delta T_{lm} \approx 75.466\,^{\circ}C\)
La diferencia media logarítimica de temperatura del intercambiador en paralelo es aproximadamente 75.466 ºC.
Intercambiador en contracorriente
\(\Delta T_{1} = 180\,^{\circ}C-55\,^{\circ}C\)
\(\Delta T_{1} = 125\,^{\circ}C\)
\(\Delta T_{2} = 78\,^{\circ}C-3\,^{\circ}C\)
\(\Delta T_{2} = 75\,^{\circ}C\)
\(\Delta T_{lm} = \frac{125\,^{\circ}C-75\,^{\circ}C}{\ln \frac{125\,^{\circ}C}{75\,^{\circ}C} }\)
\(\Delta T_{lm} \approx 97.881\,^{\circ}C\)
La diferencia media logarítmica de temperatura del intercambiador en contracorriente es aproximadamente 97.881 ºC.