1: When constructing a perpendicular bisector, why must the compass opening be greater than 1/2 the length of the segment?2. When constructing an angle bisector, why must the arcs intersect?

Answer:

\(\huge\boxed{x=\dfrac{5}{4}}\)

Step-by-step explanation:

\(\left(\dfrac{1}{2}\right)^{x-1}=2^{3x-4}\qquad\text{use}\ a^{-1}=\dfrac{1}{a}\\\\\left(2^{-1}\right)^{x-1}=2^{3x-4}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\2^{(-1)(x-1)}=2^{3x-4}\qquad\text{use the distributive property}:\ a(b+c)=ab+ac\\\\2^{(-1)(x)+(-1)(-1)}=2^{3x-4}\\\\2^{-x+1}=2^{3x-4}\iff-x+1=3x-4\qquad\text{subtract 1 from both sides}\\\\-x+1-1=3x-4-1\\\\-x=3x-5\qquad\text{subtract}\ 3x\ \text{from both sides}\\\\-x-3x=3x-3x-5\\\\-4x=-5\qquad\text{divide both sides by (-4)}\)

\(\dfrac{-4x}{-4}=\dfrac{-5}{-4}\\\\x=\dfrac{5}{4}\)

Answer:

Expanding the expression 2(d+9) gives:

2(d+9) = 2*d + 2*9

Simplifying the expression gives:

2(d+9) =2d + 18

Therefore, 2(d+9) is equivalent to 2d +18.

The simplified expression is:

Work:

To simplify this expression, I distribute 2 through the parenthesis:

\(\sf{2(d+9)}\)

\(\sf{2\cdot d + 2 \cdot9}\)

\(\sf{2d+18}\)

Answer:

83 kilometres per hour =

51.574 miles per hour

The correct answer is option b. When the homoskedasticity assumption is violated, The beta parameter estimates are biased while the rest of the OLS assumptions are correct.

When the homoskedasticity assumption is violated, the ordinary least squares (OLS) estimator is still consistent but no longer efficient. This means that the estimates of the regression coefficients (beta parameters) are still unbiased, but they have higher variances and covariances.

In other words, the OLS estimator is no longer the best linear unbiased estimator (BLUE) and it may be biased when the errors are heteroscedastic. Therefore, option b is correct.

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The sοlutiοn οf the given prοblem οf unitary methοd cοmes οut tο be  fοr Met Manufacturing tο turn a prοfit, 103,184 sunglasses must be sοld.

The well-knοwn straightfοrward apprοach, actual variables, and any relevant infοrmatiοn frοm the initial and specialist questiοns can all be used tο finish the assignment. Custοmers may be given anοther chance tο try the gοοds in respοnse. If nοt, significant expressiοn in οur understanding οf prοgrams will be lοst.

Here,

We must figure οut hοw many pairs οf sunglasses must be sοld tο cοver the fixed and variable cοsts in οrder tο reach the break-even pοint.

Assume that X sunglasses must be sοld tο break even.

Fixed cοst plus variable cοst equals tοtal cοst.

Selling price x Number οf units sοld equals tοtal revenue.

The tοtal revenue and entire expense are equal at the break-even pοint.

Thus, we can cοnstruct the equatiοn:

Fixed cοst plus variable cοst multiplied by the selling price equals the quantity sοld.

=>  $9.44 X = $748,374 + $2.19 X

=>  $9.44 X - $2.19 X = $748,374

=>  $7.25 X = $748,374

=>  X = $748,374 / $7.25

=>   X = 103,184

Therefοre, fοr Met Manufacturing tο turn a prοfit, 103,184 sunglasses must be sοld.

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Answer:

  x = 1

Step-by-step explanation:

You want to know the value of x in the trapezoid with adjacent angles (43x+2)° and 135°.

The two marked angles can be considered "consecutive interior angles" where a transversal crosses parallel lines. As such, they are supplementary.

  (43x +2)° +135° = 180°

  43x = 43 . . . . . . . . . . . . . . divide by °, subtract 137

  x = 1 . . . . . . . . . . . . . . . divide by 43

The value of x is 1.

__

Additional comment

Given that the figure is a trapezoid, we have to assume that the top and bottom horizontal lines are the parallel bases.

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The solution is : the value of y is 7.

Here, we have,

The perimeter of a rectangle is found by

P = 2 (l+w)

P = 2( 3y+3+2y)

Combine like terms

P = 2(5y+3)

We know the perimeter is 76

76 = 2(5y+3)

Divide each side by 2

76/2 = 2/2(5y+3)

38 = 5y+3

Subtract 3 from each side

38-3 = 5y+3-3

35 = 5y

Divide each side by 5

35/5 = 5y/5

7 =y

We want the length of AD = BC = 2y

AD = 2y=2*y = 14

Hence, The solution is : the value of y is 7.

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Using the radius of the Ferris wheel and the angle between the two positions, the time spent on the ride when they're 28 meters above the ground is 12 minutes

The radius of the Ferris wheel is 30 / 2 = 15 meters.

The highest point on the Ferris wheel is 15 + 4 = 19 meters above the ground.

The time spent higher than 28 meters is the time spent between the 12 o'clock and 8 o'clock positions.

The angle between these two positions is 180 degrees.

The time spent at each position is 10 minutes / 360 degrees * 180 degrees = 6 minutes.

Therefore, the total time spent higher than 28 meters is 6 minutes * 2 = 12 minutes.

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Answer: Total expenses if 3 widgets are produced is $11,018.00

Step-by-step explanation: The variable cost per unit is given by the coefficient of q in the expense function. In this case, the variable cost is $6.00 per widget. To find the variable costs to produce 2 widgets, we simply multiply the variable cost per unit by the number of units produced: Variable costs for 2 widgets = 2 x $6.00 = $12.00 Therefore, the variable costs to produce 2 widgets is $12.00. To find the variable costs to produce q widgets, we simply multiply the variable cost per unit by the number of units produced: Variable costs for q widgets = q x $6.00 = $6q Therefore, the variable costs to produce q widgets is $6q. To find the total expenses if 3 widgets are produced, we can use the expense function and substitute q = 3:E = 6.00 q + 11,000

E = 6.00 (3) + 11,000

E = 18.00 + 11,000

E = 11,018.00 Therefore, the total expenses if 3 widgets are produced is $11,018.00.

The zeros of the given function are x = 2 and x = -1

From the question, we are to determine the zeros of the given function

The given function is

f(x) = (x - 2)(3x + 3)

To determine the zeros of a function, we will set the function equal to zero

That is,

(x - 2)(3x + 3) = 0

Then,

x - 2 = 0 OR 3x + 3 = 0

x = 2 OR 3x = -3

x = 2 OR x = -3/3

x = 2 OR x = -1

Hence, the zeros of the given function are x = 2 and x = -1

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The angles A and C in the triangle with sides AC = 24, BC = 15, and angle B = 74 degrees are approximately 29.16 degrees and 45.84 degrees, respectively.

To find angles A and C in the triangle, we can use the Law of Cosines, which relates the lengths of the sides of a triangle to the cosine of the included angle.

Let's denote the angles opposite to the sides with lengths 24, 15, and AB as A, B, and C, respectively. Then, the Law of Cosines gives us:

AB^2 = AC^2 + BC^2 - 2ACBCcos(B)

AB^2 = 24^2 + 15^2 - 22415cos(74)

AB^2 ≈ 758.76

AB ≈ 27.54

Now, we can use the Law of Sines, which relates the ratios of the lengths of the sides to the sines of the opposite angles:

sin(A) / AB = sin(B) / BC

sin(A) / 27.54 = sin(74) / 15

sin(A) ≈ 0.4927

A ≈ sin^-1(0.4927) ≈ 29.16 degrees

sin(C) / AB = sin(B) / AC

sin(C) / 27.54 = sin(74) / 24

sin(C) ≈ 0.6863

C ≈ sin^-1(0.6863) ≈ 45.84 degrees

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Answer:

If we define S as the number Sprinkle's umbrellas, and H as the Hurricane's umbrellas, the profit P can be expressed as:

\(P=3S+5H\)

The restriction for cloth can be written as:

\(S+2H\leq500\)

The restriction for metal can be written as:

\(2S+3H\leq600\)

The restriction for wood can be written as:

\(4S+7H\leq800\)

The condition for S and H to be positive is:

\(S, H \geq0\)

Step-by-step explanation:

We have an objective function that, in this case, we want ot maximize.

This function is the Profit (P).

If we define S as the number Sprinkle's umbrellas, and H as the Hurricane's umbrellas, the profit can be expressed as:

\(P=3S+5H\)

We have 3 restrictions, plus the condition that both S and H are positive.

The restriction for cloth can be written as:

\(S+2H\leq500\)

The restriction for metal can be written as:

\(2S+3H\leq600\)

The restriction for wood can be written as:

\(4S+7H\leq800\)

The condition for S and H to be positive is:

\(S, H \geq0\)

Answer:

The answer is OX=72

Step-by-step explanation

Took the quiz and got it right :)

Answer:

b < 3

Step-by-step explanation:

3 ( b - 5 ) < - 2b

3 ( b ) - 3 ( 5 ) < - 2b

3b - 15 < - 2b

3b + 2b < 15

5b < 15

b < 15/5

b < 3

An equation is formed of two equal expressions. The given equation can be completed as -20-(-12)=-20+12.

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

For the given equation, if the left side of the equation is simplified, then we can get the right side of the equation, therefore, the equation will be,

-20 - (-12)

= -20 -1(-12)  

= -20 + (-1 × -12)

= -20 + 12

Hence, the given equation can be completed as -20-(-12)=-20+12.

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Answer:

9 7/8

Step-by-step explanation:

1. 4 3/8 can be converted into the improper fraction 35/8, and 5 1/2 can be converted into 11/2.

2. Now that we have 35/8 + 11/2, we have to find a common denominator. Since 2 goes into 8 four times, we can turn 11/2 into 44/8 by multiplying the numerator and denominator (the top and the bottom numbers) by 4.

3. Now we have 35/8 + 44/8. At this point, the all we have to do is add the numerators (the top numbers). 35+44=79, so our answer is 79/8, which we can simplify to 9 7/8.

a) The algebraic fraction \(\frac{{x + 2}}{{(x - 1)^2}}\) is proper. b) The algebraic fraction \(\frac{{4x^2 - 31x + 59}}{{(x - 4)^2}}\) can be expressed as \(-\frac{{31}}{{x - 4}} - \frac{{25}}{{(x - 4)^2}}\).

Let's solve each part step by step and determine whether the fraction is proper or improper, and then express it accordingly.

a) \(\frac{{x + 2}}{{(x - 1)^2}}\):

Step 1: Determine the degree of the numerator and the denominator:

  - Degree of the numerator = 1 (linear term)

  - Degree of the denominator = 2 (quadratic term)

Since the degree of the numerator is less than the degree of the denominator, the fraction is proper.

Step 2: Express the proper fraction in partial fractions:

\(\frac{{x + 2}}{{(x - 1)^2}} = \frac{A}{{x - 1}} + \frac{B}{{(x - 1)^2}}\).

Step 3: Find the values of A and B:

Multiply both sides of the equation by \(((x - 1)^2)\) to eliminate the denominators:

  (x + 2) = A(x - 1) + B.

Expand the equation and collect like terms:

  x + 2 = Ax - A + B.

Equate the coefficients of like terms:

  Coefficient of x: 1 = A.

  Constant term: 2 = -A + B.

Solve the system of equations to find the values of A and B:

From the coefficient of x, A = 1.

Substituting A = 1 into the constant term equation: 2 = -1 + B, we find B = 3.

Therefore, the partial fraction decomposition is:

  \(\frac{{x + 2}}{{(x - 1)^2}} = \frac{1}{{x - 1}} + \frac{3}{{(x - 1)^2}}\).

b) \(\frac{{4x^2 - 31x + 59}}{{(x - 4)^2}}\):

Step 1: Determine the degree of the numerator and the denominator:

  - Degree of the numerator = 2 (quadratic term)

  - Degree of the denominator = 2 (quadratic term)

Since the degree of the numerator is equal to the degree of the denominator, the fraction is proper.

Step 2: Express the proper fraction in partial fractions:

  \(\frac{{4x^2 - 31x + 59}}{{(x - 4)^2}} = \frac{A}{{x - 4}} + \frac{B}{{(x - 4)^2}}\).

Step 3: Find the values of A and B:

Multiply both sides of the equation by \(((x - 4)^2)\) to eliminate the denominators:

  (4x^2 - 31x + 59) = A(x - 4) + B.

Expand the equation and collect like terms:

  4x^2 - 31x + 59 = Ax - 4A + B.

Equate the coefficients of like terms:

Coefficient of \(x^2\): 4 = 0 (No \(x^2\) term on the right side).

Coefficient of x: -31 = A.

Constant term: 59 = -4A + B.

Solve the system of equations to find the values of A and B:

From the coefficient of x, A = -31.

Substituting A = -31 into the constant term equation: 59 = 4(31) + B, we find B = -25.

Therefore, the partial fraction decomposition is:

  \(\frac{{4x^2 - 31x + 59}}{{(x - 4)^2}} = -\frac{{31}}{{x - 4}} - \frac{{25}}{{(x - 4)^2}}\).

The above steps provide the solution for each part, including determining if the fraction is proper or improper and expressing it in partial fractions.

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Answer:

\(y = \sqrt{x} \)

D

Step-by-step explanation:

Literally substitute one of the points (4,2), using some common sense, the x is larger than the y, so it can't be A or B (makes 4 larger) and really just pur 4 in option C, it won't be a pretty nice number. So the only option is D.

Answer:

8:12

Step-by-step explanation:

It's a ratio!

How many red is there? 8!

How many blue is there? 12!

So red to blue is 8:12!

Answer: The total number of sticks in one pack of red and one pack of blue is (8 + 12).

Step-by-step explanation: it is the answer edmentum gave me

Answer:

54

Step-by-step explanation:

ratio is 7:9

7=42

9=?

9×42÷7

Answer:

  about 1.1%

Step-by-step explanation:

Given a moon has a diameter of 22% of the diameter its planet, you want the volume of the moon as a percent of the planet's volume.

The ratio of moon diameter to planet diameter is given as 22%. The ratio of moon volume to planet volume will be the cube of this scale factor:

  moon volume / planet volume = (0.22)³ ≈ 0.0106 = 1.06%

The volume of the moon is about 1.1% of the volume of the planet.

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=Answer:

Step-by-step explanation:

f(-7) = -(-7)^2 - 10(-7) = -49 +70 = 21

A. P(6, then 1) = 1/90

B. P(even, then 5) = 1/18

C. P(8, then odd) = 1/18

D. P(3, then prime) = 2/45

E. P(prime, composite) = 4/15

F. P(even, then 3, then 5) = 1/144

Given:

Total number of cards: 10

A. P(6, then 1):

P(6, then 1) = 1/10 x 1/9

= 1/90

B. P(even, then 5):

Number of favorable outcomes: 5 x 1 = 5

P(even, then 5) = 5/10 x 1/9

= 1/18

C. P(8, then odd):

Number of favorable outcomes: 1 x 5 = 5

P(8, then odd) = 1/10 x 5/9

= 1/18

D. P(3, then prime):

Number of favorable outcomes: 1 x 4 = 4

P(3, then prime) = 1/10 x 4/9

= 2/45

E. P(prime, composite):

Number of favorable outcomes: 4 x 6 = 24

P(prime, composite) = 4/10 x 6/9

= 4/15

F. P(even, then 3, then 5):

Number of favorable outcomes: 5 x 1 x 1 = 5

P(even, then 3, then 5) = 5/10 x 1/9 x 1/8

= 1/144

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The correct comparison between two function is

Both functions are increasing, but function g increases at a faster average rate.

The Correct option is (B).

If the slope of a function is continuously increasing or constant in an interval, the function is known as an increasing function.

Let us assume

f(x) = \(ab^x\)+ c

so, at x=0, f(0)=-10

a +c = -10

Similarly, by satisfying the above table in the f(x)

f(x) = -33/5 \((1/11)^x\) - 17/5

and, f'(x) > 0

Thus, f(x) is an increasing function.

Now, g(x) = -18 \((1/3)^x\) +2

g'(x) = -18 \((1/3)^x\) log(1/3)

as log 1/3 <0

So, g'(x) > 0

Thus, g(x) is an increasing function.

For any x ∈ f(x) and x ∈ g(x), g'(x) > f'(x).

Hence, Both functions are increasing, but function g increases at a faster average rate.

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Answer:

1739 Reference Books Sold.

Step-by-step explanation:

Do this problem, we have to convert 34% to a decimal by taking the whole number value of the percent then dividing by 100. This gives us 0.34.

We can then take 4700 and multiply it by 0.34 and get 1739.

This also means that 0.66 is left over to be sold that hasn't sold in the month,

Take .66 and multiply it by 4700 to get 3102.

As long as 3102+1739=4700 is true, this means we have accounted for all values in the pie chart. At this point, we know from this that 1739 is the number of reference books sold out of the 4700.

Answer:

Two times lower than last year's temperature

Let today's Temperature be x

x/2 = -8.2°

x = -8.2°*2

Answer:

\(P(C\ or\ D) = 1\)

Step-by-step explanation:

Given

\(P(C) = \frac{3}{7}\)

\(P(D) = \frac{4}{7}\)

Required

\(P(C\ or\ D)\)

Since the events are mutually exclusive, then:

\(P(C\ or\ D) = P(C) + P(D)\)

So, we have:

\(P(C\ or\ D) = \frac{3}{7} + \frac{4}{7}\)

Take LCM

\(P(C\ or\ D) = \frac{3+4}{7}\)

\(P(C\ or\ D) = \frac{7}{7}\)

\(P(C\ or\ D) = 1\)