1. What is the speed of an object and the direction it is moving?

The centre of mass of the region is bounded by y=9-x^2 y=5/2x, and the z-axis is (3.5, 33/8). Formulae used to find the centre of mass are as follows:x bar = (1/M)*∫∫∫x*dV, where M is the total mass of the system y bar = (1/M)*∫∫∫y*dVwhere M is the total mass of the system z bar = (1/M)*∫∫∫z*dV, where M is the total mass of the systemThe region bounded by y=9-x^2 and y=5/2x, and the z-axis is shown in the attached figure.

The two curves intersect at (-3, 15/2) and (3, 15/2). Thus, the total mass of the region is given by M = ∫∫ρ*dA, where ρ = density. We can assume ρ = 1 since no density is given.M = ∫[5/2x, 9-x^2]∫[0, x^2+5/2x]dAy bar = (1/M)*∫∫∫y*dVTherefore,y bar = (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]y*dA= (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]ydA...[1].

The limits of integration in the above equation are from 5/2x to 9-x^2 for x and from 0 to x^2+5/2x for y.To evaluate the above integral, we need to swap the order of integration. Therefore,y bar = (1/M)*∫[0, 3]∫[5/2, (9-y)^0.5]y*dxdy...[2].

The limits of integration in the above equation are from 0 to 3 for y and from 5/2 to (9-y)^0.5 for x.Substituting the values and evaluating the integral, we get y bar = (1/M)*[(9-5/2)^2/2 - (9-(15/2))^2/2]= (1/M)*(25/2)...[3].

Also, the x coordinate of the center of mass is given by,x bar = (1/M)*∫∫∫x*dVTherefore,x bar = (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]x*dA= (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]xdA...[4].

The limits of integration in the above equation are from 5/2x to 9-x^2 for x and from 0 to x^2+5/2x for y.To evaluate the above integral, we need to swap the order of integration. Therefore, x bar = (1/M)*∫[0, 3]∫[5/2, (9-y)^0.5]xy*dxdy...[5].

The limits of integration in the above equation are from 0 to 3 for y and from 5/2 to (9-y)^0.5 for x.

Substituting the values and evaluating the integral, we get x bar = (1/M)*[63/8]= (1/M)*(63/8)...[6]Thus, the centre of mass of the region is bounded by y=9-x^2 y=5/2x, and the z-axis is (3.5, 33/8).

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According to Archimedes' principle, the volume of the liquid displaced when the body is totally immersed in the liquid is equal to the volume of the body.

The volume of the body is equal to the volume of the immersed portion.

Thus, the volume of the liquid displaced is equal to the volume of the immersed portion of the body.

Hence, option B is the correct answer.

Answer:

I think your answer would be D

Explanation:

Answer:

Explanation: A bar of an unknown metal has a length of 0.975 m at 45°C and a length of 0.972 m at. 23°C.

Answer:

3200kg

Explanation:

F=ma

16000=5m

m=3200kg

Hope this helps!

The mass of the parked car is 3200 kg if a truck if it is accelerating at a rate of 5 m/s² and hits a parked car with a force of 16,000 newtons.

A tangible body's mass is the amount of matter it possesses. It's also a metric of inertia or the resistance to velocity when a net force is exerted.

It is given that:

If a truck if it is accelerating at a rate of 5 m/s² and hits a parked car with a force of 16,000 newtons

As we know,

Newton's second law:

F = ma

Here F is the force acting on an object.

m is the mass of the object

a is the acceleration of the object.

a = 5 m/s²

F = 16,000 N

m = 3200kg

16000 = 5m

3200 kg

Thus, the mass of the parked car is 3200 kg if a truck if it is accelerating at a rate of 5 m/s² and hits a parked car with a force of 16,000 newtons.

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A solar flare is believed to occur when energy, stored in a twist in the solar magnetic field above a sunspot, is suddenly released.

Answer:

The slope is the tangent of the angle formed by the ratio of delta y to delta x:

tg α = Δy / Δx

Partial Differential Equation (PDE)The PDE governing the temperature distribution of the heated plate is as follows: Where the value of the constant k = thermal conductivity of the material being used. A discretization method is used to convert a partial differential equation (PDE) to a set of algebraic equations to solve the problem numerically.

Using Ax = 1 m and Ay = 3 m, the equation becomes the temperature at internal nodes inside the plate is computed by replacing the differential terms with their respective finite difference approximations, and the boundary conditions are imposed at the corresponding nodes. Using the central difference approximations, we get the following difference equations. For the first equation, we have, Similarly, for all the internal nodes except the ones at the boundaries, we have, This represents n equations in n unknowns, where n is the total number of internal nodes in the mesh.

Therefore, the system of equations can be represented in matrix form as AX = B, where X is a column matrix of unknowns, A is the coefficient matrix, and B is a column matrix of constants. The MATLAB built-in functions are used to solve the system of equations, which can be represented as below: Using the forward difference approximation, the gradient of temperature at the center of the plate can be calculated as, The resultant heat flux at the center of the plate, q" = k * (dT/dy), where dT/dy = 8.651 °C/m. The area of the plate is 3 x 9 = 27 m², which is equivalent to 2,700 cm².

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Answer:

\(x = 2\sqrt 2\)

Explanation:

Given

\(Hypotenuse = 4\)

Required

Find x

Since the triangle is a 45-45-90 triangle, the following relationship exists

\(x^2 + x^2 = 4^2\) --- i.e. the other legs are equal

So, we have:

\(2x^2 = 16\)

Divide both sides by 2

\(x^2=8\)

Take square roots of both sides

\(x = \sqrt 8\)

Simplify

\(x = 2\sqrt 2\)

Answer:

7√2

Explanation:

Answer: 1. 12 MPH 2. 36m 3. 8 Hz

Explanation:

Answer:

1. 12 MPH 2. 36m 3. 8 Hz

Explanation:

For #1, I multiplied 6 by 2, For #2 I multiplied 6 by 6 and for #3 it's 8 x 2

Starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², the car will travel a distance of approximately 0.2119 meters or 21.19 centimeters in 0.75 seconds.

To determine the distance traveled and the time elapsed by the car starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², we can use the equations of circular motion.

The tangential acceleration is the rate of change of tangential velocity. Since the car starts from rest, its initial tangential velocity is zero (v₀ = 0).

Using the equation:

v = v₀ + at

where v is the final tangential velocity, v₀ is the initial tangential velocity, a is the tangential acceleration, and t is the time, we can solve for v:

v = 0 + (0.75 m/s²) * t

v = 0.75t m/s

The tangential velocity is related to the angular velocity (ω) and the radius (r) of the circular track:

v = ωr

Substituting the values:

0.75t = ω * 300

Since the car starts from rest, the initial angular velocity (ω₀) is zero. So, we have:

ω = ω₀ + αt

ω = 0 + (0.75 m/s²) * t

ω = 0.75t rad/s

We can now substitute the value of ω into the equation:

0.75t = (0.75t) * 300

Simplifying the equation gives:

0.75t = 225t

t = 0.75 seconds

The time elapsed is 0.75 seconds.

To calculate the distance traveled (s), we can use the equation:

s = v₀t + (1/2)at²

Since the initial velocity (v₀) is zero, the equation becomes:

s = (1/2)at²

s = (1/2)(0.75 m/s²)(0.75 s)²

s = (1/2)(0.75 m/s²)(0.5625 s²)

s = 0.2119 meters or approximately 21.19 centimeters

Therefore, the car travels a distance of approximately 0.2119 meters or 21.19 centimeters.

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Answer: Any particle, whether an atom, molecule or ion, that contains less electrons than protons is said to be positively charged. Conversely, any particle that contains more electrons than protons is said to be negatively charged.

Explanation: If there are more electrons than protons in a piece of matter, it will have a negative charge, if there are fewer it will have a positive charge, and if there are equal numbers it will be neutral.

To determine the work done on the object from 0s to 5s, a student can use the equation ΔK = (1/2)mv², where ΔK is the change in kinetic energy of the object, m is its mass, and v is its velocity.

Since the velocity of the object is changing with time, the student can use the equation ΔK = (1/2)mΔv², where Δv is the change in velocity of the object from 0s to 5s. To find Δv, the student can read the initial velocity, v0, from the y-axis at 0s and the final velocity, vf, from the y-axis at 5s. Then, Δv = vf - v0.

Substituting the values of Δv and m into the equation ΔK = (1/2)mΔv², the student can calculate the change in kinetic energy of the object from 0s to 5s. This change in kinetic energy represents the work done on the object during this time interval.

Using the given values in the problem, the mass of the object is 2 kg. The initial velocity, v0, can be read from the y-axis at 0s, which is approximately 0 m/s. The final velocity, vf, can be read from the y-axis at 5s, which is approximately 4 m/s.

Therefore,

Δv = vf - v0

     = 4 m/s.

Substituting these values into the equation,

we get

ΔK = (1/2)(2 kg)(4 m/s)²

      = 16 J.

Therefore, the work done on the object from 0s to 5s is 16 J.

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Answer:

6) 2.6 m/s, 31°

7) 9.2 m/s

8) 1.2 s

Explanation:

I'll do #6, #7, and #8 as examples.  You can solve #9 using the equation from #7, and #10 using the equation from #8.

6) Take north to be +y and east to be +x.

Given:

vₓ = 2.2 m/s

vᵧ =  1.3 m/s

Find: v

v² = vₓ² + vᵧ²

v² = (2.2 m/s)² + (1.3 m/s)²

v ≈ 2.6 m/s

θ = atan(vᵧ / vₓ)

θ = atan(1.3 / 2.2)

θ ≈ 31°

7) Given:

Δy = -4.3 m

v₀ = 0 m/s

a = -9.8 m/s²

Find: v

v² = v₀² + 2aΔy

v² = (0 m/s)² + 2 (-9.8 m/s²) (-4.3 m)

v ≈ 9.2 m/s

8) Given:

Δy = -6.7 m

v₀ = 0 m/s

a = -9.8 m/s²

Find: t

Δy = v₀ t + ½ at²

-6.7 m = (0 m/s) t + ½ (-9.8 m/s²) t²

t = 1.2 s

Velocity is vector quantity because it has both magnitude and direction.

Explanation:

velocity is a vector quantity because the person always returns to the original position,the motion would never result in a change in a position.

Answer:

400J

Explanation:

s=d/t

s=800/40

s=20m/s

K.E= 1/2mv^2,

=1/2*40*20

=400 J

The properties of group 18 elements, also referred to as noble gases or group 8 elements.

Eight valence electrons make them up.

They have enough electrons in their octet, therefore they don't need any more (stable).

are steady

Noble gases are those that are not reactive.

In order to gain or lose valence electrons to the element they interact with, elements create ions. They acquire a whole octet as a result. You might be wondering what a whole octet is. When an element contains all 8 valence electrons and is stable, it is said to have an octet, rendering it nonreactive.

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Newton's first and second laws of motion both do, but I think the one you're looking for is: The First Law of Motion.  That description is a little more direct.

It says that if an object is not acted on by a net external force, then it continues in "constant, uniform motion".

The change in gravitational potential energy, in joules, between the original position of the block when the spring is fully compressed and its final position after it has been released is given by:

Gravitational Potential Energy = ½ * (Mass – Mass) * Height

where:

Mass = Mass of block on Earth's surface

Height = Distance from bottom of block to top of block when it's at rest

In this case, we need to find how far the block will move upwards while it is being compressed. This can be found by multiplying its mass by its acceleration due to gravity, which is 9.8 meters per second squared (m/s2).

For example, let us suppose the height of this particular experiment was 5 cm, so we'll use an exponent of 2 for our calculation:

Gravitational Potential Energy = ½ * (5 cm – 5 cm) * 9.8 m/s2

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Answer

The cars on the higher track travel

✔ farther than

the cars on the lower track, in the same time.

This means that the cars on the higher track have a

✔ greater

average speed than those on the lower track.

This is demonstrated by the

✔ slope

of the higher track line being greater than the slope of the lower track line.

Explanation:

Answer:

farther than      greater      slope

Explanation:

have a nice day

Answer:

social justice is the correct answer

Explanation:

The electron beam in a cathode-ray television tube is indeed striking just one point on the screen at a time, but it is doing so at a very high speed. In fact, the beam is moving across the screen so quickly that it is able to draw a complete picture by painting each point on the screen one at a time, and doing so 30 to 60 times per second.

This process is known as raster scanning, and it works by moving the electron beam across the screen in a series of horizontal lines, starting at the top left corner and moving across to the right. Once it reaches the end of a line, it quickly moves back to the left side of the screen and drops down a few pixels to start the next line. This process repeats until the entire screen has been painted.

The speed at which the beam moves is crucial to creating a clear picture. If it moved too slowly, we would see the individual lines being drawn, which would look like flickering to our eyes. However, by moving so quickly, the lines are blended together and we see a smooth, continuous image.

So to summarize, while the electron beam in a cathode-ray television tube is striking just one point on the screen at a time, it is doing so in a rapid sequence that allows it to create a full picture. This process is known as raster scanning, and it works by moving the beam across the screen in a series of horizontal lines, painting each point one at a time until the entire screen has been covered.

In a cathode-ray television tube, a full picture is produced by the electron beam striking one point at a time through a process called "raster scanning." The electron beam moves rapidly across the screen, line by line, from top to bottom. As it does this, it illuminates individual phosphor dots, which then emit light to create the image. The entire process is repeated approximately 25 to 30 times per second, giving the illusion of a continuous picture. The human eye perceives this rapidly changing sequence of points as a full image due to a phenomenon called "persistence of vision."

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Answer:

Hi there!

Using Hooke's Law:

F = kx

F = Force (N)

k = Spring constant (N/m)

x = displacement (m)

Begin by converting cm to m:

280 cm = 2.8 m

Now, plug in the givens:

25 = 2.8k

k = 8.93 N/m

Answer: Final velocity is  \(3.8 m/s\)

Explanation:

We are given mass and velocity, or mass in motion, known in physics as "momentum".

The formula for momentum is \(p=mv\) (mass*velocity)

First, calculate the momentum of the person running:

\(p=60kg*4m/s\)

\(p=240(kg*m/s)\)

When the person jumps on the skateboard, the mass changes and now we're solving for the velocity. Use the same formula above to solve.

\(240=(60+4)*v\) can be rewritten as \(v=\frac{240kg*m/s}{(60+4)kg}\) or \(v=\frac{p}{m}\)

Solve and the kg cancels out and you're left with a final velocity of \(3.75 m/s\) or \(3.8m/s\) rounded to nearest tenth.

Answer: (b)

Explanation:

According to the law of conservation of momentum.

B. Emily moves forward at 2 m/s.

From the calculation, the acceleration of the body is 26m/s^2.

When an object is thrown up or down, the motion of the body is influenced by the gravitational pull on the body.

Now;

Given that;

v = 39 m/s

t = 1.5 s

u = 0 m/s

a = ?

v = u + at

v = at

a = v/t

a = 39 m/s/1.5 s

a = 26m/s^2

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Answer:

Electromagnetic waves have crests and troughs similar to those of ocean waves.

Explanation:

The distance between crests is the wavelength. hope this helps you :)