Solve for the value of x in the given rational inequalities.
Answer:
see explanation
Step-by-step explanation:
1
1 + \(\frac{x-5}{2}\) - \(\frac{x+3}{5}\) ≤ 0
multiply through by 10 ( the LCM of 2 and 5 ) to clear the fractions
10 + 5(x - 5) - 2(x + 3) ≤ 0 ← distribute parenthesis on left side and simplify
10 + 5x - 25 - 2x - 6 ≤ 0
3x - 21 ≤ 0 ( add 21 to both sides )
3x ≤ 21 ( divide both sides by 3 )
x ≤ 7
2
\(\frac{6x}{5}\) - \(\frac{2}{3}\) ≥ 4
multiply through by 15 ( the LCM of 5 and 3 ) to clear the fractions
18x - 10 ≥ 60 ( add 10 to both sides )
18x ≥ 70 ( divide both sides by 18 )
x ≥ \(\frac{70}{18}\) , that is
x ≥ \(\frac{35}{9}\)
3
\(\frac{x}{10}\) - \(\frac{2}{8}\) ≥ 1
multiply through by 40 ( the LCM of 10 and 8 ) to clear the fractions
4x - 10 ≥ 40 ( add 10 to both sides )
4x ≥ 50 ( divide both sides by 4 )
x ≥ \(\frac{50}{4}\) , that is
x ≥ \(\frac{25}{2}\)
Answer:
\(\textsf{1.} \quad x \leq 7\)
\(\textsf{2.} \quad x \geq \dfrac{35}{9}\)
\(\textsf{3.} \quad x \geq \dfrac{25}{2}\)
Step-by-step explanation:
Question 1Given inequality:
\(1+\dfrac{x-5}{2}-\dfrac{x+3}{5} \leq 0\)
\(\textsf{Add \; $\dfrac{x+3}{5}$ \; to both sides}:\)
\(\implies 1+\dfrac{x-5}{2}-\dfrac{x+3}{5} +\dfrac{x+3}{5}\leq 0+\dfrac{x+3}{5}\)
\(\implies 1+\dfrac{x-5}{2}\leq \dfrac{x+3}{5}\)
\(\textsf{Rewrite $1$ as $\dfrac{2}{2}$}:\)
\(\implies \dfrac{2}{2}+\dfrac{x-5}{2}\leq \dfrac{x+3}{5}\)
\(\textsf{Apply the fraction rule} \quad \dfrac{a}{c}+\dfrac{b}{c}=\dfrac{a+b}{c}:\)
\(\implies \dfrac{2+x-5}{2}\leq \dfrac{x+3}{5}\)
\(\implies \dfrac{x-3}{2}\leq \dfrac{x+3}{5}\)
Cross multiply:
\(\implies 5(x-3)\leq 2(x+3)\)
\(\implies 5x-15\leq 2x+6\)
Subtract 2x from both sides:
\(\implies 5x-15-2x\leq 2x+6-2x\)
\(\implies 3x-15\leq 6\)
Add 15 to both sides:
\(\implies 3x-15+15\leq 6+15\)
\(\implies 3x\leq 21\)
Divide both sides by 3:
\(\implies \dfrac{3x}{3}\leq \dfrac{21}{3}\)
\(\implies x \leq 7\)
---------------------------------------------------------------------------------------
Question 2Given inequality:
\(\dfrac{6x}{5}-\dfrac{2}{3} \geq 4\)
\(\textsf{Add \; $\dfrac{2}{3}$ \; to both sides}:\)
\(\implies \dfrac{6x}{5}-\dfrac{2}{3} +\dfrac{2}{3}\geq 4+\dfrac{2}{3}\)
\(\implies \dfrac{6x}{5}\geq \dfrac{12}{3}+\dfrac{2}{3}\)
\(\implies \dfrac{6x}{5}\geq \dfrac{12+2}{3}\)
\(\implies \dfrac{6x}{5}\geq \dfrac{14}{3}\)
Cross multiply:
\(\implies 3(6x) \geq 14(5)\)
\(\implies 18x \geq 70\)
Divide both sides by 18:
\(\implies \dfrac{18x}{18} \geq \dfrac{70}{18}\)
\(\implies x \geq \dfrac{70}{18}\)
Reduce the fraction by dividing the numerator and the denominator by 2:
\(\implies x \geq \dfrac{70 \div 2}{18 \div 2}\)
\(\implies x \geq \dfrac{35}{9}\)
---------------------------------------------------------------------------------------
Question 3Given inequality:
\(\dfrac{x}{10}-\dfrac{2}{8} \geq 1\)
\(\textsf{Add \; $\dfrac{2}{8}$ \; to both sides}:\)
\(\implies \dfrac{x}{10}-\dfrac{2}{8} +\dfrac{2}{8}\geq 1+\dfrac{2}{8}\)
\(\implies \dfrac{x}{10}\geq \dfrac{8}{8}+\dfrac{2}{8}\)
\(\implies \dfrac{x}{10}\geq \dfrac{8+2}{8}\)
\(\implies \dfrac{x}{10}\geq \dfrac{10}{8}\)
Cross multiply:
\(\implies 8(x) \geq 10(10)\)
\(\implies 8x \geq 100\)
Divide both sides by 8:
\(\implies \dfrac{8x}{8} \geq \dfrac{100}{8}\)
\(\implies x \geq \dfrac{100}{8}\)
Reduce the fraction by dividing the numerator and the denominator by 4:
\(\implies x \geq \dfrac{100 \div 4}{8 \div 4}\)
\(\implies x \geq \dfrac{25}{2}\)
PLEASE ANSWER NUMBER 15 ‼️‼️‼️‼️
Answer:
C
Step-by-step explanation:
Name the marked angle in 2 different ways.
Answer:
angle QPR and angle RPQ
Step-by-step explanation:
hope this helps!
What is the growth rate for the linear function y=mx+b?
Answer:
m
Step-by-step explanation:
the slope or growth rate of the function is the coefficient of the variable x, which is m in this case
use the fourier transform to find an integral formula for a bounded solution to the airy differential equation − d2u dx2 = xu.
The Airy differential equation is a second-order linear ordinary differential equation given by Fourier Transform:
-d^2u/dx^2 = x*u
To find a bounded solution to this equation, we can use the Fourier transform. The Fourier transform of a function f(x) is given by:
F(ω) = ∫ f(x) e^(-iωx) dx
Using the Fourier transform, we can convert the differential equation into an algebraic equation in terms of the Fourier transform F(ω):
-ω^2 F(ω) = ∫ x*u(x) e^(-iωx) dx
We can rewrite the integral on the right-hand side using integration by parts:
∫ x*u(x) e^(-iωx) dx = -∫ u(x) d/dx(e^(-iωx) dx)
= -iω∫ u(x) e^(-iωx) dx + [u(x) e^(-iωx)]^∞_0
Since we are looking for a bounded solution, the term [u(x) e^(-iωx)]^∞_0 must be equal to zero. Therefore, we have:
ω^2 F(ω) = iω∫ u(x) e^(-iωx) dx
We can then solve for the Fourier transform F(ω):
F(ω) = i/ω ∫ u(x) e^(-iωx) dx
Finally, we can take the inverse Fourier transform to find the solution u(x):
u(x) = (1/2π) ∫ F(ω) e^(iωx) dω
Substituting the expression for F(ω), we have:
u(x) = i/(2πω) ∫ ∫ u(y) e^(-iω(y-x)) dy dω
This gives us an integral formula for a bounded solution to the Airy differential equation in terms of the Fourier transform.
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simplify these expressions. a) x ⊕ 0 b) x ⊕ 1 c) x ⊕ x d) x ⊕ x
a) x b) 1 c) 0 d) x , x ⊕ x ⊕ 0 → Since 0 is the neutral element of the XOR operator, it will not affect the result of the expression. Therefore, the expression simplifies to just x.
a) x ⊕ 0 → Since 0 is the neutral element of the XOR operator, it will not affect the value of x. Therefore, the expression simplifies to just x.
b) x ⊕ 1 → Since 1 is the identity element of the XOR operator, it will return the opposite of x. Therefore, the expression simplifies to just 1.
c) x ⊕ x → Since x ⊕ x is equivalent to x XORing itself, the result will be 0. Therefore, the expression simplifies to just 0.
d) x ⊕ x ⊕ 0 → Since 0 is the neutral element of the XOR operator, it will not affect the result of the expression. Therefore, the expression simplifies to just x.
a) x ⊕ 0 simplifies to just x.
b) x ⊕ 1 simplifies to just 1.
c) x ⊕ x simplifies to just 0.
d) x ⊕ x ⊕ 0 simplifies to just x.
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Find the rectangular coordinate for the polar coordinate (4,210^0)
Please I will give Brainly
The rectangular coordinate for the polar coordinate (4, 210°) is (-3.46, -2).
What is the rectangular coordinate?The rectangular coordinate for the polar coordinate (4, 210°) is calculated by applying the following formula as shown below;
x = r cos(θ)
y = r sin(θ)
where;
r is the distance from the origin of the coordinateθ is the angle or directionFrom the given polar coordinate (4, 210°);
r = 4
θ = 210⁰
The rectangular coordinate is calculated as follows;
x = 4 x cos(210°)
y = 4 x sin(210°)
x = -3.46
y = -2
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pls help me 3 i beg of you (IM2)
The polynomial representing the area of the is 49n² - 25
How to determine the polynomialThe formula for area of a square is expressed as;
Area = a²
Where a is the side length
From the image shown, we can see that the side length takes the value (7n - 5)
Substitute the value into the formula
Area = a²
Area = (7n - 5)²
Area = (7n - 5) ( 7n + 5); this is so because of the difference of two squares
Expand the bracket
Area = 49n² + 35n - 35n - 25
collect like terms
Area = 49n² - 25
Thus, the polynomial representing the area of the cube is 49n² - 25
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The function f(x) models the average cost per unit, f(x), for Electrostuff to manufacture x units of Electrogadget IV. How many units must the company produce to have an average cost per unit of ? Round to the nearest integer.
Complete question is;
The function f(x) = (25000 + 280x)/x models the average cost per unit, f(x), for Electrostuff to manufacture x units of Electrogadget IV. How many units must the company produce to have an average cost per unit of $390?
Answer:
227 units
Step-by-step explanation:
We are given the function;
f(x) = (25000 + 280x)/x
Where;
f(x) is the average cost per unit
x is the number of units
Now, we want to find out how many units the company must produce to have an average cost per unit of $390.
Thus, plugging $390 for f(x), we have;
390 = (25000 + 280x)/x
When we cross multiply, we get;
390x = 25000 + 280x
390x - 280x = 25000
110x = 25000
x = 25000/110
x ≈ 227
Write an equation of the parabola shown. (0,4) (-5, 1.5)
the general formula of a parabola is
\(y=ax^2+bx+c\)we can replace the the points to find a,b and c
First (0,4)
\(\begin{gathered} 4=a(0)^2+b(0)+c \\ 4=0+0+c \\ c=4 \end{gathered}\)Then (-5,1.5) and c=4
\(1.5=a(-5)^2+b(-5)+4\)On the graph below where the following areas are the x - axis, the y - axis,quadrant 1,quadrant 2, quadrant 3 and quadrant 4
DESPERATE WILL GIVE BRAINLIST AND THANKS
Which table contains a set of non-linear ordered pairs?
A. x y
0 7
1 5
2 3
3 1
B.x y
0 1
1 2
2 3
3 4
C. x y
0 4
1 7
2 10
3 13
D. x y
0 1
1 2
2 5
3 10
Answer:
It was D I took the test
Step-by-step explanation:
Answer:
it is d
Step-by-step explanation:
In which quadrant is the RED point?
This was due last week! HEEEEEEELP
Answer:
4th quadrant is the red point..
Express the radical using the imaginary unit i
Answer:
\(=\pm i\sqrt{66}\)
Step-by-step explanation:
So we have:
\(\pm\sqrt{-66}\)
This is the same as:
\(=\pm\sqrt{66\cdot-1}\)
Separate:
\(=\pm\sqrt{66}\cdot\sqrt{-1}\)
Replace the second term with i:
\(=\pm i\sqrt{66}\)
The square root of 66 cannot be simplified.
So, this is our answer :)
you bike 5 miles the first day of your training, 5.5 miles the second day, 6.5 miles the third day, and 8.5 miles the fourth day. if you continue this pattern, how many miles do you bike the seventh day?
Answer:
36.5
Step-by-step explanation:
The pattern was the difference of one day and the next doubled
Calculate the following probability: Given that a couple has an Education Level = 4, what is the probability that it has SC Index = 10?
o 0.94
o 17
o 0.06
o 0
The correct option is option C: 0.06.
Given that a couple has an Education Level = 4, the probability that it has SC Index = 10 is 0.06.
What is probability?
Probability is a measure of the likelihood or chance of an event occurring. It is a number that ranges from 0 to 1.
When an event is certain to occur, its probability is 1, while when an event is impossible to occur, its probability is 0.
The probability of an event A is denoted by P(A). It can be calculated using the following formula: P(A) = (number of favorable outcomes)/(total number of outcomes)
In this question, we need to calculate the probability of the event that a couple has an Education Level = 4 and SC Index = 10.
Given that a couple has an Education Level = 4, there are a total of 50 such couples. Of these, 3 have SC Index = 10.
Therefore, the probability that a couple has an Education Level = 4 and SC Index = 10 is: P(Education Level = 4 and SC Index = 10) = 3/50 = 0.06Hence, the correct option is option C: 0.06.
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I WILL MARK BRAINLIEST!
Answer:
1.true
2.false
3.false
4.true
5.true
6.false
Step-by-step explanation:
just graph it and look at it
The measure of one acute angle of a right triangle is 6 less than twice the measure of the other acute angle. Find the measure of each acute angle.
The measure of each of the acute angles of the right triangle is 32° and 58°.
A right triangle is a kind of triangle which has a right angle (90°) and two acute angles (less than 90°).
Let x = measure of one of the acute angles
If the measure of one acute angle of a right triangle is 6 less than twice the measure of the other acute angle, then
measure of the other acute angle = 2x - 6
The sum of all the angles of any triangle is equal to 180°. Hence,
90° + x + 2x - 6 = 180°
Solve for the value of x.
3x = 96
x = 32
Solve for the measure of the other acute angle.
2x - 6 = 2(32) - 6 = 58
Hence, the two angles are 32° and 58°.
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Andres is going to invest in an account paying an interest rate of 4% compounded
continuously. How much would Andres need to invest, to the nearest dollar, for the
value of the account to reach $4,700 in 11 years?
\(~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$ 4700\\ P=\textit{original amount deposited}\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\dotfill &11 \end{cases} \\\\\\ 4700=Pe^{0.04\cdot 11} \implies 4700=Pe^{0.44}\implies \cfrac{4700}{e^{0.44}}=P\implies 3027\approx P\)
which one ?
it says i need 20 characters so i’m just typing this
Find the equation of the line specified.
The line passes through the points ( -2, 3) and ( -4, 7)
a.
y = -2x - 1
c.
y = -4x - 1
b.
y = -2x + 3
d.
y = -2x + 7
Please select the best answer from the choices provided
A
B
C
D
Answer:
D
Step-by-step explanation:
Identify the property used in each step. 12.2 18.6 â€""4.3 (â€""18.6) 12.2 â€""4.3 18.6 (â€""18.6) 12.2 â€""4.3 [18.6 (â€""18.6)] 12.2 â€""4.3 (0) 12.2 â€""4.3 7.9
Properties used in the given equation is Commutative property, Associative property, Additive inverse, Identity property.
In a commutative property multiplication and addition which posses commutative property takes place without considering the order of arrangement of data.
12.2 + 18.6 + -4.3 + (-18.6)
12.2 + -4.3 _ 18.6 + (-18.6)
The second step results into the presence of a commutative property.
12.2 + -4.3 + [18.6 + (-18.6)] is an associative property because here, regrouping of numbers which gives the same result.
[18.6 + (-18.6)] is an additive inverse since the result is zero. Additive inverse occurs when the addition of a number to another number results into zero.
12.2 + -4.3 + (0) is an identity property.
This property occurs when the addition of any number with zero eventually resulted into that number.
So here we used 4 properties which are
Commutative property,
Associative property,
Additive inverse,
Identity property.
Given question is written in wrong language.
Here is the given question 12.2 + 18.6 + -4.3 + (-18.6)12.2 + -4.3 + 18.6 + (-18.6)12.2 + -4.3 + [18.6 + (-18.6)]12.2 + (-4.3) + (0)12.2 + -4.3 7.9
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Answer #2 for me and don't forget to graph the function ! I'm not sure if my Y is correct so let me
a triangle has side lengths of 5 centimeters, 24 centimeters, and 26 centimeters. Is it a right triangle?
Answer:
Not right triangle
Step-by-step explanation:
Solve for q qq. 3 ( q + 4 3 ) = 2 3(q+ 3 4 )=23, left parenthesis, q, plus, start fraction, 4, divided by, 3, end fraction, right parenthesis, equals, 2
Answer:
q=7
Step-by-step explanation:
3(q +4/3)+2=23
3q+4+2=23
3q+2=23
3q=23-2
q=21/3=7
Answer:
- 2/3
Step-by-step explanation:
on khan academy
Express the ratio below in its simplest form
2.5 : 3.5
Answer:
5 : 7
Step-by-step explanation:
Assuming simplest form means in whole numbers, to find the ratio in simplest form, just multiply both sides by the same value until they are both whole numbers. So 2.5 : 3.5 = 2.5 * 2 : 3.5 * 2 = 5 : 7
Answer:
5:7
Step-by-step explanation:
The simplest form of 2.5 : 3.5 is 5:7 because 2.5 x 2 = 5 and 3.5 x 2 = 7
Frank kept track of the amount of money he earned each day for 2 weeks.the amounts,in dollars,are listed below.
25,30,24,20,20,22.5,75,27,27,22,22,27,22.5,28
Find and calculate the measures of center and variability that best summarize frank's data.explain
Answer:
Step-by-step explanation:
Wendy brought 4 cakes and 2 pies for $20. The cost of a cake is twice the cost of 1 pie. A) What was the cost of one cake b)What was the cost of 1 pie?
Answer:
a. The cost of one cake is $4.
b. The cost of one pie is $2.
Step-by-step explanation:
Let the cost of cake be C.Let the cost of pie be PC = 2P .....equation 1
4C + 2P = 20 .....equation 2
Substituting eqn 1 into eqn 2, we have;
4(2P) + 2P = 20
8P + 2P = 20
10P = 20
P = 20/10
Pie, P = $2
Next, we would determine the cost of a cake;
From equation 1;
C = 2P
Substituting the value of "P" we have;
C = 2 * 2
Cake, C = $4
Therefore, we would have the following answers;
a. The cost of one cake is $4.
b. The cost of one pie is $2.
Check:
From equation 2;
4C + 2P = 20
4(4) + 2(2) = 20
16 + 4 = 20
20 = 20
Look at this graph :
Is this relation a function?
Answer:
yes it relates to a function
a motorboat takes 5 hours to travel 200 miles going upstram. the return takes 2 hours going downstram. what s the rate of the boat in still water and whats the rate of the current?
Therefore, the rate of the boat in still water is 70 mph, and the rate of the current is 30 mph.
Let's denote the rate of the boat in still water as "b" and the rate of the current as "c."
When the boat is traveling upstream, it is going against the current, so the effective speed is reduced. The speed of the boat relative to the ground can be calculated as (b - c).
Given that it takes 5 hours to travel 200 miles upstream, we can set up the equation:
Distance = Speed * Time
200 = (b - c) * 5
Dividing both sides by 5, we get:
40 = b - c (Equation 1)
When the boat is traveling downstream, it is aided by the current, so the effective speed is increased. The speed of the boat relative to the ground can be calculated as (b + c).
Given that it takes 2 hours to travel 200 miles downstream, we can set up the equation:
200 = (b + c) * 2
Dividing both sides by 2, we get:
100 = b + c (Equation 2)
Now we have a system of equations consisting of Equation 1 and Equation 2:
40 = b - c
100 = b + c
We can solve this system of equations using any method of solving simultaneous equations, such as substitution or elimination.
Adding Equation 1 and Equation 2:
40 + 100 = (b - c) + (b + c)
140 = 2b
Dividing both sides by 2, we get:
b = 70
Substituting the value of b back into Equation 1 or Equation 2:
40 = 70 - c
Subtracting 70 from both sides:
-30 = -c
Multiplying both sides by -1, we get:
30 = c
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