1. W= 500 Joules
t = 25 seconds
P = ?

Answer:

they are quantities with magnitude without direction e.g weight,

The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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Explanation:

Total Resistance: 3+2 = 5 ohms

V=9V

Power = V²/R

=9²/5

=81/5

=16.2 W

Answer:

som,eythiung did cant wait

Explanation:

ya so i texted maria and she said i con c()me over so letyeyey yeah betty letty

PAINN I MISS JUOICE WORLDD PAINNNN

Answer:

1) Assuming an adult person has an average mass of m=80 kg, and assuming it takes about 30 seconds to climb 5 meters of stairs, the energy used by the person is

So the power output is

And since the estimate we made is very rough, we can say that the power output of the person is comparable to the power output of the light bulb of 100 W.

2) Based on the results we found in the previous part of the exercise, since the power output of the person is comparable to the power output of 1 light bulb of 100 W, we can say that the person could have kept burning only one 100-W light bulb during the climb.

Explanation:

The velocity in which this second particle finds itself at a distance r2 = 25,0 cm from point P is 17.22 m/s.

The electric force between the two particles is calculated from Coulomb's law of electrostatic force.

F = kq₁q₂/r²

where;

F = (9 x 10⁹ x 3.10 x 10⁻⁶ x 3.10 x 10⁻⁶) / (0.09 m)²

F = 10.68 N

The velocity in which this second particle finds itself at a distance r2 = 25,0 cm from point P is calculated by applying the principle of conservation of energy.

W = ΔK.E

where;

Fr = ¹/₂mv²

2Fr = mv²

v² = 2Fr/m

v = √(2Fr/m)

v = √(2 x 10.68 x 0.25 / 1.8 x 10⁻²)

v = 17.22 m/s

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To find:

What happens to the gravitational force when the mass of one of the objects is doubled.

Explanation:

From Newton's law of gravitation, The gravitational force between two objects is directly proportional to the product of the masses of the objects and inversely proportional to the square of the distance between the objects.

Thus the gravitational force between the objects of mass M and m that is separated by a distance of r is given by,

Where G is the gravitational constant.

Let us say the mass m is doubled, then the new value of the gravitational force between the objects is given by,

Final answer:

Thus, when the gravitational force between the objects will double if the mass of one of the objects is doubled.

Thus the correct answer is option C.

Videos can be streamed from the cloud to a computer with no loss in quality because Digital signals are used to transmit data to and from the cloud.

How do digital signals work?

An established or one that represents data as a step made up of discrete values is known as a digital signal. There is no noise produced by digital signals. Electronic signals sent as pulses are used to transmit digital signals to computers. These signals can be found in things like digital phones and computers.

Because digital signals are used to transport data to and from the cloud, it should be noted that videos are said to stream from the cloud to a computer without quality degradation.

Videos can be streamed from the cloud to a computer with no loss in quality because Digital signals are used to transmit data to and from the cloud.

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This means that the electric potential in the surface and inside the conductor must be constant.

So in the ideal case, we can say that in a perfect conductor there is no electric field inside of it.

And we know that the electric field is given by the gradient of the electric potential, so to have no electric field inside the conductor, we must have a constant electric potential.

This means that we should have the same electric potential in the whole volume of the conductor. While in reality, this does not happen, as we actually have a small electric field inside the conductor, and this happens because there is a small change in the electric potential as we reach the surface.

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Time passed between the moment the car left the table and the moment it hit the floor is 0.95 second.

Speed, amount that designates how rapid and in what route a point is moving. A point always actions in a path that is tangent to its path; for a round direction, as an instance, its route at any immediately is perpendicular to a line from the factor to the centre of the circle (a radius).

Speed is the time charge at which an object is moving along a path, at the same time as velocity is the fee and route of an item's movement.

Calculation:-

S = ut + 1/2 at²

1.83 = 0.5t²

t² = 1.83/0.5

   = 0.915

   = 0.95 Second

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Answer:

is there any more to this question

Explanation:

(PLEASE GIVE BRIANLIEST)

The average speed is not equal to the sum of the speeds divided by 2 because the car takes different times to cover the distance while going up and coming down the hill.

The average speed can be calculated as the total distance covered divided by the total time taken. As the speeds are constant, we can use the formula:

distance = speed * time

Let the distance traveled be "d". The time taken to go up the hill is "t1" and the time taken to come down is "t2".

d = 35 * t1 = 69 * t2

The total time taken for the round trip is t1 + t2.

The average speed is given by:

average speed = d / (t1 + t2) = d / (d/35 + d/69)

So the average speed can be calculated as follows:

average speed = d / (d/35 + d/69) = d * (35 + 69) / (35 * 69) = 104 / 2445 = 8 / 205 km/h

Answer:

12N

Explanation:

given- mass, acelation

Fnet=ma= .16kg*75m/s2

Fnet=12 N only force no friction given.

The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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Answer:

2.01

Explanation:

First, we need to find the centripetal acceleration.

We're given that the merry go round rotates 1 revolution in 2.09 seconds. Converting to rpm, we know that it rotates 30 revolution per minute

Now this speed gotten in rpm will be converted to m/s, to ease the calculation

30 rpm = πdN/60 m/s

30 rpm = (3.142 * 4 * 30)/60

30 rpm = 377.04/60

30 rpm = 6.284 m/s

a(c) = v²/r

a(c) = 6.284²/2

a(c) = 39.49 / 2

a(c) = 19.74 m/s²

F = ma

F = 50 * 19.74

F = 987 N

Also, Normal Force, F(n) =

F(n) = mg

F(n) = 50 * 9.81

F(n) = 490.5

We then use this to find the coefficient of static friction, μ

μ = F/F(n)

μ = 987 / 490.5

μ = 2.01

Answer:

\(metre \: per \: second\)

Explanation:

Velocity is a derived quantity and the S.I unit is metre per second.Speed is also a derived quantity which is has the S.I unit to be metre per second.

Answer:

1) We can estimate the age of the earth

2) we can calculate the speed of anything

3) we can also calculate gravity, e.t.c.

Explanation:

I could give you more just ask

Answer:

Five examples of locomotor movements are:

Hopping

Galloping

Walking

Running

Skipping

Explanation:

I hope it helps ❤❤

Answer:

B 1,3, and 4

Explanation:

Answer:

Therefore it is save to carry a 62kg adult

Explanation:

From the question we are told that:

Mass \(m=380kg\)

Height of supporting Rock \(X=85cm\)

Length of Board\(L_r=4.5m\)

Mass of board \(M_b=22kg\)

Mass of adult \(M_a=62\)  

Generally the moment of balance about wedge part about  is mathematically given by

\(N -Q + R = Mg + mg\)

\(0.85*N - Mg*2.25 - mg*(2.25 + x) = 0\)

\(0.85*N = + Mg*2.25 + mg*(2.25 + x)\)

where

\(N+R=4547\)

therefore

\(N = 570.70588 + 1608.3529 + 714.823 x\)

if N=0 at fallen person

\(x=3.04m\)

Therefore it is save to carry a 62kg adult

Answer:

The value of time T₁ is 0.323 sec

Explanation:

Given the data in the question;

The inductor will be shorted after a long time;

I = V / R

given that; I = 20.0 A and V = 240 V

we substitute

20 = 240 / R

20R = 240

R = 240 / 20

R = 12 Ohms

Now, when I = 5.00 A

voltage across inductor = 240 - ( 5.0 × 12 )

voltage across inductor = 180 V

so

180 = L × di/dt

given that; increasing at a rate of 20.0 A/s

180 = L × 20

L = 180 / 20

L = 9 H

Now, for the time constant of circuit is T₁

T₁ = L / R = 9 / 12

T₁ = 0.75 s

so

I = l₀( 1 - \(e^{(-T/T_1)\) )

we substitute

7.00 = 20.0( 1 - \(e^{(-T/0.75)\) )

7/20 = 1 - \(e^{(-T/0.75)\)

0.35 = 1 - \(e^{(-T/0.75)\)

0.35 - 1 =  - \(e^{(-T/0.75)\)

-0.65 = - \(e^{(-T/0.75)\)

0.65 = \(e^{(-T/0.75)\)

ln(0.65) = -T₁ / 0.75

-0.43078 = -T₁ / 0.75

-T₁ = -0.43078 × 0.75

-T₁ = -0.323

T₁ = 0.323 sec

Therefore, The value of time T₁ is 0.323 sec

Answer:

pendulum, quartz

Explanation:

The magnitude of the car's deceleration that slows down from 35m/s to 15m/s in 4s is -5m/s².

Deceleration is the amount by which a speed or velocity decreases (and so a scalar quantity or a vector quantity).

The deceleration of a body can be calculated by dividing the change in speed or velocity by the time taken as follows:

d = (v - u)/t

Where;

According to this question, a car slows down from 35m/s to 15m/s in 4s. The deceleration can be calculated as follows:

d = (15 - 35)/4

d = -20/4

d = -5m/s²

Therefore, -5m/s² is the magnitude of the car's deceleration.

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Answer:

The speed of light traveling through a vacuum is exactly 299,792,458 meters (983,571,056 feet) per second. That's about 186,282 miles per second — a universal constant known in equations as "c," or light speed.

\(s\frac{d}{t}\)

Explanation:

hope this helps you my friend

Answer: A. Work is done on the system and heat is transferred from the system for a net decrease in internal energy.

Explanation:

A refrigerator is a device which dispenses heat from the close system to a warmer area or in the surrounding. By dispensing the heat the internal temperature of the refrigerator drops. The system of refrigerator violates the second law of thermodynamics. As it performs the work to cool the region instead of heating the region. The work is done on the system and the internal energy decreases and the heat energy is liberated to the surrounding area. A refrigerator is an open system.

The acceleration of Thomas is 0.233 m/s^2.

Acceleration is the rate of change of velocity. Thomas the Train chugs along at a velocity of 2 m/s.

Thomas needs to go faster so more coal is shoveled into his engine and he accelerates for 10 seconds until he is going 4.33 m/s.

We are to find the acceleration of Thomas.

The formula for acceleration is given as :

acceleration = (final velocity - initial velocity) / time

In the given problem, the initial velocity of Thomas, u = 2 m/s.

The final velocity of Thomas, v = 4.33 m/s The time for which Thomas accelerates, t = 10 s.

Therefore, the acceleration of Thomas will be given as:

a = (v - u) / ta = (4.33 - 2) / 10s => 2.33 / 10s => 0.233 m/s^2

Thus, the acceleration of Thomas is 0.233 m/s^2.

To summarize, the acceleration of Thomas is 0.233 m/s^2.

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The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.

The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.

The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.

The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.

The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).

The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).

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