1. Using the "octet rule," I will write the Lewis structures for the following molecules:
(a) CH₂Cl₂: H-Cl:C-H
|
Cl
(b) NCl₃: Cl
|
Cl-N-Cl
(c) CS₂: O=C=S=O
(d) CH₃CHCHCH₃: CH₃-CH-CH-CH₃
2. For the bolded carbon atom in the molecule CH₃CHCHCH₃:
a) There are 3 areas of high electron density surrounding the indicated C (3 bonded atoms and 0 lone pairs).
b) The AXmEn notation for the C in this molecule is AX₃E₀, where m=3 and n=0.
c) The molecular geometry for the C in this molecule is trigonal planar.
d) The bond angles surrounding C are approximately 120 degrees.
3. Obeying the octet rule, nitric acid (HNO₃) has two resonance structures. They can be drawn as:
Resonance Structure 1: O=N-O-H
||
O
Resonance Structure 2: O-N=O
||
O-H
Let us learn more in detail.
1.
(a) CH₂Cl₂: Carbon is the central atom with two hydrogen atoms and two chlorine atoms attached. The Lewis structure would be:
Cl H
| |
C-H-C-Cl
| |
H Cl
(b) NCl₃: Nitrogen is the central atom with three chlorine atoms attached. The Lewis structure would be:
Cl
|
Cl-N-Cl
|
Cl
(c) CS₂: Carbon is the central atom with two sulfur atoms attached. The Lewis structure would be:
S=C=S
(d) CH₃CHCHCH₃: Carbon is the central atom with three methyl groups and one hydrogen atom attached. The Lewis structure would be:
H H H
| | |
H-C-C-C-H
| | |
H H CH₃
3. The two resonance structures for nitric acid HNO₃ would be:
O-H O
| |
H-O=N O=N-O
| |
O O-H
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how many molecules are in 45.0 g of water
Fe + CuSO4 → Cu + FeSO4
Theo phương trình cứ 56 gam Fe tan vào dung dịch thì có 64 gam Cu tách ra khỏi dung dịch. Thanh Fe tăng khối lượng nên khối lượng dung dịch phải giảm đi đúng bằng khối lượng thanh Fe tăng lên.
Vậy khối lượng thanh sắt tăng 0,8 gam → khối lượng dung dịch giảm so với ban đầu 0,8 gam.
Fe + CuSO4 (aq) → FeSO4 (aq) + Cu (s) Loại phản ứng là phản ứng chuyển vị. Trong phản ứng này, kim loại sắt có phản ứng mạnh thay thế Đồng bằng đồng sunfat bằng cách nhường hai điện tử a
g Given that the phosphoric acid that we use in the Beckmann Rearrangement is 85 % H3PO4 by weight, and the following balanced equation for the reaction of phosphoric acid and sodium carbonate and the given atomic masses; how many grams of sodium carbonate should you weigh out to neutralize all the phosphoric acid
To neutralize all the phosphoric acid, you would need to weigh out a certain amount of sodium carbonate. The balanced equation for the reaction between phosphoric acid (H₃PO₄) and sodium carbonate (Na₂CO₃) is:
2 H₃PO₄ + 3 Na₂CO₃ → 6 H₂O + Na₃PO₄ + 3 CO₂
To determine the amount of sodium carbonate needed, we need to consider the weight percentage of H₃PO₄ and the stoichiometric ratio between H₃PO₄ and Na₂CO₃.
To calculate the amount of sodium carbonate needed to neutralize all the phosphoric acid
1. Calculate the amount of H₃PO₄: If the phosphoric acid is 85% H₃PO₄ by weight, this means that 85 grams of every 100 grams of the acid is H₃PO₄. Therefore, if we have a certain mass of phosphoric acid, we can determine the mass of H₃PO₄ by multiplying it by 0.85.
2. Convert the mass of H₃PO₄ to moles: To determine the stoichiometric ratio between H₃PO₄ and Na₂CO₃, we need to convert the mass of H₃PO₄ to moles. This is done by dividing the mass of H₃PO₄ by its molar mass, which can be calculated by adding the atomic masses of hydrogen (H), phosphorus (P), and oxygen (O) in H₃PO₄.
3. Use the stoichiometric ratio: From the balanced equation, we can see that 2 moles of H₃PO₄ react with 3 moles of Na₂CO₃. This means that the stoichiometric ratio between H₃PO₄ and Na₂CO₃ is 2:3.
4. Calculate the amount of Na₂CO₃: Multiply the moles of H₃PO₄ by the stoichiometric ratio. This will give us the moles of Na₂CO₃ needed to neutralize the given amount of H₃PO₄.
5. Convert moles to grams: Finally, multiply the moles of Na₂CO₃ by its molar mass to calculate the mass of Na₂CO₃ needed.
By following these steps, we can determine the amount of sodium carbonate (Na₂CO₃) that should be weighed out to neutralize all the phosphoric acid.
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Which element is placed in the same period as ruthenium but has a higher atomic number than it?
A.bismuth
B.osmium
C.silver
D.zirconium
Answer:
The part that is put in the same time as ruthenium, but has a greater number of atoms than silver.
Answer:
The answer is silver.
Explanation:
edge 2022, trust
Which symbol is the correct notation for the element silicon?
Responses
Si
Si
SI
SI
S
S
Sil
The correct notation for the element silicon is "Si".
Silicon is a chemical element with the symbol Si and atomic number 14.
It is a metalloid, meaning that it has properties of both metals and nonmetals. Silicon is the second most abundant element on Earth, after oxygen, and it is a major component of rocks, sand, and minerals. It is also a crucial element in many technological applications, particularly in the electronics industry, where it is used to make semiconductors, computer chips, and solar cells.
Silicon has a crystalline structure and is a hard, brittle, and blue-grey material. It is not found in its pure form in nature, but is instead obtained from the purification of silicon dioxide, which is commonly found in sand and quartz. Silicon is also found in various minerals, such as mica, feldspar, and talc.
Silicon has many unique properties that make it useful in various applications. For example, it is a semiconductor, meaning that its electrical conductivity can be controlled by adding impurities to it in a process called doping. This property is essential for the production of electronic components, such as transistors and diodes.
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Give the spectator ions for the reaction that occurs when aqueous solutions of Na2CO3 and HCl are mixed.A) H+ and CO32-D) Na+ and Cl-B) Na+ and CO32-E) No spectator ions are present.C) H+ and Cl-
Na+ and Cl- are spectator ions for the reaction that occurs when aqueous solutions of \(Na_{2}CO_{3}\) and \(HCl\) are mixed.
D is the correct answer.
The reaction is given as:
\(Na_{2} CO_{3} (aq) + 2HCl_{(aq)}\) → \(2NaCl_{(aq)} + CO_{2} (g) + H_{2}O_{(l)}\)
The net ionic equation is:
\(CO_{3} ^{2-} + 2H_{3}O^{+}\) → \(CO_{2} _{(g)} + 3H_{2} O_{(l)}\)
A spectator ion is an ion that can be found in a chemical equation as both a reactant and a product. Therefore, a spectator ion can be seen in the reaction between aqueous solutions of sodium carbonate and copper(II) sulphate without changing the equilibrium.
These ions are present in both directions of chemical processes but do not participate in them. The spectator ions are cancelled from both sides of the equation in the net chemical reaction.
The presence of sodium and nitrate ions can be determined by comparing the two solutions before and after the reaction. They don't go through any kind of chemical alteration at all. These ions are known as spectator ions since they have zero involvement in the chemical reaction.
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What conclusion can you draw from the heating curve?
Answer:A heating curve graphically represents the phase transitions that a substance undergoes as heat is added to it. The plateaus on the curve mark the phase changes. The temperature remains constant during these phase transitions.
Bacteria are most important in the process of
a. combustion.
c. nitrogen fixation.
b. condensation.
d. evaporation.
Bacteria are most important in the process of nitrogen fixation. That is option C.
What is nitrogen fixation?Nitrogen fixation is defined as the important step in nitrogen cycle that aids in the conversation of the inert nitrogen gas to more-reactive nitrogen compounds such as ammonia, nitrates, or nitrites.
The bacteria microorganisms such as Azotobacter, Bacillus, Clostridium, and Klebsiella help in nitrogen fixation of nitrogen cycle pathway.
Therefore, bacteria are most important in the process of nitrogen fixation.
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33. which indication of relative acid strengths is incorrect? a) hclo2 > hclo b) h2so4 > h2so3 c) hcl > hf d) h2so3 > hno3
This is incorrect because HNO3 (nitric acid) is a stronger acid than H2SO3 (sulfurous acid). The other options are accurate comparisons of acid strengths.
The incorrect indication of relative acid strengths is d) h2so3 > hno3. This is because hno3 is a stronger acid than h2so3. The correct order of acid strengths is hcl > hf, h2so4 > h2so3, hclo2 > hclo, and hno3 > h2so3. It's important to note that the strength of an acid is determined by its ability to donate a proton (H+) to a base. A stronger acid is able to donate its proton more easily than a weaker acid.
Based on the given options, the incorrect indication of relative acid strengths is: d) H2SO3 > HNO3
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what happened to the ph of the solution as you came near to adding stoichiometrically equivalent amounts of base to your acids? why do you think that this occurred
As we add a base to an acidic solution, the pH of the solution increases.
The pH will continue to increase as we add more base until it reaches a certain point where the amount of base added is stoichiometrically equivalent to the amount of acid present in the solution. At this point, the pH of the solution will be at its highest point, known as the equivalence point.
At the equivalence point, all the acid has reacted with the base, and the solution contains only the salt and water formed by the reaction. The pH of the solution at the equivalence point will depend on the strength of the acid and base used.
The reason for the increase in pH as we add base is due to the neutralization reaction that takes place between the acid and the base. The acid donates a proton (H⁺) to the base, which accepts the proton and becomes a conjugate acid. This reaction reduces the concentration of H⁺ ions in the solution, which causes the pH to increase.
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A radioactive substance decays continuously according to the formula A = le^kt, where A is the final amount, I is the initial amount, k is a constant, and t is the time in years. If 70 grams of the substance decays to 25 grams in 8 years, determine the value of k.
Select one:
a. -0.1287
b. -0.4472
c. 0.5708
d. 0.1287
The value of k is approximately -0.1287. The correct answer is option a. -0.1287
To determine the value of k in the radioactive decay formula A = \(le^kt\), we can use the given information:
A = final amount = 25 grams
I = initial amount = 70 grams
t = time = 8 years
We can substitute these values into the formula and solve for k:
A = \(Ie^kt\)
25 = \(70e^k(8)\)
Dividing both sides of the equation by 70:
\(e^k(8)\)= 25/70
Taking the natural logarithm (ln) of both sides to isolate k:
ln\((e^k(8))\) = ln(25/70)
k(8) = ln(25/70)
Dividing both sides by 8:
k = (1/8) × ln(25/70)
Using a calculator to evaluate this expression, we find:
k ≈ -0.1287
Therefore, the value of k is approximately -0.1287.
The correct answer is: a. -0.1287
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A student argued that there is less gravity on the Moon than on Earth. The student explained, "You need an atmosphere to have gravity. The Moon doesn't have an atmosphere and therefore doesn't have a lot of gravity. Earth has a thick atmosphere and therefore has much more gravity." What do you think about the student's claim?
A. The student is correct because the atmosphere is what creates the gravitational pull on Earth
B. The student is correct because the mass of the object determines how thick the atmosphere will be
c. The student is incorrect because gravity is determined by the mass of the object and not the atmosphere
D. The student is incorrect because the thickness of the atmosphere will determine the amount of gravity on the object
Answer:
C
Explanation:
The student is incorrect.
The atmosphere weighs very little compared to the material the earth is made of. Gravity is effected by mass. The more mass, the more gravity. The only correct (and it is totally correct) answer is C
What is the mole fraction (Χ) of CH3OH, methanol, in a solution of 8.50 mL of CH3OH and 4.53 g of C6H5COOH, benzoic acid ? Density of CH3OH is 0.792 g/mLMolar mass of CH3OH is 32.04 g/molMolar mass of C6H5COOH is 122.12 g/mol
The mole fraction of \(CH_3OH\)in the solution is 0.850 or 85.0%.
To calculate the mole fraction (Χ) of methanol (CH3OH) in the given solution, we need to determine the number of moles of CH3OH and the number of moles of \(C_6H_5COOH\)(benzoic acid) in the solution.
First, we can calculate the number of moles of CH3OH using its volume and density:
Mass of CH3OH = Volume x Density = 8.50 mL x 0.792 g/mL = 6.732 g
Number of moles of CH3OH = Mass / Molar mass = 6.732 g / 32.04 g/mol = 0.210 mol
Next, we can calculate the number of moles of \(C_6H_5COOH\)using its mass and molar mass:
Number of moles of C6H5COOH = Mass / Molar mass = 4.53 g / 122.12 g/mol = 0.0371 mol
The total number of moles of solute in the solution is the sum of the moles of CH3OH and C6H5COOH:
Total number of moles = 0.210 mol + 0.0371 mol = 0.247 mol
Finally, we can calculate the mole fraction of \(CH_3OH\)using its number of moles and the total number of moles:
Mole fraction of \(CH_3OH\)= Number of moles of \(CH_3OH\)/ Total number of moles = 0.210 mol / 0.247 mol = 0.850
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What is the oxidation number of zinc in zncl2?
The oxidation number of the zinc in the ZnCl₂ is the +2.
The oxidation number, is also called as the oxidation state, the total number of the electrons that an atom either will gains or will loses in order to form the chemical bond with the another atom.
The oxidation number of the chlorine = -1
The oxidation number of the Zn is as follows :
Zn + 2( -1 ) = 0
Zn - 2 = 0
Zn = + 2.
The Oxidation number of an atom can be defined as the charge that the atom appears will have on forming the ionic bonds with the other heteroatoms.
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A 22.5 g sample of an unknown material is heated from 25oC to 90oC. If 431 J of heat energy is absorbed in the heating process, what is the specific heat of the material?
Answer:
c = 0.29 J/g.°C
Explanation:
Given data:
Mass of sample = 22.5 g
Initial temperature = 25°C
Final temperature = 90°C
Heat absorbed = 431 J
Specific heat of material = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 90°C - 25°C
ΔT = 65°C
431 J = 22.5 g × c × 65°C
431 J = 1462.5 g.°C × c
c = 431 J/1462.5 g.°C
c = 0.29 J/g.°C
Pressure is caused by __________ within the container.
comman factors that can lead to high blood pressure include.
Use the appropriate conversation to find out how many grams of NaCl are in 38.2 g of the
solution described above.
38.2 g of the solution contain 9.55 g of sodium chloride.
Seawater and the extracellular fluid of many multicellular creatures both contain a high concentration of sodium chloride, which is the salt that contributes most to these salinities. As a condiment and food preservative, salt is frequently used in its edible form.
To find out how many grams of NaCl are in 38.2 g of the solution described above, you would need to calculate the mass of NaCl by multiplying the mass of the solution by the percent composition of NaCl. The percent composition of NaCl in the solution is 0.25.
so the calculation would be 38.2 g x 0.25 = 9.55 g.
Therefore, there are 9.55 g of NaCl in 38.2 g of the solution.
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If half of the moon is always illuminated why does its appearance from earth change?
Answer:
The different angles the moon has from sunlight to the earth
Explanation:
The appearance of the moon changes from the earth because Sun lights up the different parts of the moon as the moon circles around the earth.
Why does the moon have phases?The Moon revolves around the earth at an average distance of 382,400 kilometers. Moon takes the lunar month 29.53 days to go from one new moon to the next. The Moon goes through all its phases during the lunar month.
Half of the Moon just like the earth is lit by the Sun while the other half is in dark. The dark side of the moon which does not light by the Sun. We only see the Moon because sunlight reflects from the surface of the moon back to us. The Moon circles once around the Earth during the course of a month.
As the moon revolves around the earth, the amount of the lit side changes and the location of the earth, moon, and sun. These changes are responsible for the different phases of the Moon. The appearance of the moon from the earth changes with them.
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1. What is WRONG with the setup used by the student to solve this
problem?
10 points
If 53.8 grams of Aluminum Carbide is treated with Sodium Oxide, how many moles of Aluminum Oxide is
produced?
AlqC3 +6 Na2O + 2 Al2O3 + 3 Nand
53.8 g ALC
1 mole ALC
2 mole Al2O3
101.96g Al2O3
143.92 g AL C3
1 mole ALC
1 mole Al2O3
The student used the wrong mole ratio.
O The student is solving for the wrong unit.
Ο Ο Ο
The student used incorrect steps.
The student's setup is correct.
INITI
Answer:
Trump or biden or obama or soba or you or beach
The molar mass of cu is 63. 5 g/mol. The molar mass of ag is 107. 9 g/mol. What mass, in grams, of ag is produced from a reaction of 31. 75 g of cu? 26. 95 grams 107. 9 grams 215. 91 grams 431. 82 grams.
The correct answer is 107.9 g of Ag is produced from a reaction of 31. 75 gram of Copper.
How to calculate The Molar Mass?Molar mass of a substance is the mass in grams of one mole of the compound. A mole is the measurement of the number of things, such as atoms, molecules, and ions, that are present in a substance. Any material has 6.022 x 1023 molecules in a mole, it is known as Avogadro's number . The mole is used to determine the size of the tiniest entities quantitatively, just as we use a standard value to quantify many things, such as 1 dozen = 12 items.
Formula - Molar mass = mass in grams/mole = g/mol
Molar mass of a substance can be calculated as:
Given,
n = W/M, where
W = required mass
M= molar mas
Given chemical reaction is:
Cu + 2AgNO₃ → Cu(NO₃)₂ + 2Ag
From the stoichiometry of the reaction,
1 mole of Cu = produce 2 moles of Ag
Given mass of Cu = 31.75g
Molar mass of Cu = 63.5g/mol
Moles of Cu = 31.75g / 63.5g/mol = 0.5 moles
0.5 moles of Cu = produce 2×0.5 = 1 mole of Ag
Molar mass of Ag = 107.9g/mol
Required mass of Ag = 1mol × 107.9g/mol = 107.9 g
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HELLO IS ANYONE GOOD AT SCIENCE IF SO PLEASE ANSWER THIS IS DUE TONIGHT
a student must make a buffer with a ph of 2.00. determine which weak acid is the best option at the specified ph.
Acetic acid is the best option for making a buffer with pH 2.00. Option 3 is the answer.
What is the best weak acid option for making a buffer with pH 2.00?
To make a buffer with a pH of 2.00, we need to select a weak acid with a pKa close to this value. The pKa of an acid is the pH at which half of the acid molecules are dissociated.
For a buffer, we want to choose an acid where the pH is close to its pKa value because at this point, the concentration of both the acid and its conjugate base will be approximately equal.
The Henderson-Hasselbalch equation can be used to calculate the pH of a buffer solution:
\(\mathrm{pH} &= \mathrm{pKa} + \log{\left(\frac{[\mathrm{A^-}]}{[\mathrm{HA}]}\right)} \\\)
Where [A-] is the conjugate base concentration and [HA] is the weak acid concentration.
At pH 2.00, the [H+] concentration is 10⁻² M. Therefore, we need to choose a weak acid with a pKa close to 2.00.
One possible option is acetic acid (CH₃COOH), which has a pKa of 4.76. Using the Henderson-Hasselbalch equation, we can calculate the required ratio of [A-]/[HA]:
\(2.00 &= 4.76 + \log{\left(\frac{[\mathrm{A^-}]}{[\mathrm{HA}]}\right)}\)
\(\log{\left(\frac{[\mathrm{A^-}]}{[\mathrm{HA}]}\right)} &= -2.76 \\\\\frac{[\mathrm{A^-}]}{[\mathrm{HA}]} &= 10^{-2.76} \\\\\frac{[\mathrm{A^-}]}{[\mathrm{HA}]} &= 1.63 \times 10^{-3}\)
Thus, for a buffer with a pH of 2.00, we could mix acetic acid and its conjugate base (sodium acetate) in a 1:163 ratio, which is option 3.
The complete question is -
A student must make a buffer with a ph of 2.00. determine which weak acid is the best option at the specified pH?
1. Sodium disulfate monohydrate
2. Propionic acid
3. Acetic acid
4. Formic acid
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What are the two types of taxes that working individuals pay on their earnings?
(1) individual income tax and sales tax
(2) payroll tax and sales tax
(3) individual income tax and social insurance taxes
(4) property tax and payroll tax
(5) sales tax and income tax
There are actually two types of taxes that working individuals pay on their earnings. The first one is individual income tax, which is a tax levied on the income of individuals or households.
The second one is social insurance taxes, which are taxes collected to fund social security and Medicare programs. Therefore, the correct answer to this question would be (3) individual income tax and social insurance taxes. Sales tax and income tax are not necessarily paid by working individuals on their earnings, so option (5) is not correct.
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1. If a sample of matter is uniform throughout and cannot be separated into other substances byphysical means, it is _______.A) a compoundB) either a compound or an elementC) a homogeneous mixtureD) a heterogeneous mixtureE) an element2. What volume of 10.0 M H2SO4 is required to prepare 4.0 L of 0.50 M H2SO4?A) 0.20 LB) 0.40 LC) 0.50 LD) 1.0 LE) 4.0 L3. A solution of silver nitrate is mixed with a solution of potassium fluoride. If a precipitate forms,the precipitate is:A) Silver fluorideB) Potassium nitrateC) Potassium fluorateD) Nitric fluorideE) No precipitate is formed
The answer to the first question is E) an element. The answer to the second question is C) 0.50 L. The answer to the third question is A) Silver fluoride.
A substance is a material that has a fixed composition and set of properties, and can not be separated into simpler components by physical means. It can be a pure chemical element such as iron or a compound made up of two or more elements combined in a fixed ratio, such as water (H2O). Substances can exist as solids, liquids, or gases and can be characterized by their chemical and physical properties, such as density, melting point, and boiling point. A substance is a material that has a fixed composition and set of properties, and can not be separated into simpler components by physical means. It can be a pure chemical element such as iron or a compound made up of two or more elements combined in a fixed ratio, such as water (H2O).
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Where does Respiration mainly take place in?
A - Mitochondria
B - The nucleus
C - The cell wall
D - The vacuole
At 1 atm, how much energy is required to heat 59.0 g H2O(s) at −22.0 ∘C to H2O(g) at 141.0 ∘C? STRATEGY: Calculate the energy needed for each temperature change or phase change individually. a. The energy needed to heat 59.0 g H2O(s) from −22.0 ∘C to its melting point. b. The energy needed to melt 59.0 g H2O(s) at its melting point. c. The energy needed to heat 59.0 g H2O(l) from the melting point to the boiling point. d. The energy needed to boil 59.0 g H2O(l) at its boiling point. e. The energy needed to heat 59.0 g H2O(g) from the boiling point to 141.0 ∘C. Sum the energies from each step and convert to kilojoules. Step 1. a. Going from −22.0 ∘C to the melting point of H2O (0 ∘C) is a temperature change of 22.0 ∘C. How much energy is needed to heat 59.0 g H2O(s) by 22.0 ∘C if its specific heat is 2.087 J/(g× ∘C)?
Answer:
The answer is "2736.1 J"
Explanation:
\(m= 59.0 \ g\\\\t_2 = -22\\\\\Delta t= t_1-t_2\\\\\)
\(= 0-(-22)\\= 22\)
specific heat for ice = 2.108 \(\frac{J}{gk} \\\)
Formula:
\(\bold{Q= mc \Delta t} \\\)
\(= 59 \times 2.108 \times 22\\\\= 2736.1 \ \ J\)
Which statement best describes the air behind a cold front?(1 point)
Responses. Heh Heh Heh i got like 12 question SO YALL BETTER GET GOING
A. The air is warmer and more humid.
B. The air is colder and drier.
C. The air is cold and filled with moisture.
D. The air is warm and dry.
The air is colder and drier behind a cold front. Therefore, the correct option is option B among all the given options.
What is cold front?A cold front represents the sharp end of a cooler air masses at floor level that substitutes a warmer air mass as well as rests within a noticeable low-pressure trough.
It frequently originates behind such an extratropical storm (to the west in the Hemisphere, towards the southeast in the Southern), near the leading edge of the storm's arid "conveyor belt" flow. Temperature changes across the barrier can surpass 30 degrees Celsius (54 degrees Fahrenheit) through one side to the next. The air is colder and drier behind a cold front.
Therefore, the correct option is option B.
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name five organs of the digestive system and state there function
Answer:
Organ Movement Food Particles Broken Down
Stomach Upper muscle in stomach relaxes to let food enter, and lower muscle mixes food with digestive juice Proteins
Small intestine Peristalsis Starches, proteins, and carbohydrates
Pancreas None Carbohydrates, fats, and proteins
Liver None Fats
Explanation:
To prevent formation of phosgene gas, what materials should be kept out of atmospheres penetrated by the UV radiation of gas-shielded welding operations?
Trichloroethylene and perchloroethylene prevent formation of phosgene gas, what materials should be kept out of atmospheres penetrated by the UV radiation of gas-shielded welding operations
States in the US with the highest concentrations of trichloroethylene include Pennsylvania and Illinois (TCE). In drinking water, there is a harmful pollutant called Trichloroethylene . The liquid is blue and has a chloroform-like smell. Consuming TCE can destroy your liver, kidneys, and cause cancer, thus it's not good for you. The chemical TCE is regarded as an environmental contaminant because it can be found in soil and air as well. 2) Determine the proportion of pressure from the total pressure that may be assigned to each individual gas by using the mole fraction of each gas.
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From the data in the table below, calculate the number of moles of N2 produced in a reaction. temperature 21.5 oC pressure 2.75 atm volume 110.0mL
The number of moles of N2 produced in the reaction is 3.69 moles. To calculate the number of moles of N2 produced in a reaction, we need to use the ideal gas law equation, PV = nRT.
In this equation, P represents pressure, V represents volume, n represents the number of moles, R represents the gas constant, and T represents temperature.
First, we need to convert the temperature to Kelvin by adding 273.15 to 21.5, which gives us 294.65 K.
Next, we need to convert the volume to litres by dividing 110.0 mL by 1000, which gives us 0.110 L.
Now we can plug in the values we have into the ideal gas law equation:
(2.75 atm)(0.110 L) = n(0.0821 L atm/K mol)(294.65 K)
Simplifying this equation, we get:
0.3025 = 0.0821n
To solve for n, we divide both sides by 0.0821:
n = 3.69 moles of N2
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