The concept that must be used to solve this problem is linked to Newton's laws of gravitation. Newton defined the gravitational attraction force as the product between the universal constant of gravitation, by the masses of each object, all this because of the change in the squared distance that separates them, mathematically it can be expressed as,
\(F_G = \frac{G m_1 m_2}{r^2}\)
Here,
G = Gravitational Universal Constant
\(m_{1,2}\) = Mass of each object
r = Radius
Our values are,
\(G = 6.67*10^{-11}N\cdot m^2/kg^2\)
\(m_1 = 300kg\)
\(m_2 = 140kg\)
\(r = 1.7m\)
Replacing,
\(F_G = \frac{(6.67*10^{-11}N\cdot m^2/kg^2 )(300kg)(140kg )}{(1.7m)^2}\)
\(F_G = 9.7*10^{-7} N\)
Can someone please help me with science.
How much useful energy is given out by an appliance supplied by 500 J and wastes
250 J?
Is the magnitude of the magnetic force experienced by proton 2 greater than, less than, or equal to the force experienced by proton 1? - greater than the force experienced by proton 1 - less than the force experienced by proton 1 - equal to the force experienced by proton 1
To determine the magnitude of the magnetic force experienced by proton 2 compared to proton 1, we need more information about the specific situation.
The magnetic force experienced by a charged particle depends on the strength of the magnetic field, the velocity of the particle, and the charge of the particle. Without knowing the specifics of these factors, it is impossible to determine the relative magnitude of the magnetic force experienced by proton 1 and proton 2. Therefore, the answer to the question is: we cannot determine whether the magnitude of the magnetic force experienced by proton 2 is greater than, less than, or equal to the force experienced by proton 1 without additional information.
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A simple harmonic wave of wavelength 18.7 cm and amplitude 2.34 cm is propagating in the negative x-direction at 38.0 cm/s.
Part A. Find its angular frequency.
Part B. Find its wave number.
Part C. Write a mathematical expression describing the displacement y of this wave (in centimeters) as a function of position x and time t measured in cantimeters and seconds, respectively. Assume the maximum displacement occurs at x = 0 when t = 0 .
a) Angular frequency is 12.75 rad/s b) The wave number is 33.59m c)
y ( x ,t) = 2.34 x sin(33.59 x - 12.75t)
Given,
wavelength = λ = 18.7 cm
= 0.187 m
amplitude , A = 2.34 cm
v = 0.38 m/s
A) angular frequency = ?
f = v/λ
f = 0.38/1.87 = 2.03
angular frequency ,
ω = 2π f
ω = 2π x 2.03
ω = 12.75 rad/s
B) the wave number,
K = 2π/λ = 33.59m
c) as the wave is propagating in -x direction, the sign is positive between x and t
y ( x ,t) = A sin(k x - ω t)
y ( x ,t) = 2.34 x sin(33.59 x - 12.75t)
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39
The Dominican Republic has 10.7 million people and a national population growth rate of 1.5 percent. Paraguay
has 6.8 million people and a national population growth rate of 1.5 percent. In how many years will each
country double in size?
47 years
37 years
27 years
57 years
Answer:
The correct answer is - 47 years.
Explanation:
The doubling time of the population growth depends on the rate of population growth. The formula for the calculation of the doubling time is :
time (t) = log(N/N0)/r (time)
here,
N0 (initial population) = The population at time t = 0.
N (future population) = The population at time t.
r (rate) = The rate of population change as a function of t
by the formula
t = log (2/1)/0.015
t = 46.666 years or 47 years approx.
The population of each country will become double in 47 years. hence option (A) is correct.
Given data:
The population of Dominican republic is, n = 10.7 million.
The growth rate of Dominican republic is, p = 1.5 %.
The population of Paraguay is, n' = 6.0 million.
The growth rate of Paraguay is, p' = 1.5 %.
The doubling time of the population growth depends on the rate of population growth. The formula for the calculation of the doubling time is given as,
\(t = \dfrac{ln\dfrac{n}{n_{0}}}{p}\)
Here,
\(n\) is the final population and \(n_{0}\) is the initial population and for doubling the value in future, \(n = 2 \times n_{0}\).
Solving as,
\(t = \dfrac{ln\dfrac{2\times n_{0}}{n_{0}}}{1.5/100}\\\\t \approx 47 \;\rm years\)
Thus, we can conclude the population of each country will become double in 47 years.
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Max attends a party and does not make eye contact with his acquaintance Sam. How does each view behavior?
Max attends a party and does not make eye contact with his acquaintance Sam therefore they view each other's behavior as the following:
Max: Not feeling well.Sam: socially awkwardWhat is Eye contact?This is a form of nonverbal communication and it occurs when two people look at each other's eyes at the same time.
In a scenario where Max attends a party and does not make eye contact with his acquaintance Sam then it will make the latter have a socially awkward of something not seeming right due to the feeling of him not being comfortable.
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How much electricity must flow through a light bulb to do 1 kWh of work? Mains voltage 220 V.
Given:
Energy = 1 kWh
Voltage = 220 Volts
Let's find the amount of electric current that must flow through the light bulb.
To find the amount of electric current, apply the formula:
\(P=IV\)Where:
P is the power in watts = 1 kWh = 1000 Watts
V is the voltage = 200 V
I is the electric current.
Rewrite the formula for I and solve:
\(\begin{gathered} I=\frac{P}{V} \\ \\ I=\frac{1000}{220} \\ \\ I=4.5\text{ A} \end{gathered}\)Therefore, the amount of electric current that must flow through the light bulb is 4.5 Ampere
ANSWER:
4.5 A
PLEASE HELPP I NEED TO PASS THIS !!
A roller coaster speeds up with constant acceleration for 2.3\,\text{s}2.3s2, point, 3, start text, s, end text until it reaches a velocity of 35\,\dfrac{\text{m}}{\text{s}}35
s
m
35, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction over 41\,\text{m}41m41, start text, m, end text. We want to find the initial velocity of the roller coaster before it started to accelerate.
Which kinematic formula would be most useful to solve for the target unknown?
Answer:
This one:
Explanation:
Khan academy answer
If 2.2 lbs = 1.0 kg, and Megan Progress weighs 130 lbs, what is her weight in newtons?
(F= ma). where acceleration due to gravity is 9.8 m/s2
Answer:
Force = 2802.8 Newton
Explanation:
Given the following data;
Mass = 130 lbs
But, 2.2 lbs = 1.0 kg
130 lbs to kg = 130 * 2.2 = 286 kg
Acceleration due to gravity = 9.8m/s²
To find the force in Newton;
Force = mass * acceleration due to gravity
Force = 286 * 9.8
Force = 2802.8 Newton
Laboratory experiments here on Earth have determined that each element in the periodic table emits photons only at certain wavelengths. These photons are apparent to astronomers as either emission or absorption lines in the spectrum of an astronomical object, like stars in galaxies. Astronomers can, by measuring the position of these spectral lines, determine which elements are present in the star itself or along the line of sight. When astronomers perform this analysis, they note that for most astronomical bodies, the observed spectral lines are all shifted to longer (redder) wavelengths. This is known as cosmological redshift and is analogous to the Doppler redshift. What does this redshift indicate to us about the universe in general?
A) The age of the universe.
B) The universe is expanding.
C) How much longer the universe should exist.
D) The universe is contracting into a black hole.
Answer: answer is B
Explanation:
14. Which of these is not a real penalty in Lacrosse
b) Interference
c) hooking
a) Roughing
d) Goal crease violation
Mr. Rosa’s student has a backpack with a density of 30g/mL. How much mass does the backpack have if it takes up 12.3 cm cubed of space?
Known:
Unknown:
Plug it in:
Answer:
Answer:
m = 369 grams
Explanation:
Given that,
The density of backpack, d = 30 g/mL
The volume of the backpack, V = 12.3 cm³
We need to find the mass of the backpack. The density of an object is given by :
\(d=\dfrac{m}{V}\\\\m=d\times V\\\\m=30\times 12.3\\\\m=369\ g\)
So, the mass of the backpack is 369 grams.
a 0.5 kg ball is moving horizontally with a speed of 6 m/s to the right when it strikes a vertical wall. the ball rebounds with a speed of 4 m/s. what is the magnitude of the change in linear momentum of the ball
The magnitude of the change in linear momentum of the ball is 2 kg•m/s to the left.
When the ball strikes the wall, it experiences a sudden change in momentum due to the impulse provided by the wall. Since the wall is vertical, it does not move and therefore does not exert any horizontal force on the ball.
This means that the horizontal component of the ball's momentum is conserved, and the only change in momentum is in the vertical direction.
Using the principle of conservation of momentum, the initial momentum of the ball in the horizontal direction is:
p₁ = m₁v₁ = (0.5 kg)(6 m/s) = 3 kg•m/s
The final momentum in the horizontal direction is the same as the initial momentum, since there are no external forces acting in that direction.
In the vertical direction, the initial momentum is:
p₁ = m₁v₁ = (0.5 kg)(6 m/s) = 3 kg•m/s
After rebounding, the ball is moving in the opposite direction, so its velocity is -4 m/s. Therefore, the final momentum in the vertical direction is:
p₂ = m₁v₂ = (0.5 kg)(-4 m/s) = -2 kg•m/s
The change in momentum is the difference between the final and initial momentum in the vertical direction:
Δp = p₂ - p₁ = (-2 kg•m/s) - (3 kg•m/s) = -5 kg•m/s
Since the question asks for the magnitude of the change in momentum, we take the absolute value, which gives:
|Δp| = |-5 kg•m/s| = 5 kg•m/s
However, the question asks for the direction of the change in momentum as well. Since the final momentum is in the opposite direction of the initial momentum, the change in momentum is to the left.
Therefore, change in linear momentum is 2 kg•m/s to the left.
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HELP PLEASE!!! I HAVE TO GET THIS IN QUICK!!
How would gravity cause planets to move if they did not have inertia?
A. Planets would orbit Jupiter, the largest planet
B. Planets would run into one another
C. Planets would be pulled into the sun
D. Planets would move in a straight line away from the sun
Answer: Planets would be pulled into the sun
Explanation:
This is the correct answer.
One forecasting model was used to forecast demand for a product. The forecasts and the demand are shown in the table below. B Actual Forecast 11 40 41 35 38 3 38 35 33 30 IX Calculate Moan Absolute Deviation (MAD) and Mean Squared Error (MSE). Show all details and use 1 decimal in your answer For the toolbar, press ALT+F10 (PC) or ALT+FN-F10 (Mac). BI V S Paragraph Arial 14px V QUESTION 1 The department manager is using a combination of methods to forecast sales of tonsters at a local department store. The demanders shown in the be Week Actu Demand 11 24 bo 2 bas x III A Using trend projection, calculate foresting values for week and week & Show details of your answer For the toolbar, pro ALT.F10 PC) O ALT.FN.F10 Mac BIS Paragraph Arial 14 Focus Chile we state
The estimated demand for Week 4 is 36.3
MAD(Mean Absolute Deviation) is used to calculate the average difference between forecast values and actual values. It calculates the deviation by taking the absolute value of the difference between actual and forecasted demand. The formula to calculate Mean Absolute Deviation is:
MAD= Sum of| Actual demand - Forecast demand | / number of periods
In the given table, the Actual demand is shown as B and the forecast demand is shown as F.
B Actual Forecast 11 40 41 35 38 3 38 35 33 30
Calculation of MAD:
Actual (B) Forecast (F) |B-F|11 40 29.041 35 5.043 38 0.053 3 35.054 38 3.055 35 0.056 33 3.057 30 3.058 0.0 30.0Total 103.0
The number of periods is 9 as shown in the table.
MAD= 103/9MAD= 11.44
Mean Squared Error (MSE) measures the average squared difference between the actual and forecasted values. The formula for MSE is:
MSE= Sum of (Actual demand - Forecast demand)^2 / number of periods.
Calculation of MSE:
Actual (B) Forecast (F) (B-F)^2 11 40 841 35 25 625 38 0 0 3 35 484 38 0 0 35 33 4 30 0 900Total 2854
The number of periods is 9 as shown in the table.
MSE= 2854/9MSE= 317.1
Therefore, the calculated MAD is 11.44 and MSE is 317.1.
Trend Projection formula is given by:
Y = a + bx
where Y is the estimated demand for a particular period.
a is the Y-intercept
b is the slope of the regression line x is the period number
In the given table, the Week number is shown as X and the Actual demand is shown as Y.
Week number Actual Demand 11 24 22 29
Using trend projection for Week 3, we can calculate the demand as follows:
Slope (b) = (nΣ(xy) - Σx Σy) / (nΣ(x^2) - (Σx)^2) =(2*22 - 1*24)/(2*3 - 1*1) = 20/5 = 4
Intercept (a) = Σy/n - b(Σx/n) =(24+22)/2 - 4(2/2) = 23Y = a + bx = 23 + 4(3) = 35
Therefore, the estimated demand for Week 3 is 35.
Using trend projection for Week 4, we can calculate the demand as follows:
Slope (b) = (nΣ(xy) - Σx Σy) / (nΣ(x^2) - (Σx)^2) =(2*29 - 1*24)/(2*5 - 1*1) = 34/9 = 3.78
Intercept (a) = Σy/n - b(Σx/n) =(24+22+29)/3 - 3.78(2.0) = 21.5Y = a + bx = 21.5 + 3.78(4) = 36.3
Therefore, the estimated demand for Week 4 is 36.3.
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In ptolemy’s earth-centered model for the solar system, venus always stays close to the sun in the sky and, because it always stays between earth and the sun, its phases range only between new and crescent. The following statements are all true and were all observed by galileo. Which one provides evidence that venus orbits the sun and not earth?.
Name the three basic types of carburetors as defined by airflow through the carburetor.
The three basic types of carburetors as defined by airflow through the carburetor are: updraft, downdraft, and sidedraft carburetors.
Carburetors are devices used in internal combustion engines to mix air and fuel in the correct proportions for efficient combustion. The three basic types of carburetors are determined by the direction of airflow through the carburetor. Updraft carburetors have the air and fuel mixture entering the engine from below, while downdraft carburetors have the air and fuel mixture entering from above.
Sidedraft carburetors have the air and fuel mixture entering from the side. Each type of carburetor has its own advantages and disadvantages, and the choice of carburetor depends on the specific application and engine requirements.
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True or false. Increasing the mass attached to a spring will decrease the period of its vibrations. Thank you!
False. Increasing the mass attached to a spring will decrease the period of its vibrations.
what is vibrations ?
Vibrations are oscillations in physical systems that happen in the form of kinetic energy being transferred from one point to another. They are caused by a variety of factors, including sound waves, mechanical forces, and electrical currents. Vibrations can produce both audible and inaudible sound, and can be felt as a physical sensation.
Vibrations travel through materials and can be measured using a variety of devices such as accelerometers and vibration meters. In machines and structures, vibrations can indicate the level of stress or strain on components and are used to monitor the health and performance of the system. Vibrations can cause unwanted noise and wear on components, and can be prevented by damping or isolation.
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what is the moment of inertia for a disk with mass of 500g and radius of 12 cm rotated about its diameter? group of answer choices
The moment of inertia for a disk with mass of 500g and radius of 12cm rotated about its diameter is 7.2 × 10-³kgm².
How to calculate moment of inertia?Moment of inertia is a measure of a rigid body's resistance to change in its angular velocity around a given axis.
The formula for the moment of inertia is the “sum of the product of mass” of each particle with the “square of its distance from the axis of the rotation”. The formula of Moment of Inertia is expressed as follows:
I = mr²
Where;
I = moment of inertiam = mass r = radiusAccording to this question, a disk with mass of 500g and radius of 12 cm rotated about its diameter. The moment of inertia can be calculated as follows:
I = 0.5kg × 0.12²m
I = 7.2 × 10-³kgm²
Therefore, 7.2 × 10-³kgm² is the moment of inertia of the disk.
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which event is part of a convince part of a current in the air
A. warm air sinks
B. cool air rises
C. warm air swirls
D. cool air sinks
Answer:
D
Explanation:
Cool air sinks because it's denser and warm rises because it's less dense.
This is the principle you have in your air conditioning.
As the air is cooled it keeps falling that's why it's necessary to tilt the vents of of an AC at 45° so that the cold air would be well circulated.
a 21.6 gram arrow is shot through a 7.5 cm apple. if the arrow enters the apple at 35.5 m/s and emerges with a speed of 25.3 m/s in the same direction, what is the magnitude of the force with which the apple has resisted the arrow? (assume force is exerted only on the tip of the arrow)
The magnitude of the force with which the apple has resisted the arrow is 88.06 Newton.
Using, work-energy theorem,
According to which, the work done by the all the forces on the body is equal to the change in kinetic energy of the body.
So, we can write,
Work done = ∆KE
We know,
Work done = force × displacement
The force is the resistive force by the apple and the displayed is given to be 0.075 meters.
So, we can write,
F(0.075) = 1/2M(V²-U²)
Where,
M is the mass of apple,
V is final velocity,
U is initial velocity.
Putting all the values,
F(0.075) = 1/2(0.0213)((25.3)²-(35.5)²)
Solving further,
F = 88.06 Newton
The resistive force of the apple is 88.06 Newton.
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The electric field strength at one point near a point charge is 1000 n/c. what is the field strength in n/c if (a) the distance from the point charge is doubled?
If the distance from a point charge is doubled, the electric field strength at that point decreases by a factor of 4. Thus, the new field strength in N/C can be calculated using this relationship.
The electric field strength (E) at a point near a point charge is inversely proportional to the square of the distance (r) from the charge. Mathematically, E ∝ 1/\(r{2}\)\(r^{2}\)
When the distance from the point charge is doubled, the new distance becomes 2r. Substituting this into the relationship, we have E' ∝ 1/(2r)\(^{2}\) = 1/(4r^2). From this, we can see that the new electric field strength (E') is equal to the original field strength (E) divided by 4.
Given that the original electric field strength is 1000 N/C, we can calculate the new field strength as follows: E' = E / 4 = 1000 N/C / 4 = 250 N/C.
Therefore, if the distance from the point charge is doubled, the new electric field strength would be 250 N/C.
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What depth of oil, specific gravity of 0.750, will produce a pressure of 46 psig?
The depth of oil is 43 m
We know that
P = ρ g h
where,
P = Pressure of fluid
ρ = Density of fluid
g = Acceleration due to gravity
h = Depth of fluid
Given that,
P = 46 psig = 3.2 * \(10^{5}\) N / \(m^{2}\)
s = 0.75
ρ = 0.75 * 1000 = 750 kg / \(m^{3}\)
g = 9.81 m / \(s^{2}\)
Here we round the value of g = 10 m / \(s^{2}\)
h = P / ρ g
h = ( 3.2 * \(10^{5}\) ) / ( 750 * 10 ) = 42.67 m
h = 43 m
Fluid pressure is the measurement of force per unit area that acts on an object in the fluid.
Therefore, the depth of oil is 43 m
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a styrofoam sphere of radius r has a density rho. you now carefully compress the sphere so its radius is r/2. what is the density of the compressed sphere?
The density of the compressed sphere is 8 times the original density.
The initial volume of the styrofoam sphere is
V1 = (4/3)πr³, and its mass is M = ρV1.
After compressing the sphere, its new radius is r/2, and its new volume is
V2 = (4/3)π(r/2)³.
The mass remains constant during compression.
To find the density of the compressed sphere (ρ'), use the formula ρ' = M/V2.
Since M = ρV1, we have ρ' = (ρV1)/V2.
Substituting the volume equations and simplifying, we get ρ' = 8ρ.
The density of the compressed sphere is 8 times the original density.
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a battery is rated at 12 v and 160 a-h. how much energy does the battery store? select one: a. 3.2 kj b. 1.9 kj c. 1.9 mj d. 6.0 kj e. 6.9 mj
The battery stores 6.9 MJ (megajoules) of energy. To calculate this, multiply the voltage of 12 V by the Amp-hour rating of 160 A-h. The result is 1920 watt-hours (12 V x 160 A-h = 1920 Wh). Since 1 Wh = 0.0036 MJ, the total energy stored is 1920 x 0.0036 MJ = 6.9 MJ. Answer is option e
The energy stored in a battery can be calculated by multiplying the battery's voltage (V) by its capacity in ampere-hours (Ah). In this case, the battery is rated at 12 V and 160 Ah, so the energy stored can be calculated as:
Energy (in Joules) = Voltage (in Volts) x Capacity (in Ampere-hours) x 3600 seconds
Where 3600 seconds is the number of seconds in an hour. Plugging in the given values, we get:
Energy = 12 V x 160 Ah x 3600 seconds
Energy = 6,912,000 Joules
To convert Joules to other units, we can use the following conversion factors:
1 Joule = 0.001 kilojoules (kJ)
1 Joule = 1 x 10^-6 megajoules (MJ)
Therefore, the energy stored in the battery is 6,912,000 Joules, which is equivalent to 6.9 MJ
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can someone help me with a)
Answer:
what's your problem. How may I help you Buddy
After landing on Mars, you drop a marker from the door of your landing module and observe that it takes 2.1 ss to fall to the ground. When you dropped the marker from the module door on Earth, it took 1.3 ss to hit the ground.What is the magnitude of the acceleration due to gravity near the surface of Mars?Express your answer with the appropriate units.
Answer:
Approximately \(3.43\; {\rm m\cdot s^{-2}}\), assuming that air resistance is negligible in both occasions, and that \(g_{\text{earth}} = 9.81\; {\rm m\cdot s^{-2}}\) near the surface of the Earth.
Explanation:
Let \(x\) denote the displacement of the marker. Let \(a\) denote the acceleration of the marker. Let \(t\) denote the time it takes for the marker to reach the ground.
Under the assumptions, acceleration of the marker would be constant, and the SUVAT equations would apply. Rearrange the SUVAT equation \(x = (1/2)\, a\, t^{2}\) to find acceleration \(a\):
\(\begin{aligned}a &= \frac{2\, x}{t^{2}}\end{aligned}\).
Let \(a_{\text{Mars}}\) and \(t_{\text{Mars}}\) denote the acceleration and time taken on Mars. Similarly, let \(a_{\text{Earth}}\) and \(t_{\text{Earth}}\) denote the acceleration and time taken on Earth. It is implied that the Marker travelled the same distance (same displacement, \(x\)) both on Earth and on Mars.
Using the SUVAT equation from above:
\(\begin{aligned}a_{\text{Mars}} &= \frac{2\, x}{{t_{\text{Mars}}}^{2}}\end{aligned}\).
\(\begin{aligned}a_{\text{Earth}} &= \frac{2\, x}{{t_{\text{Earth}}}^{2}}\end{aligned}\).
\(\begin{aligned}\frac{a_{\text{Mars}}}{a_{\text{Earth}}} &= \frac{\displaystyle \frac{2\, x}{{{t_{\text{Mars}}}^{2}}}}{\displaystyle \frac{2\, x}{{{t_{\text{Earth}}}^{2}}}} \end{aligned}\).
\(\begin{aligned}\frac{a_{\text{Mars}}}{a_{\text{Earth}}} &= \left(\frac{{t_{\text{Earth}}}}{{t_{\text{Mars}}}}\right)^{2}\end{aligned}\).
\(\begin{aligned}a_{\text{Mars}} &= \left(\frac{{t_{\text{Earth}}}}{{t_{\text{Mars}}}}\right)^{2}\, a_{\text{Earth}} \\ &= \left(\frac{1.3\; {\rm s}}{2.2\; {\rm s}}\right)^{2}\, (9.81\; {\rm m\cdot s^{-2}}) \\ &\approx 3.43\; {\rm m\cdot s^{-2}}\end{aligned}\).
A steel ball of mass 50 g is rolled from the left toward a ball of lead of mass 500 g. The steel ball is traveling with a velocity of 5 m/s. If no external forces act on either of the interacting bodies, then what will be the direction of the momentum of the steel ball after the head-on collision?
A) from left to right as it started off
B) from right to left, making a 180° reversal
C) at an angle of 90° to the initial direction of motion
D) at an angle of 270° to the initial direction of motion
The direction of momentum of the steel ball after the head-on collision with the lead ball can be determined using the law of conservation of momentum, which states that the total momentum of an isolated system remains constant if no external forces act on it.
The collision, the initial momentum of the steel ball can be calculated as the product of its mass (50 g) and velocity (5 m/s), which is 250 g m/s. The lead ball, being at rest, has an initial momentum of zero. After the collision, the two balls will stick together and move as a single object due to their deformation and interlocking of their surfaces. The total mass of the combined object will be 550 g. Using the law of conservation of momentum, the total momentum of the system after the collision will be equal to the initial momentum, which is 250 g m/s. Since the lead ball is much heavier than the steel ball, it will not move much and most of the momentum will be carried by the steel ball. Therefore, the direction of momentum of the steel ball after the collision will be in the opposite direction to its initial motion, which is from right to left, making a 180° reversal. Therefore, the correct answer is B.
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