To solve the first-order linear differential equation dy/dx + 2y = x² + 2x, we can use an integrating factor. Multiplying the equation by the integrating factor e^(2x), we obtain (e^(2x)y)' = (x² + 2x)e^(2x). Integrating both sides, we find the solution y = (1/4)x³e^(-2x) + (1/2)x²e^(-2x) + C*e^(-2x), where C is the constant of integration.
For the exact differential equation (1 - x²y)dx + x²(y - x)dy = 0, we determine that it is exact by checking that the partial derivatives are equal. Integrating the terms individually, we have x - (1/3)x³y + g(y), where g(y) is the constant of integration with respect to y. Equating the partial derivative of g(y) with respect to y to the remaining term x²(y - x)dy, we find that g(y) is a constant. Hence, the general solution is given by x - (1/3)x³y + C = 0, where C is the constant of integration.
For the first-order linear differential equation dy/dx + 2y = x² + 2x, we multiply the equation by the integrating factor e^(2x) to simplify it. This allows us to rewrite the equation as (e^(2x)y)' = (x² + 2x)e^(2x). By integrating both sides, we obtain the solution for y in terms of x and a constant of integration C.
In the case of the exact differential equation (1 - x²y)dx + x²(y - x)dy = 0, we check the equality of the partial derivatives to determine its exactness. After confirming that the equation is exact, we integrate the terms individually with respect to their corresponding variables. This leads us to a solution that includes a constant of integration g(y). By equating the partial derivative of g(y) with respect to y to the remaining term, we determine that g(y) is a constant. Consequently, we express the general solution in terms of x, y, and the constant of integration C.
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To solve the first-order linear differential equation dy/dx + 2y = x² + 2x, we can use an integrating factor. In the case of the exact differential equation (1 - x²y)dx + x²(y - x)dy = 0, we check the equality of the partial derivatives to determine its exactness.
Multiplying the equation by the integrating factor e^(2x), we obtain (e^(2x)y)' = (x² + 2x)e^(2x). Integrating both sides, we find the solution y = (1/4)x³e^(-2x) + (1/2)x²e^(-2x) + C*e^(-2x), where C is the constant of integration.
For the exact differential equation (1 - x²y)dx + x²(y - x)dy = 0, we determine that it is exact by checking that the partial derivatives are equal. Integrating the terms individually, we have x - (1/3)x³y + g(y), where g(y) is the constant of integration with respect to y. Equating the partial derivative of g(y) with respect to y to the remaining term x²(y - x)dy, we find that g(y) is a constant. Hence, the general solution is given by x - (1/3)x³y + C = 0, where C is the constant of integration.
For the first-order linear differential equation dy/dx + 2y = x² + 2x, we multiply the equation by the integrating factor e^(2x) to simplify it. This allows us to rewrite the equation as (e^(2x)y)' = (x² + 2x)e^(2x). By integrating both sides, we obtain the solution for y in terms of x and a constant of integration C.
In the case of the exact differential equation (1 - x²y)dx + x²(y - x)dy = 0, we check the equality of the partial derivatives to determine its exactness. After confirming that the equation is exact, we integrate the terms individually with respect to their corresponding variables. This leads us to a solution that includes a constant of integration g(y). By equating the partial derivative of g(y) with respect to y to the remaining term, we determine that g(y) is a constant. Consequently, we express the general solution in terms of x, y, and the constant of integration C.
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the dimensions of col a and nul a add up to the number of columns in a.
a. true
b. false
Using Rank theorem , the dimensions of col A and Null A add up to the number of colmns in A. It is true statement.
The rank of matrix A denoted as rank(A) is the dimension of the column space Col(A).
The nullity of matrix A written as nullity(A) is the dimension of the null space Nul(A)
Rank Theorem:
If A is a matrix with n columns, then
Rank (A) + nullity (A) = n
In other words we can say that
dim (Col(A) ) in column space + dim (Nul(A)) in empty space = total number of columns in A
The rank theorem is really important theorem.
It is gives a strong relationship between the Null space ( all possible vector x such that Ax = 0) and the column space (the set of vectors b matching Ax=b) explain the two main objectives. The more freedom we have for choosing x, the less freedom we have for choosing b, and vice versa.
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please help, I'm stuck
Answer:
Step-by-step explanation:
4
plz solve this question urgent
9514 1404 393
Answer:
2/15
Step-by-step explanation:
The given expression for θ can be rewritten to ...
5sin(θ + arctan(-3/4)) = 0
This will have solutions ...
θ +arctan(-3/4) = nπ
θ = nπ - arctan(-3/4) = nπ + arctan(3/4)
__
The corresponding values of sine and cosine will be ...
sin(arctan(3/4)) = 3/5
cos(arctan(3/4) = 4/5
or both values may be negative. Either sign will give the same result in the expression we're to find.
(2sin(θ) -cos(θ))/(sin(θ) +3cos(θ)) = (2(3/5) -(4/5))/(3/5 +3(4/5))
= ((6 -4)/5)/((3+12)/5) = 2/15
\(\boxed{\dfrac{2\sin\theta-\cos\theta}{\sin\theta+3\cos\theta}=\dfrac{2}{15}}\)
Susan had four bags of candy, each weighing 6 ounces. Isabel had one bag of candy weighing 1 pounds. Which girl has the more candy in weight? Your work will justify your answer.
Susan has more candy in weight compared to Isabel.
To compare the candy weights between Susan and Isabel, we need to ensure that both weights are in the same unit of measurement. Let's convert Isabel's candy weight to ounces for a fair comparison.
Given:
Susan: 4 bags x 6 ounces/bag = 24 ounces
Isabel: 1 bag x 16 ounces/pound = 16 ounces
Now that both weights are in ounces, we can see that Susan has 24 ounces of candy, while Isabel has 16 ounces of candy. As a result, Susan is heavier on the candy scale than Isabel.
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Name 3 biotic factors in a marine ecosystem
Answer:
Biotic factors of a marine ecosystem typically include algae, plankton, bacteria, seaweed, corals, fish, sharks, seals, whales, penguins and jellyfish.
Step-by-step explanation:
i hope this answer helped
Thanks for choosing brainly
Compare the values.
9 x 10^2 is
?
times as much as 3 x 10^-2.
Answer:
Hopefully this explains o_O, also Merry Christmas!
Step-by-step explanation:
9 x 10^2 = 9 x 100 = 900
3 x 10^-2 = 3 x 1/100 = 0.03
Ratio of 900:0.03
The first one is 30000 bigger than the second
The question is on the fill
Answer:
Your mom is annoying
Step-by-step explanation:
She keeps calling me even though its over.
Similar to 3.4.2 in Rogawski Adams Find the ROC of the volume of a cube with respect to the length of its side s when 8 = 3 d/ds (volume)|s=3 = _____ cubic units per unit increase of side length.
The ROC of the volume of a cube with respect to the length of its side is s > 0. The given rate of change of volume with respect to side length does not affect the calculation of ROC.
The volume of cube is given by V = s^3, where s is the length of its side.
Taking the derivative of V with respect to s, we get:
dV/ds = 3s^2
The rate of change of volume with respect to the length of the side s is given as:
dV/ds = 8
Substituting the value of dV/ds and solving for s, we get:
8 = 3s^2
s^2 = 8/3
s = ±√(8/3)
Since the length of side of a cube cannot be negative, we take the positive root:
s = √(8/3)
The radius of convergence (ROC) of the volume is s > 0, which means the series expansion of the volume of the cube in terms of the length of its side converges for values of s greater than zero.
Therefore, the ROC is s > 0.
The rate of change of volume does not affect the change in the calculation of ROC.
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Sketch the region bounded by the graphs of the functions, and find the area of the region. Using ordered pair form, label all points of intersection on your graph. f(y)=y 2
,g(y)=y+2
According to the question the function over the interval \(\([-1, 2]\)\) to find the area of the region.
1. Find the points of intersection by setting \(\(f(y) = g(y)\)\) and solving for \(\(y\)\).
\(\(y^2 = y + 2\)\)
Rearranging, we get \(\(y^2 - y - 2 = 0\)\)
Factoring, we have \(\((y - 2)(y + 1) = 0\)\)
So the points of intersection are \(\(y = 2\) and \(y = -1\).\)
2. Sketch the graphs of the functions \(\(f(y) = y^2\) and \(g(y) = y + 2\)\) on a coordinate plane.
3. Shade the region bounded by the two graphs between the points of intersection.
4. Calculate the area of the shaded region using definite integration:
\(\(\text{Area} = \int_{-1}^{2} (f(y) - g(y)) \, dy\)\)
To evaluate the integral and find the area of the region between the graphs of \(\(f(y) = y^2\) and \(g(y) = y + 2\)\), we need to integrate the difference between the two functions over the given interval.
The interval of integration is \(\([-1, 2]\)\), which corresponds to the points of intersection.
Using definite integration, we have:
\(\(\text{Area} = \int_{-1}^{2} (f(y) - g(y)) \, dy = \int_{-1}^{2} (y^2 - (y + 2)) \, dy\)\)
Simplifying the integrand, we get:
\(\(\text{Area} = \int_{-1}^{2} (y^2 - y - 2) \, dy\)\)
Now, integrate the function over the interval \(\([-1, 2]\)\) to find the area of the region.
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Help me pleasee I will give brainlst
Answer:
d) The angles are not equal. The sides of one of the triangles changed, thereby changing its area.
Explanation:
If you look at figure 2, the triangle on top decreased in size.
The cuboid below has a height of 42 mm
and a width of 8 mm. It has a volume of
3
5376 mm³.
What is the length of the cuboid?
Remember to give the correct units, and
give any decimal answers to 1 d.p
The length of the cuboid is 16 mm
In this question, we have been given a cuboid having height of 42 mm
and a width of 8 mm.
Also, the volume of the cuboid is 5376 mm³.
We know that, the volume of the cuboid is V = length × width × height
Here, width = 8 mm
height = 42 mm
V = 5376 mm³
We need to find the length of the cuboid.
V = length × width × height
5376 = length × 8 × 42
length = 5376 / 336
length = 16 mm
Therefore, the length of the cuboid is 16 mm
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one more question till im done! how do I figure this out
Answer:
13
Step-by-step explanation:
5^2+8^2= c^2
25+64=c^2
89=c^2
c=9.4
9.4^2+9^2=c^2
c=170
c=13
If A and B are nonsingular matrices, then use the rules of linear algebra to solve for X. You MUST simplify the final result as much as possible (You will be graded on your work, not the answer.): ((2 B)-¹ XT - 4 1)¹ = 4B, X=
The equation is solved for X as;
X = (4(I + 2B)⁻¹)T
How to solve for the variableFirst, we need to know that the determinant of non-singular matrices is non-zero, permitting them to be inverted
Multiply both sides of the equation with (2B)⁻¹, we have;
XT - 4(2B)^-1 = 4B(2B)⁻¹
Factor the terms, we get;
XT - 4(2B)⁻¹ = 4I
collect all the other term on the other side of the equation;
XT = 4I + 4(2B)⁻¹
XT = 4(I + 2B)⁻¹
Now, multiply both sides by the inverse of A, we have;
X = (4(I + 2B)⁻¹)T
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both methods requires two initial guesses x1 and x2, and it is necessary that f(x1)*f(x2) < 0
The requirement f(x1) * f(x2) < 0 for choosing initial guesses x1 and x2 with opposite signs ensures the validity and convergence of certain numerical root-finding methods such as the bisection method or the regula falsi method.
The statement you provided is true for certain numerical methods used to find roots of equations, such as the bisection method or the regula falsi method. These methods are iterative and require an initial interval or range where the root is expected to be found. To ensure convergence and a valid solution, it is necessary to choose initial guesses x1 and x2 such that the function f(x) evaluated at those points have opposite signs, i.e., f(x1) * f(x2) < 0.
The rationale behind this requirement is based on the Intermediate Value Theorem, which states that if a continuous function f(x) changes sign over an interval [x1, x2], then there exists at least one root within that interval. By ensuring that f(x1) and f(x2) have opposite signs, we guarantee the existence of a root within the interval [x1, x2].
The bisection method works by repeatedly bisecting the interval and selecting a new subinterval that contains the root. At each iteration, the method narrows down the interval by halving it, based on the sign change observed in the function evaluations.
Similarly, the regula falsi (or false position) method also operates by iteratively refining the interval based on the linear interpolation between the function values at the endpoints. The method adjusts the interval based on the sign change of the function, converging to the root.
Both methods rely on the property of opposite signs to guarantee convergence and avoid getting stuck in a non-converging or incorrect solution. If the initial guesses do not satisfy the condition f(x1) * f(x2) < 0, it is possible that the method fails to converge or converges to a different root or solution.
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Help lssshjwejjwkwkwwkk
61 matchsticks need to make 20 squares.
Given,
From the figure,
Matchsticks are used to make the pattern.
To make these 4 squares, you need 13 matchsticks.
To find the how many matchsticks do you need to make 20 squares?
Now, According to the question:
Let the need matchsticks be 'n'
The number of the squares to make 1 square , you need 4 matchsticks,
and when you need to add one square, you need three more matchsticks .
So , we have to make n no. of squares you need
4 + 3(n - 1) matchsticks (n \(\geq\) )
= 4 + 3n - 3
= 1 + 3n
When, n = 20
1 + 3 x 20
= 61
Hence, 61 matchsticks need to make 20 squares.
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A small publishing company is releasing a new book. The production costs will include a one-time fixed cost for editing and an additional cost for each book
printed. The total production cost C (in dollars) is given by the function C = 18. 95N+750, where N is the number of books.
The total revenue earned (in dollars) from selling the books is given by the function R = 34. 60N.
Let P be the profit made (in dollars). Write an equation relating P to N. Simplify your answer as much as possible
If The total revenue earned (in dollars) from selling the books is given by the function R-34.60N. the equation relating P to N is P = 18.95N - 750.
Profit made (P) can be calculated by subtracting the total production cost (C) from the total revenue earned (R), so:
P = R - C
P = 34.60N - (18.95N + 750)
P = 34.60N - 18.95N - 750
P = 15.65N - 750
Therefore, the equation relating P to N is P = 18.95N - 750.
The equation shows that the profit made by the company is a linear function of the number of books printed. The slope of the line is the revenue per book (34.60 dollars), minus the cost per book (18.95 dollars), which is 18.95 dollars.
The intercept of the line is the fixed cost for editing (750 dollars). The equation can be used to estimate the profit for any given number of books printed, and to determine the break-even point, which is the number of books that need to be sold to cover the total production cost.
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compute the critical value za/2 that corresponds to a 83% level of confidence
The critical value zₐ/₂ that corresponds to an 83% level of confidence is approximately 1.381.
To find the critical value zₐ/₂, we need to determine the value that leaves an area of (1 - α)/2 in the tails of the standard normal distribution. In this case, α is the complement of the confidence level, which is 1 - 0.83 = 0.17. Dividing this value by 2 gives us 0.17/2 = 0.085.
To find the z-value that corresponds to an area of 0.085 in the tails of the standard normal distribution, we can use a standard normal distribution table or a statistical calculator. The corresponding z-value is approximately 1.381.
Therefore, the critical value zₐ/₂ that corresponds to an 83% level of confidence is approximately 1.381.
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Hotel P offer two type of room for it cutomer: a Deluxe room and a Suite room. The price per night for the uite room for check-in on Sunday until Thurday i 70% higher than the price per night for a Deluxe room for the exact check-in period. The price per night for the Deluxe room for check-in on Friday and Saturday i 25% higher than for price per night for the Deluxe room for check-in on Sunday until Thurday. If the hotel management want to maintain the price difference between the two type of pace, and the price per night for a Suite room for check-in on Sunday until Thurday i $223, what hould be the price per night for a Suite room for check-in on Friday and Saturday?
The price per night for a Suite room for check-in on Friday and Saturday would be amount $278.50 .
The price per night for a Suite room for check-in on Friday and Saturday would be amount $278.50.
1. Calculate the price of a Deluxe room for check-in on Sunday until Thursday:
$223 / 1.70 = $131.18
2. Calculate the price of a Deluxe room for check-in on Friday and Saturday:
$131.18 x 1.25 = $163.98
3. Calculate the price of a Suite room for check-in on Friday and Saturday:
$163.98 x 1.70 = $278.50
The price per night for a Suite room for check-in on Friday and Saturday would be $278.50.
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The price of a litre of milk increased from $1.25 in 2004 to $1.35 in 2006. What is the average price increase per year?
Answer:
$0.05/year
Step-by-step explanation:
Number of years:
2006 - 2004 = 2
From 2004 to 2006 it's 2 years.
Difference in prices:
$1.35 - $1.25 = $0.10
Average change of price per year:
$0.10 / 2 years = $0.05/year
The equation of a parabola is y=2x^2 +8x +3
Write the equation in vertex form and show your work.
Answer: y = 2(x + 2)² - 5
Step-by-step explanation:
We are going to use the completing the square method to transform this quadratic equation from standard form to vertex form.
Given:
y = 2x² + 8x + 3
Factor the 2 out of the first two terms:
y = 2(x² + 4x) + 3
Add and subtract \(\frac{b}{2} ^2\):
y = 2(x² + 4x + 4 - 4) + 3
Distribute the 2 into -4 and combine with the 3:
y = 2(x² + 4x + 4) - 5
Factor (x² + 4x + 4):
y = 2(x + 2)² - 5
A 300-N force acts on a 25-kg object. the acceleration of the object is ___.
here’s the choices
1) 7,500 m/s2
2) 300 m/s2
3) 25 m/s2
4) 12 m/s2
****Please hurry, if i get this incorrect i get kicked off my softball team**
An office supply company ordered 24 cartons of specialty paper. The regular price for a carton of specialty paper is $6.88. They received a discount of $1.75 off each carton. About how much money will the office supply company need to pay for the paper? Which of the expressions gives a reasonable estimate of the answer? A. $5 × 25 B. $6 × 25 C. $7 × 20 D. $9 × 30
Answer: A. $5 × 25
Step-by-step explanation:
Given the following :
Number of cartons of specialty paper ordered = 24 cartons
Regular price for a carton = $6.88
Discount given off each carton = $1.75
Hence,
Discounted price per carton = $(6.88 - 1.75) = $5.13
Actual amount to be paid for the order :
Discounted price * number of cartons to be ordered
$5.13 * 24
Hence, a reasonable estimate will be :
$5.13 = $5( nearest whole number)
24 can be rounded to 25 (this covers for the $0.13 on the discounted cost per carton)
Reasonable estimate :
$5 × 25
Answer:
The answer is A. $5 × 25
Step-by-step explanation:
Given that the total number of cartons is 24
the price per carton originally is $6.88
the discount is $1.75
hence the company will have to pay 6.88-1.75= $5.13
hence the price per carton upon removal of the discount is $5.13
for all 24 cartons, the company will have to pay 24*5.13
A reasonable estimate from the given option is
A. $5 × 25
Three friends go to a store to rent games and movies.
Calvin rents 3 movies and 2 video games and spends a
total of $25. Samantha rents 2 movies and 1 video game
and spends a total of $14.75.
Answer:
Let x = the cost of a movie
Let y = the cost of a game
Using these variables, we can set up equations.
3x + 5y = 42 eq1
9x + 7y = 72 eq2
We have here a system of equations, where we have two or more equations with two or more different variables. We use the elimination method to solve for the variables.
Multiply eq1 by 3. Keep eq2.
9x + 15y = 126 eq1
9x + 7y = 72 eq2
Subtract eq2 from eq1 to eliminate the x terms.
8y = 54
y = 6.75
This rental cost of one video game is $6.7
Substitute the value of y into eq1 to solve for x. This will give you the rental cost of one movie.
Step-by-step explanation:
pa brainly po
The cost of movie is $4.5 and cost of video game is $5.75.
What is Equation?Two or more expressions with an Equal sign is called as Equation.
Let x be the cost of movie and y be the cost of video game
Calvin rents 3 movies and 2 video games and spends a total of $25.
3x+2y=25...(1)
Samantha rents 2 movies and 1 video game and spends a total of $14.75.
2x+y=14.75
y=14.75-2x..(2)
Substitute (2) in equation (1)
3x+2(14.75-2x)=25
3x+29.5 -4x=25
-x+29.5 = 25
Subtract 29.5 from both sides
-x=25-29.5
x=4.5
Now let us plug in x value in equation (2)
y=14.75-2(4.5)
y=5.75
Hence, the cost of movie is $4.5 and cost of video game is $5.75.
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the sum of independent normally distributed random variables is normally distributed with mean equal to the sum of the individual means and variance equal to the sum of the individual variances. if x is the sum of three independent normally distributed random variables with respective means 100, 150, and 200 and respective standard deviations 15, 20, and 25, the probability that x is between 420 and 460 is closest to which of the following?
The probability that x is between 420 and 460 is 0.25778
The sum of independent normally distributed random variables is normally distributed with mean equal to the sum of the individual means and variance equal to the sum of the individual variances.
so, the mean would be,
μ = 100 + 150 + 200
μ = 450
and standard deviation would be,
σ = 15+ 20 + 25
σ = 60
We need to find the probability that x is between 420 and 460.
P(420 < x < 460)
= P( 420 - μ < x - μ < 460 - μ)
= P((420 - μ)/σ < (x - μ)/σ < (460 - μ)/σ)
= P((420 - 450)/60 < Z < (460 - 450)/60)
= P (-1/2 < Z < 1/6)
= P(-0.5<x<0.167)
= 0.25778
Therefore, the probability is P(420 < x < 460) = 0.25778
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Can y’all help me answer these questions
Expand each expression In 4y5/x2
Answer:
\(\ln 4 -2 \ln x +5 \ln y\)
Step-by-step explanation:
\(\ln \dfrac{4y^5}{x^2}\\\\=\ln(4y^5) - \ln(x^2)~~~~~~~~~~~;\left[ \log_b\left( \dfrac mn \right) = \log_b m - \llog_b n \right]\\\\=\ln 4 + \ln y^5 - 2\ln x~~~~~~~~~~~~;[\log_b m^n = n \log_b m ~\text{and}~\log_b(mn) = \log_b m + \log_b n ]\\\\=\ln 4 + 5 \ln y -2 \ln x\\\\=\ln 4 -2 \ln x +5 \ln y\)
Answer: Answer B
Step-by-step explanation: Let's begin
Answer: B in 4 - 2 in x + 5 in y
\(\huge\text{\bold{Question:}}\)
Could anyone please help me with my homework? Thanks in advance! :)
\(\huge\bold{(x+2)^{3} }\)
No spam.
Solution:
Before you solve this question, remember this identity of the cube of a binomial.\((a + b) ^{3} = {a}^{3} + {b}^{3} + 3ab(a + b) \\ \)
Here, we have to find the cube of (x + 2).Replacing a by x and b by 2 in the above identity, we have\((x + 2) ^{3} \\ = {(x)}^{3} + (2) ^{3} + 3 \times x \times 2(x + 2) \\ = {x}^{3} + 8 + 6x(x + 2) \\ = {x}^{3} + 8 + 6x \times x + 6x \times 2 \\ = {x}^{3} + 8 + {6x}^{2} + 12x\)
Now, arrange the above expression in standard form.\( = {x}^{3} + {6x}^{2} + 12x + 8 \\ \)
Answer:
\({x}^{3} + {6x}^{2} + 12x + 8\)
Hope you could understand.
If you have any query, feel free to ask.
Given:
\((x + 2)^{3} \)
Now using algebraic identities,
\( {x}^{3} + 3(x)^{2} + 3(x)(2)^{2} + {2}^{3}\)
\( = > {x}^{3} + 3(x)^{2} + 3(x)(2)^{2} +8\)
\( = > {x}^{3} + 6x^{2} +12x +8\)
~ Benjemin360
Evaluate 1/4x+ 1/20 when x =1/5
Answer:
1/10
0.1
Step-by-step explanation:
Orpheus needs a new cat lounge. The pet store has one in stock that Orpheus likes for $33. The local sales tax rate is 4.25% where Orpheus lives. The store is running a clearance event on cat furniture with discounts of forty percent off.
Answer:
$20.64
Step-by-step explanation:
When you take 40% of 33, you are left with 19.8. You then translate the sales tax into 84 cents and add it to 19.8. That will give you $20.64 as the after tax price.
market classes and grades encompass descriptive terminology of carcasses and products for the understanding of different groups or buyers.
Market classes and grades are used to describe the quality and characteristics of agricultural products, including meat, poultry, fruits, and vegetables. True
They provide a common language for buyers and sellers to communicate about the characteristics, such as the age, sex, fat content, and muscling, of the product. Market classes and grades help ensure that buyers receive products that meet their quality standards and help sellers receive a fair price for their products. For example, beef is graded based on marbling, maturity, and lean color, with the highest grade being USDA Prime, followed by USDA Choice and USDA Select.
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Full Question: market classes and grades encompass descriptive terminology of carcasses and products for the understanding of different groups or buyers. T/F
This standardized system of classification allows for easier communication and understanding between buyers and sellers, and ensures consistency and fairness in the marketplace.
Market classes and grades refer to the categorization and labeling of carcasses and products based on their quality and characteristics. These classifications use descriptive terminology that is understood by different groups of buyers, such as meat packers, wholesalers, retailers, and consumers. Market classes typically group animals based on their intended use, such as beef cattle for slaughter, while grades are assigned based on factors such as maturity, marbling, and fat content. This standardized system of classification allows for easier communication and understanding between buyers and sellers, and ensures consistency and fairness in the marketplace.
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