1) Robert takes 10 days more than Peter to complete a job. If they work together they will
complete the job in 12 days. How long will Peter alone take to finish the job?

The volume of cylindrical tin is 1584 \(cm^3\). The depth of the oil in the tin is 9cm.

\(V_1 =\) VOLUME OF CYLINDRICAL TIN

   \(= \pi r^2 h\)

  \(=\frac{22}{7}\) x 6 x 6 x 14

  = 44 x 36

  = 1584 \(cm^3\)

\(V_2 =\) VOLUME OF RECTANGULAR TIN

    = lbh = 1584

    = (16)(11)(h) = 1584

    = 176h =1584

    = h = 1584 / 176

    = h = 9 cm

A cylinder is a three-dimensional shape that consists of a circular base and a curved surface that extends upward to meet at a point known as the apex. The volume of a cylinder is the amount of space occupied by the shape and is given by the formula V = πr²h, Once we have calculated the area of the circular base, we can multiply it by the height of the cylinder to get the volume.

To calculate the volume of a cylinder, we need to know its dimensions, which are the radius and height. The radius is the distance from the center of the circular base to the edge, while the height is the distance between the two circular bases.

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Answer:

98 copies

Step-by-step explanation:

25% of 78 is 19.5

19.5 + 78 = 97.5

Because there can't be half of a copy we round up based on the decimal. Therefore the answer would 98 copies.

Answer:

Rise is vertical, run is horizontal

Step-by-step explanation:

Answer:

B) \(\$8395.80\)

Step-by-step explanation:

\(A=P(1+rt)\\A=7996(1+0.06\cdot\frac{10}{12})\\A=7996(1+0.05)\\A=7996(1.05)\\A=\$8395.80\)

This is all assuming that r=6% is an annual rate, making t=10/12 years

The inventory management model that should be used to solve this problem is the Model Economic Quantity to Order (EOQ) model. The optimal number of notebooks to make in each order is 590 units. The annual ordering cost (AOC) is approximately $892.20. The Annual Holding Cost (AHC) is $3540. The annual product cost (APC) is $233,460. The annual total cost of managing inventory (ATC) is approximately $237,892.20. The total number of orders in the year (N) is 33. The estimated time between each order (T) is approximately 7.58 days. The daily demand is approximately 77.82 units. The reorder point (ROP) is approximately 311 units.

The inventory management model that should be used to solve this problem is the Model Economic Quantity to Order (EOQ) model.

To find the optimal number of notebooks to make in each order, we can use the EOQ formula:

EOQ = √[(2 * Demand * Ordering Cost) / Holding Cost]

EOQ = √[(2 * 19455 * 27) / 6]

EOQ ≈ 589.96

Since the number of notebooks must be a whole number, the optimal number to order would be 590 notebooks.

The annual ordering cost (AOC) can be calculated by dividing the annual demand by the EOQ and multiplying it by the ordering cost:

AOC = (Demand / EOQ) * Ordering Cost

AOC = (19455 / 590) * 27

AOC ≈ $892.20

The Annual Holding Cost (AHC) is calculated by multiplying the EOQ by the holding cost per unit:

AHC = EOQ * Holding Cost

AHC = 590 * 6

AHC = $3540

The annual product cost (APC) is calculated by multiplying the annual demand by the cost per unit:

APC = Demand * Cost per unit

APC = 19455 * 12

APC = $233,460

The annual total cost of managing inventory (ATC) is the sum of the annual ordering cost, annual holding cost, and annual product cost:

ATC = AOC + AHC + APC

ATC = 892.20 + 3540 + 233460

ATC ≈ $237,892.20

The total number of orders in the year (N) can be calculated by dividing the annual demand by the EOQ:

N = Demand / EOQ

N = 19455 / 590

N ≈ 33

The estimated time between each order (T) can be calculated by dividing the number of working days in a year by the total number of orders:

T = Number of working days / N

T = 250 / 33

T ≈ 7.58 days

The daily demand is calculated by dividing the annual demand by the number of working days in a year:

Daily Demand = Demand / Number of working days

Daily Demand = 19455 / 250

Daily Demand ≈ 77.82 units/day

The reorder point (ROP) is the number of units at which a new order should be placed. It can be calculated by multiplying the daily demand by the lead time (time taken for the supplier to deliver the order):

ROP = Daily Demand * Lead Time

ROP = 77.82 * 4

ROP ≈ 311.28 units

Therefore, the reorder point would be approximately 311 units.

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Answer:

65%

Step-by-step explanation:

To find percentage, we take the fraction of the total and multiply it by 100.

\(\frac{325}{500} \times=\frac{325}{5}=65\)

Answer:

\(153.84\%\)

Step-by-step explanation:

\( 1. \: \frac{500}{3.25} \\ 2. \: 153.84\%\)

Answer: 9 units

Step-by-step explanation:

If you draw this one out, you should be able to notice that it is only a vertical distance it travels, which means that the difference in y-units should give you the distance.

THe variable is w, because currently, w is the variable.

COMMON SENSE =)

The domain of the function giving the total time she swims according to the number of laps is:

10 ≤ laps ≤ 20.

The domain and the range can be explained by these two following bullet points:

In the context of this problem, the total time she swims is calculated according to the number of laps that she swims, hence the input and the output are defined as follows:

As stated in the problem, every day she swims between 10 and 20 laps, inclusive, hence the domain of the relation is given as follows:

10 ≤ laps ≤ 20.

The problem asks for the domain of the relation.

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Answer:

240 cm²

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

This one is pretty simple, the triangle that sits on the upper left side of the shape fits right where there is a missing triangle shape on the upper right side. So just simply add 5.5 and 6.5 to get the total height of the figure and multiply it by the width (20).

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

5.5 cm + 6.5 cm = 12 cm

                 ↓  

12cm × 20 cm = 240 cm²

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Your answer is 240 cm²

Have a great day!

~Siascon~

Answer:

Step-by-step explanation:

if this much has help you

please fillowww me yrr

The value of x is 7. Therefore, the point on the line will be (7, 3).

The given points on the line are R(-5, -3), S(-1, -1) and T(x, 3).

The number of points required to find the equation of the line is 2.

The slope, m, of the line using points R(-5, -3) and S(-1, -1) is given as follows;

m = (-1+3)/(-1+5)=1/2

The equation of the line in slope and point form, using point S(-1, -1) is, therefore;

y +1= (1/2)(x +1) = 2y+2=x+1

Put T(x, 3) in 2y+2=x+1, that is 6+2=x+1

so, x=7

Therefore, the value of x is 7.

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The closest solution to this total among the available possibilities is 0.68, indicating that the portfolio is likely to surpass its benchmark in three or fewer quarters over the course of a year.

The field of mathematics concerned with probability is known as probability theory. Although there are various distinct interpretations of probability, probability theory approaches the idea rigorously mathematically by articulating it through a set of axioms.

Here,

The probability that the portfolio outperforms its benchmark in three or fewer quarters over the course of a year is the sum of the probabilities of outperforming the benchmark in exactly 0 quarters, 1 quarter, 2 quarters, and 3 quarters.

Since the probability of outperforming the benchmark in any quarter is 0.75, the probability of not outperforming the benchmark in a quarter is 1 - 0.75 = 0.25.

The probability of not outperforming the benchmark in exactly 0 quarters is 0.25⁰ = 1

The probability of not outperforming the benchmark in exactly 1 quarter is 0.25¹= 0.25

The probability of not outperforming the benchmark in exactly 2 quarters is 0.25² = 0.0625

The probability of not outperforming the benchmark in exactly 3 quarters is 0.25³ = 0.015625

So, the probability of outperforming the benchmark in exactly 0 quarters, 1 quarter, 2 quarters, and 3 quarters is 1 - 0.25⁰, 1 - 0.25¹, 1 - 0.25², and 1 - 0.25³, respectively.

The sum of these probabilities is the probability of outperforming the benchmark in three or fewer quarters over the course of a year:

P(outperform in three or fewer quarters) = 1 - 0.25⁰ + 1 - 0.25¹ + 1 - 0.25² + 1 - 0.25³

This expression can be calculated to get an exact answer, but to get the closest answer to the options given, we can round off the intermediate results to 2 decimal places:

P(outperform in three or fewer quarters) = 1 + 0.75 + 0.94 + 0.98

The closest answer to this sum among the options given is 0.68, so the probability that the portfolio outperforms its benchmark in three or fewer quarters over the course of a year is closest to 0.68.

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In the given recipe, There are 4/9 cups of sugar should be used for every 1 cup of flour to maintain the ratio.

What are the ratio?

A ratio in maths is a comparison of two or more numbers that shows how big one is big in comparison to the other one. The dividend or number being divided is referred to as the antecedent, and the divisor or number that is dividing is referred to as the consequent. A ratio compares two numbers by division.

A recipe requires for 1/3 cup of sugar for every 3/4 cups of flour.

Let x be the sugar that should be used for every 1 cup of flour.

The ratio for the given quantities and required quantities will be same,

So, The cups of sugar required for every 1 cup of flour is given by:

\(\frac{x}{1} = \frac{1/3}{3/4}\)

\(\frac{x}{1} = \frac{4}{9}\)

x = 4/9

Therefore, 4/9 cups of sugar is required for 1 cup of flour.

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Answer:

29

Step-by-step explanation:

5^2=25

2^2=4

25+4=29

Answer: 29 is the final answer

Step-by-step explanation: Have a nice day - Lily ^_^

Answer:

x = 180-35 = 145

y = 35

Hope it helps

Answer:

commission also doubles

Commission = $5,160

Step-by-step explanation:

Commission rate = 6%

Sales = $43,000

Commission = 6% of 43,000

= 0.06 × 43,000

= $2,580

Suppose sales would double. What would be true about the​ commission?

If sales doubles, that is,

Sales = $86,000

Then, commission also doubles

Commission = $5,160

Check:

Sales = $86,000

Commission rate = 6%

Commission = 6% of $86,000

= 0.06 × 86,000

= $5,160

Isa took 4 hour when  isa go from UK to USA and took 14 hour when she returns and time difference will be 10 hours

What is a definition distance?

the extent or amount of space between two things, points, lines, etc. the state or fact of being apart in space, as of one thing from another; remoteness

when isa travels to the usa for a holiday he leaves the uk at 1.00 pm local time and lands at 5.00 pm local time.

so isa took 4 hour

on the return journey he leaves at 8.00 pm local time and lands at 10.00 am local time the next day

isa tool 14 hour

find the length of the flight in hours and the time difference between the uk and the part of the usa that isa visited

length of flight is 18 hour

time difference will be 14-4 = 10 hour

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Answer:

D. g(-13) = 20

Step-by-step explanation:

Given information:

Option A, g(-4) = -11 cannot be true for g since the y-value of -11 is not in the given range.

Option B, g(7) = -1 cannot be true for g since the x-value of 7 is not in the given domain.

Option C, g(0) = 2 cannot be true for g since we have been given g(0) = -2.

Option D, g(-13) = 20 is true for g since the x-value of -13 is in the given domain, and the y-value of 20 is in the given range.

Answer:

300 new employees

Step-by-step explanation:

1:3

x + 3x = 1,200

4x = 1200

x = 300

She uses 1/2 quart of yellow paint for every 9/2 quarts of blue paint. Then, she uses 1/2 quart of yellow paint for every 1/2 + 9/2 = 10/2 = 5 quart of paint.

We can use the next proportion:

Solving for x:

She uses 1/10 quart of yellow paint for every quart of paint

Answer:

The correct answer is 2³*3*5²

a. The mean and standard deviation of the sampling distribution of the difference in sample means xF - xM are 1.5 and 1.65 minutes.

b. The probability of getting a difference in sample means xF - xM that is less than 0 is approximately 0.20

What is Probability?

Probability is a field of mathematics that calculates the likelihood of an experiment occurring. We can know everything from the chance of getting heads or tails in a coin to the possibility of inaccuracy in study by using probability.

a. The mean of the sampling distribution of the difference in sample means, xF - xM, is equal to the difference of the population means, μF - μM = 8.8 - 7.3 = 1.5 minutes.

where σF and σM are the standard deviations of the populations of female and male students, respectively, and nF and nM are the sample sizes of female and male students, respectively.

\(Standard\ Deviation = \sqrt{3.3^2/8 + 2.9^2/8} \\\\Standard\ Deviation = \sqrt{{2.75} }\\\\Standard\ Deviation = 1.65\ minutes\)

So, the mean and standard deviation of the sampling distribution of the difference in sample means xF - xM are 1.5 and 1.65 minutes, respectively.

b. The probability of getting a difference in sample means xF - xM that is less than 0 can be found using a standard normal distribution table. First, we need to standardize the difference in sample means xF - xM by subtracting the mean and dividing by the standard deviation:

z = (xF - xM - (μF - μM)) / standard deviation

z = (0 - 1.5) / 1.65 = -0.91

Looking up -0.91 in a standard normal distribution table, we find that the probability of getting a difference in sample means xF - xM that is less than 0 is approximately 0.20.

So, there is a 20% probability of getting a difference in sample means xF - xM that is less than 0.

Hence, The mean and standard deviation of the sampling distribution of the difference in sample means xF - xM are 1.5 and 1.65 minutes and probability of getting a difference in sample means xF - xM that is less than 0 is approximately 0.20.

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Answer:

1679 songs

Step-by-step explanation:

         23

       x73

----------------------------

            69

    +   1610

-------------------------------

         1679

Answer

2

Step-by-step explanation:

1+1=2

Answer: Window

Step-by-step explanation:

1+1 the the = on top :D

Answer:

4618.1 ft³

Step-by-step explanation:

Volume of the cone:

\(V_{cone} = \frac13 \pi r^2 h\)

\(V_{cone} = \frac13 \cdot \pi \cdot 49 \cdot 12 = 196\pi\)

Volume of the cilinder:

\(V_{cilinder} = \pi r^2 h\)

\(V_{cilinder} = \pi \cdot 49 \cdot 22 = 1078\pi\)

Total volume is 2*Vcone + Vcilinder = 1470π ≈ 4618.1 ft³

Answer:

C

Step-by-step explanation:

it was correct for me on edge

Note that sides AD and BE are perpendicular on the same side AC. So the angles CAD and CBE, both are equal to 90 degrees.

Beig the corresponding angles, ADC and BEC are also equal.

And the angle ACD is the common angle in both the triangles.

Therefore by the AAA criteria, the triangles CAD and CBE are similar.

So their corresponding sides must be proportional,

The line integral of (x⁸y + sin(x)) dy along the arc of the parabola y = x² is equal to 1/9.

To evaluate this line integral, we need to parameterize the curve C, which is the arc of the parabola y = x². Let's choose the parameterization x = t and y = t², where t ranges from 0 to 1.

Now we can express dy in terms of dt: dy = (dy/dt) dt = (2t) dt.

Substituting this into the integrand, we have (x⁸y + sin(x)) dy = (t⁸(t²) + sin(t)) (2t) dt = 2t¹⁰ + 2tsin(t) dt.

The integral of 2t¹⁰ with respect to t is (2/11)t¹¹. The integral of 2tsin(t) with respect to t is -2tcos(t) - 2sin(t).

Evaluating these integrals from t = 0 to t = 1, we have

\(\[\left(\frac{2}{11}(1^{11}) - 2(1)\cos(1) - 2\sin(1)\right) - \left(\frac{2}{11}(0^{11}) - 2(0)\cos(0) - 2\sin(0)\right)\]\).

Simplifying further, we get  \(\(\frac{2}{11} - 2\cos(1) - 2\sin(1)\)\).

This is approximately equal to 0.0893.

Hence, the line integral is approximately 0.0893, or equivalently, 1/9.

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Answer

bruh where's the explanation

Step-by-step explanation: