1. Name three branches of
science.

Answer:

C. 6.2 m/s

Explanation:

The magnitude of the distances are

East direction
| d1 | = 80 m

West direction

| d2 | =75m

Total magnitude of distance = 80 + 75 = 155

Total time taken = 5 + 20 = 25 s

Magnitude of speed = 155/25 = 6.2 m/s

Answer:

3

Explanation:

From the question given above, the following data were obtained:

Length (L) = 3 m

Height (H) = 1 m

Mechanical advantage (MA) =.?

The ideal mechanical advantage for the system can be obtained as follow:

MA = L/H

MA = 3/1

MA = 3

Therefore, the ideal mechanical advantage for the system is 3

Answer:

Explanation:

Mechanical Advantage is the ratio of Input Distance / Output Distance.

In this case, the output distance is to bring up the cart by 1m.

The input distance is to push the cart by 3m.

Assume an ideal machine, MA = 3/1 = 3

Answer:

La energía potencial elástica es la energía asociada con los materiales elásticos. Por ejemplo, un resorte al ser comprimido o elongado almacena energía potencial elástica y, al ser soltado, puede realizar trabajo sobre un objeto.

Para mantener el resorte comprimido o alargado una cierta longitud x, a partir de su largo natural, es necesario que, en este caso, la mano aplique una fuerza F_{M} sobre el resorte; esta fuerza es directamente proporcional a x.

Explanation:

ón conocida como ley de Hooke.

Para encontrar una expresión que describa la energía potencial asociada con la fuerza del resorte, se determina el trabajo que se requiere para comprimir el resorte desde su posición de equilibrio hasta cierta posición final arbitraria x. Debido a que la fuerza varía desde O hasta kx, se utiliza la fuerza promedio \frac{(F_{0}+F_{X})}{2}.

 \[ \bar{F}=\frac{0+K X}{2}=\frac{1}{2}kx \]

fuerza-sobre-un-resorte

Fuerza sobre un resorte. La fuerza para estirar un resorte aumenta linealmente con su elongación .

El trabajo realizado por la fuerza aplicada será: W=\bar{Fx}=\frac{1}{2}kx^{2}

El trabajo realizado se almacena en el resorte comprimido en forma de energía potencial elástica como:

 \[ \boxed{ Ep_{elas}=\frac{1}{2}kx^{2}} \]

Una vez que se ha comprimido o estirado el resorte respecto a su posición de equilibrio, la energía potencial elástica se puede considerar como la energía almacenada en el resorte deformado. Esta energía siempre es positiva en un objeto deformado al depender de x^{2}.

Por ejemplo, en la figura se observa que un resorte realiza trabajo sobre un bloque. El resorte que se encuentra sin deformar (a) cuando es empujado por un bloque de masa m, se comprime una distancia x (b). Cuando el bloque se suelta (c), partiendo del reposo, la energía potencial plástica almacenada en el sistema se transforma en energía cinética del bloque.

energia-potencial

Air is used to pressurize water in a tank, and the pressure is then measured. by a multifluid manometer so Consequently, the air pressure in the tank is 129.45KPa.

In the physical sciences, pressure is defined as either the stress at a place within a confined fluid or the perpendicular force per unit area. The weight of the atm is atmospheric pressure, which is approximately 15 pounds per square inch at sea level. Each square meter of the Earth's surface is under pressure from the atmosphere.

atmospheric pressure (\(P_{atm\))=85.6kPa

 \(P_{atm\)=85600Pa

density of water=\(\rho =\)1000 kg/\(m^3\)

density of oil(\(\rho_0\))=850kg/\(m^3\)

density of mercury(\(\rho_{m\))=13600 kg/\(m^3\)

height of water column(\(h_1\))= 0.1m

height of oil column from water level(\(h_2\))=0.2m

height of mercury column (\(h_3\))=0.35m

pressure at point B

\(P_B=P_{air} +\:\rho_0gh_1\: +\rho_wgh_2 \: \rightarrow(1)\)

\(P_B=P_{atm} +\:\rho_mgh_3\: \rightarrow(2)\)

\(P_{air} +\:\rho_0gh_1\: +\rho_wgh_2 \:=P_{atm} +\:\rho_mgh_3\:\)

\(P_{air} =\:-\rho_0gh_1\: -\rho_wgh_2 \:+P_{atm} +\:\rho_mgh_3\:\rightarrow(3)\)

\(\rho _mgh_3\)=13600x9.8x0.35=46648 Pa

\(\rho _0gh_1\) =850x9.8x0.1=833 Pa

\(\rho _wgh_2\) =1000x9.8x0.2=1960 Pa

By putting the value in eq.3

\(P_{air\)=85600+46648−833−1960 = 129455Pa

therefore pressure of air in the tank is 129.45KPa

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The total distance traveled by the block in a one full or complete cycle is  2A.

option C.

If a block on the end of a spring is pulled to position x = A and released. In one full cycle of its motion, it will travel the following distance as shown below;

x = A cos (ωt)

where;

During a half cycle the block will travel a total distance of A.

During another half cycle the block will travel a total distance of A.

The total distance traveled by the block in a one full or complete cycle is calculated as follows;

distance = A + A

distance = 2A

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Answer:

  72.5 A

Explanation:

There are about 13.6 coulombs of free electron charges in each cubic mm of copper. So, the rate of movement of charge is that quantity multiplied by the volume in the flow.

  V = πr²h  . . . . .  volume of a cylinder

  V = π(1.947 mm/2)²(1.79 mm/s) = 5.329 mm³/s

Then the charge flow rate is ...

  (13.6 C/mm³)(5.329 mm³/s) = 72.5 C/s

The magnitude of the current is about 72.5 amperes.

______

Additional comment

The volume of free charge in copper can be computed from the density, molar mass, number of atoms in a mole, number of charges in a coulomb, and the number of free charges per atom. Some of the combinations of necessary calculations can be found with a web search, so it is not unreasonable to presume that the charge density is known.

At pH = 8, the ratio of H+ ions to OH- ions is 1:1, indicating a neutral solution. The concentration of H+ ions and OH- ions is approximately 1 x 10^(-8) mol/L. The calculated and approximated ratios should match.

To calculate the ratio of H+ ions to OH- ions at pH = 8, we need to use the relationship between pH and the concentration of H+ ions. The pH scale is a logarithmic scale that measures the acidity or alkalinity of a solution based on the concentration of H+ ions.

The formula to calculate the concentration of H+ ions (\(C_H\)+) from pH is:

\(C_H\)+ = \(10^(^-^p^H^)\)

Substituting pH = 8 into the formula:

\(C_H\)+ = \(10^(^-^8^))\)

Using the properties of logarithms, we can calculate the concentration of H+ ions:

\(C_H\)+ ≈ 1 x \(10^(^-^8^))\) mol/L

According to the concept of neutrality in water, the concentration of H+ ions is equal to the concentration of OH- ions. Therefore, the concentration of OH- ions (\(C_O_H\)-) is also approximately 1 x \(10^(^-^8^))\)mol/L.

To calculate the ratio of H+ ions to OH- ions, we divide the concentration of H+ ions by the concentration of OH- ions:

Ratio = \(C_H\)+ / \(C_O_H\)-

Ratio = (1 x \(10^(^-^8^))\) / (1 x \(10^(^-^8^))\))

Ratio = 1:1

The ratio of H+ ions to OH- ions at pH = 8 is 1:1, indicating a neutral solution. This means that the concentration of H+ ions is equal to the concentration of OH- ions, resulting in a balanced ratio.

When comparing the calculated ratio of 1:1 to the approximated ratio at pH = 8, they should be the same because the ratio of H+ ions to OH- ions is determined solely by the pH value, which is consistent and mathematically derived. Therefore, the approximated and calculated ratios should match.

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a ) The x and y-components of average velocity and average acceleration between points A and B are 3.8 m/s, 3.8 m/s and 0.46 m/s², - 0.46 m/s²

e ) The magnitude of the runner’s average velocity between A and B is

t = 2 π r / v

t = 2 * 3.14 * 50 / 6

t = 52.4 s for full lap

t per quarter = 52.4 / 4 = 13.1 s

v = Δx / Δt

a = Δv / Δt

a ) From A to B,

vx = ( 0 - ( - 50 ) ) / 13.1

vx = 3.8 m / s

vy = ( 50 - 0 ) / 13.1

vy = 3.8 m / s

ax = ( 6 - 0 ) / 13.1

ax = 0.46 m / s²

ay = ( 0 - 6 ) / 13.1

ay = - 0.46 m / s²

b ) From A to C,

t = 52.4 / 2

t = 26.2 s

vx = ( 50 - ( - 50 ) ) / 26.2

vx = 3.8 m / s

vy = 0

ax = 0

ay = ( - 6 - 6 ) / 26.2

ay = - 0.46 m / s²

c ) From C to D,

t = 13.1 s

vx = ( 0 - 50 ) / 13.1

vx = - 3.8 m / s

vy = ( - 50 - 0 ) / 13.1

vy = - 3.8 m / s

ax = ( - 6 - 0 ) / 13.1

ax = - 0.46 m / s²

ay = ( 0 - ( - 6 ) ) / 13.1

ay = 0.46 m / s²

d ) From A to A,

Since the starting and ending points are exactly the same, there is no displacement. So the average velocity will be zero. Due to no change in velocity, there will be no acceleration

e ) From A to B,

v = √ vx² + vy²

v = √ 3.8² + 3.8²

v = 5.4 m / s

Displacement is the shortest distance between two points. So it will basically be a straight line. But the athlete runs in a circular motion. So distance will be larger than the displacement. So speed will be higher than velocity.

s = 6 m / s

v = 5.4 m / s

s > v

f ) At constant speed in a circular motion, only the magnitude is constant. Its direction keeps changing. So velocity cannot be constant in a circular motion.

Therefore,

a ) vx = 3.8 m / s, vy = 3.8 m / s ; ax = 0.46 m / s², ay = 0.46 m / s²

b ) vx = 3.8 m / s, vy = 0 ; ax = 0, ay = - 0.46 m / s²

c ) vx = - 3.8 m / s, vy = - 3.8 m / s ; ax = - 0.46 m / s², ay = 0.46 m / s²

d ) vx = 0, vy = 0 ; ax = 0, ay = 0

e ) v = 5.4 m / s

f ) Due to change in direction.

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Answer:the answer is galaxy

Explanation:

The weight of child can be given as,

Substitute the known values,

Divide the value of force with the weight.

Thus, the force is 23.9 times the weight of child.

A normal force is a force applied perpendicular to a surface on an object in contact with it. The weight is the gravitational force imposed on an object, and it is equal to the mass multiplied by the acceleration due to gravity.

When an object is put on a scale at rest on a level surface, the normal force equals the weight. In this instance, the normal force acting upwards from the scale on the object is equal to the weight acting downwards.

Here are two instances of normal forces that are not equal to weight:

When a person stands on an inclined plane or ramp, the normal force applied by the plane is less than the person's weight, because some of the weight is resolved parallel to the plane, causing the person to slide down if enough friction exists.

The normal force exerted by the air or other medium on a person in free fall is zero, while their weight due to gravity stays constant.

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Sound waves are a type of mechanical wave that propagate through a medium, typically air but also other materials such as water or solids.

Frequency: the frequency of a sound wave refers to the number of cycles or vibrations it completes per second and is measured in Hertz (Hz).

Amplitude: the amplitude of a sound wave refers to the maximum displacement or intensity of the wave from its equilibrium position. It represents the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds and smaller amplitudes corresponding to softer sounds.

Wavelength: the wavelength of a sound wave is the distance between two consecutive points in the wave that are in phase, such as from one peak to the next or one trough to the next. It is inversely related to the frequency of the wave.

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Total mass lost by the comet is 30.24 x 10¹⁰ kg.

Rate at which mass is lost, R = 35 x 10⁴ kg/s

Time period, T = 100 days = 8.64 x 10⁶s

Therefore,

Total mass lost by the comet, m = R x T

m = 30.24 x 10¹⁰ kg

So,

The fraction of loss = (30.24 x 10¹⁰)/(5 x 10¹⁵) = 60.48 x 10⁻⁵

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The value added by the baker is $3. The bread's contribution to GDP is the final sale price of the bread, which is $6

In this scenario, each person involved in the production and sale of the bread adds value to the final product. The concept of value added refers to the increase in the market value of a product at each stage of production.

The farmer grows the wheat and sells it for $1. The value added by the farmer is $1.

The miller processes the wheat into flour, increasing its value. The miller sells the flour to the baker for $3, so the value added by the miller is $3 - $1 = $2.

The baker uses the flour to make bread, further adding value to the product. The baker sells the bread to the engineer for $6, so the value added by the baker is $6 - $3 = $3.

The engineer consumes the bread, but since no further economic value is added, there is no additional value added by the engineer.

The bread's contribution to GDP (Gross Domestic Product) is the final sale price of the bread, which is $6. GDP measures the total value of all goods and services produced within a country's borders, and the sale of the bread represents the final output of the production chain.

Overall, the value added at each stage contributes to the final price of the bread, and the final sale price of the bread represents its contribution to GDP.

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Answer: See the explanation.

Explanation:

When we say a substance is magnetic it means the atoms are lined in a way that created a magnetic field that goes from one side to the other

These are essentially two aspects of the same thing, because a changing electric field creates a magnetic field, and a changing magnetic field creates an electric field. This is the relationship.

Answer: Copper isn't ferromagnetic,

Aluminum isn't ferromagnetic,

String does have a ferromagnetic property

A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. The nonconservative work done on the boy is approximately -42.7 kilojoules.

To find the nonconservative work done on the boy, we need to consider the change in the boy's mechanical energy during the process. Mechanical energy is the sum of the boy's kinetic energy (KE) and gravitational potential energy (PE).

The initial mechanical energy of the boy is given by the sum of his kinetic energy and potential energy when he catches the wave:

E_initial = KE_initial + PE_initial

The final mechanical energy of the boy is given by the sum of his kinetic energy and potential energy after he drops through the height:

E_final = KE_final + PE_final

The nonconservative work done on the boy is equal to the change in mechanical energy:

Work_nonconservative = E_final - E_initial

Let's calculate each term:

KE_initial = (1/2) * m * v_initial^2

= (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = m * g * h_initial

= 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * m * v_final^2

= (1/2) * 66.1 kg * (8.51 m/s)^2

PE_final = m * g * h_final

= 66.1 kg * 9.8 m/s^2 * 0

Since the boy ends at ground level, the final potential energy is zero.

Substituting the values into the equation for nonconservative work:

Work_nonconservative = (KE_final + PE_final) - (KE_initial + PE_initial)

Simplifying:

Work_nonconservative = KE_final - KE_initial - PE_initial

Calculating the values:

KE_initial = (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * 66.1 kg * (8.51 m/s)^2

Substituting the values:

Work_nonconservative = [(1/2) * 66.1 kg * (8.51 m/s)^2] - [(1/2) * 66.1 kg * (1.60 m/s)^2 - 66.1 kg * 9.8 m/s^2 * 1.59 m]

Calculating the result:

Work_nonconservative ≈ -42.7 kJ

Therefore, the nonconservative work done on the boy is approximately -42.7 kilojoules. The negative sign indicates that work is done on the boy, meaning that energy is transferred away from the boy during the process.

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Answer:

D

Explanation:

Answer:

I think it's D

Explanation:

Answer:

18 kg * m/s

Explanation:

The equation for momentum is:

momentum = mass * velocity

And although the problem already gave velocity, you must calculate the mass from the graviational force.

Fg = 3.4N = mg = 9.8m

mass = 3.4 N / 9.8 m/s^2 = 0.3469 kg

Momentum = 52m/s * 0.3469 kg - 18.041 kg * m/s = 18

Answer:

If a ball is thrown straight up, its instantaneous velocity at the top of its path is 0 m/s, but its acceleration is 10 m/s2. ... Its acceleration can't be zero - that would mean that its velocity would not change

Explanation:

When a ball is hurled straight up, it has an instantaneous top speed of 0 m/s but an acceleration of 10 m/s². Since its velocity wouldn't change if its acceleration were zero, it can't be.

The instantaneous speed, as its name suggests, has to do with how fast an item is moving at a particular moment in time. The brief distance that an object has gone divided by the equivalent amount of time can also be used to determine its instantaneous speed. With each instant that passes, the instantaneous speed can fluctuate.

An automobile's speedometer, for instance, displays the vehicle's current speed. The instantaneous speed of the car might be 50 kmph at one point, and with a light press of the pedal, it might increase to 54 kmph at the next.

When the ball is thrown straight up, with the increase in height the speed of the ball starts to reduce, at the top the speed will become zero.

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Answer:

Granite

Explanation:

Trust me I learned this 2years ago

Answer:

C. Gas

Explanation:

Segment CD represents gaseous phase of matter as segment CD shows highest energy which is in case of gas.

Matter in chemistry, is defined as any kind of substance that has mass and occupies space that means it has volume .Matter is composed up of atoms which may or not be of same type.

Atoms are further made up of sub atomic particles which are the protons ,neutrons and the electrons .The matter can exist in various states such as solids, liquids and gases depending on the conditions of temperature and pressure.

The states of matter are inter convertible into each other by changing the parameters of temperature and pressure.The intermolecular forces of attraction are different in different states of matter.Particles of matter have different sizes.

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Answer:

Explanation:

Given,

F = 100 , M = 25

Now, let's find the value of A

\( \sf{F = MA}\)

plug the values

⇒\( \sf{100 = 25 A}\)

Swap the sides of the equation

⇒\( \sf{25A = 100}\)

Divide both sides of the equation by 25

⇒\( \sf{ \frac{25A}{25} = \frac{100}{25} }\)

Calculate

⇒\( \sf{A = 4}\)

Hope I helped!

Best regards!!

Given:-

To find out:-

Calculate the acceleration, a ?

Formula applied:-

F = m × a

Solution:-

We know,

\( \sf{F = m × a}\)

Substituting the values of mass and acceleration,we get

\( \sf\implies \: 100 = 25 \times a\)

\( \sf \implies a = \cancel \dfrac{100}{25} \)

\( \sf \implies a = 4 \: ms {}^{ - 1} \)

Answer:

Ein: 2.75*10^-3 N/C

Explanation:

The induced electric field can be calculated by using the following path integral:

\(\int E_{in} dl=-\frac{\Phi_B}{dt}\)

Where:

dl: diferencial of circumference of the ring

circumference of the ring = 2πr = 2π(5.00/2)=15.70cm = 0.157 m

ФB: magnetic flux = AB (A: area of the loop = πr^2 = 1.96*10^-3 m^2)

The electric field is always parallel to the dl vector. Then you have:

\(E_{in}\int dl=E_{in}(2\pi r)=E_{in}(0.157m)\)

Next, you take into account that the area of the ring is constant and that dB/dt = - 0.220T/s. Thus, you obtain:

\(E_{in}(0.157m)=-A\frac{dB}{dt}=-(1.96*10^{-3}m^2)(-0.220T/s)=4.31*10^{-4}m^2T/s\\\\E_{in}=\frac{4.31*10^{-4}m^2T/s}{0.157m}=2.75*10^{-3}\frac{N}{C}\)

hence, the induced electric field is 2.75*10^-3 N/C

Answer:

Photovoltaic detection is a technique that converts light into electrical energy. It is a process that involves the use of a photovoltaic cell, which is made up of semiconductor materials, to generate an electric current when exposed to light.

The photovoltaic cell absorbs the photons of light, which then knock electrons out of their orbits, creating a flow of electricity. The amount of electricity produced is proportional to the intensity of the light. The photovoltaic cell is commonly used in solar panels to generate electricity from sunlight. The efficiency of the photovoltaic cell is dependent on several factors, including the type of semiconductor material used, the purity of the material, and the thickness of the cell.

The photovoltaic cell has many applications, including in solar power generation, telecommunications, and remote sensing. The technique of photovoltaic detection is an important area of research, as it has the potential to provide a clean and renewable source of energy that can help mitigate climate change.

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The weight of the pail and sand necessary to start the pumpkin moving in this case is less than 11 N.

The force of friction acting on the pumpkin depends on the weight of the pumpkin and the coefficient of static friction.

F = μW

where;

The weight of the pumpkin is calculated as follows;

W = mg

where;

W = 1.8 kg  x  9.8 m/s²

W = 17.64 N

The static friction force preventing the pumpkin from moving is calculated as follows;

F = μW

F = 0.55 x 17.64 N

F = 9.7 N

Thus, the minimum force required to move the pumpkin is 9.7 N which is less than 11 N.

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The complete question is blow:

Suppose the coefficient of static friction is 0.55 rather than 0.61. is the weight of the pail and sand necessary to start the pumpkin moving in this case greater than, less than or equal to 11 N? calculate the required weight. mass of the pumpkin is 1.8 kg.

Answer:

Gravitational pull of the sun

Explanation:

Answer:

2.5m/s

Explanation:

Using the law of conservation of energy;

m1u1 + m2u2 = (m1+m2)v

m1 and m2 are the masses

u1 and u2 are the initial velocities

v is the final velocity

Substitute the given values in the formula

2(10)-2(5) = (2+2)v

20-10 = 4v

10 = 4v

v = 10/4

v = 2.5m/s

Hence the velocity of the combined object after collision is 2.5m/s

Answer:

weight, acceleration

Explanation:

weight = mass x gravity(meaning the direction of the mass)

acceleration = v-u/t

v-u is the change in velocity

Answer:

temperatures is directly proportional to kinetic energy

Explanation:

in increasing the temperature,kinetic energy also increases

hope it helps...