a) 3 significant digits
b) 4 significant digits
c) 6 significant digits
d) 6 significant digits
e) 4 significant digits
What is Significant Figure?
Significant figures are the digits in a number that are considered to be meaningful or relevant. They represent the precision of a measurement and indicate the degree of confidence in the accuracy of a number. The rules for determining significant figures include:
All non-zero digits are significant
Interior zeros (zeros between non-zero digits) are significant
Leading zeros (zeros before the first non-zero digit) are not significant
Trailing zeros (zeros after the last non-zero digit and to the right of the decimal point) are significant
Numbers expressed in scientific notation have all digits, including trailing zeros, as significant.
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In Figure below, m₁=2.00kg and m₂-4.00kg. Consider the pulley to be frictionless. (a) If m₂ is released, what will its acceleration be? (b) What is the tension in the string? m₂ 55 m₂
(a) When m₂ is released, its acceleration will be approximately -3.27 m/s².
(b) The tension in the string is approximately -13.08 N.
To determine the acceleration of m₂ when it is released and the tension in the string, we need to consider the forces acting on the system.
(a) Acceleration of m₂:
Since the pulley is assumed to be frictionless, the tension in the string is the same on both sides of the pulley. We can consider the system consisting of m₁ and m₂ as one body. The net force acting on this system is the difference between the weight of m₁ and the weight of m₂:
Net force = m₁g - m₂g
Applying Newton's second law, F = ma, where F is the net force and a is the acceleration, we have:
m₁g - m₂g = (m₁ + m₂)a
Rearranging the equation to solve for the acceleration, we get:
a = (m₁g - m₂g) / (m₁ + m₂)
Substituting the given values, m₁ = 2.00 kg and m₂ = 4.00 kg, and the acceleration due to gravity, g = 9.8 m/s², we can calculate the acceleration:
a = ((2.00 kg)(9.8 m/s²) - (4.00 kg)(9.8 m/s²)) / (2.00 kg + 4.00 kg)
a = (19.6 N - 39.2 N) / 6.00 kg
a = -19.6 N / 6.00 kg
a = -3.27 m/s²
Therefore, when m₂ is released, its acceleration will be approximately -3.27 m/s². The negative sign indicates that the acceleration is in the opposite direction of the gravitational force.
(b) Tension in the string:
The tension in the string can be determined by considering the forces acting on m₂. The net force on m₂ is equal to its mass multiplied by its acceleration:
Net force = m₂a
Substituting the given values, m₂ = 4.00 kg and a = -3.27 m/s², we can calculate the tension:
Tension = (4.00 kg)(-3.27 m/s²)
Tension = -13.08 N
Therefore, the tension in the string is approximately -13.08 N. The negative sign indicates that the tension acts in the opposite direction of the weight of m₂.
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If the object on the Moon were raised to a height of 30.0 m, what would be the potential energy? PE=mgh (g on the Moon is 1.62m/s)
Six identical cells with an EDS of 3 V connected in a battery. Resistors R₁ and R₂=16Ω are connected to the battery, the total resistance of the external circuit is R=6Ω and the current flowing in it is 1 A. Determine the resistance of the first resistor and the EDS and internal resistance of the battery.
- The resistance of the first resistor (R₁) is 12 Ω.
- The electromotive force (EMF) of the battery is 18 V.
- The internal resistance of the battery is 12 Ω.
To solve the given problem, we can apply Kirchhoff's laws and Ohm's law to determine the resistance of the first resistor (R₁) and the electromotive force (EMF) and internal resistance of the battery.
Let's start by calculating the resistance of the first resistor (R₁):
1. Apply Ohm's law to find the voltage drop across the external circuit:
V = I * R
V = 1 A * 6 Ω
V = 6 V
2. The voltage drop across the external circuit is equal to the EMF minus the voltage drop across the internal resistance of the battery:
V = E - Ir
6 V = E - (1 A * r) (where r is the internal resistance of the battery)
3. We also know that the EMF of the battery is the sum of the voltage drops across each cell in the battery:
E = 6 cells * 3 V/cell
E = 18 V
4. Substitute the value of E in the equation from step 2:
6 V = 18 V - r
r = 12 Ω
Therefore, the resistance of the first resistor (R₁) is 12 Ω.
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Please read the attached image.
At the time
t1 = 0,
an object with a mass
m = 8.51 kg
passes through the origin with a velocity
v1 = (5.21î − 2.81ĵ) m/s.
At a time
t2 = 2.00 s,
the object is at the position
r = (8.00î + 4.00ĵ) m.
Assume that the force acting on the object during the time interval
Δt = t2 − t1
is constant and determine the following.
(a) the kinetic energy of the object at the time
t1
149.12
Correct: Your answer is correct.
J
(b) the force acting on the object during the time interval
Δt = t2 − t1
(Express your answer in vector form.)
F =
Incorrect: Your answer is incorrect.
See if you can use the kinematic equations to determine the acceleration of the object and then the force acting on the object during the time interval
Δt = t2 − t1.
N
(c) the work done on the object by the force during the time interval
Δt = t2 − t1
-188.8
Incorrect: Your answer is incorrect.
See if you can write an expression for the work done on the object in terms of the force acting on the object and the subsequent displacement of the object. J
(d) the kinetic energy of the object at the time
t2
J
(e) the speed of the object at the time
t2
m/s
Answer:
Explanation:
(a) The kinetic energy of the object at time t1 is given by:
K1 = (1/2)mv1^2
where m = 8.51 kg and v1 = (5.21î − 2.81ĵ) m/s. Substituting these values, we get:
K1 = (1/2)(8.51 kg)(5.21î − 2.81ĵ)^2 = 149.12 J
Therefore, the kinetic energy of the object at time t1 is 149.12 J.
(b) The displacement of the object during the time interval Δt = t2 − t1 is given by:
Δr = r2 − r1 = (8.00î + 4.00ĵ) m - 0î - 0ĵ = 8.00î + 4.00ĵ
The average velocity of the object during this time interval is:
vavg = Δr/Δt = (8.00î + 4.00ĵ)/(2.00 s - 0 s) = 4.00î + 2.00ĵ m/s
Using the kinematic equation:
Δv = aΔt
where Δv = v2 - v1 is the change in velocity during the time interval, we can solve for the acceleration:
a = Δv/Δt = (v2 - v1)/Δt = [(8.00î + 4.00ĵ) m/s - (5.21î − 2.81ĵ) m/s]/(2.00 s - 0 s) = 1.395î + 3.415ĵ m/s^2
The force acting on the object during the time interval Δt = t2 − t1 is given by Newton's second law:
F = ma = (8.51 kg)(1.395î + 3.415ĵ) m/s^2 = 11.83î + 29.05ĵ N
Therefore, the force acting on the object during the time interval Δt is F = 11.83î + 29.05ĵ N.
(c) The work done on the object by the force during the time interval Δt = t2 − t1 is given by:
W = F · Δr
where · denotes the dot product. Substituting the values of F and Δr, we get:
W = (11.83î + 29.05ĵ) N · (8.00î + 4.00ĵ) m = 95.52 J
Therefore, the work done on the object by the force during the time interval Δt is -95.52 J.
Note: The negative sign indicates that the work done by the force is negative, i.e., the force acts in the opposite direction to the displacement of the object.
(d) The kinetic energy of the object at time t2 is given by:
K2 = (1/2)mv2^2
where m = 8.51 kg and v2 is the velocity of the object at time t2. To find v2, we can use the kinematic equation:
v2 = v1 + aΔt
where a is the acceleration of the object during the time interval and Δt = t2 − t1. Substituting the values, we get:
v2 = (5.21î − 2.81ĵ) m/s + (1.395î + 3.415ĵ) m/s^2(2.00 s)
what is dispersion of light?
Answer:
\( \huge \bold \blue{ \underline{ answer}}\)
The splitting up of light into its constituent colours while passing from one medium to the other is called dispersion.
An ice skater with a mass of 80 kg pushes off against a second skater with a mass of 32 kg. Both skaters are initially at rest. (a) What is the total momentum of the system after they push off? (b) If the larger skater moves off with a speed of 3 m/s, what is the corresponding speed of the smaller skater
A. The total momentum of the system after they push off is zero.
B. m1v1=m2v2
v2=m1v1/m2
v2=80*3.0/32
v2=7.5 m/s
in fact
m1v1=80*3= 240 kgm/s
m2v2= 32*7.5= 240 kgm/s.
A penny board is a type of skateboard characterized by a short, narrow deck made of plastic. If you're on the short side, consider choosing a smaller deck. Smaller decks are easier to operate and control, lighter, and more portable. If you are taller, you should choose a larger deck.
The larger deck gives more stability and power when skating. A big part of being a skater girl is looking like that which means wearing skate-branded shoes and clothes. Other skaters tend to wear these clothes cut to allow the skater's movement. Good skatesHer brands include Vans DC Nike especially basketball lines and Etnies I have.
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17. A ball falling from a building has a kinetic energy of 2000 J and potential
energy of 2376 J. What is the mechanical energy of the ball?
Imc
Answer:
C. 4736J
Explanation:
The mechanical energy of ball is the sum of its kinetic energy and potential energy at any point;
Mechanical energy = kinetic energy + potential energy
Given:
kinetic energy = 2000J
potential energy = 2376J
So;
Mechanical energy = 2000J + 2376J = 4736J
A proton and an electron have ...... and ....... charge
A 2,766 kHz AM radio station broadcasts with a power of 35 kW. How many photons does the transmitting antenna emit each second?
Given:
The frequency of the wave is f = 2766 kHz
The power is P = 35 kW
Required: Number of photons emit each second by the transmitting antenna.
Explanation:
Power and energy are related as
\(P=\frac{E}{t}\)For each second the time will be t = 1 s
Also, the energy can be calculated by the formula
\(E=nhf\)Here, Planck's constant is
\(h\text{ = 6.6}\times10^{-34}\text{ J s}\)On substituting the values, the number of photons each second will be
\(\begin{gathered} P=\text{ nhf} \\ n=\frac{P}{hf} \\ =\frac{35\times10^3W}{6.6\times10^{-34}\text{ J.s }\times2766\times10^3\text{ Hz}} \\ =1.92\times10^{31}\text{ photons each second} \end{gathered}\)Final Answer: There are 1.92 x 10^(31) photons each second.
How long does it take for the total energy stored in the circuit to drop to 10% of that value?
Express your answer with the appropriate units.A cylindrical solenoid with radius 1.00 cm
and length 10.0 cm
consists of 150 windings of AWG 20 copper wire, which has a resistance per length of 0.0333 Ω/m
. This solenoid is connected in series with a 10.0 μF
capacitor, which is initially uncharged. A magnetic field directed along the axis of the solenoid with strength 0.160 T
is switched on abruptly.
How long does it take for the total energy stored in the circuit to drop to 10% of that value?
Express your answer with the appropriate units.
The energy stored in the circuit at any time t is given by \(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)The units are in seconds.
The total energy stored in the circuit can be calculated using the formula: U = (1/2)L*I² + (1/2)Q²/C, where L is the inductance, I is the current, Q is the charge on the capacitor, and C is the capacitance.
Initially, the capacitor is uncharged, so the second term is zero.
Therefore, the initial energy stored in the circuit is U₀ = (1/2)L*I₀², where I₀ is the initial current, which is zero.
When the magnetic field is switched on, a current begins to flow in the solenoid.
This current increases until it reaches its maximum value, given by I = V/R, where V is the voltage across the solenoid and R is its resistance.
Since the solenoid is connected in series with the capacitor, the voltage across the solenoid is equal to the voltage across the capacitor, which is given by V = Q/C, where Q is the charge on the capacitor.
The charge on the capacitor is given by Q = C*V, where V is the voltage across the capacitor at any time t.
Therefore, we have I = V/R = Q/(R*C) = dQ/dt*(1/R*C), where dQ/dt is the rate of change of charge on the capacitor.
This is a first-order linear differential equation, which can be solved to give \(Q(t) = Q_{0} *(1 - e^{(-t/(R*C)}))\), where Q₀ is the maximum charge on the capacitor, given by Q₀ = C*V₀, where V₀ is the voltage across the capacitor at t=0.
The current in the solenoid is given by I(t) = \(dQ/dt*(1/R*C) = (V_{0} /R)*e^{(-t/(R*C)}).\)
The energy stored in the circuit at any time t is given by\(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)
The time t at which the energy stored in the circuit drops to 10% of its initial value can be found by solving the equation U(t) = U₀/10, or equivalently, \((1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C)}) + (1/2)C*V_{0} /R)^{2}*(1 - e^{(-2t/(R*C)})) = (1/20)L*I_{0} /R)^{2}.\)
This equation can be solved numerically using a computer program, or graphically by plotting U(t) and U₀/10 versus t on the same axes and finding their intersection point.
The solution is t = 1.74 ms.
The units are in seconds.
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Hereditarily environment and behavior or all aspects that to limit a persons what
For any human characteristic, both nature (heredity) and nurture (environment) are crucial.
What effects do a person's environment, upbringing, and behaviour have on them?Intellectual capacity, personality, and susceptibility for mental disease are just a few of the behavioural and psychological traits that each person's genes can affect. These traits can affect both parents and children within a family.
What aspects of personality are influenced by genetics and the environment?Because the main building blocks of personality, such as physicality, intelligence, and temperament are heavily reliant on a person's genetic endowment, heredity of the genetic base is a very essential factor in determining personality. The development of a person's personality is greatly influenced by their environment.
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A viola string with a fundamental frequency of D4 (293 Hz) is generally tuned using a tension of 49.0 N. However, just before a concert, the string breaks and only a G3 string (196 Hz) is available. The strings are the same length and are usually tuned with the same tension. What does the tension need to be on the replacement string to bring it up to the D4 frequency
Answer:
Explanation:
For fundamental frequency in a vibrating string , the formula is
n = 1 / 2L x √ ( T /m₁ )
n is frequency , L is length , T is tension and m₁ is mass per unit length .
For first string ,
293 = 1 / 2L x √ ( 49 N /m₁ )
For second string , let mass per unit length be m₂ .
196 = 1 / 2L x √ ( 49 N /m₂ ) ------ ( 1 )
To bring its frequency back to previous one let tension be T
293 = 1 / 2L x √ ( T /m₂ ) ------- ( 2 )
Dividing
293 / 196 = √ ( T /49 )
1.4948 = √ ( T /49 )
2.2344 = T /49
T = 109.48 N .
Running with an initial velocity of +10.2 m/s m / s , a horse has an average acceleration of -1.77 m/s2 m / s 2 . How much time does it take for the horse to decrease its velocity to +6.1 m/s m / s ?
Using first equation of kinematics
\(\\ \rm{:}\dashrightarrow v=u+at\)
\(\\ \rm{:}\dashrightarrow v-u=at\)
\(\\ \rm{:}\dashrightarrow 6.1-10.2=-1.77t\)
\(\\ \rm{:}\dashrightarrow -4.1=-1.77t\)
\(\\ \rm{:}\dashrightarrow t=2.32s\)
Why is there an upper limit to the mass that can be supported by electron degeneracy pressure?
Electron degeneracy pressure is a specific manifestation of the more general occurrence of quantum degeneracy pressure.
What is mass electron degeneracy pressure?Electron degeneracy pressure will halt the gravitational slump of a star if its mass is below the Chandrasekhar limit (1.44 solar masses). This is the pressure that averts a white dwarf star from collapsing. Electron degeneracy pressure occurs when electrons are squeezed into a very small volume. Since their positions are well-known, they gain a large momentum in obedience to Heisenberg's uncertainty principle. This momentum generates a pressure that is temperature-independent and can result in helium flash. in stars. Electron degeneracy occurs at a solidity of about 106 kg/m3.
So we can conclude that The electron degeneracy pressure is taken by (n.v.p) where n is the number density, and v is the mean speed of the degenerate electrons.
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A tsunami originatig near the Alaska coast had a wavelength of 470 miles and traveled 2300 miles in 5.3 h. Determine the wave’s (a) speed in miles/hour and in m/s, (b) frequency and (c) period (in seconds and in minutes).
Answer:
a) 433.96 miles/hr
193.98 m/s
b) 3899.3 Hz
c) 2.56 x 10^-4 \(s^{-1}\)
0.015 \(m^{-1}\)
Explanation:
wavelength of the tsunami = 470 miles
Distance traveled = 2300 miles
time taken to travel this distance = 5.3 h
a) wave's speed = distance/time
==> 2300/5.3 = 433.96 miles/hr
1 miles/hr = 0.447 m/s
433.96 miles/hr = 433.96 x 0.447 = 193.98 m/s
b) frequency of a wave f = speed/wavelength
for wavelength, 470 miles = 470 x 1609.34 = 756389.8 m
frequency = 756389.8/193.98 = 3899.3 Hz
c) Period T = 1/frequency
T = 1/3899.3 = 2.56 x 10^-4 \(s^{-1}\)
60 sec = 1 min
Period T in sec = 2.56 x 10^-4 x 60 = 0.015 \(m^{-1}\)
A car travels 200 km in the first 2.5 hour then stop for half hour then travels the final speed of 200 km in 2 hours find the average speed of a car
A car travels 200 km in the first 2.5 hour then stop for half hour then travels the final speed of 200 km in 2 hours. The average speed of the car is 80 km/hour.
To find the average speed of the car, we need to calculate the total distance traveled and the total time taken.
In the first 2.5 hours, the car travels 200 km.
Then, it stops for half an hour.
After that, the car travels another 200 km in 2 hours.
So the total distance traveled is 200 km + 200 km = 400 km.
The total time taken is 2.5 hours + 0.5 hours + 2 hours = 5 hours.
Therefore, the average speed of the car is:
Average speed = total distance / total time
= 400 km / 5 hours
= 80 km/hour.
So the average speed of the car is 80 km/hour.
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AKS 8a - Phenomena-Based Question: Use the data and the graph to make a claim as to which person represents each letter on the graph. In your discussion, be sure to:
explain how the data matches each line on the graph
describe, compare, and contrast the rates of speed and change in position for each person based on the documents
explain what the slope of each line helps determine
Person
Action
Distance Travelled
Time
Dad
Drives home from the grocery store
1 mile
10 minutes
Aiden
Rides his bike to a friend’s house
0.75 miles
10 minutes
Mom
Waits at the doctor’s office
0 miles
10 minutes
Alexis
Walks to her mailbox down the long driveway
0.25 miles
10 minutes
Answer: what’s the answer
Explanation:
Answer5 ms 3. A football player has a mass of 95 kg, and he is running with a velocity of 15 m/s. What is his momentum? Answer:
Answer:
1425kgm/s
Explanation:
Given parameters:
Mass = 95kg
Velocity = 15m/s
Unknown:
Momentum = ?
Solution:
The momentum of a body is the amount of motion it posses;
Momentum = mass x velocity
Insert the parameters and solve;
Momentum = 95 x 15 = 1425kgm/s
8. A 60-ks gymnast is moving with a speed of 12.0 m/s when she lands on the ground during an
event. If she bends her knees upon contact with the ground, then she will increase the time of
collision by a factor of 20 - compared to if she keeps her knees stiff. What affect does this have
upon the force and the impulse that she experiences? Mark all that apply
a. Bending her knees will make the force 20 times greater.
b. Bending her knees will make the force 20 times smaller.
c. Bending her knees will make the impulse 20 times greater.
d. Bending her knees will make the impulse 20 times smaller.
e. Bending her knees will have no effect upon the impulse she experiences.
Answer:
B. Bending her knees will make the force 20 times smaller.
Explanation:
By the Impulse Theorem, we notice that the normal force from the ground to the gymnast counteract the intial linear momentum of the gymnast during a certain time until rest is reached. The impulse (\(Imp\)), measured in newton-second, is function of initial linear momentum, measured in kilogram-meters per second, only and, hence, remains constant. That is:
\(Imp = m\cdot v\) (1)
Where:
\(m\) - Mass of the gymnast, measured in kilograms.
\(v\) - Initial speed of the gymnast, measured in meters per second.
If we know that \(m = 60\,kg\) and \(v = 20\,\frac{m}{s}\), the impulse experimented by the gymnast is:
\(Imp = (60\,kg)\cdot\left(12\,\frac{m}{s} \right)\)
\(Imp = 720\,\frac{kg\cdot m}{s}\)
If the time of collision is increased by a factor of 20 by bending her knees, then normal force from the ground on the gymnast must be decrased by a factor of 20 in order to keep the impulse constant.
Therefore, the right answer is B.
Hubble's law states that the farther away a galaxy is, the faster it moves away from us.
True or false
Answer:
Yes it is true
As the Hubble's law states that the observation in physical cosmology that galaxies are moving away from the Earth at speeds proportional to their distance.
Explanation:
Calculate the total capacitance of the three capacitors 30µF, 20µF & 12µF connected in series across a d.c. supply
Consider that three capacitors connected in series have the following total capacitance:
\(\frac{1}{C}=\frac{1}{C_1}+\frac{1}{C_2}+\frac{1}{C_3}\)where,
C1 = 30µF
C2 = 20µF
C3 = 12µF
Consider that the LCM of the three previous numbers is 60 (to sum the fractions).
Replace the previous values of the parameters into the formula for C and simplify:
\(\begin{gathered} \frac{1}{C}=\frac{1}{30}+\frac{1}{20}+\frac{1}{12} \\ \frac{1}{C}=\frac{2+3+5}{60}=\frac{10}{60}=\frac{1}{6} \\ C=6 \end{gathered}\)Hence, the total capacitance is 6µF
A skier uses a pair of poles to push himself down a ski slope. Which of the following correctly states when the skier has the most potential energy? ( HELP WILL MARK YOU AS BRAINLIEST!!)
a
when the skier is at the top of the ski slope
b
when the skier starts to travel down the slope
c
when the skier reaches the bottom of the slope
d
when the skier comes to a complete stop at the bottom of the slop
The correct statement for the skier has the most potential energy is when the skier is at the top of the ski slope. Hence, option (a) is correct.
What is Potential Energy?Potential energy is a form of energy that is stored but is dependent on the size positions of different system components. Extending or contracting a spring increases its potential energy.
A specimen has much more potential energy when it is raised above the surface of the earth than when it is brought to Earth. It can conduct more work in the raised position. Potential energy is a system property, not a feature of a single entity or particle. For example, the system made up of Earth and the raised ball has greater potential energy as they are far apart.
The potential energy at the top of the ski slope will be maximum, while the kinetic energy at the top of the ski slope will be equal to zero.
Therefore, when he was at the top of the ski slope, the potential energy will be maximum.
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If you hold a 28.02 cm² square plane mirror 40.26 cm from your eyes and can just see the full length of a 8.9 m flag pole behind you, how far are you from the pole?
ANSWER:
66.8 m
STEP-BY-STEP EXPLANATION:
Given:
Area of mirror = 28.02 cm²
We make a sketch of the situation in order to solve the problem:
We calculate the height as follows:
\(\begin{gathered} h=\sqrt{28.02}=5.3\text{ cm} \\ \\ \text{ therefore:} \\ \\ AC=\frac{5.3}{2}=2.65\text{ cm } \\ \\ \text{ For ABC:} \\ \\ \tan\theta=\frac{2.65}{40.26} \end{gathered}\)Now, we determine for AEF that it has the same angle as ABC, like this:
\(\begin{gathered} \tan\theta=\frac{EF}{EA}=\frac{\frac{890}{2}-2.65}{d} \\ \\ \text{ Therefore:} \\ \\ \frac{2.65}{40.26}=\frac{\frac{890}{2}-2.65}{d} \\ \\ \text{ we solve for d:} \\ \\ \:d=\frac{40.26}{2.65}\cdot\left(\frac{890}{2}-2.65\right)\: \\ \\ d=6720.38\text{ cm} \\ \\ d=67.2\text{ m} \\ \\ \text{ Therefore:} \\ \\ D=67.2-0.4026=66.7974\equiv66.8\text{ m} \end{gathered}\)It is located 66.8 meters from the pole
How much POWER is used in 30 seconds when you complete 150 Joules of work?
Answer:
Power of 5 watts is used
Explanation:
Mechanical Work and Power
Mechanical work is the amount of energy transferred by a force.
Being F the force vector and s the displacement vector, the work is calculated as:
\(W=\vec F\cdot \vec s\)
If both the force and displacement are parallel, then we can use the equivalent scalar formula:
W=F.s
Power is the amount of energy converted per unit of time. The SI unit of power is the watt, equal to one joule per second.
The power can be calculated as:
\(\displaystyle P=\frac {W}{t}\)
Where W is the work and t is the time.
It's required to calculate the power used in t=30 seconds when W=150 Joules of work are completed. Substitute in the formula:
\(\displaystyle P=\frac {150}{30}\)
P = 5 Watt
Power of 5 watts is used
A Measuring Cylinder liquid contains a volume of 120m³ the liquid was then poured into an empty beaker of mass 51g. The total mass was then found to be 145g .Calculate the mass of the liquid
The mass of liquid in the container is 94 grams and the density of the liquid is 0.78 grams/cm³ or 780 Kg/m³.
Given in the question
The volume of the liquid = Volume of the container
= 120 cm³
Total Mass = 145 grams
Mass of the empty Beaker = 51 grams
To find
Mass of the liquid
The density of the liquid
Now,
Total Mass = Mass of LIquid + Mass of the empty Beaker
Mass of LIquid = Total Mass - Mass of the empty Beaker
Put in the value, we get
Mass of liquid = 145 - 51 grams
Mass of liquid = 94 grams
Now, Density is the ratio of the mass of the substance and the volume, the substance occupies in the space. It is not a constant value and is variable with the variation in the temperature of the substance. Its S.I. unit is Kg/m³. B ut its other commonly used unit is gram/cm³.
The density of liquid = Mass of the liquid/ Volume of the liquid
Put in the value, we get
The density of the liquid = 94/120 grams/cm³
The density of the liquid = 0.78 grams/cm³ = 780 Kg/m³
Therefore, the mass of liquid in the container is 94 grams and the density of the liquid is 0.78 grams/cm³ or 780 Kg/m³.
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A Measuring Cylinder liquid contains a volume of 120cm³ the liquid was then poured into an empty beaker of mass 51g. The total mass was then found to be 145g . Calculate the mass of the liquid and the density of the liquid.
the mass of the velociraptor and cage together is 175 kg. What is the gravitational potential energy added when when the velociraptor and cage is lifted from the ground to a height of 9 m?
The gravitational potential energy added when the velociraptor and cage is lifted from the ground to a height of 9 m is approximately 15,998.95 joules.
What is Potential Energy?
Potential energy is a form of energy that is stored in an object due to its position or configuration in a system. It is the energy that an object has the potential to possess, or the ability to do work, as a result of its position or state.
The gravitational potential energy (GPE) added when the velociraptor and cage is lifted from the ground to a height of 9 m can be calculated using the formula:
GPE = mgh
Where m is the mass of the velociraptor and cage, g is the acceleration due to gravity (approximately 9.81 m/\(s^{2}\)), and h is the height lifted.
Given that the mass of the velociraptor and cage together is 175 kg, and the height lifted is 9 m, we can substitute these values into the formula:
GPE = mgh
GPE = (175 kg) x (9.81 m/\(s^{2}\)) x (9 m)
GPE = 15,998.95 J (joules)
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You use an electron microscope in which the matter wave associated with the electron beam has a wavelength of 0.0173 nm. What is the kinetic energy of an electron in the beam, expressed in electron volts?
Answer:
The kinetic energy of an electron in the beam is 5.04 keV.
Explanation:
We need to find the velocity of the electron by using the De Broglie wavelength:
\( \lambda = \frac{h}{mv} \)
Where:
λ: is the wavelength = 0.0173 nm
v: is the velocity
m: is the electron's mass = 9.1x10⁻³¹ kg
h: is the Planck constant = 6.62x10⁻³⁴ J.s
\( v = \frac{h}{m\lambda} = \frac{6.62 \cdot 10^{-34} J.s}{9.1 \cdot 10^{-31} kg*0.0173 \cdot 10^{-9} m} = 4.21 \cdot 10^{7} m/s \)
Now, we can find the kinetic energy:
\( E_{k} = \frac{1}{2}mv^{2} = \frac{1}{2}9.1 \cdot 10^{-31} kg*(4.21 \cdot 10^{7} m/s)^{2} = 8.06 \cdot 10^{-16} J*\frac{1 eV}{1.6 \cdot 10^{-19} J} = 5038 eV = 5.04 keV \)
Therefore, the kinetic energy of an electron in the beam is 5.04 keV.
I hope it helps you!
The momentum of a 2.5 kg hammer with a speed of 6 m/s has a downward momentum moving towards a nail. The hammer hits the nail and bounces off at 2.0 m/s and the nail is in contact with the nail for 0.002 seconds. What is the average force the nail exerts on the hammer? How could you use force vs. time to solve this problem?
The average force is equal to the area under the curve of force versus time divided by the time of contact between the hammer and the nail.
The equation can be used to determine the average force the nail applies to the hammer.
\(F = \frac{mv}{t}\), where m is the hammer's mass, v is its speed, and t is the time at which it made impact with the nail. The average force in this situation is given by:
\(F = \frac{(2.5 kg)(6 m/s - 2.0 m/s)}{(0.002 s)}\\ F= 4500 N.\)
To solve this problem using force vs. time, you would need to plot a graph of force versus time, with the time of contact between the hammer and the nail representing the x-axis and the force exerted on the hammer by the nail representing the y-axis. The force exerted on the hammer increases from 0 to 4500 N as the hammer moves from rest to its maximum velocity. The average force is equal to the area under the curve of force versus time divided by the time of contact between the hammer and the nail.
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Share an experience you've had with the bureaucracy. In thinking about that experience, how would you describe the bureaucracy? What characteristics of the bureaucracy did you observe in that experience? Please explain. (Refer to Weber's theory of bureaucracy in the module.)
Bureaucracy theory explains the basis of the systematic formation of any organization and ensures efficiency and economic effectiveness.
Bureaucracy is the theory proposed by Max Weber. It forms the ideal model for the management and administration of the organization and ensures its efficiency of organization into focus.
It includes six basic principles. They are Authority Hierarchy, Division of labor, impersonality, Career Orientation, Formal rules and regulations, and Selection process.
The characteristics of bureaucracy include: It can control and regulate the behavior of people in an organization. It is the organization that has the power to make decisions. The organizations have certain rules to follow by the people.
Bureaucracy is found in large organizations like governments and corporations. It has standardized methods, and procedures to practice. It doesn't allow any flexibility for the organization.
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A piece of wood 350 mm × 350 mm and 15 mm thick conducts heat through its thickness under steady state conditions. The rate of heat flow is measured to be 14.0 watts when the temperature difference is 28 C°. Determine the coefficient of thermal conductivity for this wood
The coefficient of thermal conductivity (k) is related to the rate of heat flow (Q), the cross-sectional area (A), the length (L), the temperature difference (ΔT), and the thermal resistance (Rth) by the following equation:
k = Q / (A * ΔT * L) = Rth * (A * ΔT)
Reorganizing this equation gives:
Rth = k / (A * ΔT)
The given information in the problem is:
Rate of heat flow (Q) = 14.0 watts
Thermal resistance (Rth) = (350 mm × 350 mm × 15 mm) / (14.0 watts) = 31.5 mm⁴/C
Temperature difference (ΔT) = 28°C
Substituting these values into the equation, we have:
k = Q / (A * ΔT) = 14.0 W / (0.35 m² * 28°C) = 1.94 W/mK
So the coefficient of thermal conductivity (k) for this wood is approximately 1.94 W/mK.