Explanation:
a 1 ( only "s"
b 2 ( "s" ,"p" )
c 3 ( "s" , "p" , "d")
d 4 ( "s", "p" , "d", "f")
e 5 ( "s", "p", "d", "f", "g")
f 6 ( "s", "p", "d", "f", "g", "h" )
The number of atoms of any element in the given chemical formula is the number that is written on the food of the symbol of that element. Therefore, sublevels are present in the principal energy levels.
What is atom?Atom is the smallest particle of any matter. Atom combines to form element and element combine to form molecule or compound.
Atom consists of electron, proton and neutron. The total mass of atom is inside the nucleus. Inside the nucleus proton and neutron is there. So calculate mass of an atom, total mass of all protons is added to the total mass of neutron. Electrons revolve around the nucleus.
principal energy levels sublevels
1 s
2 s,p
3 s,p,d
4 s,p,d,f
5 s,p,d,f,g
6 s,p,d,f,g,h
Therefore, sublevels are present in the principal energy levels.
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how many chloride ions are there in 3.00 mol of aluminum chloride?
There are 9.00 mol of chloride ions in 3.00 mol of aluminium chloride.
To determine the number of chloride ions in 3.00 mol of aluminium chloride, we must first understand the chemical formula for aluminium chloride, which is AlCl₃. This formula tells us that for every molecule of aluminium chloride, there are three chloride ions.
Therefore, to find the number of chloride ions in 3.00 mol of aluminium chloride, we simply multiply the number of moles by the number of chloride ions in each molecule:
3.00 mol × 3 chloride ions = 9.00 mol of chloride ions
So, there are 9.00 mol of chloride ions in 3.00 mol of aluminium chloride.
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Why is baking soda a necessary ingredient in some cake recipes?
A. It adds heat to the cake.
B. It causes cakes to stay flat and even.
C. It neutralizes acids.
D. It acts slowly to release acids.
Answer:
c
Explanation:
took it
Identify this parasitic organism.
Answer:
Schistosoma or blood fluke
Explanation:
Parasitic organisms are defined as the organisms that depends on other organisms body called host for their nutrition and harm the host body.
The given image is of Schistosoma that is commonly known as blood flukes. Schistosoma are flatworms which causes group of infections in humans known as schistosomiasis. Schistosoma is a water-borne parasite and found in veins near the human intestine.
Hence, the correct answer is "Schistosoma or blood fluke".
additions to the carbonyl groups of aldehydes or ketones generally consist of a. protonation of the carbonyl carbon. b. nucleophilic attack on the carbonyl group. c. protonation of the nucleophile. d. electrophilic attack on the carbonyl group.
When it comes to additions to the carbonyl groups of aldehydes or ketones, the most common mechanisms involve either protonation of the carbonyl carbon or nucleophilic attack on the carbonyl group. Protonation of the carbonyl carbon occurs when a proton is added to the carbon atom of the carbonyl group, making it more electrophilic and allowing for easier nucleophilic attack. This mechanism is often seen in acid-catalyzed reactions.
On the other hand, nucleophilic attack on the carbonyl group involves a nucleophile (an electron-rich species) attacking the carbonyl carbon, leading to the formation of a new bond and the creation of an intermediate species. This mechanism is often seen in base-catalyzed reactions.
It is important to note that both aldehydes and ketones can undergo these mechanisms, although the reactivity may differ slightly between the two. Additionally, protonation of the nucleophile and electrophilic attack on the carbonyl group are less common mechanisms in these types of reactions.
Overall, understanding these mechanisms and their differences is crucial in predicting and understanding the outcomes of various reactions involving aldehydes and ketones.
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Write the formula for sodium chloride.
Write the formula for sodium oxide.
Answer:
The formula for sodium chloride is NaCl
The formula for sodium oxide is Na2O
Explanation:
a student was given the task of titrating a 20.ml sample of 0.10mhcl(aq) with 0.10mnaoh(aq). the hcl(aq) was placed in an erlenmeyer flask along with two drops of an appropriate acid-base indicator. an equation for the reaction that occurs during the titration is given above. (a) according to the equation for the reaction, if the number of moles of reactants is halved, how does this affect the number of moles of h2o(l) produced in the reaction?
According to the equation for the reaction, if the number of moles of reactants is halved, the number of moles of H₂O (l) produced in the reaction is halved as well.
What is a titration?A titration is a procedure in volumetric analysis in which a given volume of a solution of a known concentration is added to a given volume of a solution of an unknown concentration to determine the unknown concentration.
The moles of the substances that reacted as given in the equation of the reaction are used to determine the unknown concentration.
The equation of the given reaction is given below:
HCl + NaOH ---> NaCl + H₂O
1 mole of HCl reacts with 1 mole of NaOH to form 1 mole of water.
Hence, halving the moles of reactants would halve the mole of water formed.
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Which of the following happens to the particles when the temperature of liquid water drops?
kinetic energy decreases
kinetic energy increases and then decreases
kinetic energy increases
kinetic energy stays constant
Answer:
The Kinetic energy decreases
Explanation:
because the speed of the molecules slows down.
Describe the proper handling of explosive materials to prevent
initial combustion that leads to explosion?
Explosive materials need to be handled carefully and stored appropriately to avoid the possibility of initial combustion. The following are some of the precautions to take when handling explosive materials: Avoid any type of friction, impact, or shock, whether small or large, when handling explosive materials.
Keep the containers of explosive materials tightly sealed to prevent the infiltration of moisture or contaminants. Store the explosives in a cool, dry, and well-ventilated environment, keeping them away from any heat sources or flammable materials. Keep the explosives away from direct sunlight to prevent the heat from building up and causing an explosion.
In conclusion, explosive materials should be handled and stored with care to prevent initial combustion, which may lead to an explosion. Explosives should be stored in a dry, cool, and well-ventilated area, and containers should be kept tightly sealed to prevent moisture or contaminants from entering. Explosives should also be kept away from any heat sources or flammable materials.
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Which of the following is the best definition of a physical property?
A. Something that can be observed or measured while changing the identity of the substance.
B. Tearing paper in half.
C. Something that can be observed or measured without changing the identity of the substance.
D. The ability of something to undergo a change or reaction.
Answer:
The answer is either A or C figure it out sorry
The answer is A) Something that can be observed or measured while changing the identity of the substance. C) Something that can be observed or measured without changing the identity of the substance.
What's a physical property and examples?A physical asset is a function of count that isn't associated with a change in its chemical composition. Familiar examples of bodily homes consist of density, coloration, hardness, melting and boiling factors, and electric conductivity.
Physical homes are those popular properties you word maximum readily approximately a substance, including its length, state of being counted (stable, liquid, or gas), color, mass, density, and power. Values for physical residences can be determined via tests that do not modify the substance being tested.
The definition of bodily is matters which are of nature or of the frame. An example of physical is plantlife developing in the ground. An example of physical is a person constrained to a wheelchair because of disabilities. A bodily exam.
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a study was conducted to see if increasing thesubstrate concentration has an appreciable effect onthe velocity of a chemical reaction. with a substrateconcentration of 1.5 moles per liter, the reaction wasrun 15 times, with an average velocity of 7.5 micro-moles per 30 minutes and a standard deviation of 1.5.with a substrate concentration of 2.0 moles per liter,12 runs were made, yielding an average velocity of 8.8micromoles per 30 minutes and a sample standard de-viation of 1.2. is there any reason to believe that thisincrease in substrate concentration causes an increasein the mean velocity of the reaction of more than 0.5micromole per 30 minutes? use a 0.01 level of signifi-cance and assume the populations to be approximatelynormally distributed with equal variances.
we have reason to believe that increasing the substrate concentration causes an increase in the mean velocity of the reaction by more than 0.5 micromole per 30 minutes.
Our null hypothesis is that the mean velocity is the same for both substrate concentrations, and the alternative hypothesis is that the mean velocity for the higher concentration is greater than the mean velocity for the lower concentration by more than 0.5 micromole per 30 minutes.
Using the given data, we can calculate the pooled standard deviation as 1.37\((sqrt(((15-1)(1.5^2) + (12-1)(1.2^2))/(15+12-2)))\). The t-test statistic is then calculated as (8.8-7.5-0.5)/(1.37*sqrt(1/15+1/12)) = 3.01.
Looking up the critical value for a two-tailed test with 0.01 level of significance and 25 degrees of freedom (the total sample size minus 2), we get 2.492. Since our calculated t-statistic (3.01) is greater than the critical value (2.492), we can reject the null hypothesis and conclude that there is a significant difference in mean velocity between the two substrate concentrations at the 0.01 level of significance.
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Using a t-distribution table or calculator, we find the critical t-value to be 2.63.
sp = √(((n1-1)*s1² + (n2-1)*s2²) / (n1+n2-2))
Using the given data, we have:
sp = √((15-1)*1.5² + (12-1)*1.2²) / (15+12-2)) = 1.394
Next, we calculate the t-statistic using the formula:
Using the given data, we have:
t = (8.8 - 7.5 - 0.5) / (1.394 * √t(1/15 + 1/12)) = 2.63
Finally, we compare the calculated t-value to the critical t-value at a significance level of 0.01 and degrees of freedom equal to the sum of the sample sizes minus two (n1+n2-2).
T-distribution is a statistical concept used to estimate the uncertainty of a measurement or experiment. It is a probability distribution that arises when the population variance is unknown and must be estimated from the sample data.
The t-distribution is similar to the standard normal distribution, but with heavier tails, which means it accounts for more variability in small sample sizes. It is characterized by a parameter called the degrees of freedom (df), which is the sample size minus one. As the sample size increases, the t-distribution becomes more similar to the standard normal distribution. The t-distribution is commonly used in chemistry to calculate confidence intervals, which are ranges of values that are likely to contain the true value of a parameter with a certain level of confidence.
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questionyou heat two substances, a and b. both substances change color. when cooled, both substances return to their original colors.what most likely happened in this situation?
Two substances, a and b were heated. Both substances change color. when cooled, both substances return to their original colors.
What is a physical change and examples?Changes within the size or form of matter are examples of physical change. Physical changes include transitions from one state to a different , like from solid to liquid or liquid to gas. Cutting, bending, dissolving, freezing, boiling, and melting are a number of the processes that create physical changes.
Why it's a physical change?Physical changes occur when objects or substances undergo a change that doesn't change their chemical composition. This contrasts with the concept of chemical process in which the composition of a substance changes or one or more substances combine or break up to form new substances.
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18.) Convert 83.2 grams per milliliter (g/mL) to pounds per cubic inch (lb/in³), given that 1 lb= 453.6 g and 1 in³ = 16.37 mL.
Answer:
3.00
Explanation:
Adaptations ONLY help an organism stay alive when they are physical and NOT when they are behavioral. true or false??
Answer:
true
Explanation:
i hope it's true, if not, then it's false, if anyone else answered but got it from the link, let me know to report it or you report it
Answer:
False.
Explanation:
Hibernation is an example of a physical adaptation. False.
A materials scientist has created an alloy containing aluminum, copper, and zinc, and wants to determine the percent composition of the alloy. The scientist takes a 12.066 g sample of the alloy and reacts it with concentrated HCl. The reaction converts all of the aluminum and zine in the alloy to aluminum chloride and zine chloride in addition to producing hydrogen gas. The cpper does not react with the HCl. Upon copletion of the reaction, a total of 10.1 of hydrogen gas was collected at a pressure of 735 torr and a temperature of 27.0∘C. Additionally, 2.29g of unreacted copper is recovered. Calculate the mass of hydrogen gas formed from the reaction. mass Calculate the mass of alminum in the alloy sample. mass: What is the mass percent composition of the alloy
The mass of hydrogen gas formed from the reaction is 0.222 g. The mass of aluminum in the alloy sample is 6.68 g. The mass percent composition of the alloy is 37.94%. the mass percent composition of the alloy is 55.42% aluminum, 14.50% zinc, and 19.01% copper.
Mass of the alloy sample (m) = 12.066 g
Mass of unreacted copper = 2.29 g
Pressure of the collected hydrogen gas (P) = 735 torr
Temperature of the collected hydrogen gas (T) = 27.0∘C
= 300.15 K
The balanced chemical equation for the reaction of aluminum and zinc with HCl can be given as follows:
Al + 3HCl → AlCl3 + 3H2Zn + 2HCl → ZnCl2 + H2
We can see that 3 moles of H2 are produced per mole of aluminum reacted with HCl.
So, the moles of H2 produced due to the reaction with aluminum in the sample can be calculated as: moles of H2 produced = moles of Al in sample x 3 moles of Al in sample
= mass of sample / molar mass of Al
Molar mass of Al = 26.98 g/mol
Molar mass of Zn = 65.39 g/mol
Molar mass of H2 = 2.02 g/mol
The mass of aluminum in the sample can be calculated as follows: mass of Al in sample = (mass of sample - mass of unreacted copper) - mass of Zn Moles of H2 produced due to the reaction with aluminum can be calculated as follows: moles of H2 produced = (P V) / (n R T)Where V is the volume of the collected hydrogen gas in liters, n is the number of moles of H2 produced, R is the gas constant (0.0821 L atm mol−1 K−1), and T is the temperature of the collected gas in kelvins.
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Study the reaction and read the statement.
Xe+3F2→XeF6
The rate constant for this reaction is 0.025, and the reaction is second order in Xe and first order in F2.
What is the rate of the reaction if [Xe] is 0.25 M, and [F2] is 0.4 M?
4.0 × 10–^4
2.5 × 10–^3
1.5 × 10–^3
6.3 × 10–^4
Answer:
6.3 × 10–^4
Explanation:
Hello there!
In this case, since the rate laws are written in terms of the rate constant and the concentration of the species contributing to the rate of reaction, as this one is second order in Xe and first order in F2, the rate law would be:
\(r=k[Xe]^2[F_2]\)
Thus, by plugging in the rate constant and concentrations, we obtain:
\(r=(0.025\frac{1}{M^2*s} )(0.25M)^2(0.4M)\\\\r=6.3x10^{-4}M/s\)
Best regards!
consider the equilibrium reaction between mgo (s) and co2 (g) resulting in the formation of mgco3 (s). which one of the following factors will affect both the value of the equilibrium constant and the position of equilibrium? (you may need to write the balanced chemical equation)
Magnesium carbonate breaks down into solid magnesium (MgO) & gaseous carbon dioxide in the aforementioned mechanism, which is a chemical property (CO2).
A fundamental chemical equation is what?In these equations, chemical reactions are represented by chemical formulae and symbols. Chemical equations have two sides: the reactants are on the left, and the products are on the right.
What is an illustration of a chemical equation?Chemical equations represent the transformation of reactants into products in this process. Take the combination of iron (Fe) with sulfur (S) to create iron sulfide as an example. Fe(s) = S(s) + FeS (s) Iron and sulfur react, as indicated by the plus symbol.
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Consider the reaction below.
H₂PO4+H₂O → H3O+ + HPO4²-
Which of the following is a base-conjugate acid pair?
OH₂O and H3O+
OH₂O and H₂PO4
OH₂PO4 and HPO4²-
OH₂PO4 and H3O+
The strong acid and strong base has high rate constant of dessociation. Weak acid and base are the one whose rate constant for the dissociation is low, they do not dissociate readily in water. Therefore, the correct option is option A.
What are acid and base?Acid is a solution which releases H⁺ hydrogen ion when dissolved in water. Base are the solution which releases hydroxide ion OH⁻ ion when dissolved in water.
The balanced equation is
H₂PO\(_4\)+H₂O → H\(_3\)O+ + HPO\(_4\)²-
H₂PO\(_4\) is a acid and if we remove one hydrogen ion from this then we get an anion called conjugate base. The pair is called acid base conjugate pair. H₂O is acid over here and if we give one hydrogen ion to this then the cation that we will get is called conjugate acid. The pair is called base conjugate acid pair.
Therefore, the correct option is option A.
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is calcium a metal? yes or no answer please
for the reaction 2ch4 (g) 3 cl2 (g) → 2 chcl3 (l) 3 h2 (g), δh° = -118.6 kj. δh°f = -134.1 kj/mol for chcl3 (l). find δh°f for ch4 (g).
For the reaction 2CH₄ (g) 3 Cl₂ (g) → 2 ChCl₃ (l) 3 H₂ (g), ΔH° = -118.6 kj. ΔH°f = -134.1 kj/mol for ChCl₃ is 29.65 KJ and CH₄ is 58.5 KJ by using Hess law.
The enthalpy change for a reaction can be related to the enthalpy of formation values for the compounds involved. In this case, we are given the enthalpy change (ΔH°) for the reaction and the enthalpy of formation (ΔH°f) for ChCl₃ (l). We need to calculate the ΔH°f for CH₄ (g).
The balanced equation for the reaction shows that 2 moles of Hess law CH₄ (g) are consumed to form 2 moles of ChCl₃ (l). Therefore, the enthalpy change for the formation of 2 moles of ChCl₃ (l) can be related to the enthalpy change for the formation of 2 moles of CH4 (g).
ΔH°f of ChCl₃= 58.5 KJ
Using the given values, we can set up a proportion to solve for ΔH°f of CH₄ (g). Since the enthalpy change is given as ΔH° = -118.6 kJ, and the enthalpy of formation for ChCl₃ (l) is given as ΔH°f = -134.1 kJ/mol, we can write the proportion:
(-118.6 kJ) / (2 mol) = ΔH°f / (2 mol)
Simplifying the equation, we can solve for ΔH°f of CH₄(g).
ΔH°f=29.65 KJ
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wafting the air above a chemical is one way to it directly
Answer:
Explanation:
All it takes is a momentary lapse in concentration. When you are in the laboratory and take a direct sniff of the chemicals you are using, you run the risk of damaging your mucous membranes or your lungs.
As the temperature of air is reduced to its dew point, which of these is most likely to occur? group of answer choices freezing condensation melting supercooling evaporation
Condensation is also more likely to occur when the temperature drops to the dew point.
What is condensation?Condensation is the process of turning a gas or vapor into a liquid. This happens when gas molecules come into contact with a cold surface and attract each other, creating tiny droplets of liquid. In nature, condensation is observed when water vapor in the air forms clouds and then rains. It can also be seen when water vapor from boiling water or steam forms droplets on the outside of a cold glass or spoon. Condensation is an important process in the water cycle and essential for fresh water production.
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What is the IUPAC name of the compound shown here?
Answer:
2-methylpropanoic acid
Explanation:
no probs chief
krypton has a completely blank p sublevel, giving it chemical stability. bromine needs one electron to achieve a completely filled p sublevel and thus has a highly blank electron affinity. therefore, it easily takes on an electron and is reduced to the bromide ion, giving it the added stability of the filled p sublevel.
Bromine is more reactive than krypton because of its electronic configuration. Bromine is a member of the halogen family, meaning it has seven valence electrons in its outermost shell. This makes bromine more reactive than krypton, which has eight valence electrons in its outermost shell.
Bromine has a higher reactivity because it is more willing to accept electrons, which allows it to form bonds with other elements more easily.
This is due to the fact that bromine has the ability to form a stable octet of electrons in its outermost shell by gaining one more electron as its valence shell has 4s²4p⁵.
On the other hand, krypton has a full outer shell of eight electrons 4s²4p⁶, and it is not as willing to accept additional electrons, making it less reactive. Therefore, bromine is more reactive than krypton in the periodic table.
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Lanthanum emits gamma radiation with a wavelength of 1.24 x 10-31 meters. How
much energy is in this gamma ray?
Answer:
e = 1.60x10⁶J
Explanation:
It is possible to find the energy from the wavelength of the radiation as follows:
e = c*h / λ
Where e is energy in joules
c is light velocity (3.0x10⁸m/s)
h is Planck's constant (6.626x10⁻³⁴Js)
And λ is wavelength in meters (1.24x10⁻³¹m)
e = 3.0x10⁸m/s*6.626x10⁻³⁴Js / 1.24x10⁻³¹m
e = 1.60x10⁶J
The density of chlorine gas at 1.21 atm and 34.9 °C is g/L. Select one: a. 0.0479 b. 0.423
c. 3.39 d. 1.70 e. 0.295
The density of chlorine gas at 1.21 atm and 34.9 °C is 3.39 g/L.
To calculate the density, we can use the ideal gas law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.
First, we need to convert the given temperature from Celsius to Kelvin by adding 273.15:
34.9 °C + 273.15 = 308.05 K
Next, we can rearrange the ideal gas law equation to solve for density (d = mass/volume). Since we are given the pressure and temperature, we can assume a fixed volume of 1 liter.
Using the molar mass of chlorine gas (Cl2) as approximately 70.906 g/mol, we can calculate the number of moles (n) as follows:
n = (PV) / (RT)
= (1.21 atm * 1 L) / (0.0821 atm·L/mol·K * 308.05 K)
≈ 0.048 mol
Finally, we can calculate the density:
density = mass / volume
= (0.048 mol * 70.906 g/mol) / 1 L
≈ 3.39 g/L
Therefore, the correct answer is c. 3.39.
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Identify two issues that can arise when measuring heat changes for a chemical reaction using a calorimeter.
Long-term heat loss to the calorimeter is a problem, especially for slow-moving processes.
How does a calorimeter work as a heat meter?The water iscontained in a tank whose thermal capacity and weight were predete partially rmined before the experiment began. Calculating heat and flow rates involves measuring the rise in water temperature and volume over a predetermined period of time.
What takes place when a calorimeter absorbs heat?In contrast, if the reaction absorbs heat, heat is transmitted from the calorimeter to the system, lowering the calorimeter's temperature.
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Not every earthquake has a(n) ______, but every earthquake has _____that occur in _____ the mainshock.
1.
Aftershock
Foreshock <------
2.
Aftershock <-------
Foreshock
3.
Places far away from
The Same place as <------
Am i right?
Not every earthquake has a(n) Foreshock, but every earthquake has an Aftershock that occurs in the Same place as the mainshock.
What is an earthquake?
An earthquake is defined as a natural disaster in which there are tectonic plates that are present on the earth's crust collides with each other.
An Earthquake can be minor as well as natural depending upon the frequency it causes the damage. Earthquake is the Shaking of Earth and was much destruction of the economy and manpower.
Surroundings are being disturbed like trees will fall, and buildings will collapse which will cause damage to the economy as well as to human life.
Foreshock is the before shop which happens before the earthquake and aftershock is the other socks that happen after the earthquake
Thus, the correct options are 1. Foreshock, 2. Aftershock, 3. The Same place as.
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Which statement is true regarding a chemical reaction?(1 point)
Responses
The total number of atoms does not change, so mass is conserved in the reaction.
The total number of atoms does not change, so mass is conserved in the reaction.
Even if the total number of atoms does not change, mass may not be conserved in the reaction.
Even if the total number of atoms does not change, mass may not be conserved in the reaction.
The total number of atoms changes, so mass is conserved in the reaction.
The total number of atoms changes, so mass is conserved in the reaction.
Even if the total number of atoms changes, mass may not be conserved in the reaction.
According to the law of conservation of mass,the total number of atoms does not change and so mass is conserved in the reaction.
What is law of conservation of mass?According to law of conservation of mass, it is evident that mass is neither created nor destroyed rather it is restored at the end of a chemical reaction .
Law of conservation of mass and energy are related as mass and energy are directly proportional which is indicated by the equation E=mc².Concept of conservation of mass is widely used in field of chemistry, fluid dynamics.
Law needs to be modified in accordance with laws of quantum mechanics under the principle of mass and energy equivalence.This law was proposed by Antoine Lavoisier in the year 1789.
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"The Law of Conservation of Mass and Energy ("matter can neither be created nor destroyed") clearly states that a chemical change cannot alter the number of atoms in a given reaction. The atoms can only rearrange so that it can yield a new molecule/compound but the number of atoms should stay the same."
Credit to where I found the information: Socratic Q&A
so the total number of atoms does not change.
Label the different parts of the atom.
Answer:(a) electrons
(b) nucleus
(c) protons
(d) neutrons
(e) mass number
Explanation:
consider a half life of 5.3years for co-60. exactly 15.9 years ago you start with a co-60 sample with an initial decay rate of 15 mu c i. what is the strength of the source now? hint:
The strength of the Co-60 source now is approximately 2.64 microcuries.
The decay rate or activity (A) of a radioactive substance is given by the equation;
A = λN
where λ is the decay constant, and N is the number of radioactive atoms present.
The decay constant will be related to the half-life (\(t_{1/2}\)) by the equation:
λ = ln(2) / \(t_{1/2}\)
Substituting the given half-life of Co-60, we have;
λ = ln(2) / 5.3 years
λ ≈ 0.1313 years⁻¹
15.9 years have passed since the initial measurement, so the fraction of the original radioactive atoms remaining (R) is given by:
R =\(e^{(-λt)}\) = \(e^{(-0.1313X15.9)}\)
≈ 0.176
The current activity of the sample can be calculated by multiplying the initial activity (A0) by the fraction of remaining radioactive atoms:
A = A0 x R = 15 mu Ci x 0.176
≈ 2.64 mu Ci
Therefore, the strength of the source is 2.64 microcuries.
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