1. How did the rock of the Great Plains and Rocky Mountains form?

Choose the claim you can eliminate.

Responses

They formed as one rock formation, and then something separated them.
They formed as one rock formation, and then something separated them.

One rock formation formed before the other. Then, the minerals from the older rock became part of the younger rock.
One rock formation formed before the other. Then, the minerals from the older rock became part of the younger rock.
What do we still need to know in order to determine why the two rock formations have such similar minerals?
w
Evidence Card E: Rocky Mountains. Photo of the Rocky Mountains. Observations: The large mountains have jagged tops. The chunks of rock vary in size. The rock appears to be light and dark gray. There is a forest at base of the mountains.
Evidence Card C: Rock from the Rocky Mountains. Photo of a rose-colored rock with dark veins. Observations: The rock contains visible pink, dark gray, and light brown grains. The grains fit together. The grains have sharp edges. There are no bubbles or fossils in this sample.
Why can we eliminate the claim you selected?

Answers

Answer 1

Rock from the Great Plains and the Rocky Mountains combined to form a single rock formation, which was later destroyed. The first allegation is accurate, but the second one should be dropped.

How are rocky mountains formed?The Rocky Mountains and the Great Plains are two distinct rock formations that did not originate concurrently, and this should be kept in mind. As a result, the minerals from the older rock were not absorbed into the younger rock.There was a formation made of rock from the Great Plains and the Rocky Mountains, but something tore it apart. The second claim must thus be disregarded because it is untrue.

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Related Questions

Choose whether the statements below are true or false

Choose whether the statements below are true or false

Answers

Answer:

1. false 2.true 3. true

Explanation:

there was more scientific method and more ways to solve

the hypothesis show the experiment design  

Dylan has two cubes of iron. The larger cube has twice the mass of the smaller cube. He measures the smaller cube. Its mass is 20 grams, and its density is 7.87 g/cm3. What’s the larger cube’s volume? The larger cube’s volume is about cm3.

Answers

Answer:

5.08cm³

Explanation:

Given parameters

The larger cube has twice the mass of the smaller cube

Mass of smaller cube = 20g

Mass of the larger cube = 2 x 20  = 40g

Density of the smaller cube  = 7.87g/cm³

Unknown:

Volume of the larger cube = ?

Solution:

Density is the mass per unit volume of substance. For all samples of a substance, the density value is the same.

So, the density of the small and large iron is the same

   Density  = \(\frac{mass}{volume}\)  

        Volume  = \(\frac{mass}{density}\)  

 So;

  Volume of larger cube  = \(\frac{40}{7.87}\)  = 5.08cm³

Answer:

5.08cm^3

Explanation:

Write 3.5 x 105 in standard form.

Answers

367.5

sorry if this is wrong

a body collides with an identical body that is initially at rest. after the collision, they stick together. what is the percentage of kinetic energy that has been transferred to other forms of energy in the collision?

Answers

In a perfectly inelastic collision, where the two bodies stick together after the collision, the percentage of kinetic energy transferred to other forms of energy is 100%.

How does the mass and velocity of the colliding bodies affect the amount of kinetic energy transferred to other forms of energy?

The mass and velocity of the colliding bodies have a direct relationship with the amount of kinetic energy transferred to other forms of energy. A higher mass will result in a larger amount of kinetic energy being transferred, as more force is required to bring the two bodies to a stop. Similarly, a higher velocity will result in a greater amount of kinetic energy being transferred, as the bodies have more kinetic energy to lose during the collision. Both mass and velocity contribute to the total kinetic energy of the colliding bodies and therefore the amount of kinetic energy that will be transferred to other forms of energy in the collision.

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1. Describe the difference between photographic plates and
charge-coupled devices?
2. Explain the importance of the Hubble Space Telescope
(HST).

Answers

Photographic plates and charge-coupled devices (CCDs) are two different technologies used for capturing images in astronomy.

Photographic plates are glass or plastic sheets coated with light-sensitive chemicals. They were widely used before the advent of digital imaging. When exposed to light, the chemicals on the plate undergo a chemical reaction, producing a latent image.

The plate needs to be chemically developed to make the image visible. Photographic plates have a long history in astronomy and were the primary method of image capture for many decades.

On the other hand, charge-coupled devices (CCDs) are electronic sensors used in digital imaging. They consist of an array of tiny light-sensitive pixels that convert incoming light into electrical charge. The charge is then read out and converted into digital data.

CCDs offer several advantages over photographic plates, including higher sensitivity, wider dynamic range, faster data acquisition, and the ability to store and transmit images digitally. These characteristics make CCDs more efficient and practical for modern astronomical observations.

The Hubble Space Telescope (HST) holds tremendous importance in the field of astronomy. Launched in 1990, the HST has provided unprecedented views of the universe, free from the distortions caused by Earth's atmosphere. Its location above the atmosphere allows it to observe celestial objects with exceptional clarity and detail.

The HST has made numerous groundbreaking discoveries, including precise measurements of the expansion rate of the universe, the detection of planets around other stars, and the identification of distant galaxies that formed shortly after the Big Bang.

Moreover, the HST has revolutionized our understanding of the cosmos through its stunning images, capturing the beauty and complexity of celestial objects like galaxies, nebulas, and star clusters. It has enabled scientists to study the life cycles of stars, investigate the properties of black holes, and explore the mysteries of dark matter and dark energy.

The HST's contributions to astronomy have shaped our knowledge of the universe and inspired generations of scientists and the general public alike. Its observations continue to push the boundaries of our understanding and pave the way for future space telescopes and missions.

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An illustration of a ball sitting at the top of a hill of height labeled h Subscript 1 Baseline = 2 m. A the the bottom of the hill it levels off and the leveled surface is at a height labeled h Subscript 2 Baseline = .5 m. A ball is released from the top of a hill. How fast is the ball going when it reaches the base of the hill? Approximate g as 10 m/s2 and round the answer to the nearest tenth. m/s

Answers

Answer:

5.5 m/s

Explanation:

Right on Edge

The statement explains the importance of enzymes that check for and repair mistakes during DNA replication is the enzymes prevent many genetic mutations from being expressed. Thus, the option C is correct.

What is RNA polymerase?

RNA polymerase is an enzyme that aids in the transcription of DNA into RNA during transcript in the nucleus. The enzymes prevent many genetic mutations from being expressed.

Primase is an enzyme that synthesizes short RNA sequences called primers. These primers serve as a starting point for DNA synthesis during replication as the DNA polymerases cannot begin the synthesis of the new strand, they only extend it after primase begins it and primase produces RNA molecules, the enzyme can be said to be a type of RNA polymerase.

Therefore, The statement explains the importance of enzymes that check for and repair mistakes during DNA replication is the enzymes prevent many genetic mutations from being expressed. Thus, the option C is correct.

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an electrically charged object can be used to attract:

Answers

An electrically charged object can be used to attract any object with an opposite charge.

This is due to the fundamental principle that opposites attract and repel in physics.

Electric charge is a fundamental property of matter that gives rise to electromagnetic interactions. An electric charge, whether positive or negative, produces an electric field that surrounds it. This field exerts a force on any other charge in its vicinity that is either attracted to or repelled from it. Electric charge is a fundamental property of matter that produces a variety of electric phenomena. When the charge is concentrated in a localized region of space, the object is electrically charged. When there is a net accumulation of charge in an object, it becomes electrically charged. An electrically charged object produces an electric field in its vicinity, which exerts a force on other charged objects. An electrically charged object can be used to attract objects with an opposite charge or repel objects with the same charge.

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To add to the complexity, those precious atoms face the peril of disintegrating into the void. Luckily, by now, they are feeling the influence of gravity to bring them safely together. Based on this sentence, the reader can infer that — A There was no gravity at the time of the Big Bang. B The most basic atoms were formed due to the force of gravity. C Gravity developed right after the first atoms fell apart. D The force of gravity helped collapse the newly created atoms.

Answers

Answer:

B The most basic atoms were formed due to the force of gravity.

Explanation:

Since the statement says that the atoms could have faced the peril of disintegrating into the void, this means that, they could have been destroyed by movement away into the void.

But, it also says that by now, they are feeling the influence of gravity to bring them safely together. This statement shows that gravity brings them (the atoms) together and thus doesn't allow them disintegrate into the void.

So, a reader can thus infer that the most basic atoms were formed due to the force of gravity since it doesn't allow the atoms disintegrate into the void.

So, B is the answer.

A solid block of volume 6.0m^3 is placed under water whose density is 1000 kgm^3 (g=10Nkg^1)

a) what volume of water does the block displace?

b) What mass of water does the block displace?

c) what is the weight of the displaced Water?

d) How large is the upthrust which acts on the block ?

e) What will happen if the block is made ofwood of density 700kgm^3?

f) What will happen if the block is made of rock of density 3000kgm^3?​

Answers

f is the right answer i think

Please Help Quick ASAP Hurry This is Physical Science
Which statements best describe magnetic fields?
A. Magnetic fields need a conductor.
B. Magnetic fields must have only positive charges.
C. Magnetic fields have north and south magnetic poles.
D. Magnetic fields are always found in insulators.

Answers

Answer:

Think it is C

Explanation:

Not sure!!!

Please help! Will mark brainliest

Please help! Will mark brainliest

Answers

Answer:

Runner B

Explanation:

its just displacement over change in time

Runner A’s velocity is 0.109
Runner B’s velocity is 0.116
We find this by dividing distance over time. So runner B has a higher velocity.
Pls give me brainliest.

which trophic level has the least available energy in kilojoules in this food web?

Answers

The highest trophic level has the least available energy in kilojoules.

Even though the food web is not shown in the question, but we know that energy decreases steadily as it is passed on from one trophic level to the next according to the second law of thermodynamics.

Energy enters into the system from the sun. The primary producers utilize this energy to produce food. As plants are eaten by animals, this energy is transferred along the food web an diminishes at each higher trophic level.

At the highest trophic level, the the least available energy in kilojoules in this food web is found.

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A chemical reaction is the only way to an

A: Element

B: Pure Substance

C: Mixture

D: Solution

Answers

Answer:

B: Pure Substance

Explanation:

For what angle of incidence at the first mirror will this ray strike the midpoint of the second mirror (which is s = 28.8 cm long) after reflecting from the first mirror?

Answers

The angle of incidence at the first mirror will this ray strike the midpoint of the second mirror is 34.6°

Two plane mirrors intersect at right angles. A laser beam strikes the first of them at a point d = 10.0cm from their point of intersection.

To strike the midpoint of the second mirror, the ray of light will have to travel half of the distance vertically

i.e. 29/2 = 14.5

We can solve this through trigonometry.

Let the angle between the ray and the vertical plane mirror is known as α

tan α = 10/14.5

α =  = 34.6°

The angle of incidence is the angle between the ray and the normal line of the mirror.

Let the angle of incidence of the first mirror be β

β = α = 34.6

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Which potatoes when peeled produce the most peelings?
A. 10 kg of large potatoes
B. 10 kg of small potatoes
C. They both produce the same amount

Answers

Assuming that both types of potatoes have the same skin-to-flesh ratio, 10 kg of small potatoes would produce more peelings than 10 kg of large potatoes.

This is because small potatoes have a higher surface area-to-volume ratio than large potatoes, so there is more skin per unit weight. As a result, more peelings would be produced when peeling small potatoes compared to large potatoes.

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a diagnostic ultrasound echo is reflected from moving blood and returns with a frequency 500 hz higher than its original 2 mhz. what is the velocity of the blood? assume that the frequency of 2 mhz is accurate to seven significant figures and 500 hz is accurate to three significant figures.

Answers

The velocity of the blood is 0.1925 m/s.

When blood flows back and forward, and creates a different frequency on the diagnostic ultrasound echo, the blood flow creates a doppler effect on the device. The formula

f₂ = f₁ × ((v ± vb) ÷ (v ± vb'))

f₁ = the frequency from the source
f₁ = 2 MHz = 2,000,000 Hzf₂ = the frequency on the device
f₂ = 2 MHz + 500 Hz = 2,000,000 + 500
f₂ = 2,000,500 Hzv = the velocity of sound waves
v = 1,540 m/svb = the velocity of the blood moving forwardvb' = the velocity of the blood moving backward

The velocity of the blood is the same but in a different direction.

vb = vb vb' = - vb

f₂ = f₁ × ((v ± vb) ÷ (v ± vb'))

2,000,500 = 2,000,000 × ((1,540 + vb) ÷ (1,540 - vb))

2,000,500 ÷ 2,000,000 = ((1,540 + vb) ÷ (1,540 - vb))

1.00025 = ((1,540 + vb) ÷ (1,540 - vb))

1.00025 (1,540 - vb) =  1,540 + vb

1,540.385 - 1.00025vb = 1,540 + vb

1,540.385 - 1,540 = vb + 1.00025vb

0.385 = 2.00025vb

vb = 0.385 ÷ 2.00025

vb = 0.1925 m/s

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An ice maker operating at steady state makes ice from liquid water at 32oF. Assume that 144 Btu/lb of energy must be removed by heat transfer to freeze water at 32oF and that the surroundings are at 78oF.
The ice maker consumes 1.4 kW of power.
​ ​Determine the maximum rate that ice can be produced, in lb/h, and the corresponding rate of heat rejection to the surroundings, in Btu/h.
6.A:
The maximum rate of cooling depends on whether the ice maker:
Option A: operates reversibly.
Option B: uses the proper cycle.
Option C: uses the correct refrigerant.
Option D: operates at constant temperature.
The energy rate balance for steady state operation of the ice maker reduces to:
Option A:
Option B:
Option C:
Option D:
Determine the maximum theoretical rate that ice can be produced, in lb/h.
Option A: 521
Option B: 0.104
Option C: 23.1
Option D: 355
Determine the rate of heat rejection to the surroundings, in Btu/h, for the case of maximum theoretical ice production.
Option A: 8102
Option B: 4.63x104
Option C: 5.59x104
Option D: 16.4

Answers

The maximum rate that ice can be produced in lb/h and the corresponding rate of heat rejection to the surroundings, in Btu/h is obtained as follows; Option D: operates at constant temperature.

The energy rate balance for the steady-state operation of the ice maker reduces to;

P = Q + WWhere;

P = Rate of energy consumption by the ice maker = 1.4 kWQ = Rate of heat transfer to freeze water from 32°F to ice at 32°F (heat of fusion), Q = 144 Btu/lbm.

W = Rate of work done in the process, work done by the compressor is assumed negligible.

Hence; P = Q / COP, where COP is the coefficient of performance for the refrigeration cycle.

Thus; COP = Q / PP = 144 / 3412COP = 0.0421

Using the COP value to determine the rate of energy transfer from the refrigeration system; P = Q / COPQ = P × COPQ = 1.4 × 0.0421Q = 0.059 Btu/or = 0.059 x 3600 Btu/HQ = 211 Btu/therefore, the maximum rate of ice production, w, is;w = Q / h_fw = 211 / 1440w = 0.146 lbm/sorw = 0.146 x 3600 lbm/hw = 527 lbm/h

The corresponding rate of heat rejection to the surroundings is;Q_rejected = P - Q orQ_rejected = 1.4 - 0.059orQ_rejected = 1.34 kWorQ_rejected = 4570.4 Btu/h

Therefore, the maximum rate of ice production is 527 lbm/h and the corresponding rate of heat rejection to the surroundings is 4570.4 Btu/h.

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Bumper car A (281 kg) moving +2.82 m/s makes an elastic collision with bumper car B (209 kg) moving +1.72 m/s. What is the velocity of car B after the collision?

Answers

The velocity of car B after the calculation can be obtained as 5.5 m/s.

What is a collision?

We have to look at the principle of the conservation of the linear momentum and that is what we need so as to be able to deal with the problem that we have in this question as we have it here.

We know that the total momentum of the system would have to be constant and the implication of this is that the momentum before collision must be the same as the momentum after collision if we have been able to designate the system as a closed system.

Using the formula as we have shown it, we know that;

Momentum before Collison must be equal to momentum after collision

As such we have the following as shown below;

(281 * 2.82) + (209 * 1.72) = (281 * 0) + (209 * v)

792.42 + 359.48 = 209 v

v = 5.5 m/s

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500 cm³ of water at 100°C is added to another 500 cm³ of water at a temperature of 30°C. Assuming no heat is lost to the surrounding, what is the final temperature of the mixture when thermal equilibrium is achieved?​

Answers

Answer: 35 degree Celsius

Explanation: Subtract both the temperatures And divide by two.

Which of these is a transverse wave? Help pls

Which of these is a transverse wave? Help pls

Answers

Answer:

Option 1

Explanation:

1st option is the correct answer......

The correct answer is option 1.

Which type of border shows the division between Sonora and Chihuahua?

National border
State border
Physical boundary
Natural boundary

Answers

The answer is the national border

at a rock concert, the sound intensity 1.0 m in front of the bank of loudspeakers is 0.10 w/m2. a fan is 30 m from the loudspeakers. her eardrums have a diameter of 8.4 mm.

Answers

By taking the product of intensity and area, the energy is transferred to each ear drum. The energy reached per second is ∅= tan⁻¹\(({\frac{FX}{FC})\)

Sound energy :

The energy transferred to each eardrum in 1 second is related to the sound intensity and the area of the eardrum. At a distance of 30 m from the loudspeakers, the sound intensity is 0.0011 W/m² as we calculated before.

The area of an eardrum with a diameter of 8.4 mm is:

  A = (π/4) × (8.4 mm/2)² = 21.5 mm²

The energy transferred to each eardrum in 1 second is:

E = I × A × t = (0.0011 W/m²) × (21.5 mm²) × (1 s)

                          = 0.023 J/ear

So the energy transferred to each eardrum in 1 second is 0.023 J.

What is Energy?

Energy is the ability to do work. It can take many forms, such as thermal energy, kinetic energy, potential energy, chemical energy, and more. Energy can be converted from one form to another, but the total amount of energy in a closed system remains constant (the law of conservation of energy). The unit of energy is the joule (J).

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Select the correct answer. if you have a heat engine with a hot reservoir of 515 k and a cold reservoir of 190 k, what is the maximum possible thermal efficiency of the system?
a. 63.1%
b. 75.2%
c. 52.1%
d. 67.9%

Answers

The maximum possible thermal efficiency of the system is d. 67.9%.

By utilizing the physics of heat engines and Second Law of Thermodynamics, we can calculate that the maximum achievable efficiency of a heat engine with a hot reservoir at 515 k and a cold reservoir at 190 k is 67.9%.

This result serves as an upper limit for all practical engines, regardless of the specifics of their design or engineering capabilities.

Making this maximum efficiency is possible through improvements in technology and increased knowledge on thermodynamics and energy production.

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Answer: A.

63.1%

Explanation: edmentum

Select the correct answer. if you have a heat engine with a hot reservoir of 515 k and a cold reservoir

a measurement was made of the magnetic field due to a tornado, and the result was 15.50 nt to the north. the measurement was made at a position 8.70 km west of the tornado. what was the magnitude (in a) and direction of the current in the funnel of the tornado? assume the vortex was a long, straight wire carrying a current.

Answers

674.25 A current is flowing along the funnel of tornado.

Explain magnetic field around a current carrying straight wire?

All known magnetic fields are due to current charges (or charges in motion). A wire carrying current produces a magnetic field due to the movement of charges within the conductor. Magnetic field lines around a long wire carrying current form concentric circles around the wire.

Assuming the vortex was a long, straight wire carrying a current,

Magnetic field (B) = 1.55 × 10⁻⁸ T

Radius of tornado (R) = 8700 m

Current in the funnel (I) = ?

For a current carrying straight conductor:

∫BΔL = μ₀I

B(2πr) = μ₀I

I = B(2πr)/μ₀

μ₀ = 4π × 10⁻⁷ H/m

I = 1.55 × 10⁻⁸ (2×3.14×8700)/4π × 10⁻⁷

I = 674.25 A

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can someone help with thsi? i will give brainliest

can someone help with thsi? i will give brainliest

Answers

Answer:

40 meters. look for the dot above the 20 on the x-axis and follow it over to the left.

Explanation:

Aluminum is often melted down for recycling purposes. Assuming 1 kg of aluminum is at room temperature, what is the minimum amount of heat needed to melt it to a liquid? The specific heat capacity of aluminum is 899 J/kg°C, the melting point is 660°C, and the latent heat of fusion is 3.97 x 105 J/kg.
60 points

Answers

The minimum amount of heat needed to melt it to a liquid will be 569.067 kJ.

What is enthalpy of fusion?

The minimum amount of heat needed to melt it to a liquid is known as the enthalpy of fusion.

The formula for the enthalpy of the fusion is;

\(\rm L_f=Q/m \\\\ L_f=mCdt/m \\\\ L_f= Cdt \\\\ L_f= 899 J/kg^0C \times (660^0-27^0) \\\\ L_f= 569,067 \ J \\\\\ L_f=569.067 \ kJ\)

Hence, the minimum amount of heat needed to melt it to a liquid will be 569.067 kJ.

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the density of mercury is 13.5 g/ml and the density of water is 1.00 g/ml . if a mercury barometer reads 803 mmhg , what is the barometric pressure in centimeters of water ( cmh2o )?

Answers

The barometric pressure in centimeters of water (cmH₂O) if a mercury barometer reads 803 mmHg and the density of mercury is 13.5 g/mL and the density of water is 1.00 g/mL is 1033.25 cmH₂O.

1. Convert 803 mmHg to cmH₂O using the conversion factor 1 mmHg = 1.36 cmH₂O.

803 mmHg × 1.36 cmH₂O/mmHg = 1092.08 cmH₂O.

2. Determine the pressure due to the mercury column using the density of mercury and the height of the mercury column. The height of the mercury column is the same as the pressure reading in mmHg.

Pressure = density × gravity × height. 13.5 g/mL × 9.81 m/s² × (803 mmHg ÷ 760 mmHg/atm) × (1 atm/101325 Pa) = 101.47 kPa.

3. Determine the pressure due to the air above the mercury column. This is the difference between the atmospheric pressure and the pressure due to the mercury column.

Atmospheric pressure = 1 atm = 101.325 kPa.

Pressure due to air = atmospheric pressure − pressure due to mercury column.

Pressure due to air = 101.325 kPa − 101.47 kPa = −0.145 kPa.

4. Convert the pressure due to air to centimeters of water using the conversion factor 1 cmH₂O = 0.098 kPa. −0.145 kPa × (100 cmH2O/0.098 kPa) = −148.47 cmH2O.5.

Add the pressure due to the mercury column and the pressure due to the air to get the barometric pressure in cmH₂O.

Barometric pressure = pressure due to mercury column + pressure due to air.

Barometric pressure = 1092.08 cmH₂O + (−148.47 cmH₂O) = 943.61 cmH₂O.

However, since the pressure due to the air is negative, the actual barometric pressure is higher than the calculated value.

The correct answer is 1092.08 cmH₂O − 148.47 cmH₂O = 943.61 cmH₂O + 1090.86 cmH₂O = 1033.25 cmH₂O.

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A team of students builds a lever as a science project. They expend 100 Joules of energy to lift some bricks with the lever. If 60 Joules of energy are applied to the bricks, what is the lever’s efficiency?

Answers

If 60 Joules of energy are applied to the bricks, so   the lever’s efficiency is 60%.

Efficiency is a measure of how well a machine or system transforms input energy into useful output energy. It is a ratio of output energy to input energy. In this case, the team of students builds a lever as a science project. They expend 100 Joules of energy to lift some bricks with the lever. If 60 Joules of energy are applied to the bricks, what is the lever’s efficiency? In this case, we have;

Total input energy, I = 100 J

Total output energy, O = 60 JEfficiency, η = Output energy/Input energyη = O/II = O/ηη = O/I = 60/100 = 0.6

or 60%Therefore, the efficiency of the lever is 60%.

This implies that the lever converts 60% of the input energy to useful output energy. That is, it requires 100 J of input energy to lift the bricks, but only 60 J of energy is applied to the bricks. The remaining 40 J is lost due to friction, air resistance, or other forms of energy dissipation.

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You hold a pen up in the air and then let go of it. The pen's inertia is its tendency to
- maintain a constant speed
why is this

Answers

Explanation:

The gravity gives the pen a constant force pointing to the center of the earth. And because of Newton's Second law: The acceleration of an object is directly proportional to the force it receives, inversely proportional to its mass, and the direction of acceleration is the same as the direction of the force.

So the pen has a tendency to going straight down on the ground. I don't think it maintain a constant speed but a constant acceleration. And the rate of the acceleration is approximate 9. 8m/s^2.

And as for its inertia, Newton's original statement in Principia mathematica was that any body should remain in uniform motion in a straight line or at rest until an external force forces it to change its motion. Bodies are too lazy to move if you don't force them. The moment you let go of the pen, the initial speed is zero. And it gains a acceleration of 9. 8m/s^2

According Newton's law of inertia, the pen tends to continue in its state of motion or rest. Hence, the pen tends to move in a constant velocity.

What is inertia ?

Newton's first law of motion states that, every objects tends to continue on the state of motion or rest until an external force acts on it. This tendency of objects is called inertia.

We can experience inertia in many situations. A very common example is ,when a stationary bus move backward when it started quickly that it tends to stay on rest. Similarly we will move forward when the bus suddenly breaks.

The similar effect is encountered in the pen here. When it moves through the air, except the air resistance no other force to resist its motion and it tends to move in a constant speed.

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a particle is projected from the surface of earth with a speed equal to 3 times the escape speed. when it is very far from earth, what is its speed?

Answers

Answer:

1/2 m v^2 = G M m / R         speed of object at surface of earth

v^2 = 2 G M / R        escape speed needed

V = 3 v     if original speed = 3 * escape speed

v^2 / 9 = 2 G M / R

v^2 = 18 G M / R    where v is initial speed

v^2 = G M / R  * (18 - 2) = 16 G M / R     very far from earth

v = (16 G M / R)^1/2

v = (16 * 6.67E-11 * 5.98E24 / 6.37E6)^1/2

v = 31650 m/s = 19.7 mi/sec

When a particle is projected from the surface of Earth with a speed equal to 3 times the escape speed, its final speed when very far from Earth will be 2 times the escape speed.


The escape speed is the minimum speed required for an object to overcome Earth's gravitational pull and move indefinitely away from it.

When a particle is projected with a speed 3 times the escape speed, it has more than enough energy to escape Earth's gravity.

As the particle moves away from Earth, it loses some of its kinetic energy due to Earth's gravitational force. Eventually, when the particle is very far from Earth, it will have lost an amount of kinetic energy equal to the escape speed.


Summary: When a particle is projected with a speed 3 times the escape speed and reaches a point very far from Earth, its speed will be 2 times the escape speed.

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