1. Harry is playing on a swing set at a park. It takes 17. 3 seconds for him to swing back and forth 5 times. What is the swing's period?

2. What is the frequency of a wave that occurs 278 times every 20 seconds?

3. The lowest frequency that the average human ear can hear is 20 Hz. This sound wave travels at a speed of 331 m/s through the air. What is the wavelength of this sound wave?

Answers

Answer 1

The lowest frequency that the average human ear can hear is 20 Hz. This sound wave travels at a speed of 331 m/s through the air, the wavelength of this sound wave is 16.55 meters

1. To determine the swing's period, we need to divide the total time it takes for Harry to swing back and forth by the number of oscillations. In this case, it takes 17.3 seconds for him to swing 5 times. The period (T) can be calculated as follows: T = 17.3 seconds / 5 oscillations. The swing's period is 3.46 seconds.

2. To find the frequency of a wave, we need to divide the number of occurrences by the time interval. In this case, the wave occurs 278 times every 20 seconds. The frequency (f) can be calculated as follows: f = 278 occurrences / 20 seconds. The frequency of the wave is 13.9 Hz.

3. The average human ear can hear a frequency as low as 20 Hz. Given that the speed of sound in air is 331 m/s, we can find the wavelength (λ) of this sound wave using the formula: speed = frequency × wavelength, or λ = speed / frequency. Plugging in the values, λ = 331 m/s / 20 Hz. The wavelength of this sound wave is 16.55 meters.

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Related Questions

Which would increase the speed of a sound wave?

- A wave passes from a solid to a liquid while remaining the same temperature.
- The medium increases in temperature while remaining in the same phase.
- The medium decreases in temperature while remaining in the same phase.
- A wave passes from a liquid to a gas while remaining the same temperature.

Answers

Answer:

B. The medium increases in temperature while remaining in the same phase

Explanation:

Good luck on all your tests and Exams!

The sound wave will increase when the medium increases in temperature while remaining in the same phase.

What is a sound waves?

Sound waves are composed of compressions and rare factions. Sound is a mechanical wave hence it moves by the vibration of air particles.

As such, the sound wave will increase when the medium increases in temperature while remaining in the same phase.

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Which does a reference point provide? Select two options. a position from which to measure future distance a set of standard units for measuring displacement a standard method for evaluating variables a method for determining the speed of an object a way to detect an object’s motion

Answers

Answer:

hope this helps you :)

Explanation:

An object is in motion if its position changes relative to another object. To decide if you are moving, you can use your chair as a reference point. A reference point is a place or object used for comparison to determine if something is in motion.

Two kids push a 100 N toy car. Biff pushes 30 N to the right while his older brother Buff pushes at 50 N to the left. Draw a free body diagram of the car.
Draw a free body diagram of the car. Label all forces.
What is the net force on the car?
Will the car accelerate? If so, in what direction is the acceleration?

Answers

Answer:

Explanation:

Since forces are acting in opposite direction

Net force on the car = 50 - 30 = 20 N

mass of car

= weight / g

= 100 / 10

m = 10 kg

acceleration of car = net force / mass

= 20 / 10

= 2 m /s² .

Two kids push a 100 N toy car. Biff pushes 30 N to the right while his older brother Buff pushes at 50

A positive test charge of 5.0x10 -6 C is in an electric field that exerts a force of 2.0x10 -4 N on it. What is the magnitude of the electric field at the location of the test charge

Answers

answer:

click on the picture, hope it helps

A positive test charge of 5.0x10 -6 C is in an electric field that exerts a force of 2.0x10 -4 N on it.

The magnitude of the electric field at that location is is 40  N.C⁻¹.

What is electric field?

The force per unit charge exerted on a positive test charge that is at rest at a given position is the force per unit charge that is used to define the electric field analytically.

Electric charge or magnetic fields with variable amplitudes can produce an electric field.

Given parameters:

Charge of the positive test charge, q =  5.0x10⁻⁶ C.

Electric force exerted by the electric field, F = 2.0x10⁻⁴ N.

Then, electric field at the position, E = F/q

= 2.0x10⁻⁴ / 5.0x10⁻⁶ N.C⁻¹.

= 40  N.C⁻¹.

Hence,  the magnitude of the electric field at the location of the test charge is 40  N.C⁻¹.

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if a subway train is moving to the left and then comes to a stop, what direction is the acceleration

Answers

The subway train is moving to the left and then comes to a stop, what direction is the acceleration will be towards right and will be positive.

The train comes to a stop, this means that the velocity gradually decreases. Hence, the acceleration must be positive and points towards the right.

velocity and acceleration:

velocity is the charge of alternate inside the position of an object, at the same time as acceleration is the rate of trade of the fee. consider the movement alongside a line. If the velocity and acceleration are in the same route, then the charge constantly will growth in time. inside the meantime, if the speed and acceleration are in contrary instructions, then the rate steadily decreases to 0 speed, reverses route, and now the velocity is in the identical path of the acceleration.

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The rate at which the temperature increases with depth is called the geothermal gradient. What is the geothermal gradient in a tectonically stable region where the temperature is 119° C at a depth of 5.0 km?
(Assume a surface rock temperature of 14° C.)

Answers

The geothermal gradient in the tectonically stable region is approximately 21°C/km, indicating that the temperature increases by an average of 21 degrees Celsius per kilometer of depth.

To calculate the geothermal gradient, we need to find the rate at which the temperature increases with depth.

Temperature at the surface (T₁) = 14°C

Temperature at a depth of 5.0 km (T₂) = 119°C

Temperature difference = T₂ - T₁ = 119°C - 14°C = 105°C

Depth difference = 5.0 km - 0 km = 5.0 km

Geothermal gradient = Temperature difference / Depth difference

Geothermal gradient = 105°C / 5.0 km

Calculating this expression, we find:

Geothermal gradient ≈ 21°C/km

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help plssss!!!!!!!!!!!!!

help plssss!!!!!!!!!!!!!

Answers

Answer:

C. Left

Explanation:

Correct if im wrong

berikut ini yang bukan satuan internasional adalah​

Answers

191919191819181818181818

Two airplanes leave an airport at the same time. The velocity of the first airplane is 650 m/h at a heading of 16.9 ◦ . The velocity of the second is 590 m/h at a heading of 161◦ . How far apart are they after 1.8 h? Answer in units of m.

Answers

Distance of train after 1.8 h is 485.099 m

Distance is a measurement of how far apart two things or points are, either numerically or occasionally qualitatively. Distance can refer to a physical length in physics or to an estimate based on other factors in ordinary language.

Distance of the first plane = 650 x 1.8 = 1170 m

Distance of the second plane = 590 x 1.8 = 1062m

The angle between 2 planes

161◦ - 16.9◦ = 144.1°

Using the law of cosine

d^2 = (1170)^2 + (1062)^2 - 2*1170*1062*cos 144.1°

d = 485.099 m

Hence, distance of train after 1.8 h is 485.099 m

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an object starts from rest and falls freely. what is the velocity of the object at the end of 3.00 seconds?

Answers

The velocity of the object at the end of 3.00 seconds is 29.4 m/s.

Find the initial velocity of an object by dividing the time it took the object to travel the specified distance by the total distance. An object at rest has zero velocity and remains so. Such an object does not change its state of motion unless an unbalanced force acts on it. The velocity of a body at rest must be zero, but the acceleration of a body at rest obviously cannot be zero.

Particles thrown vertically upwards will momentarily stop at the highest point of their movement. In free fall the object is affected only by gravitational acceleration. Acceleration is a non-zero value, so the velocity changes and increases as the object falls. This is because acceleration is defined as the rate of change of velocity with respect to time.

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Missy's favorite ride at the Topsfield Fair is the rotor, which has a radius of 4.0 m. The ride
takes 2.0 s to make one full revolution. a) What is Missy's linear speed on the rotor? b) What is
Missy's centripetal acceleration on the rotor? If her mass is 50-Kg, how is the centripetal force
compare to her weight?


Answers

Answer:

a. 12.57 m/s b. 39.5 m/s² c. Her centripetal force is four times her weight.

Explanation:

a. What is Missy's linear speed on the rotor?

Missy's linear speed v = 2πr/T where r = radius = 4.0 m and T = time it takes to complete one revolution = 2.0 s

So, v = 2πr/T

= 2π(4.0 m)/2.0 s

= 4π m/s

= 12.57 m/s

b. What is  Missy's centripetal acceleration on the rotor?

Missy's centripetal acceleration, a = v²/r where v = linear velocity = 12.57 m/s and r = radius = 4.0 m

a = v²/r

= (12.57 m/s)²/4.0 m

= 158.01 m²/s² ÷ 4.0 m

= 39.5 m/s²

c. If her mass is 50-Kg, how is the centripetal force  compare to her weight?

Her centripetal force F = ma where m = mass = 50 kg and a = centripetal acceleration = 39.5 m/s².

Her weight W = mg where m = mass = 50 kg and g = acceleration due to gravity = 9.8 m/s².

So, comparing her centripetal force to her weight, we have

F/W = ma/mg

= a/g

= 39.5 m/s² ÷ 9.8 m/s²

= 4.03

≅ 4

So her centripetal force is four times her weight.

which term best describes the quantity of water moving through a stream?

Answers

Explanation:

Generally, stream flows are measured in CFS   = Cubic Feet per Second

The bit-rate for a 16-bit stereo sound sampled at 32 kHz is 1.024 Mbps. What is the highest usable audible frequency in the digital media file?

Answers

The highest usable audible frequency in the digital media file is 16 kHz.

What is the highest usable audible frequency in the digital media file?

To find the highest usable audible frequency in a 16-bit stereo sound sampled at 32 kHz with a bit-rate of 1.024 Mbps, you can use the Nyquist theorem. The theorem states that the highest frequency that can be accurately represented is half of the sampling rate.

Identify the sampling rate.
The sampling rate is 32 kHz.

Apply the Nyquist theorem.
The highest usable audible frequency = (Sampling rate) / 2
The highest usable audible frequency = 32 kHz / 2

The digital media file's maximum usable audible frequency is 16 kHz.

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It is very common for the P waves in Atrial Tachycardia to be:
a. hidden in the T wave
b. flat
c. sawtooth
d. irregular

Answers

The correct option is option (c): In Atrial Tachycardia, the P waves are commonly seen as irregular or have a sawtooth pattern.

Atrial Tachycardia is a condition characterized by a rapid heart rate originating from abnormal electrical activity in the atria of the heart. In this condition, the P waves, which represent the electrical activity generated by the atria, can exhibit certain characteristic patterns. One common finding in Atrial Tachycardia is irregular P waves.

The irregularity occurs because the electrical signals responsible for generating the P waves are not originating from the sinus node, the normal pacemaker of the heart, resulting in a lack of consistent rhythm. Another common presentation of P waves in Atrial Tachycardia is a sawtooth pattern, known as "sawtooth flutter waves."

These waves have a distinct appearance, resembling a series of sharp peaks and valleys, which can be observed on an electrocardiogram (ECG). The irregular or sawtooth P waves in Atrial Tachycardia can help differentiate this condition from other types of tachycardia and aid in its diagnosis.

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Which mineral has a blue color and will scratch the garnet?

Topaz
Pyrite
Magnetite
Garnet
Augite
Talc

Which mineral has a blue color and will scratch the garnet? TopazPyriteMagnetiteGarnetAugiteTalc

Answers

Answer:

Topaz

Explanation:

It's harder than garnet and comes in various colors

Answer:

garnet

Explanation:

A 14-gauge copper wire of diameter 1.628 mm carries a current of 12.5 What is the potential difference across a 2.00 - m length of the wire? *p=1.47x10^-8

Answers

Answer:

\(V=1.76\times 10^{-4}\ V\)

Explanation:

Given that,

The diameter of a wire, d = 1.628 mm

Radius, r = 0.814  mm = 0.000814m

Current, I = 12.5 mA

The length of the wire, l = 2m

The resistivity of the wire, \(\rho=1.47\times 10^{-8}\ \Omega-m\)

We need to find the potential difference across the wire. We know that the resistance of the wire is given by :

\(R=\rho\dfrac{l}{A}\)

Also, V = IR

\(\dfrac{V}{I}=\rho\dfrac{l}{A}\\\\V=\dfrac{\rho l I}{A}\\\\V=\dfrac{1.47\times 10^{-8}\times 2\times 12.5\times 10^{-3}}{\pi \times (0.000814)^2}\\\\V=1.76\times 10^{-4}\ V\)

So, the potential difference of the wire is \(1.76\times 10^{-4}\ V\).

What is the unit of momentum formula?

Answers

The unit of momentum depends on the system of units used to express its constituent quantities. In the International System of Units (SI), momentum is given by the product of mass and velocity, and its unit is kilogram meters per second (kg·m/s).

Symbolically, momentum can be expressed as:

p = m * v

Where p represents momentum, m represents mass, and v represents velocity.

Other common units of momentum include:

gram centimeter per second (g·cm/s)

newton second (N·s)

pound foot per second (lb·ft/s)

The momentum is a vector quantity, which means it has both magnitude and direction. Therefore, the units of momentum are always accompanied by a direction, which is usually indicated using a positive or negative sign or a vector notation.

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How do you find the molar mass of an unknown compound?.

Answers

The molar mass of a compound can be found by adding the molar masses of all of the atoms in the compound.

The molar mass of an atom can be found on the periodic table by looking at the atomic mass listed for that element.

For example, to find the molar mass of water (H2O), we would add the molar masses of two hydrogen atoms (2 x 1.01 g/mol) and one oxygen atom (16.00 g/mol) to get a total molar mass of 18.02 g/mol.

Another way is by finding the molecular formula of the compound, it can be done by analyzing the compound's chemical and physical properties and then using the mass spectrometer to determine the molecular weight.

In conclusion, the molar mass of a compound can be found by adding the molar masses of the atoms in the compound using the atomic masses listed on the periodic table, or by determining the molecular formula of the compound and using a mass spectrometer to find the molecular weight.

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A clock which has brass pendulum beats correctly at 30C will it run faster or slower if temperature increase or decrease​

Answers

Answer:

We know that the period of a pendulum is written as:

T = 2*pi*√(L/g)

where:

g = gravitational acceleration = 9.8m/s^2

pi = 3.1415...

L =  length of the pendulum, in this case, is the length of the brass pendulum.

Now, we know that the brass dilates when the temperature increases.

Then if the temperature increases, the value of L will increase, which means that the period T will also increase, because L is in the numerator of T.

If the period increases the complete motion of the pendulum needs more time, this would mean that the clock will run slower.

If the temperature decreases, the opposite occurs, the value of L decreases, and then the period also decreases, which means that the clock will run faster.

winter beaches: question 36 options: are narrower than summer beaches due to high-energy waves during the winter. are wider than summer beaches due to low-energy waves during the winter. contain more sediment than summer beaches due to high-energy waves during the winter. contain less sediment than summer beaches due to low-energy waves during the winter. have better smaller offshore bars to sand deposition on the beach during the winter.

Answers

Winter beaches may have better smaller offshore bars for sand deposition on the beach during the winter, which can contribute to the beach's overall shape and size.

Summer beaches product high-energy waves during the winter?

Winter beaches are generally narrower than summer beaches due to the high-energy waves that occur during the winter. These waves tend to erode the beach, causing it to become narrower. Additionally, winter beaches may contain more sediment than summer beaches due to the high-energy waves that bring sediment onto the beach.

In areas where there are low-energy waves during the winter, the beach may actually be wider than during the summer. In this case, the low-energy waves may deposit sediment on the beach, causing it to widen.

Winter beaches may have better smaller offshore bars for sand deposition on the beach during the winter, which can contribute to the beach's overall shape and size.

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Summarize how changing the capacitance changes the rise and fall times. How does changing the voltage change the rise and fall times?

Answers

Changing the capacitance changes the rise and fall and changing the voltage change the rise and fall times:

decreasing the distance between the platesdecreasing the voltage

The formula of finding capacitance between 2 parallel plate is as follows:

                                     C=ϵA/d

where A is area of the plate

d is the distance between two plates  

ϵ determines the permittivity of the medium in which the plates are                           kept / connected

C is the capacitance of the Capacitor

The formula of finding the capacitance would be

                                     C=Q/V

where Q is the plates' charge in Coulombs

V is the plates' voltage

So, Capacitance of capacitor is inversely proportional to the voltage and proportional to the Charge.

Therefore, Changing the voltage leads to rise and fall times

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Biker 1 is on a motorcycle facing West is initially at rest. The motorcycle speeds up from rest to 25 mph in three seconds.
Biker 2 is right by his side to start. He speeds up from rest to 85 mph in eight seconds.

Which biker has a greater acceleration?

Answers

Biker 1's acceleration:

(25 mph) / (3 s) = ((25 mi/h) • (1/3600 h/s)) / (3 s) ≈ 0.00231 mi/s²

Biker 2's acceleration:

(85 mph) / (8 s) = ((85 mi/h) • (1/3600 h/s)) / (8 s) ≈ 0.00295 mi/s²

Biker 2 has the greater acceleration.

the apparen t magnitude of each star is given in parentheses after its name. altair (0.77), capella pollux rigel which of the stars looks brightest in the night sky. (True or False)

Answers

The given statement is False.

The apparent magnitude of a star is a measure of its brightness as seen from Earth. The lower the number, the brighter the star appears in the night sky. For example, a star with an apparent magnitude of 1.0 will appear brighter than a star with an apparent magnitude of 2.0.

The correct apparent magnitudes for the stars are as follows:

Altair: Apparent magnitude (0.77)

Capella: Apparent magnitude (0.08)

Pollux: Apparent magnitude (1.14)

Rigel: Apparent magnitude (0.18)

Based on the correct apparent magnitude values, Capella is indeed the brightest star among the options given. It has the lowest apparent magnitude, indicating a higher brightness in the night sky compared to the other stars.

In this case, Altair has an apparent magnitude of 0.77, which means it appears brighter than Capella, Pollux, and Rigel. Therefore, the statement is true - Altair looks brightest in the night sky out of the given stars.

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a proton in a high-energy accelerator moves with a speed of c/2. use the work–kinetic energy theorem to find the work required to increase its speed to the following speeds. (a) 0.740c (b) 0.873c

Answers

The work required to increase the speed of the proton to Therefore, the work required to increase the speed of the proton to (a) 0.740c is -3.52 x 10⁻¹¹ J and (b) 0.873c is 5.27 x 10⁻¹¹ J

The work-kinetic energy theorem states that the net work done on an object is equal to its change in kinetic energy. Therefore, we can use this theorem to find the work required to increase the speed of a proton in a high-energy accelerator.

Let's first find the kinetic energy of the proton with speed c/2. The kinetic energy (K) of an object with mass m and speed v is given by:

K = (1/2)mv²

Since the proton has a rest mass of 1.67 x 10⁻²⁷ kg, we can calculate its kinetic energy:

K = (1/2)(1.67 x 10⁻²⁷ kg)(c/2)²

K = 9.41 x 10⁻¹¹ J

(a) To find the work required to increase the speed of the proton to 0.740c, we first need to find its final kinetic energy. Since kinetic energy is proportional to the square of the speed, we can use the ratio of speeds to find the final kinetic energy:

(K_final)/(K_initial) = (v_final²)/(v_initial²)

(K_final) = (v_final²)/(v_initial²) * (K_initial)

(K_final) = (0.74c/c/2)² * (9.41 x 10⁻¹¹J)

(K_final) = 5.89 x 10⁻¹¹ J

The change in kinetic energy is:

ΔK = K_final - K_initial

ΔK = 5.89 x 10⁻¹¹ J - 9.41 x 10⁻¹¹J

ΔK = -3.52 x 10⁻¹¹ J

Since the final speed is greater than the initial speed, the work done on the proton is positive. Therefore, the work required to increase the speed of the proton to 0.740c is:

W = ΔK

W = -3.52 x 10⁻¹¹J

(b) To find the work required to increase the speed of the proton to 0.873c, we follow the same steps as in part (a). The final kinetic energy is:

(K_final) = (0.873c/c/2)² * (9.41 x 10⁻¹¹ J)

(K_final) = 1.47 x 10⁻¹⁰J

The change in kinetic energy is:

ΔK = K_final - K_initial

ΔK = 1.47 x 10⁻¹⁰ J - 9.41 x 10⁻¹¹ J

ΔK = 5.27 x 10⁻¹¹ J

Since the final speed is greater than the initial speed, the work done on the proton is positive. Therefore, the work required to increase the speed of the proton to 0.873c is:

W = ΔK

W = 5.27 x 10⁻¹¹J

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Which examples best demonstrate likely tasks for Legal Services workers? Check all that apply.

Cisco inspects an office building to make sure it meets fire safety regulations.
Gina gathers information about a court case.
Saul oversees inmates at a correctional facility.
Hana interviews and advises a person who has been accused of a crime.
Pamela pursues and arrests a person suspected of a crime.
Dewayne creates the paperwork for a business contract.

Answers

Answer:

b. d. f.

Explanation:

Got it right on Edge

Answer:

2. Gina gathers information about a court case.

4. Hana interviews and advises a person who has been accused of a crime.

6. Dewayne creates the paperwork for a business contract.

An object orbiting the sun in an ellipse can be said to be:.

Answers

Answer:

always accelerating

Explanation:

Answer:

B. Always accelerating

Explanation:

I recently did a review with an identical flashcard!

An object orbiting the sun in an ellipse can be said to be:.
An object orbiting the sun in an ellipse can be said to be:.

(ii) One possible path of the spacecraft as it approaches the planet is shown in fig.1.1 The spacecraft enters the orbit at point A with speed 3.7x10^3 ms^-1.At point B, a distance of 5.00x10^7 from the centre of the planet, the spacecraft has a speed of 4.1x10^3ms^-1. The mass of the spacecraft is 650kg. For the spacecraft moving from point B to point A, show that the change in gravitational potential energy of the spacecraft is8.3x10^9

(ii) One possible path of the spacecraft as it approaches the planet is shown in fig.1.1 The spacecraft
(ii) One possible path of the spacecraft as it approaches the planet is shown in fig.1.1 The spacecraft
(ii) One possible path of the spacecraft as it approaches the planet is shown in fig.1.1 The spacecraft

Answers

The change in gravitational potential energy of the spacecraft as it moves from point B to point A is 8.3x10^9 J.

The change in gravitational potential energy of the spacecraft as it moves from point B to point A can be calculated using the formula:

                    \(ΔPE = -GMm(1/rA - 1/rB)\) , where

ΔPE is the change in gravitational potential energy,

G is the gravitational constant,

M is the mass of the planet,

m is the mass of the spacecraft,

rA is the distance from the planet's center at point A, and

rB is the distance from the planet's center at point B.

Using the given values, we have:

\(ΔPE = -(6.67x10^-11 Nm^2/kg^2)(1.50x10^24 kg)(650 kg)(1/5.00x10^7 m - 1/0)\)\(ΔPE = -(6.67x10^-11 Nm^2/kg^2)(1.50x10^24 kg)(650 kg)(1/5.00x10^7 m - 1/0)\)

Simplifying the expression, we get:

\(ΔPE = -8.3x10^9 J\)

Therefore, the change in gravitational potential energy of the spacecraft as it moves from point B to point A is \(8.3x10^9\)J, which is a negative value because the spacecraft is moving closer to the planet and its gravitational potential energy is decreasing.

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a passenger rushes down onto a subway platform and finds her train already departing. she stops and watches the cars go by. each car is 8.60 m long. the first moves past her in 2.10 s and the second in 1.83 s. what is the constant acceleration of the train?

Answers

A passenger rushes down onto a subway platform and finds her train already departing. she stops and watches the cars go by. each car is 8.60 m long. the first moves past her in 2.10 s and the second in 1.83 s. The constant acceleration of the train is 236.16 m/s².

To calculate the constant acceleration of the train, we can use the following equation:

acceleration = 2 * (change in distance) / (change in time)²

Given:

Length of each car = 8.60 m

Time taken for the first car to pass = 2.10 s

Time taken for the second car to pass = 1.83 s

Step 1: Calculate the change in distance between the two cars:

change in distance = length of each car = 8.60 m

Step 2: Calculate the change in time between the two cars:

change in time = time taken for the second car to pass - time taken for the first car to pass

change in time = 1.83 s - 2.10 s = -0.27 s (The negative sign indicates that the second car passed before the first car)

Step 3: Calculate the acceleration:

acceleration = 2 * (change in distance) / (change in time)²

acceleration = 2 * 8.60 m / (-0.27 s)²

acceleration = 2 * 8.60 m / (0.27 s)²

acceleration = 2 * 8.60 m / 0.0729 s²

acceleration = 17.2 m / 0.0729 s²

acceleration = 236.16 m/s²

Therefore, the constant acceleration of the train is approximately 236.16 m/s².

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Complete the following sentence: How much you pay in taxes depends on _________________________.

Answers

Answer:

How much you pay in taxes depends on the amount of your taxable income

Explanation:

The total amount expected to be payed as taxes is a factor of the amount of taxable income earned within the given tax period.

The taxable income is found by subtracting the amount of deductions and exemption allowed in the tax year from the gross income. It is also specified as the adjusted gross income

The set marginal  tax rate indicates the percentage of the taxable income that is to be paid as taxes, such that there are three different ranges or tax brackets and taxes are paid according to the bracket to which a taxable income belongs.

If Siobhan hits a 0.25 kg volleyball with 0.5 N of force, what is the acceleration of the ball?

m/s2

Answers

Answer:

2ms-2

Explanation:

F = ma

a = F/m

= 0.5 / 0.25

= 2ms-2

Answer 2m/s^2

Explanation:

mass=0.25kg

Force =0.5N

Acceleration=force/ mass

Acceleration=0.5/0.25

Acceleration=2

Acceleration =2m/s^2

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