The boiling point of the solution is 80.58 °C, which is prepared by dissolving 2. 50 g of biphenyl (C₁₂ H₁₀).
To determine the boiling point of the solution, we need to use the equation;
Δ\(T_b}\) = \(K_{b}\) x m
Where ΔTb is boiling point elevation, is molal boiling point elevation constant, and m is molality of the solution.
First, we to calculate the molality of the solution;
moles of biphenyl =2.50 g / 154 g/mol
= 0.0162 mol
mass of benzene = 85.0 g
moles of benzene = 85.0 g / 78.11 g/mol
= 1.088 mol
molality = moles of solute/mass of solvent (in kg)
molality = 0.0162 mol / 0.085 kg
= 0.19 mol/kg
Next, we need to look up the molal boiling point elevation constant (\(K_{b}\)) for benzene. The value of \(K_{b}\) for benzene is 2.53 °C/m.
Finally, we alculate the boiling point elevation;
Δ\(T_b}\) = \(K_{b}\) x m
Δ\(T_b}\) = 2.53 °C/m x 0.19 mol/kg
= 0.481 °C
The boiling point elevation (Δ\(T_b}\)) is the difference between the boiling point of the solution and the boiling point of the pure solvent. The boiling point of pure benzene is 80.1 °C. Therefore, the boiling point of the solution will be;
Boiling point of solution = 80.1 °C + 0.481 °C
= 80.58 °C
So, the boiling point of the solution is 80.58 °C.
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Balance this equation (#7)
Calculate the amount of solid NH4Cl to add to 60.0 mL of 0.100 M ammonia to form a mixture that has a pH
To calculate the amount of solid NH4Cl to add to 60.0 mL of 0.100 M ammonia to form a mixture that has a pH, let's first write the balanced equation for the reaction between ammonia and ammonium chloride:NH4Cl(s) + NH3(aq) ⇌ NH4+(aq) + NH2-(aq)Now, let's write the equilibrium constant expression for the above reaction:Kb = ([NH4+][NH2-])/[NH3]
Since we want to form a mixture with a specific pH, we can use the following relationship:pH + pOH = pKwwhere Kw is the ion product constant for water (1.00 x 10^-14 at 25°C).At 25°C, pKw = 14.00, so:pOH = 14.00 - pHNow, we can use the relationship between pH, pOH, and the hydroxide ion concentration to solve for the hydroxide ion concentration:[OH-] = 10^-pOHNow, we can use the Kb expression to solve for the ammonium ion concentration:Kb = ([NH4+][NH2-])/[NH3][NH4+] = (Kb[NH3])/[NH2-]We can assume that the initial concentration of NH3 is equal to the concentration of ammonia in the mixture, which is 0.100 M. We can also assume that the initial concentration of NH4+ is zero. Therefore:[NH4+] = (Kb[NH3])/[OH-]Next, we can use the mass balance equation to calculate the amount of NH4Cl needed to form the desired mixture:m1 = m2 x (M2/M1)where m1 is the mass of NH4Cl needed, m2 is the mass of ammonia in the mixture, M1 is the molar mass of NH4Cl, and M2 is the molar mass of NH3.Substituting the given values into the above equation:m1 = (0.060 L x 0.100 mol/L x (10^-pH))/((Kb x 0.100 mol/L) / 10^-pH))(53.5 g/mol / 17.0 g/mol)where the factor (53.5 g/mol / 17.0 g/mol) is used to convert moles of NH4Cl to grams of NH4Cl. Simplifying the above expression yields:m1 = 0.108 gTherefore, 0.108 g of NH4Cl should be added to 60.0 mL of 0.100 M ammonia to form a mixture that has a pH of the desired value.For such more question on equilibrium
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1. A gas at 24.0 Celsius and.900 atm fills a 0.95 Liter container.
What is its ending pressure (in atm) if the temperature changes
to 75 Celsius? Show all your work.
Answer:
P₂ = 1.05 atm
Explanation:
Given data:
Initial temperature = 24.0 °C (24+273 = 297 K)
Initial pressure = 0.900 atm
Final pressure = ?
Final temperature = 75 °C (75 + 273 =348 K)
Volume = constant
Solution:
According to Gay-Lussac Law,
The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.
Mathematical relationship:
P₁/T₁ = P₂/T₂
Now we will put the values in formula:
0.900 atm / 297 K = P₂/348 K
P₂ = 0.900 atm × 348 K / 297 K
P₂ = 313.2 atm. K /297 K
P₂ = 1.05 atm
*
In the table, which is NOT a physical change in size or shape?
(17 Points)
O A.W
B. X
Ос. Ү
O D.Z
Answer:
Oc. Y is your correct answer
Answer:
k Nishant
Explanation:
the answer is oC . Y
How many fluorine atoms are present in 125.0g of phosphorus pentafluoride?
molar mass of PF5 = 125.966 g/mol
125 g PF5 × (1 mol PF5/125.966 g PF5) = 0.992 mol PF5
0.992 mol PF5 × (6.022 × 10^23 molecules PF5);
= 5.97 × 10^23 molecules PF5
Since there 5 fluorine atoms per molecule of PF5,
(5.97.× 10^23 molecules PF5) × (5 atoms F/1 molecule PF5)
= 2.99 × 10^24 atoms F
what is the pH of a solution with [H+] = 1.25 x 10^-10M?
Answer:
9.90
Explanation:
Given [H+] = 1.25 x 10^-10 M, we can calculate the pH using the formula:
pH = -log10([H+])
pH = -log10(1.25 x 10^-10)
Using logarithmic properties:
pH = -log10(1.25) - log10(10^-10)
Since log10(10^-10) is equal to -10:
pH = -log10(1.25) - (-10)
pH = -log10(1.25) + 10
Now, evaluating the logarithm using a calculator:
pH = -0.0969 + 10
pH = 9.9031
Therefore, the pH of the solution with [H+] = 1.25 x 10^-10 M is approximately 9.9031. Rounding it to two decimal places, the pH is approximately 9.90.
When the same quantity of electricity was passed through a dilute solution of sodium hydroxide and through a molten solution of lead bromide, 0.050 mol of lead was produced. what amount (in mol) of hydrogen gas was evolved
0.050 moles of hydrogen gas are liberated when a given quantity of charge liberates 0.050 moles of lead.
What amount in moles of hydrogen will be produced?The amount in moles of hydrogen produced when the same quantity of electricity is passed through different electrolytes is inversely proportional to the charge on the ions.
The charge on the Lead ion is +2.
The charge on the hydrogen ion is +1.
2 atoms of hydrogen gives one molecule of hydrogen gas.
Hence, equal charge liberates equal amounts in moles of lead and hydrogen gas.
Therefore, 0.050 moles of hydrogen gas are liberated when a given quantity of charge liberates 0.050 moles of lead.
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Why does the carbon anode burn away in the electrolysis of aluminium chloride?
what is preferential discharge of ions
Answer:
During the process of electrolysis, ions that are formed will get discharged to reform neutral atoms at the state of electrons, whereas the preferential meaning which in case one or more kind of cations and anions in the electrolyte, the one with the higher concentration or at a lower position activity will get discharged first.
A solution with ph 4 has __________ the h concentration of a solution with ph 8.
A solution with ph 4 has 10000 times the h concentration of a solution with ph 8.
the solution, in chemistry, is a homogeneous mixture of two or more substances whose relative amounts can be varied continuously up to the so-called solubility limit. The term solution is usually applied to the liquid state of aggregation, but gaseous and solid solutions are also possible. Hypotonic, isotonic, and hypertonic solutions (tonic).
A solution is a homogeneous mixture of two or more components with particle sizes less than 1 nm. Common examples of solutions are the sugar in water and salt in water, soda water, etc. In solution, all components appear as a single phase.
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How many mls of solvent are required to make a 48% solution from 25 g of solute? (round to the nearest tenth with no units!)
To make a 48% solution from 25 g of solute, you would need approximately 52.08 mL of solvent.
To calculate the volume of solvent required, we need to consider the mass percent of the solution. The mass percent is defined as the ratio of the mass of solute to the total mass of the solution, multiplied by 100. In this case, the mass percent is given as 48%.
To find the volume of solvent, we can set up a proportion using the mass percent. Let's assume the total volume of the solution is V mL. We can set up the following equation:
(25 g)/(V mL) = (48 g)/(100 mL)
Cross-multiplying and solving for V, we get:
25V = 48 * 100
V = (48 * 100)/25
V ≈ 192 mL
Therefore, you would need approximately 192 mL of the solvent to make a 48% solution from 25 g of solute.
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explain why the measured pressure of a gaseous system under conditions that are very close to those that ewould result in condensation will be lowered than what the ideal gas law would redict
The deviation from the ideal gas law prediction is approximately 150 times when a gas is near its boiling point.
The ideal gas law is dependent on the notion that there is no intermolecular attraction between gas particles. As a result, ideal gas law predictions differ from the actual measured pressure of a gaseous system under conditions that are very close to those that would result in condensation by about 150 times.
According to the ideal gas law, PV=nRT. It implies that the product of the pressure and volume of a gas is proportional to the number of molecules, absolute temperature, and gas constant. But when gas is compressed, its pressure grows and the density of molecules becomes high.
As the volume decreases, the gas particles come closer, and they start to attract each other with intermolecular forces.This intermolecular attraction between gas particles lowers the measured pressure of a gaseous system under conditions that are very close to those that would result in condensation.
Therefore, the ideal gas law cannot explain why there is a reduction in pressure under such circumstances.
The deviation from the ideal gas law prediction is approximately 150 times when a gas is near its boiling point.
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What part of ATP is broken to release energy for use in chemical reactions? a. the adenosine molecule b. the bond between the first and second phosphates c. the bond between the first phosphate and the adenosine molecule d.the bond between the second and third phosphates
The bond between the second and third phosphates is broken to release energy for use in chemical reactions.
What is ATP?
ATP is the abbreviated form of adenosine triphosphate. ATP is a nucleotide that is crucial to cellular metabolism since it serves as a way for cells to transport energy between chemical reactions.
In simple words, ATP is the molecule that our cells utilize as their primary source of energy. ATP provides the energy that our cells require to perform their everyday tasks, from moving to synthesizing complex molecules.
The energy stored in ATP is released through the breaking of the bond between the second and third phosphates, a high-energy bond. The removal of one phosphate group from ATP is referred to as hydrolysis, and it results in the formation of ADP (adenosine diphosphate) and an inorganic phosphate group.
ATP hydrolysis yields a considerable amount of energy, which is then used by the cell for various purposes.
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Which functional group does the molecule below have?
H H H H
H-Ċ-Ċ-Ċ-Ċ-0-H
| | | |
н ннн
O A. Amino
O B. Ester
O C. Ether
O D. Hydroxy
COMPUESTOS ORGANICOS Escribe el nombre correctamente de los siguientes compuestos orgánicos: necesito ayuda con esto por favor!
Answer:
a. p-bromofenol o 4-bromo-fenol.
b. Diisopropil éter.
c. p-nitrofenol o 4-nitro-fenol.
d. isopropil-fenil éter o fenóxido de isopropilo.
Explanation:
Hola.
En este caso, siguiente las normas IUPAC de nomenclatura orgánica, obtenemos los siguientes nombres:
a. p-bromofenol o 4-bromo-fenol: nota que el bromo es un radical presente en el cuarto carbono del fenol dado.
b. Diisopropil éter: en este caso, nota que el oxígeno central hace que la molécula sea un éter, cuyos radical son ambos isopropil.
c. p-nitrofenol o 4-nitro-fenol: nota que el nitro (NO2) es un radical presente en el cuarto carbono del fenol dado.
d. isopropil-fenil éter o fenóxido de isopropilo: nota que el oxígeno central hace que la molécula sea un éter, cuyos radical son isopropily y el otro fenil, por lo que se nombran en orden alfabético o de número de carbonos (de más a menos).
¡Saludos!
A sample of gas at 15 atmospheres and 445 K is cooled to 250 K. What pressure will the gas be under after it is cooled? Round to the nearest hundredth.
A. 26.7 atm
B. 25 atm
C. 8.43 atm
D. 10 atm
Answer:
Explanation: 8.43
which of the following would increase the (gas) pressure of a system? a increase the temperature b pump in more gas c decrease the volume d all of these
According to the Boyle's law and the ideal gas equation the pressure of a system will increase by increasing the temperature, decreasing the volume, pumping more number of gas. Option (d) is correct.
Boyle's Law can be explained as a basic law in chemistry describing the behavior of a gas held at a constant temperature. This law was discovered by Robert A. Boyle in 1662. This law states that at a fixed temperature the volume of gas is inversely proportional to the pressure exerted by the gas. This law tells us that the volume of gas increases as the pressure decreases.
According to the Ideal gas law all gases obey an equation of state known as the ideal gas law,
PV = n RT
Here n is the number of moles of the gas and R is the universal gas constant.
This law of ideal gas is said to be a hypothetical gas whose molecules occupy negligible space and have no interactions. This obeys the gas laws exactly. Ideal gas is defined as a gas that follows all the gas laws at all temperature and pressure.
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The activation energy of a certain reaction is 45.5 kJ/mol . At 21 ∘C , the rate constant is 0.0110s−1 . At what temperature in degrees Celsius would this reaction go twice as fast?
The temperature in degrees Celsius that the reaction will go twice as fast is 32.4 ⁰C.
Temperature when the reaction rate is twice fasterln(k₂/k₁) = E/R(1/T₁ - 1/T₂)
where;
T₁ is initial temperature = 21 ⁰C = 294 Kk₁ is initial ratek₂ is final rateT₂ is final temperatureE is activation energyR ideal gas constantwhen rate is twice faster, k₂ = 2k₁ = 2(0.011) s⁻¹ = 0.022 s⁻¹
ln(0.022/0.011) = (45,500/8.31)(1/294 - 1/T₂)
0.693 = 5475.33(1/294 - 1/T₂)
1.2657 x 10⁻⁴ = 1/294 - 1/T₂
1/T₂ = 1/294 - 1.2657 x 10⁻⁴
1/T₂ = 3.275 x 10⁻³
T₂ = 305.4 K = 32.4 ⁰C
Thus, the temperature in degrees Celsius that the reaction will go twice as fast is 32.4 ⁰C.
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A student measured the pH of his soda and found it to be 4.5.
Calculate the [H3O+] in the soda.
Answer:
0.0111 M
Explanation:
pH = 4.5
[H3O+] = ?
Relationship between both quantitiesis given by:
pH = -log₁₀ [H3O+]
-pH = log₁₀ [H3O+]
-4.5 = log₁₀ [H3O+]
[H3O+] = e ^ (-4.5)
[H3O+] = 0.0111 M
what is the ph of this solution of cobalt(ii) hydroxide?
The pH of this solution of cobalt(II) hydroxide is likely to be basic. When cobalt(II) hydroxide dissolves in water, it hydrolyzes to produce cobalt(II) ions and hydroxide ions. As a result, the concentration of hydroxide ions increases, resulting in a basic solution.
Cobalt(II) hydroxide, on the other hand, is a base. When it dissolves in water, the OH- ion concentration increases, resulting in a basic pH. This is because hydroxide ions act as a proton acceptor and bind with protons, reducing their concentration. The pH of the solution of cobalt(II) hydroxide can be calculated by subtracting the logarithm of the hydroxide ion concentration from 14.
The pH of the solution will be greater than 7 if the concentration of hydroxide ions is greater than that of H+ ions (which is equivalent to having a pOH greater than 7).
In conclusion, the pH of a solution of cobalt(II) hydroxide is expected to be basic. The solution will have a pH greater than 7, since hydroxide ions increase the concentration of OH- ions, which are basic.
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what is the molecular formula of first 20 elements
Answer:
H
He
Li
Be
B
C
N
O
F
Ne
Na
Mg
Al
Si
P
S
Cl
Ar
K
Ca
What is the mass in grams 5.04x1023platinum atoms
The mass of \(5.04 * 10^{23}\) platinum atoms is approximately 163.29 grams.
To calculate the mass of \(5.04 * 10^{23}\) platinum atoms, we need to use the concept of molar mass. The molar mass of platinum (Pt) is approximately 195.08 grams per mole (g/mol). Since one mole of any substance contains Avogadro's number of particles, which is \(6.022 * 10^{23}\) atoms, we can use this information to determine the mass of the given number of platinum atoms.
First, let's find the fraction of a mole that \(5.04 * 10^{23}\) atoms represent:
(\(5.04 * 10^{23}\) atoms) / (\(6.022 * 10^{23}\) atoms/mol) ≈ 0.837 moles of Pt
Next, we can use the molar mass to find the mass of the 0.837 moles of platinum:
Mass = (Moles) x (Molar Mass)
Mass = (0.837 mol) x (195.08 g/mol) ≈ 163.29 grams
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How many different signals would you expect to see in the 1H NMR of the given compounds? (i.e. different chemical shifts)? 10 Compound A- Compound B- 6 Compound C- 4 6 Compound D- 9 Compound E- Compound F-
Nuclear magnetic resonance spectroscopy (NMR) is used to study the electronic environment of atoms and the bonding nature of a compound.
The number of different signals observed in the 1H NMR spectra of the given compounds are as follows: Compound A: 10 signals, Compound B: 6 signals ,Compound C: 4 signals Compound D: 6 signals ,Compound E: 9 signals, Compound F: 3 signals
In proton nuclear magnetic resonance spectroscopy (1H NMR), the magnetic field strength and electronic environment of the protons influence the chemical shifts. The shielding effect or deshielding effect of the nearby atoms, bond length, and bond angle, among other factors, all influence the chemical shifts. There are five different types of proton environments, which correspond to five different chemical shifts, in this case: Type 1: Hydrogen atoms that are covalently bonded to sp3 hybridized carbons. Type 2: Hydrogen atoms that are covalently bonded to sp2 hybridized carbons. Type 3: Hydrogen atoms that are covalently bonded to sp hybridized carbons. Type 4: Hydrogen atoms that are covalently bonded to aromatic carbons. Type 5: Hydrogen atoms that are directly bonded to electronegative elements such as nitrogen, oxygen, or halogens.
Here, to determine the number of signals expected in the 1H NMR of the compounds. Compound A: 10 different proton environments => 10 signals. Compound B: 6 different proton environments => 6 signals. Compound C: 4 different proton environments => 4 signals. Compound D: 6 different proton environments => 6 signals. Compound E: 9 different proton environments => 9 signals. Compound F: 3 different proton environments => 3 signals.
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Chemical disequilibrium is likely to be present in:_________
Chemical disequilibrium is likely to be present in any system where the forward and reverse reactions are not in balance.
This can occur in a variety of situations, such as when the reactants are not present in the correct proportions, when the reaction conditions are not ideal, or when there are external factors affecting the reaction. For example, in a chemical reaction where one product is constantly being removed from the system, the reaction may never reach equilibrium.
Similarly, in a reaction where the temperature or pressure is constantly changing, the equilibrium may shift in one direction, leading to a chemical disequilibrium. Ultimately, chemical disequilibrium occurs when a reaction is not able to maintain a stable equilibrium state. Chemical disequilibrium is likely to be present in environments where reactions are ongoing and not yet in a stable state. These situations can be found in systems experiencing changes in temperature, pressure, or concentrations of reactants and products. Examples include volcanic areas, hydrothermal vents, or chemical industries where continuous production or consumption of reactants occurs. The presence of chemical disequilibrium provides opportunities for further reactions to take place, leading to new products and potential energy releases. Understanding these environments can offer insights into various natural processes and technological applications.
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An unknown substance is a white solid at room temperature and has a melting point of 78 "c. Which of the following substances is most likely to be the identity of
the unknown sample?
The molecular solid naphthalene had always been the unidentified solid with such a melting point around 78 degrees Celsius.
At normal temperature as well as pressure, an ionic compound would be almost certainly a solid, even though a covalent compound could be a solid, a liquid, or even a gas.
The temperature when a solid can transform into a liquid is known as that of the melting point.
Strong intermolecular interactions have led to greater melting points for some substances, while weakly attractive molecules have lower melting points.
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A meteoroid is approaching Earth's surface. Which meteoroid is currently most affected by the Earth's gravitational pull?
The meteoroid that is currently most affected by Earth's gravitational pull is the one closest to the Earth's surface.
A meteoroid is a small celestial object that orbits the Sun and is significantly smaller than an asteroid. Typically ranging in size from a grain of sand to a few meters in diameter, meteoroids are remnants left behind by comets or asteroids. They are composed of various materials, including rock, metal, and ice.
When a meteoroid enters the Earth's atmosphere, it is called a meteor. Friction with the atmosphere heats up the meteoroid, causing it to glow brightly and create a streak of light across the sky. This phenomenon is commonly referred to as a shooting star or meteor. Most meteors burn up completely before reaching the Earth's surface, but occasionally, larger and more robust meteoroids survive the atmospheric entry and impact the ground.
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In the combustion of octane, 2 C8H18 +25 O2 --> 16 CO2 + 18 H2O, if 376.0 liters of carbon dioxide formed at STP, then the volume of oxygen used was A. 587.5 L B. 240.6 L C. 839.3 L D. 299.1 L
Answer:
587.5 L (Option A)
Explanation:
The reaction is:
2 C₈H₁₈ + 25O₂ → 16CO₂ + 18H₂O
We know that in STP conditions 1 mol of any gas is contained in 22.4L
Then, we can make a rule of three, to determine the moles of produced carbon dioxide.
22.4L is the volume for 1 mol
376 L will be the volume for (376 . 1) 22.4 = 16.78 moles at STP conditions.
Stoichiometry is 16:25.
16 moles of CO₂ are produce by the reaction of 25 moles of O₂
Then, 16.78 moles of CO₂ were produced by (16.78 . 25) /16 = 26.2 moles.
Now, the rule of three again.
1 mol of oxygen gas is contained at 22.4L, at STP conditions
26.2 moles might be contained at (26.2 . 22.4)/1 = 587.5 L
Question: Find The Concentration Of Cu+ In Equilibrium With CuBr(S) And 0.10 M Br-
In this instance, the equilibrium concentration of Cu⁺ with 0.10 M Br⁻ is similarly 0.10 M.
To determine the concentration of Cu⁺ in equilibrium with CuBr(s) and 0.10 M Br⁻, we need to consider the solubility equilibrium of CuBr.
The solubility equilibrium for CuBr can be represented as follows:
CuBr(s) ⇌ Cu⁺(aq) + Br⁻(aq)
The solubility product constant (Ksp) expression for this equilibrium is:
Ksp = [Cu⁺][Br⁻]
Since the stoichiometry of the reaction is 1:1 between Cu⁺ and Br⁻, the concentration of Cu⁺ in equilibrium will be equal to the concentration of Br⁻.
Therefore, in this case, the concentration of Cu⁺ in equilibrium with 0.10 M Br⁻ is also 0.10 M.
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The concentration of Cu+ in equilibrium with solid CuBr and 0.10M Br- is 7.9 x 10-5 M. This happens due to the common ion effect, which is the presence of extra Br- ions in solution that suppress the dissolution of CuBr.
Explanation:You are asked to find the concentration of Cu+ in equilibrium with solid CuBr and 0.10M Br-. The solubility product constant (Ksp) defines the equilibrium between a solid and its constituent ions in a solution. The balanced equation for this dissolution process is:
CuBr(s) <==> Cu+ (aq) + Br- (aq)
For CuBr, the Ksp value is 7.9 x 10-5 M. This represents product of concentrations of its ions in the solution. However, we already have 0.10M Br-, which is much higher than that provided by the dissolution of CuBr. Therefore, the Cu+ concentration in equilibrium is essentially equal to the Ksp, i.e. 7.9 x 10-5 M.
Here, the concept of the common ion effect comes into play. The presence of extra Br- ions from the solution suppresses the dissolution of CuBr, thereby controlling the Cu+ concentration in the solution.
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Evaluate the following reactions:
REACTION 1. The hydrolysis of phosphoenolpyruvate (PEP) to pyruvate and inorganic phosphate (Pi) is represented by the reaction: PEP + H2O ---> Pyruvate + Pi + H+ and has a ΔG’of: -61.9 kJ mol -1.
REACTION 2. The hydrolysis of ATP is represented by the reaction: H2O + ATP --> ADP + Pi + H+ and has a ΔG’ of: -30.5 kJ mol-1.
a. What is the ratio of Pyruvate versus PEP under the equilibrium conditions in REACTION 1?
b. What is the ratio of ATP versus ADP under standard conditions for equilibrium in REACTION 2?
c. Under cellular conditions, these reactions are thermodynamically coupled. PEP in REACTION 1 can drive the synthesis of ATP in REACTION 2. Write the net coupled chemical equation for the synthesis of ATP from ADP and inorganic phosphate using the hydrolysis of PEP into Pyruvate. Show REACTION 1 and REACTION 2 in either forward or reverse direction AND the final overall coupled reaction equation.
d. Calculate the ΔG’ for the overall net coupled reaction. Using complete sentences, indicate whether the overall net coupled reaction would be spontaneous or non-spontaneous and why. Remember, show your work indicating the common intermediates and using appropriate units to receive full credit.
e. Calculate the ratio of products and reactants for the overall net coupled reaction.
a. Under equilibrium conditions, the ratio of Pyruvate to PEP is \(3.78 * 10^6.\)
b. Under standard conditions for equilibrium, the ratio of ATP to ADP is 441.
c. This equation shows that PEP can drive the synthesis of ATP from ADP and Pi. REACTION 1 is in the forward direction, while REACTION 2 is in the reverse direction.
d. The overall net coupled reaction is exergonic or spontaneous because the ΔG' is negative (-92.4 kJ/mol). This means that the reaction releases energy and can proceed spontaneously without the addition of energy.
e. At equilibrium, the concentrations of PEP, ADP, Pi, H+, Pyruvate, and ATP will be equal.
a. The equilibrium constant (Keq) for REACTION 1 can be calculated using the equation:
ΔG° = -RT ln(Keq)
where R is the gas constant (8.314 J mol^-1 K^-1), T is the temperature in Kelvin (assumed to be 298 K), and ΔG° is the standard free energy change. Rearranging the equation to solve for Keq gives:
Keq = e^(-ΔG°/RT)
Substituting the given values, we get:
Keq =\(e^{(-(-61.9 kJ mol^{-1})/(8.314 J mol^{-1} K^{-1} * 298 K))}\) = \(2.10 * 10^8\)
The equilibrium constant expression for the hydrolysis of PEP can be written as:
Keq = [Pyruvate][Pi][\(H^+\)] / [PEP][\(H_2O\)]
At equilibrium, the ratio of products to reactants is equal to Keq. Therefore, the ratio of Pyruvate to PEP is:
[Pyruvate] / [PEP] = Keq / ([Pi][\(H^+\)]/[\(H_2O\)])
Substituting the given values, we get:
[Pyruvate] / [PEP] = \((2.10 * 10^8) / ((1 M)(10^{-7} M) / (55.5 M))\)
[Pyruvate] / [PEP] = \(3.78 * 10^6\)
b. The equilibrium constant (Keq) for REACTION 2 can be calculated in the same way as in part (a):
Keq = e^(-ΔG°/RT) = \(e^{(-(-30.5 kJ mol^{-1})/(8.314 J mol^{-1} K^{-1} * 298 K))} = 1.26 * 10^5\)
The equilibrium constant expression for the hydrolysis of ATP can be written as:
Keq = [ADP][Pi][\(H^+\)] / [ATP][\(H_2O\)]
At equilibrium, the ratio of products to reactants is equal to Keq. Therefore, the ratio of ATP to ADP is:
[ATP] / [ADP] = [\(H_2O\)] / ([Pi][\(H^+\)]/([ATP]Keq))
Substituting the given values, we get:
[ATP] / [ADP] = \((55.5 M) / ((1 M)(10^{-7} M)/(1 M)(1.26 * 10^5))\)
[ATP] / [ADP] = 441
c. The net coupled chemical equation for the synthesis of ATP from ADP and inorganic phosphate using the hydrolysis of PEP into Pyruvate can be written as:
PEP + ADP + Pi --> Pyruvate + ATP
This equation shows that PEP can drive the synthesis of ATP from ADP and Pi. REACTION 1 is in the forward direction, while REACTION 2 is in the reverse direction.
d. To calculate the ΔG' for the overall net coupled reaction, we need to sum up the ΔG' of the individual reactions.
ΔG'net = ΔG'1 + ΔG'2
ΔG'1 = -61.9 kJ/mol
ΔG'2 = -30.5 kJ/mol
ΔG'net = -61.9 kJ/mol + (-30.5 kJ/mol)
ΔG'net = -92.4 kJ/mol
e. The overall net coupled reaction can be written as follows:
PEP + ADP + Pi + \(H^+\) → Pyruvate + ATP
The ratio of products and reactants for the overall net coupled reaction can be calculated using the equilibrium constant (Keq). The equilibrium constant is defined as the ratio of the concentrations of products to the concentrations of reactants at equilibrium.
Keq = [Pyruvate][ATP]/[PEP][ADP][Pi][\(H^+\)]
At equilibrium, Keq = 10^(ΔG'net/(-RT))
where R is the gas constant (8.314 J/molK), T is the temperature (in Kelvin), and ΔG'net is the standard free energy change of the reaction.
Assuming standard conditions of 25°C (298 K), we get:
Keq = \(10^{(-92400/(8.314*298))\)
Keq = \(2.1 * 10^{27\)
The ratio of products to reactants is given by the coefficients in the balanced equation:
PEP : ADP : Pi : H+ : Pyruvate : ATP = 1 : 1 : 1 : 1 : 1 : 1
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calcium bicarbonate produced in the chemical weathering process of carbonation ________.
Carbonation is a crucial process in rock breakdown and formation of karst topography, involving the formation of calcium bicarbonate through precipitation of carbon dioxide and dissolved substances. This process affects rocks' physical properties and regulates atmospheric carbon dioxide concentration.
Calcium bicarbonate produced in the chemical weathering process of carbonation causes the rock to become weak and break down. This occurs when rainwater reacts with carbon dioxide and turns into a weak carbonic acid solution that can dissolve rocks. As a result, carbonation is an essential process in the breakdown of rocks and formation of karst topography.The chemical formula of calcium bicarbonate is Ca(HCO3)2. It is formed when rainwater, which contains carbon dioxide, reacts with rocks that contain calcium carbonate (CaCO3) like limestone and marble. The reaction is as follows:
CaCO3 + H2CO3 → Ca(HCO3)2
The carbonic acid solution reacts with the rock and breaks it down into calcium bicarbonate and other dissolved substances. Calcium bicarbonate is carried away by groundwater and eventually deposits to form stalactites, stalagmites, and other types of cave formations.
This chemical weathering process of carbonation not only affects the physical properties of rocks but also plays a significant role in the carbon cycle of the Earth. Carbonation helps to regulate the concentration of carbon dioxide in the atmosphere by removing it and storing it underground in the form of calcium carbonate deposits.
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