[1] b) In a local election there were 8000 registered voters. Of these 3200 voted. What was the percentage that voted? [1] <​

Answer:  **

H-N-H

   |

  H

Explanation:

Look at a periodic table to determine how many electrons you need to account for. Hydrogen (H) only has 1 electron, while Nitrogen (N) has 5. We have three Hydrogen atoms and one Nitrogen atom, so the total number of electrons will be 3 * 1 + 5 = 8 e-.

Now, place the center atom, which will be Nitrogen and place the three Hydrogens on three sides of it as above in the answer. You should use single bonds for this. Each single bond is a pair of electrons, so since we have three single bonds so far, we have accounted for 2 * 3 = 6 electrons. However, we need 2 more electrons for the total of 8. We put these electrons in as a lone pair above Nitrogen.

We check to see if everything follows the octet rule: Nitrogen has three single bonds, so that's 6 e-, as well as one lone pair, so that's another 2 e- for a total of 8 e-. Check. Now look at Hydrogen: H is the only element whose full orbital is 2 e-. Each H has a single bond with Nitrogen, so each does have 2 e-.

Thus, we know this is the correct diagram, and we are done.

Explanation:

A bond line structure of a compound has H N H in linear plane and a hydrogen is branching upward, and the compound is H N (H) H. The nitrogen has two dots at its bottom represents a lone pair of electrons. So ,the correct answer is option C.

The correct Lewis structure for ammonia (\(NH_3\)) is option C. It shows a bond line structure with three hydrogen atoms (H) bonded to a central nitrogen atom (N) in a linear plane.

One hydrogen atom branches upward from the plane. Additionally, the nitrogen atom in this structure has two dots at its bottom, indicating a lone pair of electrons. This arrangement follows the octet rule, as nitrogen has formed three covalent bonds with hydrogen, completing its valence shell. The lone pair on nitrogen gives ammonia its characteristic properties.

Thus, option C accurately represents the Lewis structure of ammonia, showing the bonding and lone pair arrangement of its atoms.

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Answer:

Explanation:

The first step in order to solve this particular question is to make sure that the two reactions given in the question is balanced. Therefore, we have;

Reaction 1: C6H12O6 -----------------------------> 2 C2H5OH + 2 CO2.

Reaction 2: C6H12O6 ------------------------------> 2 C2H3CO2H + 2 H2O.

Next, we determine the number of moles of water and that of glucose. Recall that we are given from the question that the open flow reactor =  4000 kg of a 12% glucose-water solution flows in that is to say the percentage for water is [100% - 12% = 88%]. Also, the molar mass of water = H₂O = 18 kg/kmol and that for glucose =180 kg/kmol.

Number of moles of water = (4000 kg × 88%) ÷ 18 = 195.6 kmol.

Number of moles of glucose= (4000kg × 12%) ÷ 180 = 2.67 kmol.

Next thing to do is to determine the number of moles in the unreacted glucose . Therefore, the 90 kg of unreacted glucose ÷ 180kg/kmol = 0.5  kmol.

So, we have that During fermentation, 120 kg of carbon dioxide is produced.  Thus, the number of kmol = 120kg÷ 44kg/mol = 2.73kmol.

For reaction 1, we have 2 moles of CO₂ that is to say the extent of the reaction = 2.73kmol / 2 moles of CO₂ = 1.365 kmol.

For reaction 2, we have 2 moles of CO₂ that is to say the extent of the reaction = 2.67kmol - 0.5  kmol - 1.365kmol = 0.805 kmol.

For both reaction, the kmol for outflow of glucose = 2.73 kmol.

Also, 2 × 0.805 + 1.365 × 0 = 1.61kmol.

Hence, 195.6 kmol + 1.61 =197.21 kmol.

The mass of ethanol = 46.1 kg/kmol × 2.73 kmol = 125.853 kg.

The weight percent of ethanol has been 29.72%, and the percent mass of propionic acid has been 47.79%.

The balanced chemical equations of the reactions have been:

\(\rm C_6H_1_2O_6\;\rightarrow\;2\;C_2H_5OH\;+\;2\;CO_2\)

\(\rm C_6H_1_2O_6\;\rightarrow\;2\;C_2H_3CO_2H\;+\;2\;H_2O\)

The solution has consisted of 12% glucose.

Water in the solution = 88%

The mass of the solution = 4000 kg.

The moles of glucose = 12% of 4000 kg

Moles of glucose = \(\rm \dfrac{12}{100}\;\times\;4000\;\times\;\dfrac{1}{180\;g/mol}\)

Moles of glucose = 2.67 kmol.

Moles of water =  88 % of 4000 kg

Moles of water = \(\rm \dfrac{88}{100}\;\times\;4000\;\times\;\dfrac{1}{18\;g/mol}\)

Moles of water = 195.6 kmol.

The unreacted glucose in the mixture = 90 kg

Moles of unreacted glucose:

Moles = \(\rm \dfrac{weight}{molecular\;weight}\)

Moles of unreacted glucose = \(\rm \dfrac{90\;\times\;1000\;g}{180\;g/mol}\)

Moles of unreacted glucose = 0.5 kmol

The mass of carbon dioxide produced = 120 kg.

Moles of carbon dioxide produced = \(\rm \dfrac{120\;\times\;1000\;g}{44\;g/mol}\)

Moles of carbon dioxide produced = 2.73 kmol

Since 1 mole of glucose produces 2 moles of carbon dioxide.

2.73 kmol of carbon dioxide has been produced from 1.365 kmol of glucose.

The moles of ethanol produced by reaction 1 = 2 moles/ mole glucose.

The glucose present has been 2.67 kmol.

The ethanol produced = 5.34 kmol.

Moles of propionic acid produced = 5.34 kmol.

The mass of 5.34 kmol ethanol = Moles × molecular weight

The mass of ethanol produced = 5.34 × 1000 × 46.07g/mol

The mass of ethanol produced = 246.0138 kg.

The mass of propionic acid produced = 5.34  × 1000 × 74.08 g/mol

The mass of propionic acid produced = 395.5872 kg.

The mass of water produced = 5.34 × 1000 × 18 g/mol

The mass of water produced = 96.12 kg.

The remained glucose = 90 kg

The total mass in the reactor:

= Mass of glucose + water + propionic acid + ethanol

= 90 + 96.12 + 395.5872 + 246.0138 kg

= 827.721 kg.

% Mass of ethanol = \(\rm \dfrac{246.0138}{827.721}\;\times\;100\)

% Mass of ethanol = 29.72%

% Mass of Propionic acid = \(\rm \dfrac{395.5872}{827.721}\;\times\;100\)

% Mass of Propionic acid = 47.79 %.

The weight percent of ethanol has been 29.72%, and the percent mass of propionic acid has been 47.79%.

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Answer:

1. solid

2. liquid

3. plasma

4. gas

Those are the four parts of matter.

Explanation:

I hope this helps.

Inter-conversion of glucose and fructose occurs with an equilibrium constant of 1.0. Glucose isomerase catalyzes this reaction. The final concentration of fructose at equilibrium from 40mM glucose is a. 40 mM.

Using this formula to find the  final concentration of fructose

Final concentration of fructose  =Equilibrium from glucose/ Equilibrium constant

Where:

Equilibrium constant = 1.0

Equilibrium from glucose = 40 mM

Let plug in the formula

Final concentration of fructose  = 40mM / 1.0

Final concentration of fructose  =  40mM

Therefore we can conclude that the correct option is A.

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The complete question is:

Inter-conversion of glucose and fructose occurs with an equilibrium constant of 1.0. Glucose isomerase catalyzes this reaction. The final concentration of fructose at equilibrium from 40mM glucose is

a. 40 mM

b. 20 mM

c. 10 mM

d. 0 mM​

The measure of the length of events and the duration of intervals between events is time.

The duration of events or the gaps between them can be measured, compared, or even ordered using time. The lengthy period of time that the Earth's geologic history takes up is known as geologic time. Starting at the beginning of the Archean Eon  formal geologic time runs until the present. Geology is defined as the "Science of the Earth."

Geology is the fundamental Earth science that examines how the earth created, its structure and composition, and the various forces acting on it. It is sometimes known as geoscience or earth science.

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Answer: B.) -12.4

Explanation: This is because the sign of heat transfer is determined by the system's perspective. In this case, the system is releasing heat to the surroundings, which means that heat is flowing out of the system, making the heat transfer negative. The magnitude of the heat transfer is 12.4 J.

This element is in group 1.

According to the octet rule, this element would be expected to form an ion with a charge of +1.

If X is in period 5, the ion formed has the same electron configuration as the noble gas Krypton

The symbol for the ion is Rb⁺

Electronic configuration refers to the arrangement of electrons in the orbitals of an atom or molecule, indicating the energy level of the electrons, the number of electrons in each energy level, and the number of electrons in each orbital.

Considering the given element:

It has one valence electron, hence it is in group 1. Group 1 elements form ions with a charge of +1.

Losing one electron will give the ion the same electron configuration as Kyrton since it is the noble gas in Period 4.

The element is rubidium and the ion is Rb⁺.

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No, Ag₂SO₄ will not precipitate when 100ml of .050M AgNO3 is mixed with 10ml of 5x10-2 m Na₂SO₄ solution because the precipitate is made only in an aqueous solution.

Precipitation is the solid extract that is collect in a place. Precipitate is the concentration of the substance in a solution in a specific place.

Thus, No, Ag₂SO₄ will not precipitate when 100ml of .050M AgNO3 is mixed with 10ml of 5x10-2 m Na₂SO₄ solution because the precipitate is made only in an aqueous solution.

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Answer:

What are the options

Explanation:

Answer:

"People with more knowledge of science are always healthier"

Explanation:

A kiln is a specialized oven used in ceramic art to harden clay objects to a temperature that causes irreversible chemical changes in the clay, resulting in a permanent transformation of the material into ceramics.

What is a kiln and how is it used in ceramic art?

A kiln is a specialized oven used in ceramic art to harden clay objects to a temperature that causes irreversible chemical changes in the clay, resulting in a permanent transformation of the material into ceramics.

The temperature required for this transformation depends on the type of clay being used and the desired final product, but it typically ranges from around 1,000 to 1,400 degrees Celsius (1,800 to 2,550 degrees Fahrenheit). Kilns can be used for a variety of ceramic techniques, including firing, glazing, and decorating clay objects.

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The enthalpy of combustion for 1kg of urea is -1223525.84 J/mol.

Urea is a compound that is used in fertilizers and in some plastics.The enthalpy of combustion for urea is the amount of energy that is released when urea is burned. In order to calculate the enthalpy of combustion for 1kg of urea, we need to use the information that is provided to us in the question. Let us start by writing down the balanced equation for the combustion of urea: CO(NH2)2 + 3/2 O2 → CO2 + 2H2O + N2
The balanced equation shows that 1 mole of urea reacts with 1.5 moles of oxygen gas to produce 1 mole of carbon dioxide, 2 moles of water, and 1 mole of nitrogen gas. The enthalpy change for this reaction is equal to the amount of energy that is released when 1 mole of urea is burned.
The heat of combustion (ΔHc) of urea is -632.6 kJ/mol. This means that 632.6 kJ of energy is released when 1 mole of urea is burned. We know that 12g of urea raised the temperature of water by 30°C. We can use this information to calculate the amount of energy that was released when 12g of urea was burned.
The specific heat capacity of water is 4.18 J/g°C. This means that it takes 4.18 J of energy to raise the temperature of 1 gram of water by 1°C. Therefore, it takes 4.18 x 1000 = 4180 J of energy to raise the temperature of 1 kg of water by 1°C.
We know that 12g of urea raised the temperature of water by 30°C. Therefore, the amount of energy that was released when 12g of urea was burned is:
Energy = mass x specific heat capacity x temperature change
Energy = 0.012 kg x 4180 J/kg°C x 30°C
Energy = 1497.6 J
We can now use this information to calculate the enthalpy of combustion for 1kg of urea:
Enthalpy of combustion = energy released / moles of urea burned
Enthalpy of combustion = 1497.6 J / (0.012 kg / 60.06 g/mol)
Enthalpy of combustion = - 1223525.84 J/mol
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The intermolecular force between bromine and benzene is primarily a van der Waals force known as London dispersion forces.

London dispersion forces occur due to temporary fluctuations in electron distribution, creating temporary dipoles in molecules. In the case of bromine and benzene, both molecules are nonpolar, meaning they have no permanent dipole. However, they still experience London dispersion forces.

Benzene is a cyclic aromatic hydrocarbon with a hexagonal ring structure. It consists of delocalized π electrons above and below the plane of the molecule. Bromine is a halogen element with seven valence electrons, which forms diatomic molecules. In the solid or liquid state, bromine molecules exist as Br2.

The London dispersion forces between bromine and benzene arise from the temporary shifts in electron density within their electron clouds. The π electrons in benzene induce temporary dipoles in the bromine molecules, resulting in attractive forces between them. These temporary dipoles continuously form and break due to electron movements, resulting in an overall attractive force between the bromine and benzene molecules.

While London dispersion forces are generally weaker than other intermolecular forces like dipole-dipole interactions or hydrogen bonding, they still contribute to the stability of the system and affect properties such as boiling points and melting points.

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Answer:

Explanation:

C. warm weather

Answer:

stormy weather

the maximum amount of product that can be formed is 124.39 g SO₃, and there will be 36.8 g of excess O₂ left over.

To find the amount of excess reagent, you need to first determine which reactant is limiting and which is in excess.

Determine the limiting reagent:

Use stoichiometry to determine how much product can be formed from each reactant:

mol SO2:

2 SO₂ + O₂ -> 2 SO₃

2 mol SO₃/2 mol SO₂ = 1 mol SO₃/mol SO₂

1 mol SO₃ = 80.06 g SO₍₃₎

From 2.7 mol O₂

2 SO₂ + O₂ -> 2 SO₃

1 mol SO₃/1 mol O₂ = 1 mol SO₃/mol O₂

1 mol SO₃ = 80.06 g SO₃

2.7 mol O₂ x (1 mol SO₂/1 mol O₂) x (80.06 g SO₂/mol SO₂) = 216.45 g SO₂

Since the amount of SO₂ produced from 3.1 mol of SO₂ is less than the amount produced from 2.7 mol of O₂, SO₂ is the limiting reagent.

Calculate the amount of excess reagent:

To find the amount of excess O₂, use the balanced equation to determine how much O₂ is required to react with all of the SO₂:

2 SO₂ + O₂ -> 2 SO

3.1 mol SO2 x (1 mol O₂/2 mol SO2) = 1.55 mol O₂

Subtract the amount of O₂ used from the initial amount of O₂:

2.7 mol O₂ - 1.55 mol O2 = 1.15 mol O₂

Finally, convert the excess O₂ to mass:

1.15 mol O₂ x 32.00 g/mol = 36.8 g O₂

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Answer:

The amount of work required to raise the TV from point A to point B is equal to the amount of gravitational potential energy the TV gains from its height above the ground. This is generally true for any object ...

Answer:

Mark me as brainlest

Explanation:

Microorganisms present in our body Re viruses, bacteria, fungi, algae, and protozoa among which most of them cause immense benefits to the body. There are some harmful microorganisms too known as pathogens which cause disease and cause a threat to all existing life forms of the earth which can result in death at times.

Answer:

An example of microorganisms acting in a harmful way is a bacteria spoiling food.

Answer:

all of the above

Explanation:

i got the answer right on cK-12

Answer:

solid

Explanation:

If you were to leave the gallium in the interior of the car at those temperatures the gallium would still be in a solid physical state when you return. This is because the temperature in Fahrenheit when you return is 85.08F which converted to Celsius would equal 29.488C. This is close to Gallium's melting of 29.768C point but does not exceed it, meaning that it is close to melting but has not yet done so and is, therefore, still a solid.

The strand 1 of hydrocarbons is used to produce plastic, hence option D is correct.

Raw resources like natural gas, oil, or plants that have been processed into ethane and propane are used to make plastics. The subsequent "cracking" procedure uses heat to transform ethane and propane into ethylene and propylene. To produce various polymers, these components are mixed.

Propylene is a substance found in large quantities in petroleum. In order to speed up chemical processes, refiners combine heated propylene with a catalyst to create plastic. Propylene molecules start to cluster together like beads on a thread as a result.

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Answer:

Explanation:

One system available in the industry for the detection of foreign substances in cotton is the High Volume Instrument (HVI) system. The HVI system measures several properties of cotton fibers, such as length, strength, micronaire, color, and foreign matter content. The foreign matter content measurement detects and quantifies any extraneous materials present in the cotton fibers, such as dirt, seed coat fragments, and leaf particles. The HVI system is widely used in the cotton industry for quality control and grading purposes.

Answer:

21.7 kj

Explanation:

The heat required to change the phase of a matter is calculated by using the latent heat formula, Q=ML, where M is the mass released or absorbed during the phase change and L is the latent heat of a material. Since ice is melted into water, this process is technically called the heat of endorthermic phase change that is Q_in=ml

The latent heat of water is 334 kg/kj. In order to melt 65. 0g of ice Q=0.065 x 334kj/kg =21.71 of heat required

Answer:

Although you might think of a machine as complex system of gears, drive belts and and a motor, the definition physicists use is much simpler. A machine is simply a device that does work, and there are only six different types of simple machines. They include the lever, the pulley, the wheel and axle, the screw, the wedge and the inclined plane.

Explanation:

Answer

89.0 g

Explanation

Given information:

Equation of the reaction: 2Na + Cl₂ → 2NaCl₂

Reacting mass of Na = 35.0 g

Reacting mass of Cl₂ = 100.0 g

What to find:

The maximum amount of NaCl that can be produce from 35.0g of Na and 100.0g of Cl₂.

Step-by-step solution:

From the given balanced chemical equation for the reaction; 2 moles of Na reacts with 1 mole of Cl₂ to produce 2 moles of NaCl₂.

The next step is to convert the given masses to moles

From the Periodic Table:

Molar mass of Na = 22.989769 g/mol

Molar mass of Cl₂ = 35.453 g/mol

The formula to calculate mole is:

Therefore,

The next step is to determine the limiting reactant.

To get that, divide the moles of Na and Cl₂ with their respective coefficients in the given equation:

For Na = 1.52/2 = 0.75

For Cl₂ = 2.82/1 = 2.82

Hence, Na is the limiting reactant.

Now you can compare the mass of the mass of Na to the mass of NaCl₂ produced as follows:

The maximum amount of NaCl that can be produce from 35.0g of Na and 100.0g of Cl₂ is 89.0 g

The question is incomplete. The complete question is :

C. Balance these fossil-fuel combustion reactions. (1 point)

C8H18(g) + 12.5O2(g) →    ____CO2(g) + 9H2O(g) + heat

CH4(g) + ____O2(g) →     ____CO2(g) + ____H2O(g) + heat

C3H8(g) + ____O2(g) →    ____CO2(g) + ____H2O(g) + heat

C6H6(g) + ____O2(g)  →   ____CO2(g) + ____H2O(g) + heat

Solution :

C8H18(g) + 12.5O2(g) →    __8__CO2(g) + 9H2O(g) + heat

When 1 part of octane reacts with 12.5 parts of oxygen, it gives 8 parts of carbon dioxide and 9 parts of water along with liberation of energy.

CH4(g) + __2__O2(g) →     __1__CO2(g) + __2__H2O(g) + heat

When 1 part of methane reacts with 2 parts of oxygen, it gives 1 part of carbon dioxide and 2 parts of water along with liberation of energy.

C3H8(g) + __5__O2(g) →    __3__CO2(g) + __4__H2O(g) + heat

When 1 part of propane reacts with 5 parts of oxygen, it gives 3 part of carbon dioxide and 4 parts of water along with liberation of energy.

C6H6(g) + __1/2__O2(g)  →   __6__CO2(g) + __3__H2O(g) + heat

When 1 part of propane reacts with 1/2 parts of oxygen, it gives 6 part of carbon dioxide and 3 parts of water along with liberation of energy.

Answer:

atoms

Explanation:

.......................................

At its heart, chemical reactions are the breaking and making of bonds, and the shuffling around of atoms.

Chemical reactions are defined as a procedure that takes place when multiple molecules combine to create a new product. Reactants are substances that interact to make new substances, whereas products are those substances that result from the interaction. Nearly all of the materials you come into contact with on a daily basis are the product of chemical transformations, however nuclear processes can also create new matter.

Bond disassociation is the breaking of a bond. Bond formation is the same as bond making. The hydrolysis is a type of chemical process in which the connection between two molecules is severed while water is added. Two molecules are produced when a bond is broken. Water molecules have hydrogen ions connected to one molecule and hydroxyl ions bound to another.

Thus, at its heart, chemical reactions are the breaking and making of bonds, and the shuffling around of atoms.

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Answer:

A. Eight

Explanation:

Although there are eight major endocrine glands scattered throughout the body, they are still considered to be one system because they have similar functions, similar mechanisms of influence, and many important interrelationships.