Answer:
B. 3/4 Mile
Step-by-step explanation:If she ran 1/3 the way to school and that was 1/4 of a mile, all you have to do is multiply 1/4 by 3 to get 3/4 of a mile
Regina Falange is 173 cm tall, making her line of sight exactly 163 from the ground. She is looking at a hawk in a tree and both are on level ground. The trunk of the tree is 10 meters away from her location and the angle of elevation from her eyeline to the hawk is 30 degrees. What is the hawk’s height above the ground?
a. Drawn a diagram that outlines the situation. Be sure to label the tree, hawk, Regina, the angle, etc.
b. Find the height of the hawk above the ground in cm. (Hint: Remember Regina’s height.) Round to the nearest hundredth.
Answer: 7.40 meters
Step-by-step explanation:
I went with 163 cm for the height because it says her eyeline is at 163 cm. I don't assume she would be looking from the top of her head so I went with that over 173 cm(h for hawk)
All you do is:
tan(30)=opposite/adjacent
tan(30)=h/10
10*tan(30)=h
h≈5.77 meters
163cm converted to meters is 1.63 meters, so add it to 5.77 and you will get 7.40 meters
This might help as well: https://www.ck12.org/book/ck-12-trigonometry-concepts/section/1.13/
Please help me with this homework
Answer:
-620
Step-by-step explanation:
Answer:
-620
Step-by-step explanation:
You just need to do the ten's time tables
on which of the following roads are you least likely to lose traction
Roads that are well-maintained, dry, and free from hazards are generally less likely to result in traction loss.
The likelihood of losing traction depends on various factors such as road conditions, weather, vehicle type, and driver behavior. However, in general, roads that are well-maintained, dry, and free from debris or hazards are less likely to result in traction loss. Additionally, roads with good grip surfaces, such as asphalt or concrete, tend to provide better traction compared to unpaved or slippery surfaces. It's important to drive cautiously and adapt to the specific conditions of the road to minimize the risk of losing traction.
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The perimeter of a triangle is 44cm. The area of the rectangle is 117cm2. Find the length of the shorter side of the rectangle. Help please
Shorter side = 9 cm
Question:The perimeter of a rectangule is 44cm. The area of the rectangle is 117cm2. Find the length of the shorter side of the rectangle.
Let:Length rectangle be a.Width of rectangle be b.To find?Length of the shorter side of the rectangle.Given:Perimeter of rectangle = 44cmArea of rectangle = 117cm²Answer :A/Q
Perimeter of rectangle = 44cm
We know:
p=2(L+B)
.°. ⇒44 =2(a+b)
⇒44 /2 =a+b
⇒22=a+b
So:
a=22-b
b=22-a
Now Let's put values in formula of Area
A/Q
Area of rectangle = 117cm²
We know:
Area =L×B
.°.117=ab
Put value of b in this equation
⇒117=a(22-a)
⇒117=22a-a²=0
⇒a-22a²+117=0
⇒(a- 9)(a- 13) = 0
.°. a=9
a=13cm
Let's put value of a as 13 to find b
⇒b=22-a
⇒b=22-13
⇒b=9cm
So the side having 9cm is shorter i.e. b
The mean score of 7 boys and 16 girls is 49. If the scores of the boys are 42,85,47,29,58,54and 72, find the mean score of the girls
Answer:
\(\bar x_{girls} = 46.25\)
Step-by-step explanation:
Given
\(Boys = 7\\Girls = 16\)
\(\bar x = 49\)
Required
Mean of girls
The mean of the boys and girls is calculated as:
\(\bar x = \frac{\sum x}{n}\)
This gives:
\(\bar x = \frac{\sum(boys) + \sum(girls)}{boys + girls}\)
So, we have:
\(49= \frac{42+85+47+29+58+54+ 72 + \sum(girls)}{7 + 16}\)
\(49= \frac{387 + \sum(girls)}{23}\)
Cross multiply
\(23 * 49=387 + \sum(girls)\)
\(1127=387 + \sum(girls)\)
Subtract by 387
\(1127-387 = \sum(girls)\)
\(740= \sum(girls)\)
\(\sum(girls) = 740\)
The mean of girls is:
\(\bar x_{girls} = \frac{\sum(girls)}{girls}\)
\(\bar x_{girls} = \frac{740}{16}\)
\(\bar x_{girls} = 46.25\)
Which multiplication expression can be used to check this division problem: 2/5 divided by 4/15 =3/2.
A. 2/5 x 4/15
B. 3/2 x 4/15
C.3/2 x 15/4
D. 5/2 x 15/4
Btw D is wrong ://
Help!!
Answer:
the answer is B
Step-by-step explanation:
1. Please help if possible :)
Answer:
54
Step-by-step explanation:
6x=9x-27
x=9
9*9-27=54
If 7 pencils cost $4. 20, then 3 pencils costs
$0. 60
$1. 80
$12. 60
$29. 40
Therefore, the cost of 3 pencils is approximately $1.80.
To find the cost of 3 pencils, we can set up a proportion based on the given information:
7 pencils cost $4.20
Let's assign the cost of 3 pencils as x dollars.
The proportion can be set up as: 7 pencils / $4.20 = 3 pencils / x
To solve for x, we can cross-multiply: 7 * x = 3 * $4.20
7x = $12.60
Dividing both sides of the equation by 7:
x = $12.60 / 7
x ≈ $1.80
Therefore, the cost of 3 pencils is approximately $1.80.
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the city of Picayune has set aside $900,000 to build a new water tower in the shape of a cylinder. If the price per cubic foot is $10.50, what is the largest measure for the radius and height of the cylinder in order to not exceed the budget?
Answer:
So as not to exceed the budget, where π = 22/7, we have;
The radius = 10 ft and the height = 3/11 ft
For standard 40 ft. height, the radius is approximately 0.8259 ft
Step-by-step explanation:
The amount set aside for the water tower = $900,000
The price (amount) per cubic foot = $10.50
Therefore, we have;
\(The \ volume \ of \ the \ water \ tower \ to \ be \ built = \dfrac{The \ amount \ set aside \ for \ the \ water \ tower}{The \ price \ (amount) \ per \ cubic \ foot }\)
\(\therefore The \ volume \ of \ the \ water \ tower \ to \ be \ built = \dfrac{\$ 900,000}{\$10.50/ft\\ ^3} = \dfrac{600}{7} ft.^3 = 85 \frac{5}{7} ft^3\)
Whereby the height of a standard water tower = 40 ft., we have;
The shape of the water tower = The shape of the water tower
∴ The volume of the water tower V = π × r² × h
Where;
r = The radius of the water tower
h = The height of the water tower
Taking π = 22/7
600/7 = 22/7 × r² × h
r² × h = 600/7/(22/7) ≈ 300/11 = 100 × 3/11
Solving to get exact dimensions so as to not exceed the budget, we have;
r² × h = 100 × 3/11 = 10 × 10 × 3/11
Therefore, the radius can be 10 ft. and the height = 3/11 ft.
Or for standard 40 ft. height, we have;
r² = 600/7/(π × 40)
r ≈ 0.8259 ft.
An elevator went up 15 floors, down 9 floors, up 11 floors, and down 21
floors. Where is the elevator now?
-5 54 2 -4 1
What y’all think is the right answer ?
One of them
Answer:
-4
Step-by-step explanation:
15-9= 6
6+11= 17
17-21= -4
5. (0,0) and (-2,-8) Slope=_ Equation=_
3+6/2+2-3•2 you must show your work
Answer:
your answer is 2.
Step-by-step explanation:
3+6/2+2-3*2
3+3+2-3*2
3+3+2-6
6+2-6
8-6
2
Basically, follow PEMDAS (parenthesis, exponents, multipulcation, division, addition, and subtraction.) You move from left to right, Always remember that, ok.
0 0
U
Un emprendedor sabe que para vender x de sus productos diariamente el precio de cada uno debe ser 96.800-10x pesos. ¿Cuál es el precio, en pesos, al que debe cobrar sus productos para vender 200 unidades diarias? *
Responder:
94,800 pesos
Explicación paso a paso:
Dado que:
Para vender x de un producto diariamente, el precio al que debe vender cada uno de sus productos = 96800 - 10x pesos
Por lo tanto, para vender 200 unidades al día, el precio a cobrar será:
Sustituye 200 en lugar de x en la ecuación de precio anterior,
Es decir ;
x = 200
Precio = 96,800 - 10 (200) pesos
Precio = 96,800 - 2000
Precio = 94,800 pesos
De ahí que el precio a cobrar al vender 200 unidades diarias sea de 94.800 pesos.
Please help me with the below question.
Answer:
its blury i can't understand
minimum possible integral value of k such that the equation 2^2x - 2(k-1)2x+k=0 has one root less than 1 and other root greater than 1
Finding the smallest possible integer value of k requires analyzing the given equation and determining the conditions under which one root is less than 1 and the other is greater than 1.
The equation is:
2^(2x) - 2(k-1)^(2x) + k = 0
Let's break down the conditions step by step.
1. Square root less than 1:
To make the square root less than 1, we need to substitute x = 1 into the equation and get a positive value. So if x = 1, then
2^(2*1) - 2(k-1)^(2*1) + k > 0
4 - 2(k-1)^2 + k > 0
Extensions and simplifications:
4 - 2(k^2 - 2k + 1) + k > 0
4 - 2k^2 + 4k - 2 + k > 0
-2k^2 + 5k + 2 > 0
2k^2 - 5k - 2 < 0 xss=removed xss=removed xss=removed xss=removed > 0.
Now we can combine both conditions to find the smallest integer value of k.
2k^2 - 5k - 2 < 0 > 0 (Condition 2)
By solving these conditions simultaneously, we can find the range of values of k that satisfy both conditions and determine the smallest integer value of k. However, this process requires calculations and algebraic manipulations beyond the scope of simple text-based answers.
It is recommended to use an algebraic calculator or software to solve the equation and find the smallest integer value of k that satisfies the given conditions.
IMPORTANT:Kindly Heart and 5 Star this answer, thanks!h(x) = 4x - 1; Find h( - 1)
Answer:
h(-1) = -5
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDASStep-by-step explanation:
Step 1: Define
h(x) = 4x - 1
h(-1) is x = -1
Step 2: Evaluate
Substitute: h(-1) = 4(-1) - 1Multiply: h(-1) = -4 - 1Subtract: h(-1) = -5And we have our final answer!
Chase ordered a set of beads. He received 4,000 beads in all. 3,000 of the beads were green. What percentage of the beads were green?
75% of the beads are green in color.
What is Percentage?percentage, a relative value indicating hundredth parts of any quantity.
Given that Chase ordered a set of beads
He received 4,000 beads in all.
3,000 of the beads were green.
We need to find the percentage of the beads were green of 4000.
x/100×4000=3000
40x=3000
Divide both sides by 40
x=75%
Hence, 75% of the beads are green in color.
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can u hurry and help please
Answer:
18.84
Step-by-step explanation:
Hope this helps :)
Answer:
18.84
The equation for circumference is 2πr which means that you times 2 by pi and then the radius which is 6 divided by 2 so 3. Then you get 6π which is 18.84
Find the rate of change of y with respect to x if dy dx x²y-5+2 ln y = x³
The rate of change of y with respect to x is given by dy/dx = xy - (3/2)x²y.
To find the rate of change of y with respect to x, we need to differentiate the given equation. The rate of change can be determined by taking the derivative of both sides of the equation with respect to x.
First, let's differentiate each term separately using the rules of differentiation.
Differentiating x²y with respect to x gives us 2xy using the product rule.
To differentiate 5, we know that a constant has a derivative of 0.
Differentiating 2ln(y) with respect to x requires the chain rule. The derivative of ln(y) with respect to y is 1/y, and then we multiply by dy/dx. So, the derivative of 2ln(y) is 2/y * dy/dx.
Differentiating x³ gives us 3x² using the power rule.
Now, we can rewrite the equation with its derivatives:
2xy - 2/y * dy/dx = 3x²
To solve for dy/dx, we can isolate it on one side of the equation. Rearranging the equation, we get:
2xy = 2/y * dy/dx + 3x²
To isolate dy/dx, we move the term 2/y * dy/dx to the other side:
2xy - 2/y * dy/dx = 3x²
2xy = 2/y * dy/dx + 3x²
2/y * dy/dx = 2xy - 3x²
Now, we can solve for dy/dx by multiplying both sides by y/2:
dy/dx = (2xy - 3x²) * (y/2)
Simplifying further, we have:
dy/dx = xy - (3/2)x²y
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The Baldwin family walked 4/5 of a mile in 4/9 of an hour. What is their unit rate in miles per hour?
Answer:
1.8
Step-by-step explanation:
Unit rate in mile per hour
= 4/5 mile / 4/9 hour
= 4/5 * 9/4 = 9/5 miles per hour
= 9/5 = 1.8 miles per hour
a recipe for lemenade calls for 1 cup of sugar and 5 cups of water. how much suger is used per cup of water
alternate interior angles
If the speed and the charge of a particle moving across a magnetic field are each doubled, the deflecting force will be: Select one: a. doubled b. halved c. quartered d. quadrupled
If the speed and the charge of a particle moving across a magnetic field are each doubled, the deflecting force will be:
d. The deflecting force will be quadrupled.
The deflecting force experienced by a charged particle moving across a magnetic field is given by the equation F = qvBsinθ, where F is the deflecting force, q is the charge of the particle, v is its velocity, B is the magnetic field strength, and θ is the angle between the velocity vector and the magnetic field vector.
If both the speed (v) and charge (q) of the particle are doubled, the deflecting force (F) can be calculated by substituting the new values into the equation:
F' = (2q)(2v)Bsinθ = 4(qvBsinθ) = 4F
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What type of triangle is △str? right triangle equilateral triangle isosceles triangle scalene triangle
The type of triangle is △STR is isosceles triangle.
What's triangleA triangle is a flat shape bounded by three sides. In another sense, a triangle is formed by three line segments called sides and each side intersects with two other sides.
When classified from its angles, triangles consist of acute triangles, right triangles, and obtuse triangles. Even so, the sum of the angles of a triangle is always 180 degrees. Based on the classification of its sides, triangles consist of equilateral triangles, arbitrary triangles, and acute triangles.
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How do you write the slope-intercept form of the equation of the line through the given point and parallel to the given line?.
The slope-intercept form of the equation of the line through the given point and parallel to the given line is y=x−14.
In the given question we have to write the slope-intercept form of the equation of the line through the given point and parallel to the given line.
The given points are (–2, –16).
The given equation of line is y = x – 5.
Standard equation of line is y=mx+c.
After comparing to the standard equation.
Slope m(1) = 1
The line passes through (−2,−16), so the point will satisfy the equation y=mx+c. So
−16=−2*1+c
Simlifying
−16=−2+c
Add 2 on both side, we get
c = −16+2
c = −14
As we know that if line is parallel then
m(1)=m(2)
So the value of solpe m = 1
Now the equation of line
y=1*x+(−14)
y=x−14
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The right answer is:
How do you write the slope-intercept form of the equation of the line through the given point and parallel to the given line?
Point (−2,−16), y = x – 5
HELP PLEASE !!!!!
Subtract.
(9w² + 3w) - (6w² + w)
Answer:
3w²+2w
Step-by-step explanation:
(9w² +3w)-(6w²+w)
=9w²+3w-6w²-w
collecting like terms
=9w²-6w²+3w-w
=3w²+2w
=w(2+3w)
Mount Mo is 5323 feet tall dawn climbed it in five days she climbed 821 feet on the last day how many feet did she climb in the first four days
Answer:
1,125.5
Step-by-step explanation:
You subtract the amount she climbed on the last day then divide the difference by four
Answer:
She climbed 4502 feet the first four days and if she climbed the same amount each of those four days she climbed 1125.5 each day!
Help mee !! I’ll give points !!
Answer: It is (x - 3)(x + 5)
Simplify
(2 Points)
2a xa x 3a + b x 45
Answer:
\(6a^3+45b\)
Step-by-step explanation:
\(2a\times a\times 3a+b\times 45\)
\(2a\times 1a\times 3a+b\times 45\)
\(2\times 1\times 3 \times a \times a \times a+b\times 45\)
\(6a^3+b \times45\)
\(=6a^3+45b\)
Answer:
6a^3 + 45b
Step-by-step explanation:
=2a × a × 3a + b × 45
=2a × 1a × 3a + b × 45
=2 × 1 × 3 × a × a × a + b × 45
=6a^3 + b × 45
= 6a^3 + 45b
answer this qusten and ill mark u brainlyest 6+6 hhehehe
Answer:
6+6= 30 billion
Step-by-step explanation:
Answer:
6 + 6 = 66 or 12
Step-by-step explanation:
I'm not sure