1- An unbounded problem is one for which ________. remains feasibleA. the objective is maximized or minimized by more than one combination of decision variablesB. there is no solution that simultaneously satisfies all the constraintsC. the objective can be increased or decreased to infinity or negative infinity while the solutionD. there is exactly one solution that will result in the maximum or minimum objective2- If a model has alternative optimal solutions, ________.A. the objective is maximized or minimized by more than one combination of decision variablesB. there is no solution that simultaneously satisfies all the constraintsC. the objective can be increased or decreased to infinity or negative infinityD. there is exactly one solution that will result in the maximum or minimum objective3- The ________ indicates how much the value of the objective function will change as the right-hand side of a constraint is increased by 1.A. objective coefficientB. shadow priceC. binding constraintD. reduced cost

Answers

Answer 1

A) An unbounded problem is one for which the objective can be increased or decreased to infinity or negative infinity while the solution remains feasible.

B) If a model has alternative optimal solutions the objective is maximized (or minimized) by more than one combination of decision variables, all of which have the same objective function value.

In mathematics, a function from a set X to a set Y assigns to each element of X exactly one element of Y. The set X is called the domain of the function and the set Y is called the codomain of the function.

C) The shadow price indicates how much the value of the objective function will change as the right-hand side of a constraint is increased by 1.

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Related Questions

Five and one half minus 7

Answers

The answer to five and one half minus 7 is 2

Answer:

- 1 1/2

Step-by-step explanation:

5 1/2 - 7 = - 1 1/2

The tens digit of a two-digit number is one more than the units digit. The number itself is 6 times the sum of the digits. Find the number.

Answers

If the tens digit of a two-digit number is one more than the units digit and the number itself is 6 times the sum of the digits, then the solution is a two-digit number 54.

Let's assume that the units digit of the two-digit number is x. According to the problem statement, the tens digit is one more than the units digit, which means that the tens digit is x + 1. Therefore, the two-digit number can be expressed as 10(x+1) + x, which simplifies to 11x + 10.

The problem also states that the number is 6 times the sum of its digits. The sum of the digits is x + (x + 1) = 2x + 1. Therefore, we can set up an equation:

11x + 10 = 6(2x + 1)

Simplifying the equation, we get:

11x + 10 = 12x + 6

Subtracting 11x from both sides, we get:

10 = x + 6

Subtracting 6 from both sides, we get:

x = 4

Therefore, the units digit is 4, and the tens digit is one more than that, which is 5. The two-digit number is 54. We can check that this is indeed 6 times the sum of its digits:

54 = 6(4 + 5)

54 = 6(9)

54 = 54

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10.4 For the following situation. fal determine which evatuation nethod is probably the cusiese and lasitest (o apply hy hand and hy eomputer in order 10 selece from the five allematives, and (h) thst

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Based on the provided question, it seems like you are asking about the most efficient evaluation method, either by hand or using a computer. To determine which method is the most suitable, you need to consider the complexity of the evaluation process and the number of alternatives.


Using a computer is generally faster and more accurate when dealing with large datasets or complex calculations. On the other hand, evaluating by hand may be more suitable for smaller datasets or simpler calculations. It can provide a more hands-on approach, allowing for a deeper understanding of the evaluation process. However, this method is generally more time-consuming and prone to human error.

To select the most appropriate evaluation method, consider the complexity of the task and the available resources. If the evaluation involves a large amount of data or complex calculations, using a computer would likely be the most efficient choice. However, if the task is relatively simple or involves a smaller dataset, evaluating by hand may suffice. In conclusion, the choice between evaluating by hand or using a computer depends on the complexity of the task and the available resources. Consider these factors to determine the most suitable method.

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A ____________ can be used to help us determine the extent of how much an outcome is achieved.

Answers

A metric can be used to help us determine the extent of how much an outcome is achieved.

What is metric?

A metric is a quantifiable gauge that is employed to assess, scrutinize, and appraise diverse facets of a system, procedure, or outcome. It furnishes a standardized and unbiased approach to gauge and monitor performance or advancement towards particular objectives or goals. Metrics are commonly formulated based on precise criteria or prerequisites and can manifest as numerical or qualitative in essence.

They find application in various domains such as commerce, finance, science, engineering, and myriad others to evaluate performance, facilitate well-informed decisions, and oversee progress over time.

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Find the distance of LINE SEGMENT ​rs.

Find the distance of LINE SEGMENT rs.

Answers

Answer:

11

Step-by-step explanation:

QS = QR + RS ➡ 19 = -1 + x + 2x - 7 add like terms

19 = 3x - 8

27 = 3x

9 = x

RS = 2x - 7 so 2×9 - 7 = 11

Please help me I need this answer

Please help me I need this answer

Answers

The feature that will be the same as the original is:

The perimeter is the same.

The coordinate of C' is (3, 4).

The slope of A'C' is 1/4.

We have,

To rotate a point 180 degrees clockwise around another point, you can follow these steps:

- Calculate the displacement vector from the center of rotation to the point you want to rotate.

- Reverse the direction of the displacement vector.

- Apply the reversed displacement vector to the center of rotation.

- Let's apply these steps to each vertex of triangle ABC to find the coordinates of A', B', and C'.

So,

- Coordinate of A' (rotated point of A around (3, 4)):

Displacement vector: (A' - Center of rotation) = (A - Center of rotation) = (-5, 2) - (3, 4) = (-8, -2).

Reverse the direction of the displacement vector:

Reversed displacement vector: (-8, -2) * (-1) = (8, 2).

Apply the reversed displacement vector to the center of rotation:

Coordinate of A': (3, 4) + (8, 2) = (11, 6).

- Coordinate of B' (rotated point of B around (3, 4)):

Displacement vector: (B' - Center of rotation) = (B - Center of rotation) = (-2, 5) - (3, 4) = (-5, 1).

Reverse the direction of the displacement vector:

Reversed displacement vector: (-5, 1) * (-1) = (5, -1).

Apply the reversed displacement vector to the center of rotation:

Coordinate of B': (3, 4) + (5, -1) = (8, 3).

- Coordinate of C' (rotated point of C around (3, 4)):

Displacement vector: (C' - Center of rotation) = (C - Center of rotation) = (3, 4) - (3, 4) = (0, 0).

Reverse the direction of the displacement vector:

Reversed displacement vector: (0, 0) * (-1) = (0, 0).

Apply the reversed displacement vector to the center of rotation:

Coordinate of C': (3, 4) + (0, 0) = (3, 4).

So,

The coordinate of A' is (11, 6).

The coordinate of B' is (8, 3).

The coordinate of C' is (3, 4).

To find the perimeter and area of a triangle, we can use the coordinates of its vertices.

Let's start by finding the perimeter and area of triangle ABC.

Triangle ABC:

A = (-5, 2)

B = (-2, 5)

C = (3, 4)

The perimeter of triangle ABC:

The perimeter of a triangle is the sum of the lengths of its sides. We can use the distance formula to calculate the lengths of each side and then sum them up.

Length of side AB:

\(d_{AB} = \sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2)\)

= √((-2 - (-5))² + (5 - 2)²)

= √(3² + 3²)

= √(18)

= 3√2

Length of side BC:

\(d_{BC} = \sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2)\)

= √((3 - (-2))² + (4 - 5)²)

= √(5² + 1²)

= √(26)

Length of side CA:

\(d_{CA}= \sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2)\)

= √((-5 - 3)² + (2 - 4)²)

= √((-8)² + (-2)²)

= √(64 + 4)

= √(68)

= 2√17

The perimeter of triangle ABC:

\(P_{ABC} = d_{AB} + d_{BC} + d_{CA}\)

= 3√2 + √26 + 2√17

Area of triangle ABC:

The area of a triangle can be calculated using the coordinates of its vertices with the Shoelace formula.

Area of triangle ABC:

A_ABC = 1/2 x |(x1 x y2 + x2 x y3 + x3 x y1) - (y1 x x2 + y2 x x3 + y3 x x1)|

= 1/2 x |((-5 x 5) + (-2 x 4) + (3 x 2)) - ((2 x -2) + (5 x 3) + (4 x -5))|

= 1/2 x |(-25 - 8 + 6) - (-4 + 15 - 20)|

= 1/2 x |-27 - (-9)|

= 1/2 x |-27 + 9|

= 1/2 x |-18|

= 9

Now let's find the perimeter and area of triangle A'B'C', which is the rotated triangle of ABC.

Triangle A'B'C':

A' = (11, 6)

B' = (8, 3)

C' = (3, 4)

The perimeter of triangle A'B'C':

Using the same approach as before, we calculate the lengths of the sides:

Length of side A'B':

d_A'B' = √((x2 - x1)^2 + (y2 - y1)^2)

= √((8 - 11)^2 + (3 - 6)^2)

= √((-3)^2 + (-3)^2)

= √(18)

= 3√2

Length of side B'C':

d_B'C' = √((x2 - x1)^2 + (y2 - y1)^2)

= √((3 - 8)^2 + (4 - 3)^2)

= √((-5)^2 + 1^2)

= √(26)

Length of side C'A':

d_C'A' = √((x2 - x1)^2 + (y2 - y1)^2)

= √((3 - 11)^2 + (4 - 6)^2)

= √((-8)^2 + (-2)^2)

= √(68)

= 2√17

The perimeter of triangle A'B'C':

P_A'B'C' = d_A'B' + d_B'C' + d_C'A'

= 3√2 + √26 + 2√17

Area of triangle A'B'C':

Using the same Shoelace formula as before:

Area of triangle A'B'C':

A_A'B'C' = 1/2 x |(x1 x y2 + x2 x y3 + x3 x y1) - (y1 x x2 + y2 x x3 + y3 x x1)|

= 1/2 x |((11 x 3) + (8 x 4) + (3 x 6)) - ((6 x 8) + (3 x 3) + (4 x 11))|

= 1/2 x |(33 + 32 + 18) - (48 + 9 + 44)|

= 1/2 x |(83) - (101)|

= 1/2 x |-18|

= 9

Now,

The perimeter of triangle ABC is 3√2 + √26 + 2√17, and the area of triangle ABC is 9.

The perimeter of triangle A'B'C' is 3√2 + √26 + 2√17, and the area of triangle A'B'C' is 9.

The slope of A'C' can be calculated using the coordinates of A' and C'.

The slope of a line can be calculated using the formula:

slope = (y2 - y1) / (x2 - x1)

For A'(11, 6) and C'(3, 4), the slope of A'C' is:

slope = (4 - 6) / (3 - 11)

= -2 / -8

= 1/4

Thus,

The feature that will be the same as the original is:

The perimeter is the same.

The coordinate of C' is (3, 4).

The slope of A'C' is 1/4.

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Question 3(Multiple Choice Worth 2 points)
(Evaluating Inequalities MC)
Determine which integer(s) from the set S:(-24, 2, 20, 35) will make the inequality m-5 +3 false.

Answers

From the given set S, the only integer that makes the inequality m - 5 + 3 false is m = -24.

How to determine the integer from the set  will make the inequality false.

To determine which integer(s) from the set S: (-24, 2, 20, 35) will make the inequality m - 5 + 3 false, we need to substitute each integer from the set into the inequality and check if the inequality becomes false.

The inequality is:

m - 5 + 3 < 0

Substituting each integer from the set S into the inequality:

For m = -24:

(-24) - 5 + 3 < 0

-26 + 3 < 0

-23 < 0 (True)

For m = 2:

2 - 5 + 3 < 0

0 < 0 (False)

For m = 20:

20 - 5 + 3 < 0

18 < 0 (False)

For m = 35:

35 - 5 + 3 < 0

33 < 0 (False)

From the given set S, the only integer that makes the inequality m - 5 + 3 false is m = -24.

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the average lifespan for a certain type of vehicle is 8 years and follows an exponential distribution. a lot contains 200 of these vehicles, brand new. 1. how many of the 200 would you expect to fail in their first 2 years?

Answers

Of the 200, 44 failures during the first two years are to be expected.

Given;

A specific kind of vehicle has an exponential lifespan that is typically 8 years long. There are 200 of these new cars on a lot.

The probability of failure in the first 2 years is first computed here as:

P(T < 2) for  X = exp(1/8) as for exponential distribution, the parameter is the reciprocal of the mean. Therefore, now using the CDF for the exponential distribution, we get here;

⇒ 1 - \(e^\frac{-2}{8}\) = 0.2212

Therefore, 0.2212 is the probability here.

Now the expected number which fails in the first 2 years here is computed as;

⇒ 200 * 0.2212 = 44.24 is the required expected value here.

Hence, 44 of the 200 would you expect to fail in their first 2 years.

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Three children are riding on the edge of a merry-go-round that is 142 kg, has a 1.60 m radius, and is spinning at 21.3 rpm. The children have masses of 22.4, 29.5, and 40.8 kg. If the

Answers

The problem describes three children riding on the edge of a merry-go-round with given masses. The task is to calculate the angular momentum of the system.

To calculate the angular momentum of the system, we need to consider the angular momentum of both the merry-go-round and the children.

Calculating the moment of inertia of the merry-go-round: \((1/2) × 142 kg × (1.60 m)^2 = 181.76 kg·m^2.\)

The angular momentum of the merry-go-round is then: angular momentum = \(181.76 kg·m^2 × (21.3 rpm × 2π/60) = 766.34 kg·m^2/s.\)

For the children, we calculate their individual angular momenta using the formula: angular momentum = mass × velocity × radius. Since the children are riding on the edge of the merry-go-round, their velocities are equal to the tangential velocity of the merry-go-round.

Calculating the angular momentum for each child:

Child 1: 22.4 kg × \((1.60 m × 21.3 rpm × 2π/60) = 471.95 kg·m^2/s\)

Child 2: 29.5 kg × \((1.60 m × 21.3 rpm × 2π/60) = 622.20 kg·m^2/s\)

Child 3: 40.8 kg × (1.60 m × 21.3 rpm × 2π/60) = 855.01 kg·m^2/s

The total angular momentum of the system is the sum of the angular momenta of the merry-go-round and the children:

Total angular momentum = \(766.34 kg·m^2/s + 471.95 kg·m^2/s + 622.20 kg·m^2/s + 855.01 kg·m^2/s = 2715.50 kg·m^2/s.\)

Therefore, the total angular momentum of the system consisting of the merry-go-round and the three children is \(2715.50 kg·m^2/s.\)

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Indicate the equation of the given line in standard form, in the equation box below.

The line through (-3,4) and perpendicular to a line that has a slope 2/5

Answers

Perpendicular lines have slopes that are negative reciprocals of each other, so the equation of the line in point-slope form is:

\(y-4=-\frac{5}{2}(x+3)\)

Rewriting this in standard form,

\(2y-8=-5(x+3) \\ \\ 2y-8=-5x-15 \\ \\ \boxed{5x+2y=-7}\)

Indicate the equation of the given line in standard form, in the equation box below. The line through

Pls help question about total pay
Show working out

Pls help question about total pay Show working out

Answers

\(7\frac{1}{2}\implies 7.5\hspace{5em}1\frac{1}{4}\implies 1.25 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{ \textit{Monday through Friday} }{\stackrel{ days }{(5)}\stackrel{ rate }{(10.80)}\stackrel{ hours }{(7.5)}}~~ + ~~\stackrel{ Saturday }{\stackrel{ days }{(1)}\stackrel{ rate }{(10.80)(1.25)}\stackrel{ hours }{(7.5)}} \\\\\\ 405~~ + ~~101.25\implies \text{\LARGE 506.25}\)

please help i need to get this done ayo i will give brainliest

please help i need to get this done ayo i will give brainliest

Answers

Answer:

172

Step-by-step explanation:

I promise you that this is right!

geometric averages are usually blank______ arithmetic averages. multiple choice question. the same as smaller than larger than

Answers

Geometric averages are usually smaller than arithmetic averages.

The geometric average is a type of average that is calculated by taking the nth root of the product of n numbers. It is commonly used when dealing with growth rates, ratios, and exponential functions. On the other hand, the arithmetic average, also known as the mean, is calculated by summing up a set of numbers and dividing it by the count of those numbers.

The relationship between the geometric average and the arithmetic average can be understood by considering the behavior of the numbers being averaged. When the numbers being averaged have a wide range or vary significantly, the geometric average tends to be smaller than the arithmetic average. This is because the geometric average gives more weight to smaller values, which can pull down the average.

For example, if we have a set of numbers that includes both very small values and very large values, the geometric average will be more influenced by the small values, resulting in a smaller average compared to the arithmetic average. This is because the geometric average emphasizes the impact of each individual value's proportionate contribution to the overall average.

In summary, geometric averages are usually smaller than arithmetic averages when dealing with sets of numbers that have a wide range or significant variation. However, it is important to note that the relationship between these averages can vary depending on the specific dataset and its characteristics.

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Find the total surface area of this triangular prism.
10cm
6 cm
4cm
8 cm

Find the total surface area of this triangular prism. 10cm 6 cm 4cm 8 cm

Answers

Method:

Front: 6x8 = 48/2 = 24

Back: Also 24

Base: 8x4 = 32

Left: 6x4=24

Add your answers:

24 + 24 + 24 + 32 + 40

Answer:

TSA is 144 cm²


translate this sentence to an equation 11 less than Helenas saving is 75.h represent saving

Answers

The equation representing the sentence "11 less than Helena's saving is 75" is h - 11 = 75.

In this equation, we assign the variable h to represent Helena's saving. Since the sentence states that Helena's saving is 11 less than a certain value (which we don't know yet), we subtract 11 from h. The result of this subtraction is then equal to 75, as stated in the sentence.

By writing the equation as h - 11 = 75, we have translated the sentence into a mathematical representation that can be solved to determine the value of h, representing Helena's saving.

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Determine the margin of error for a confidence interval to estimate the population mean with n=45 and a = 37 for the following confidence levels.

Answers

The margin of error for a confidence interval to estimate the population mean with n=45 and a = 37 can be determined using the appropriate formula.

For a 90% confidence level, the margin of error can be calculated as 1.98.

For a 95% confidence level, the margin of error can be calculated as 2.27.

For a 99% confidence level, the margin of error can be calculated as 2.71.

The margin of error represents the range within which the true population mean is likely to fall. It is influenced by the sample size and the chosen confidence level. Larger sample sizes generally result in smaller margins of error, while higher confidence levels lead to larger margins of error.

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Approximating the sum of the series by the fifth partial sum, we have the following.
[infinity]∑ ₙ₋₁ 1/n⁵ ≈ 1/1⁵ + 1/2⁵ + 1/3⁵ + . . . . + 1/5⁵
≈ ____ (rounded to four decimal places)

Answers

The approximation of the sum of the series by the fifth partial sum is approximately 1.0367.

To approximate the sum of the series ∑ₙ₋₁ 1/n⁵ using the fifth partial sum, we consider the terms up to the fifth term: 1/1⁵ + 1/2⁵ + 1/3⁵ + 1/4⁵ + 1/5⁵

Each term represents the reciprocal of the fifth power of the corresponding natural number. We calculate each term separately:

1/1⁵ = 1/1 = 1

1/2⁵ = 1/32 = 0.03125

1/3⁵ ≈ 0.004115226

1/4⁵ ≈ 0.000976563

1/5⁵ ≈ 0.00032

Adding up these terms, we get: 1 + 0.03125 + 0.004115226 + 0.000976563 + 0.00032 ≈ 1.0367

Therefore, by summing the first five terms of the series, we obtain an approximation of approximately 1.0367. This approximation is obtained by considering a finite number of terms, and it becomes more accurate as we include more terms in the sum.

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ai mi is starting a running plan to train for a race. in the first week of her running plan, ai mi will run 5 miles. the plan calls for ai mi to increase her weekly milage by 1.5 miles every week. if ai mi sticks to the plan, how many miles would she be expected to run during her 16th week of the training plan?

Answers

If Ai Mi sticks to the plan, she would be expected to run 27.5 miles during her 16th week of the training plan.

The number of miles Ai Mi would be expected to run during her 16th week of the training plan, we need to determine the pattern of mileage increase.

In the first week, Ai Mi runs 5 miles. The plan calls for an increase of 1.5 miles every week. This means that for each subsequent week, Ai Mi's mileage will be 1.5 miles more than the previous week.

To find the mileage for the 16th week, we can use the formula

Mileage = Initial Mileage + (Week Number - 1) * Weekly Increase

In this case, the initial mileage is 5 miles, the weekly increase is 1.5 miles, and we want to find the mileage for the 16th week.

Mileage = 5 + (16 - 1) × 1.5

Mileage = 5 + 15 × 1.5

Mileage = 5 + 22.5

Mileage = 27.5

Therefore, if Ai Mi sticks to the plan, she would be expected to run 27.5 miles during her 16th week of the training plan.

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a. Use the Product Rule to find the derivative of the given function. a. Use the product rule to find the derivative of the function. Select the correct answer below and fill in the answer box(es) to complete your choice. A. The derivative is (x−7)(2x+1)+ ? ,B. The derivative is (x−7) (?)∣+(2x+1)(?) ,C. The derivative is (?)(x−7). D. The derivative is (?)x(2x+1). E. The derivative is (x−7)(2x+1)(?)

Answers

Using the Product Rule to find the derivative of the given function we get the derivative (x - 7)(2x + 1) + 4x - 13.

To use the Product Rule to find the derivative of the given function, we need to differentiate the two factors separately and then combine them using the Product Rule.

Let's denote the function as f(x) = (x - 7)(2x + 1).

Using the Product Rule, the derivative of f(x) is given by:

f'(x) = (x - 7)'(2x + 1) + (x - 7)(2x + 1)'.

Now let's differentiate each factor:

The derivative of (x - 7) with respect to x is 1.

The derivative of (2x + 1) with respect to x is 2.

Plugging these values back into the derivative expression:

f'(x) = 1 * (2x + 1) + (x - 7) * 2.

Simplifying:

f'(x) = 2x + 1 + 2x - 14.

Combining like terms:

f'(x) = 4x - 13.

Therefore, the correct answer is A. The derivative is (x - 7)(2x + 1) + 4x - 13.

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What is the approximation of the value cos (1) obtained by using the fifth-degree Taylor polynomial about x=0 for cos (x) Select one:
1 - 1/2 + 1/24
1 - 1/2 + 1/4
1 - 1/3 + 1/5
1 - 1/6 + 1/120

Answers

The approximation of cos(1) using the fifth-degree Taylor polynomial is 1 - 1/2 + 1/24.

The approximation of the value cos(1) obtained by using the fifth-degree Taylor polynomial about x=0 for cos(x) is 1 - 1/2 + 1/24.

The Taylor series expansion for cos(x) centered at x=0 is given by:

cos(x) = 1 - (x^2)/2! + (x^4)/4! - (x^6)/6! + (x^8)/8! - ...

To approximate cos(1), we consider the terms up to the fifth-degree polynomial:

cos(x) ≈ 1 - (x^2)/2! + (x^4)/4!

Substituting x=1 into the polynomial, we get:

cos(1) ≈ 1 - 1/2 + 1/24

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Let U = {(x, y, z) € R^3 | x + 2y – 3z =0}. a) (2pt) Show directly (by verifying the conditions for a subspace) that U is a subspace of R^3. You may not invoke results learned in class or from the notes. b) (2pts) Find a basis for U. You must explain your method. c) (1pt) Using your answer from part b) determine Dim(U).

Answers

a) U is subspace of R^3.

b) The set {(3, -2, 0), (0, 1/2, 1)} is a basis for U.

c) 2.

a) To show that U is a subspace of R^3, we need to verify the following three conditions:

i) The zero vector (0, 0, 0) is in U.

ii) U is closed under addition.

iii) U is closed under scalar multiplication.

i) The zero vector is in U since 0 + 2(0) - 3(0) = 0.

ii) Let (x1, y1, z1) and (x2, y2, z2) be two vectors in U. Then we have:

x1 + 2y1 - 3z1 = 0 (by definition of U)

x2 + 2y2 - 3z2 = 0 (by definition of U)

Adding these two equations, we get:

(x1 + x2) + 2(y1 + y2) - 3(z1 + z2) = 0

which shows that the sum (x1 + x2, y1 + y2, z1 + z2) is also in U. Therefore, U is closed under addition.

iii) Let (x, y, z) be a vector in U, and let c be a scalar. Then we have:

x + 2y - 3z = 0 (by definition of U)

Multiplying both sides of this equation by c, we get:

cx + 2cy - 3cz = 0

which shows that the vector (cx, cy, cz) is also in U. Therefore, U is closed under scalar multiplication.

Since U satisfies all three conditions, it is a subspace of R^3.

b) To find a basis for U, we can start by setting z = t (where t is an arbitrary parameter), and then solving for x and y in terms of t. From the equation x + 2y - 3z = 0, we have:

x = 3z - 2y

y = (x - 3z)/2

Substituting z = t into these equations, we get:

x = 3t - 2y

y = (x - 3t)/2

Now, we can express any vector in U as a linear combination of two vectors of the form (3, -2, 0) and (0, 1/2, 1), since:

(x, y, z) = x(3, -2, 0) + y(0, 1/2, 1) = (3x, -2x + (1/2)y, y + z)

Therefore, the set {(3, -2, 0), (0, 1/2, 1)} is a basis for U.

c) Since the basis for U has two elements, the dimension of U is 2.

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if f(x)= 3/x^2 - 2 and g(x)=4x then g(f(3))= ?
A.) 3/7
B.) 2/3
C.) 12/3
D.) 12/7
E.) 14/7

Answers

Answer:

https://corbettmaths.files.wordpress.com/2015/03/functions-answers.pdf

Step-by-step explanation:

Sorry if this is not right

Which is the same as
25/100
A. 0.0025%
B. 0.025%
C. 0.25%
D. 2.5%
E. 25%

Answers

Answer:

the anwser is a i think im helping you out dont repoty

The answer is E because E is the best answer

A graduate student is designing a research study. She is hoping to show that the results of an experiment are statistically significant. What type of p-value would she want to obtain?.

Answers

The required type of p-value would she want to obtain is small p-value.

What is hypothesis test?

Hypothesis testing is a type of measurable surmising that utilizes information from an example to make inferences about a populace boundary or a populace probability distribution. Initial, a speculative supposition that is made about the boundary or dispersion.

According to question:

P-value  shows that the outcomes are genuinely huge.

P-value  in Measurements assists with performing speculation test and it assists with deciding the meaning of the outcomes.

A little P-value  commonly (P<0.05) demonstrates solid proof against the invalid speculation in this way, we reject the invalid speculation, on opposite when P-esteem is enormous we can't dismiss the invalid speculation.

Thus, required answer is small p-value.

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Find FH

FH = {Blank}

Find FHFH = {Blank}

Answers

Answer:

22

Step-by-step explanation:

\(FH=8+14=22\)

Answer:

FH = 22

Step-by-step explanation:

The equation will be,

→ FH = FG + GH

Then the value of FH will be,

→ FH = 8 + 14

→ [ FH = 22 ]

Hence, the value of FH is 22.

A bag of sand originally weighing 320 pounds was lifted at a constant rate. As it rose, sand also leaked out at a constant rate. The sand was half gone by the time the bag has been lifted to 27 ft. How much work was done lifting the sand this far

Answers

we need to use the formula Work = Force x Distance. First, we need to figure out the force required to lift the bag of sand. We know that the bag originally weighed 320 pounds, so the force required to lift it would also be 320 pounds.



Next, we need to figure out the distance the bag was lifted. We are given that the bag was lifted to a height of 27 ft. Now, we need to take into account that sand was leaking out of the bag at a constant rate as it was being lifted. We are told that by the time the bag was lifted to a height of 27 ft, half of the sand had leaked out.

This means that the bag now weighs 160 pounds, So, we can calculate the work done lifting the sand by using the formula: Work = Force x Distance, Work = 320 pounds x 27 ft, Work = 8,640 foot-pounds, But we also need to take into account the sand that leaked out.

If the bag now weighs 160 pounds, then 160 pounds of sand leaked out, We can calculate the work done by the leaking sand by using the formula: Work = Force x Distance, The force here is the weight of the sand that leaked out, which is 160 pounds.


The distance is the same as the distance the bag was lifted, which is 27 ft, Work = 160 pounds x 27 ft, Work = 4,320 foot-pounds, To get the total work done lifting the sand,

we need to add the work done by lifting the bag and the work done by the sand that leaked out: Total work = Work done lifting the bag + Work done by leaking sand, Total work = 8,640 foot-pounds + 4,320 foot-pounds, Total work = 13,960 foot-pounds, Therefore, the work done lifting the sand this far is 13,960 foot-pounds.

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A 16-foot ladder is resting against a wall when the bottom of the ladder begins to slip from the wall at a rate of 0.75 ft/s. Find the rate at which the top of the ladder is sliding down the wall when the bottom of the ladder is 10 ft away from the wall.

Answers

Answer:

8 feet from the wall.

Which postulate can be used to prove the two triangles are congruent if you know that
UQ ≅ AC and QD ≅ AU

Which postulate can be used to prove the two triangles are congruent if you know thatUQ AC and QD AU

Answers

The postulate that can be used to prove the two triangles are congruent is (c) None of the other answers are correct

How to prove the congruency of the triangles

The figure represents the given parameter

There are two triangles in the figure

Such that the triangles are similar triangles or congruent

From the question, we understand that the triangles are congruent

Also, we know that

UQ ≅ AC and QD ≅ AU

There is no point C on any of the triangles

This means that we cannot ascertain the congruency of the triangles

Hence, the true statement is (c)

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A uniform distribution is defined over the interval from 2 to 5.
What is the range of the random variable, x?
Over the range, what is the probability of the random variable, x?
What is the area of this uniform distribution?

Answers

The probability of x within this range is constant and equal to 1/3. The area under the uniform distribution curve is 1.

The range of the random variable, x, in a uniform distribution from 2 to 5 is [2, 5]. It represents the entire interval of possible values for x.

The probability of the random variable, x, in a uniform distribution is constant over the range. Since it is a uniform distribution, the probability density function is equal for all values within the range. Therefore, the probability of x taking any specific value within the range [2, 5] is the same, and it is given by 1 divided by the length of the range:

Probability of x = 1 / (length of range)

= \(P(x) = \frac{1}{5 - 2} = \frac{1}{3}\)

The area of the uniform distribution is represented by the probability density function over the range. Since it is a uniform distribution, the probability density is constant within the range. Therefore, the area under the curve is equal to the length of the range multiplied by the constant probability density:

Area = (length of range) * (probability density) = (5 - 2) * (1 / (5 - 2)) = 3 * (1 / 3) = 1.

Hence, the area of the uniform distribution is 1.

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Write a unit rate for the situation. Round to the nearest hundredth if necessary. 210 heartbeats in 3 minutes

Answers

Answer:

70 heartbeats per second

Step-by-step explanation:

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