1. A force of ION causes aspring to extend by 20mm. find A.the spring constant of the spring in N/m
B.the extentsion of the spring in N/m
C. the force applied that causes an externos Of 9mm.​

The answer is yes because of conservation of momentum. That is, the momentum before collision is equal to the momentum after collision.

Momentum is the product of mass and velocity. It is a vector quantity. And it is measured in Kgm/s

If two vehicles have a head-on collision, the vehicles essentially stick together and travel a certain distance for 20 seconds before coming to a complete stop. The final velocity for both vehicles immediately after the crash can be obtain by using the formula

v = u - at

Where

If you are able to obtain the mass of both vehicles, the initial velocity for Vehicle A, and the final velocity for both vehicles immediately after the crash, then you can determine the momentum of both vehicles before the collision by calculating the momentum of both after the collision because momentum is always conserved.

Or by first calculating the initial velocity for vehicle B by using the formula below

\(M_{1}U_{1} - M_{2}U_{2} = (M_{1} + M_{2} )V\)

where

After we obtain initial velocity for vehicle B, we can calculate the momentum of both vehicles before the collision

Therefore, the momentum of both vehicles before the collision can be determined.

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the correct option is: a.into the picture (in the direction opposite to that of I1 and I3).

if we resolve the force on I3, one component would be towards I1 and one away from I3.

thus force between I1 and I3 is attractive while the force between I3 and I2 is repulsive.

Since force between I3 and I2 is repulsive, they have parallel currents in opposite directions.

therefore the answer is (A), the direction of current in I2 is into the picture (in the direction opposite to that of I1 and I3)

The magnetic force is a result of the electromagnetic force, one of the four basic forces of nature, and is brought about by the movement of charges. Two items containing accuses of a similar bearing of movement have a magnetic fascination force between them. Essentially, objects with charges moving in inverse bearings have a frightful force between them.

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Answer:

At point A, the cart has high potential energy. At point b, the cart is pulled down by gravity. At point c, the cart gains its highest kinetic energy. At point d, the cart returns back to the same state but with lower potential energy.

The total momentum vectors will not change prior to or following a collision. When two objects collide at an angle from one another, their momentum will not change. Thus, the momentum of objects colliding remains constant.

Because momentum is dependent on mass and velocity, objects in space can have momentum. Mass is a property that does not change depending on where an object is, unlike other properties like weight.

Simply said, mass is the continuous amount of matter that makes up an item. Thus, momentum is a property of objects in space.

Therefore, Both the ship and the individual are moving at a 2 km/h rate.

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Answer:

1

Explanation:

How many digits are in front of the decimal in scientific notation?

Answer:

Caused by gravity and the roller coaster's position, the potential energy is stored in the roller coaster. For example, this ball is at the top of a hill, where potential energy is at it's highest.

Explanation:

Answer:

745.4K ~ 472.3 C

Explanation:

This is an Ideal Gas Law problem where we have to manipulate the equation a bit. Let's start with the basic:

PV = nRT will be used for both the initial and final, so we will rearrange this problem to state:

(V(initial))/(T(Initial)) = nR/P

Since we know that the pressure, number of moles of He, and ideal gas constant (R) remain the same from start to finish so we can write the problem as such:

(V(initial))/(T(Initial)) = nR/P = (V(final))/(T(final))

                             or

(V(initial))/(T(Initial)) = (V(final))/(T(final))

Now lets define some of these values:

T(initial) = 25degree (assuming degrees Celsius) ~ 298.15K

V(initial) = 2.0L

V(final) = 5.0L

T(final) = ?

Since we are solving for T(final) let's rearrange the problem once more to be solving for T(final):

T(final) = (V(final)T(Initial))/V(initial)

Now plug in your values:

T(final) = (5.0L*298.15K)/(2.0L) ~ 745.4K ~ 472.3degrees Celsius

Answer:

c

Explanation:

a, b, and d are examples of moving forward

while c is moving backwards.

Answer:

i) Power = Force * Velocity = 1100 * 15 = 16500 W = 16.5 kW(ii)  Find the value of k first: F = 400 + k(15^2)                                              k = 28/9    F = 400 +(28/9)(30^2) = 320

Explanation:

Answer:

40

Explanation: 1 hour and 15 min is 1.25 hour.

50km   -->    1.25 h

x km     -->    1 h

50 km * 1h = x km*1.25h

x = 40 average speed of car is 40

Answer:

b

Explanation:

i know

Answer:

b one will not accelerate

third down, chris is correct

The question is: Two masses with values ​​of 8kg and 12kg each are separated by a distance of 1m. Determine the force of gravitational attraction between them if compared with the value of their weights. What is this value?

Answer: The force of gravitational attraction between them if compared with the value of their weights is \(640.704 \times 10^{-11} N\).

Explanation:

Given: \(m_{1}\) = 8 kg,       \(m_{2}\) = 12 kg

Distance = 1 m

Formula used is as follows.

\(F = \frac{G \times m_{1} \times m_{2}}{r^{2}}\)

where,

F = force of gravitational attraction

G = gravitational constant = \(6.674 \times 10^{-11} N m^{2}/kg^{2}\)

\(m_{1}\) = mass of object 1

\(m_{2}\) = mass of object 2

r = distance between the centers of these two objects

Substitute the values into above formula as follows.

\(F = \frac{G \times m_{1} \times m_{2}}{r^{2}}\\= \frac{6.674 \times 10^{-11} Nm^{2}/kg^{2} \times 8 kg \times 12 kg}{(1 m)^{2}}\\= 640.704 \times 10^{-11} N\)

Thus, we can conclude that the force of gravitational attraction between them if compared with the value of their weights is \(640.704 \times 10^{-11} N\).

Therefore, the velocity of the ball just before it hits the ground is approximately 22.1 m/s. Therefore, the closest value to this option is 21.0 m/s.

When a ball of mass 0.25 kg falls from a height of 50 m, we can calculate its velocity using the principle of conservation of energy. According to this principle, the sum of the potential and kinetic energy of an object remains constant.

Therefore, we can equate the potential energy at the initial height to the kinetic energy at the final velocity.Let's calculate the potential energy of the ball at the initial height

:Eg = mghEg = 0.25 kg × 9.81 m/s² × 50 m

Eg = 122.625 J

This is the energy that the ball has due to its position. As it falls, this energy is transformed into kinetic energy. At the moment the ball reaches the ground, all the potential energy has been transformed into kinetic energy

.Ek = 1/2mv²Ek = Egv² = 2Ek/mv = √(2Ek/m)

Let's plug in the values we obtained:Eg = 122.625 Jm = 0.25 kgv = √(2Ek/m)

We obtain:v = √(2 × 122.625 J / 0.25 kg)v = √(245.25 J/kg)v = 22.116 m/s

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Answer:

the process of comparing unknown quantities with known standards quantities are known as measurement

Answer:

Weight of the box? 980 N

Value of the normal force? 630 N

Acceleration of the box? 7.5 m/s^2

Explanation:

I got the answer right

Throwing one shoe southward at 10 m/s will give you more momentum toward the north.

Momentum is defined as the product of an object's mass and its velocity. The momentum of an object can be determined using the equation:

Momentum = mass × velocity

In this case, both scenarios involve throwing shoes southward, which means the velocity is directed to the south. The key difference is the magnitude of the velocity.

When throwing one shoe southward at 10 m/s, the velocity is higher compared to throwing two shoes southward at 5 m/s. Since momentum depends on velocity, the higher velocity of the single shoe results in a greater momentum.

The mass of the shoes does not play a role in determining which action gives more momentum toward the north since the mass is the same in both scenarios. Therefore, throwing one shoe southward at 10 m/s will give you more momentum toward the north compared to throwing two shoes southward at 5 m/s.

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The angular acceleration of the electric motor is -100 rotations per second squared.

To determine the angular acceleration of the electric motor, we can use the formula for angular acceleration:

Angular acceleration (α) = (final angular velocity - initial angular velocity) / time

Given:

Initial angular velocity (ω₁) = 900 rotations

Final angular velocity (ω₂) = 400 rotations

Time (t) = 5 seconds

Plugging in these values into the formula, we can calculate the angular acceleration:

α = (ω₂ - ω₁) / t

= (400 - 900) / 5

= -500 / 5

= -100 rotations per second squared

Therefore, the angular acceleration of the electric motor is -100 rotations per second squared. The negative sign indicates that the motor is decelerating or slowing down.

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Answer: I believe that it is A and D. Or A or D.

A, D

Explanation:

Answer: A and C

Explanation: The rest of the thermal energy goes to the engine making it heat up thats why is can overheat also letting it get destroyed

Answer:

v₂ = 48 mph

Explanation:

We know that,

Speed = distance/time

A German Shepherd takes 4 hours to cover a distance, if it travels at a speed of 36mph.

We need to find the speed to cover the same distance in 3 hours.

\(\dfrac{v_1}{v_2}=\dfrac{t_2}{t_1}\\\\v_2=\dfrac{v_1t_1}{t_2}\\\\v_2=\dfrac{36\times 4}{3}\\\\v_2=48\ mph\)

So, the new speed is 48 mph.

Answer:

the answer is main sequence star

Answer:

she saw it in a movie

Explanation:

she said her mom and her saw it in Step up 3 and fell in love

Answer:

A wave that transmits speech, music, and other signals

Explanation:

Hope it helps

(Give a thank OR mark as brainliest if it's the right answer)

Answer:

a wave that transmits speech, music, and other signals :)

Explanation:

The magnitude of the vector is approximately 14.87 units, the angle between the vector and the positive x-axis is approximately 159.44 degrees.

(a) To find the magnitude of the vector, we can use the Pythagorean theorem. The magnitude (or length) of a vector with components (x, y) is given by the formula:

\(magnitude = \sqrt{(x^2 + y^2)\\\)

In this case, the x-component is -14.0 units and the y-component is 5 units. Plugging these values into the formula, we have:

\(magnitude = \sqrt{((-14.0)^2 + 5^2)\)

\(= \sqrt{(196 + 25)}\\= 14.87 units\)

Therefore, the magnitude of the vector is approximately 14.87 units.

(b) To find the angle between the vector and the positive x-axis, we can use the inverse tangent function (arctan). The angle (θ) is given by the formula:

\(\theta = arctan(y / x)\)

In this case, the y-component is 5 units and the x-component is -14.0 units. Plugging these values into the formula, we have:

\(\theta = arctan(5 / -14.0)\\= -20.56 degrees\)

Note that the angle is negative because the vector points in the negative x-direction. To find the angle in the positive x-direction, we can add 180 degrees:

\(\theta = -20.56 + 180\\= 159.44 \:degrees\)

Therefore, the angle between the vector and the positive x-axis is approximately 159.44 degrees.

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When fueling a boat with a power ventilation system, it is important to allow sufficient time for the ventilation system to effectively remove any built-up fumes or vapors before starting the engine. While the exact duration may vary depending on the specific boat and ventilation system, it is generally recommended to follow the manufacturer's guidelines or the safety recommendations provided for your particular boat.

Typically, a common recommendation is to run the power ventilation system for at least four to five minutes or until you can no longer detect any strong fuel odors in the engine compartment or surrounding areas. This time frame allows for the ventilation system to circulate fresh air and remove potentially hazardous fuel vapors.

It's worth noting that some boats may have more powerful ventilation systems or specific instructions from the manufacturer, so it's essential to consult the owner's manual or any safety guidelines provided by the boat manufacturer for accurate information on the appropriate duration for your specific boat.

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COMPLETE QUESTION:

You are operating a boat with a power ventilation system. you have just fueled this boat. how long should you let the ventilation system run before starting the engine?

Answer:

A. amplitude

Explanation:

please vote me brainliest?? thanks:)

Answer:

i dont undertsnad what do u ned hep wit?

Explanation: