1. A block with a mass of 0.28 Kg is attached to a horizontal spring. The block is pulled back from its equilibrium position until the spring exerts a force of 1.0 N on the block. When the block is released, it oscillates with a frequency of 1.2 Hz.
a. How far was the block pushed back till it was released?
b. Find the maximum Potential energy of the block.
c. Find the maximum Kinetic energy of the block.
d. Find the maximum velocity of the block.
e. Find the velocity of the block at a distance of half the amplitude.
f. Find the force and acceleration at a distance of half the amplitude position.
Answers
The displacement x = -0.098 m
The maximum potential energy of the block = 0.049 J
The maximum kinetic energy of the block = 0.075 J
The maximum velocity of the block = 0.73 m/s
The velocity of the block at a distance of half the amplitude.= 0.60 m/s
How to find the maximum Potential energy of the blockTo solve this problem, we will use the equations of motion for a mass-spring system.
The frequency of oscillation is given by:
f = 1/2π * √(k/m)
where
f is the frequency of oscillation, k is the spring constant, and
m is the mass of the block.
The force exerted by the spring is given by:
F = -kx
where
F is the force,
k is the spring constant, and
x is the displacement from the equilibrium position.
a. To find the displacement x, we can use the force equation:
1.0 N = -kx
using the equation for frequency:
1.2 Hz = 1/2π * √(k/0.28)
Solving for k, we get:
k = (1.2*2π)^2 * 0.28
k = 10.17 N/m
Now we can solve for x:
1.0 N = -(10.17 N/m) * x
x = -1.0 N / (10.17 N/m)
x = -0.098 m
b. The maximum potential energy of the block occurs at the maximum displacement from equilibrium, which we can find using the displacement x we just calculated:
= (1/2)kx^2 = (1/2)(10.17 N/m)(-0.098 m)^2 = 0.049 J
c. The maximum kinetic energy of the block occurs at the equilibrium position, where the velocity is maximum:
K_max = (1/2)mv^2
We can find the velocity using the frequency and the displacement:
v_max = 2πf * |x| = 2π(1.2 Hz)(0.098 m) = 0.73 m/s
Plugging in the values,
K_max = (1/2)(0.28 Kg)(0.73 m/s)^2 = 0.075 J
d. The maximum velocity = 0.73 m/s
e. To find the velocity of the block at a distance of half the amplitude, we can use the conservation of energy:
K_max + U_max = (1/2)kx^2 + (1/2)mv^2
At half the amplitude, the displacement is x/2:
K_max + U_max = (1/2)k(x/2)^2 + (1/2)mv^2
Solving for v, we get:
v = √[(K_max + U_max - (1/2)k(x/2)^2)/(1/2)m]
Plugging in the values, we get:
v = √[(0.075 J + 0.049 J - (1/2)(10.17 N/m)((-0.098 m)/2)^2)/(1/2)(0.28 Kg)]
v = 0.60 m/s
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One of the greatest dangers in a tornado is from flying objects. A 15 pound piece of lumber can turn into a flying missile that could severely damage walls and homes. A piece of steel with a mass of 200 pounds and travelling at the same velocity would cause even more damage. Select any evidence from the list below that you could use to explain why a 200 pound piece of steel would cause more damage than a 15 pound piece of wood travelling at the same velocity.
As the kinetic energy of an object increases, the force it can exert on another object decreases.
As the kinetic energy of an object increases, the force it can exert on another object increases.
Objects with more mass have less kinetic energy.
Objects with more mass have more kinetic energy.
As the velocity of an object increases, its kinetic energy decreases.
As the velocity of an object increases, its kinetic energy increases.
Answers
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what is the work done on the box from x = 0m to 16m
Answers
Answer:
Explanation:
The Workdone is the product of force and distance, Hence, the Workdone on the box from distance x = 0 meters and x = 16 meters is 0 Joules.
Using the graph given :
The work done from x = 0 to x = 16 metres ;
The distance can be split evenly into :
(x = 0 to x = 8) and (x = 8 to x = 16)
Workdone = Force × distance
Workdone from ; x = 0 to x = 8 ;
Force at a distance of 8 meters = - 40N
Workdone = - 40N × 8 m = -320 Nm
Workdone from ; x = 8 to x = 16 ;
Force at a distance of 16 meters = 40 N
Workdone = 40 N × 8 m = 320 Nm
The total workdone :
(-320 + 320) Nm = 0 J
.
Therefore, the Workdone ls 0 Joules.
1) How many joules of heat are required to raise the temperature of 550 g of water from
12.7 °C to 28.8°C ? Specific heat of liquid water is 4.184 J/g °C.
Answers
Answer:
Explanation:
You can use \(Q = mc\Delta T=(550)(4.184)(28.8-12.7)=37049.32\) joule.
A student measured the density of Galena to be 7.9g/cm3 however the known density of Galena is 7.6g/cm3 . Calculate the percent error of the measurements.
Answers
.............
Answer:
~4%
Explanation:
% = |(7.6 - 7.9)|/7.9
= 0.3/7.9 ≈ 0.04 = 4%
Find the resistance at 100°C of a silver wire 1 mm in diameter and 1000 centimetre long ?
Answers
Answer:
Ro=19.350 & R¹⁰⁰=26.703
Explanation:
Sunlight is composed of wavelengths of light that make up part of the electromagnetic spectrum. Towson University Exam Question. The frequency of a wave is directly proportional to the speed at which the wave is traveling. Do NOT Copy! Calculate the frequency (in Hz) of light at the following wavelength:
Answers
Answer:
\(f= 5.11 * 10^{10}Hz\)
Explanation:
Given
\(\lambda = 0.587cm\)
See comment for complete question
Required
Calculate the frequency
Frequency is calculated using:
\(f = \frac{c}{\lambda}\)
Where
\(c \to\) speed of light
\(c =299792458 ms^{-1}\)
\(\lambda = 0.587cm\)
Convert wave length to meters
\(\lambda = 0.587 * 0.01m\)
\(\lambda = 0.00587m\)
So, we have:
\(f = \frac{c}{\lambda}\)
\(f=\frac{299792458 ms^{-1}}{0.00587m}\)
\(f=\frac{299792458}{0.00587}Hz\)
\(f= 5.11 * 10^{10}Hz\)
A hockey puck moves 22 meters northward, then 16 meters southward, and finally 4 meters northward.
For this motion, what is the distance moved?
What is the magnitude and direction of the displacement?
Answers
Answer:
Distance moved = 42 meters
Mag and Dir = 10 meters northward
Explanation:
Distance is total distance traveled which = 22+16+4 = 42 meters
Displacement is the amount of distance moved from the start point to the end point straight line so our equation for the magnitude is 22-16+4 = 10 meters. Then the direction is northward from the start point. This answer would also be a vector because it has a magnitude and direction.
What is the answer to this question number 2?
Answers
Answer:
1⁺ ion
Explanation:
Metals in the first group on the periodic table will prefer to form 1⁺ ion. This is because the 1 valence electron in their orbital.
Most metals are electropositive and would prefer to lose electrons than to gain it.
Like all metals, the group 1 elements called the alkali metals would prefer to lose and electron.
On losing an electron the number of protons is then greater than the number of electrons. This leaves a net positive charge.
what does personal mission statement?
Answers
Answer:
A personal mission statement defines who you are as a person (or as a team member where you work) and identifies your purpose, whether that's in the office or simply in life.
Explanation:
It explains how you aim to pursue that purpose, and why it matters so much to you.
If the distance between the first order maximum and the tenth order maximum of a double-slit pattern is 18 mm and the slits are separated by 0.15 mm with the screen 50 cm from the slits, what is the wavelength of the light used
Answers
Answer:
Wavelength of light is 600 nm
Explanation:
Given
Distance between the first order maximum and the tenth order maximum of a double-slit pattern = 18 mm
Separation between the slits = 0.15 mm
Distance of screen from the slits = 50 cm
Wavelength
\(= \frac{18*10^{-3} * 0.15 *10^{-3}}{0.50*9} \\= 6 *10^{-7}\\= 600\)nm
At the top of a flight of stairs, a woman is 16m above the ground and has 9094J of potential energy. What is the mass of the woman?
Answers
Answer:
Mass = 56.83 Kg
Explanation:
\(PE = mgh\\9094 J = 16m*10 m/s^2*mass\\mass = \frac{PE}{g*h} \\mass = \frac{9094 J}{16*10} = 56.83 kg\)
2. A) How much torque of is exerted on the pivot point P by a 51.2 N force F exerted a rod that is 33.3 cm in length.
B) How much torque of is exerted on the pivot point P if the 51.2 N force is applied at an angle of 56.3 degrees above the radial line?
Answers
A) Torque exerted on the pivot point P by force F is: 17.02 Nm B) torque exerted on the pivot point P by force F at an angle of 56.3 degrees above the radial line is: 13.83 Nm.
What is torque?Torque is a measure of the rotational force on any object around an axis or pivot point.
A) Torque = Force x Lever arm
Given force F is 51.2 N and the lever arm is 33.3 cm.
Lever arm = 33.3 cm = 0.333 m
Therefore, torque exerted on the pivot point P by the force F is:
Torque = 51.2 N x 0.333 m = 17.02 Nm
B) If the force F is applied at an angle of 56.3 degrees above the radial line, Perpendicular force = Force x sin(angle)
Perpendicular force = 51.2 N x sin(56.3°) = 41.48 N
The lever arm is still 0.333 m. Therefore, torque exerted on the pivot point P by force F at an angle of 56.3 degrees above the radial line is:
Torque = Perpendicular force x Lever arm = 41.48 N x 0.333 m = 13.83 Nm.
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the part of the brain stem called the has been shown to related to arousal in lab animals. when this part is stimulated the animal is awake when it is severed cut the animal goes into coma
Answers
Answer:
Its called PSY
Explanation: I so do not know why they named it this way but, hope i helped.
A monarchy is the type of government that the colonist do not want true or false
Answers
Answer:
Monarchy is rule from kings and queens
Explanation:
alex is pushing a heavy box.The force he exerts is represented by the white arrow. In order to make his task easier in which direction should an additional force be applied?
Answers
Answer:
The other arrow/force should be in the same direction that Alex is pushing the heavy box.
Explanation:
If Alex is pushing the heavy box to the right, then another person helping him that is also pushing the heavy box to the right would lessen the amount that he has to push.
A 200-W light bulb is connected across a 110-V dc power supply. What current will flow through this bulb
Answers
Answer:
it should be 1.8
a girl stands on a boat and feels the boat rise and fall 7 times In 1 minute. what is the period of the water wave? give your answer to 3 significant figures
Answers
Explanation:
hope it's helpful
have a nice day!!!! ;)
1. A 1.15-kg block is released from rest on a frictionless inclined plane. The inclined plane forms an angle of 35° with the
ground. The block slides down the inclined plane and compresses a spring at the bottom by 3.5 cm and stops momentarily.
If 334 N are required to compress the spring by 2.4 cm, what distance has the block travelled?
>
Answers
Answer:
Explanation:
We can use the work-energy principle to solve this problem. The work-energy principle states that the work done on an object is equal to the change in kinetic energy of the object.
We can begin by finding the spring constant (k) of the spring. The spring constant is the force required to compress a spring by a certain distance. We can use the information given to us in the problem to find the spring constant:
k = F / x = 334 N / 0.024 m = 13,916.67 N/m
Now we can use the spring constant, the compression distance (3.5 cm) and the mass of the block (1.15 kg) to find the work done on the block as it compresses the spring:
work = 1/2 * k * x^2 = 1/2 * 13,916.67 N/m * (0.035 m)^2 = 97.4 J
Since the block is released from rest, its initial kinetic energy is zero. So, the work done on the block as it compresses the spring is equal to its final kinetic energy.
We know that the block slides down on a frictionless incline, so we need to consider the work done by gravity on the block during its motion. The work done by gravity is given by the equation:
work = force * distance * cos(theta)
where force is the force of gravity acting on the block, distance is the distance the block slides down the incline and theta is the angle of the incline with the ground.
force = m * g , where m = 1.15 kg and g = 9.8 m/s^2
distance = s
theta = 35°
substituting the values
work = (1.15 kg * 9.8 m/s^2) * s * cos(35°)
Now we can add the work done by gravity to the work done by the spring to find the total work done on the block.
work = 97.4 J + (1.15 kg * 9.8 m/s^2) * s * cos(35°) = 97.4 J + (11.37 N) * s * cos(35°)
Now we can solve for s, the distance the block travelled.
s = (97.4 J) / (11.37 N * cos(35°))
The final answer will be in meters.
Should genetic genealogy be used to solve crimes ? Yes or no and why?
Answers
Answer:
yes
Explanation:
because it will help find who did the crime and it can also open jobs and opportunities for the people who likes sicnenae
In a 2X4X3 factorial design, how many levels does the second independent variable have?
Answers
Answer:
The second independent variable in a 2x4x3 factorial design has 4 levels.
Explanation:
Exercising helps reduce?
Answers
Answer:
stress,depression and anxiety by improving self esteem.
Planets A and B have the same size, but planet A is half the mass of planet B.
Which statement correctly explains the weight you would experience on each
planet?
A. You would weigh the same on both planets because the planets
are the same size.
B. You would weigh less on planet A because it has less mass than
planet B.
C. You would weigh the same on both planets because your mass
would be the same on both.
D. You would weigh more on planet A because it has less mass than
planet B.
Answers
Answer:
B
Explanation:
The more mass an object has, the more gravity it has.
The statement which correctly explains the weight you would experience on each planet is: B. You would weigh less on planet A because it has less mass than planet B.
Weight can be defined as the force acting on a body or an object as a result of gravity.
Mathematically, the weight of an object is given by the formula;
\(Weight = mg\)
Where;
m is the mass of the object.g is the acceleration due to gravity.Hence, we can deduce that the weight and gravity acting on an object is highly dependent on the mass of an object.
Therefore, the higher the mass in a planet, the higher the gravity existing there.
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An electron with a velocity of 14.4 m/s in the positive y-direction enters a region where there is a uniform electric field of 201 N/C in the positive x-direction. The mass of the electron is 9.109 × 10−31 kg.
What is the y-component of the electron’s displacement 2.40 μs after entering the electric-field region if no other forces act on it in μm?
What is the x-component of the electron’s displacement 2.40 μs after entering the electric-field region if no other forces act on it in m?
Answers
1. The electron experiences acceleration and moves independently in the y-direction.
2. The y-component of the electron's displacement after 2.40 μs in the electric field is -8.11 μm.
3. The x-component of displacement remains zero.
To calculate the y-component and x-component of the electron's displacement, we need to consider the motion of the electron in the electric field. Let's break it down step by step:
1. Acceleration of the Electron:
The electric field causes a force on the electron given by the equation: F = qE, where F is the force, q is the charge of the electron, and E is the electric field.
Since the charge of an electron is -1.6 × \(10^-^1^9\) C, and the electric field is 201 N/C, we can calculate the force:
F = (-1.6 × \(10^-^1^9\)C) * (201 N/C)
= -3.216 × \(10^-^1^7\) N
Using Newton's second law, F = ma, we can find the acceleration (a) of the electron:
a = F / m
= (-3.216 × \(10^-^1^7\) N) / (9.109 ×\(10^-^3^1\) kg)
= -3.530 × \(10^1^3 m/s^2\)
2. Displacement in the y-direction:
Since no other forces act on the electron, its motion in the y-direction is independent of the electric field. The equation for displacement (y) under constant acceleration is:
y = (1/2) * a *\(t^2\)
Substituting the values, where the time (t) is 2.40 μs (2.40 ×\(10^-^6\) s), we can calculate the y-component of displacement:
y = (1/2) * (-3.530 ×\(10^1^3 m/s^2\)) * (2.40 ×\(10^-^6 s)^2\)
= -8.11 μm
Therefore, the y-component of the electron's displacement 2.40 μs after entering the electric-field region is -8.11 μm.
3. Displacement in the x-direction:
Since the electron's velocity is only in the y-direction initially, the x-component of the displacement remains zero. Without any forces acting in the x-direction, the electron continues to move in the y-direction without changing its x-position.
Hence, the x-component of the electron's displacement 2.40 μs after entering the electric-field region is 0 meters.
Please note that the calculations provided are based on the given values and the provided formulas for displacement and acceleration.
For more such information on: acceleration
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An 11-kg bowling ball traveling at 3.6 m/s, a 450-g soccer ball traveling at 22.0 m/s, and a 14-g tennis ball traveling at 42 m/s. Which object has the most kinetic energy?
Answers
Answer:
Object with the mass 14g
Explanation:
First object-K.E=1/2mv²
1/2×11×3.6²
=71.28J
Second object- K.E=1/2×0.45×22²
K.E=108.90J
Third object- K.E=1/2×0.014×42²
K.E=12.35J
So second object has the highest kinetic energy
Describe how the force between two charged objects changes as the objects move closer to each other
Answers
Answer:
the electrical force between two charged objects is inversely related to the distance of separation between the two objects. Increasing the separation distance between objects decreases the force of attraction or repulsion between the objects. And decreasing the separation distance between objects increases the force of attraction or repulsion between the objects. Electrical forces are extremely sensitive to distance.
A spaceship hovering over the surface of Venus drops an object from a height of 33 m. How much longer does it take to reach the surface than if dropped from the same height on Earth? Neglect air resistance in both cases. [The acceleration due to gravity on Venus is 90.7% of that on Earth,
gVenus = (0.907)g.]
Answers
Andres buys a new scooter. He goes 8 Km north from the beach. He then
travels 5 Km to the east. Then chases a friend 8 Km north. What distance
did he cover?
What was Andres's displacement?
Answers
Answer:
Distance: 21km
Displacement: ~16.76km
a girl whose mass is 40kg walk up a flight of 20steps each 15mm hight in 10seconds.find power developed by the girl showing the solution
Answers
Answer: Approximately 11.76 joules per second
=========================================================
Work Shown:
Mass = 40 kg
Force pulling down = (mass)*(gravity) = 40*9.8 = 392 newtons
Roughly 392 newtons of force are pulling down on her.
To climb the steps, she must apply 392 newtons of force upward.
---------------
Displacement = 20*(15 mm) = 300 mm = 0.3 m
Work = Force*Displacement
Work = 392*0.3
Work = 117.6 joules of energy
---------------
Power = (Work)/(Time)
Power = (117.6 joules)/(10 seconds)
Power = (117.6/10) joules per second
Power = 11.76 joules per second, which is approximate
While you push a box you begin to decrease the force you are exerting on the box. When will the box reach equilibrium?
A. When the force you are exerting on the box is equal to 0.
B. When Fyou on box = -Fbox on you.
C. When the force of the box becomes Fyou on box < Fbox on you
D. The box will never reach equilibrium.
Answers
The application of a force on the box overcomes the friction and causes the box to accelerate
While the force is decreasing, the box will stabilize;
B. When \(\underline{F_{you \, on \, box} = -F_{box \, on \, you}}\)Reason:
Newton's third Law of Motion states that action and reaction are equal in magnitude and opposite in direction
When the box is pushed with a force, \(F_{you \, on \, box}\), the reaction of the box of mass, m, is as follows;
\(F_{you \, on \, box}\) = \(F_{friction}\) + m × accelerationWhere;
\(F_{friction}\) = \(-F_{box}\) for example
The negative sign is due to the direction of the friction force, or \(F_{box}\) is opposite to the direction of the applied force
When the force is decreased to F₂ = \(F_{you \, on \, box}\), such that we have;
\(F_{you \, on \, box}\) = \(-F_{box \, on \, you}\) , which is the condition for equilibrium, and the net
force is zero and according to Newton's first law of motion, the box moves
at constant speed no acceleration
Therefore the box will reach equilibrium when;
\(\mathbf{\underline{F_{you \, on \, box} = -F_{box \, on \, you}}}\)Learn more about equilibrium here;
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Answer:
When the force you are exerting on the box is equal to 0
Explanation:
Once again expert verifiers are sabotaging people here is the actual answer.
A golf ball is hit so that it leaves the club face at a velocity of 45m/s at an angle of 40° to the horizontal. by ignoring the effect of air resistance and spin on the ball, use the information to answer the question (a) to (d).
a) Calculate the horizontal component of the velocity
b) Determine the vertical component of the velocity.
c) Find the time taken for the ball to reach its maximum height.
d) Calculate the horizontal distance travelled when the ball is at its maximum height.
Answers
Answer:a)45cos40 b)45sin40 c) 2.95 d)102
Explanation:
a) \(v_{x} = 45 cos40\)
b) \(v_{y}=45sin40\)
c) Since air resistance is negligible, the only force acting on the golf ball is gravity. Thus, its vertical acceleration is -g. We know the final velocity must be 0 m/s, because this will be when the golf ball reaches the maximum height and starts to change direction (it falls back to the ground). We also know initial velocity in the vertical direction (see part b). Thus, we can use this equation: \(v_{f} = v_{i} + at\).
\(0 m/s = 45sin40 + (-9.8m/s^2)t\\t = 2.95s\)
d) The horizontal distance traveled is dependent on (1) how long the ball is in the air and (2) what the horizontal velocity is. (1) was found in part c, and (2) was found in part a.
\(x=vt\\x=45cos40(2.95) =102m\)