Answer:
True
Step-by-step explanation:
1/200=0.005
Hope It Helps
Sorry If I'm Wrong
A population of values has a normal distribution with μ = 245.3 and σ = 96 . You intend to draw a random sample of size n = 50 . Find the probability that a single randomly selected value is greater than 246.7. P(X > 246.7) = 0.0146 Incorrect Find the probability that a sample of size n = 50 is randomly selected with a mean greater than 246.7. P(M > 246.7) = Enter your answers as numbers accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
Answer:
0.4589
Step-by-step explanation:
We solve using z score formula
The z score formula for a random number of samples is:
z = (x-μ)/σ/√n, where x is the raw score, μ is the population mean, and σ is the population standard deviation
Hence:
z = 246.7 - 245.3/96/√50
z = 0.10312
Probability value from Z-Table:
P(x<246.7) = 0.54107
P(x>246.7) = 1 - P(x<246.7) = 0.45893
Approximately to 4 decimal places = 0.4589
The probability that a single randomly selected value is greater than 246.7 is 0.4589
What is the value of the "3" in the number 17,436,825? A. 30,000 B. 300,000 C. 3,000 D. 300
Answer:
30,000
Step-by-step explanation:
3 is in the place value of 5 over from the decimal. This means the place value is 30,000
Answer:
Step-by-step explanation:
A
A sampling frame a. is a list of population elements from which the sample will be drawn. b. is the list of population elements actually included in the sample. c. usually provides biased statistics. d. is a form of probability sampling.
Answer:
A. is a list of population elements from which the sample will be drawnStep-by-step explanation:
Sampling frame is the list of people or items from which a sample is taken.
Sampling is used because it is almost impossible to study entire population. Sampling allows us to find information about a population on the basis of results from a subset of the population, without studying every individual. It is easier and cost effective process.
A sampling frame refers to A. a list of population elements from which the sample will be drawn.
Sampling frame simply means the actual set of units from where the sample will be drawn.A sampling frame consists of all the items that are in the population. Therefore, a sampling frame is a list of population elements from which the sample will be drawn.Read related link on:
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Find the value of x that would make p the incenter of the triangle. x = find the value of x that would make p the circumcenter of the triangle. x =
The solutions are,
x = 7° is the value of x that will make P the triangle's incenter.
P, the circumcenter of the triangle, is made by the value of x, which is x = 6°.
Given condition;
The triangle has a point of concurrency at P. Find the value of x that would make P the incenter of the triangle. x = Find the value of x that would make P the circumcenter of the triangle;
To know the values and relations;
Incenter of a triangle:
A triangle's incenter is the point at which its circumscribed circle is at its center.
Given that x determines P, the triangle's incenter, we may calculate the following;
(3x + 3) = 24 x = 21/3 = 7.
x = 7° is the value of x that will make P the triangle's incenter.
Triangle circumcenter:
The triangle's circumcenter is the center of the circle that encircles the triangle.
As a result, the distance between P and the vertices is equal to the radius of the circle circumscribed by,
(5x - 4) = 26 x = 30/5 = 6
P, the circumcenter of the triangle, is made by the value of x, which is x = 6°.
Hence,
The value of x that will make the P the incenter of the triangle is x = 7°
The value of x, which makes P, the circumcenter of the triangle, is x = 6°
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Problem 18 Last summer, Lisa and her family went on vacation. They drove from their home to Florida. They drove four days, about 540 miles each day. About how many miles did they drive altogether?
Answer:
2160
Step-by-step explanation:
Distance covered per day =540miles
Number of days travelled = 4 days
Therefore,the mil we s travelled altogether= 540×4= 2160
Please help! Correct answer only!
For a fundraiser, there is a raffle with 100 tickets. One ticket will win a $150 prize, and the rest will win nothing. If you have a ticket, what is the expected payoff?
$ ___
Answer:
Expected Payoff ⇒ $ 1.50 ; Type in 1.50
Step-by-step explanation:
Considering that 1 out of the 100 tickets will have a probability of winning a 150 dollar prize, take a proportionality into account;
\(100 - Number of Tickets,\\1 - Number of Tickets You Can Enter,\\\\1 / 100 - Probability of Winning,\\$ 150 - Money Won,\\\\Proportionality - 1 / 100 = x / 150, where x - " Expected Payoff "\\\\1 / 100 = x / 150,\\100 * x = 150,\\\\Conclusion ; x = 1.5 dollars\)
Thus, Solution ; Expected Payoff ⇒ $ 1.50
1. If f(x) = (3x-2)/(2x+3), then f'(x) =
Answer:
\(f'(x)= \frac{13}{(2x+3)^2}\\\)
Step-by-step explanation:
\(f(x)= \frac{3x-2}{2x+3} \\\)
\(f'(x)=\frac{dy}{dx} = \frac{d}{dx}(\frac{3x-2}{2x+3})\\ f'(x)= \frac{(2x+3)\frac{d}{dx}(3x-2)-(3x-2)\frac{d}{dx}(2x+3) }{(2x+3)^{2} } \\f'(x)= \frac{(2x+3)(3)-(3x-2)(2)}{(2x+3)^{2} } \\\)
\(f'(x)= \frac{6x+9-6x+4}{(2x+3)^{2} }\\ f'(x)= \frac{13}{(2x+3)^2}\\\)
a dish has 1 yellow, 1 red, 2 green and 6 blue m&m’s. a person randomly selects 3. Let X count the number of different colors in the selection. Compute E(X). Please find a way of computing this expected value without deriving the distribution of X.
The value of E(x) for the X count the number of blue colours in the selection is 9/5 and for the Y count the number of different colours in the selection is 25/3.
What is permutation and combination?
Permutations and combinations are the several ways that items from a set can be chosen, usually without replacement, to generate subsets. When order is a factor in the subset selection, it is referred to as a permutation; when it is not, it is referred to as a combination.
As per question given,
Given that a dish has 1 yellow, 1 red, 2 green and 6 blue m&ms.
A person randomly selected 3.
X count the number of blue colours in the selection:
So possible value of X are 0, 1, 2, 3
Total colours = 1 + 1 + 2 + 6 = 10
So, P (x = 0) = ⁴C₃ / ¹⁰C₃
= 4 / 120
Similarly, P (x = 1) = (⁴C₂ × ⁶C₁) / ¹⁰C₃
= 36 / 120
Similarly, P (x = 2) = (⁴C₁ × ⁶C₂) / ¹⁰C₃
= 60 / 120
Similarly, P (x = 3) = (⁶C₃) / ¹⁰C₃
= 20 / 120
Compute, E(x) = ∑ xi P(xi)
So, E(x) = (40 / 120) × 0 + (36 / 120) × 1 +(60 / 120) × 2 +(20 / 120) × 3
E(x) = 0 + (36 / 120) + (60 / 60) + (20 / 40)
E(x) = 0 + 3 / 10 + 1 + 1 / 2
E(x) = 9 / 5
Y count the number of different colours in the selection:
= Total selection - all same colour selection
= ¹⁰C₃ - ⁶C₃
= 120 - 20
= 100
So,
P = 100 / 120
P = 5 / 6
From Binomial distribution Mean is nP.
E (4) = nP
Now P = 5 / 6 and n = 10
Substitute values respectively,
E (4) = 10 × 5 / 6
E (4) = 25 / 3
Hence, the value of E (4) is 25 / 3.
Hence, the value of E (x) for the X count the number of blue colours in the selection is 9/5 and for the Y count the number of different colours in the selection is 25 / 3.
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The position of a particle as a function of time is given by x=(6m/s)t+(−2m/s2)t2.A) Find the average velocity of the particle from t=0 to t=1s.B) Find the average speed from t=0 to t=1s.
A) The average velocity of the particle from t=0s to t=1s is 4 m/s.
B) The average speed from t=0s to t=1s is 4 m/s.
The position of a particle as a function of time is given by x=(6m/s)t+(−2m/s²)t².
A) To find the average velocity of the particle from t=0 to t=1s, we can use the formula:
average velocity = change in position / change in time
The change in position from t=0 to t=1s is:
x(1s) - x(0s) = [(6m/s)(1s) + (-2m/s²)(1s)²] - [(6m/s)(0s) + (-2m/s²)(0s)²]
= 4m
The change in time is:
1s - 0s = 1s
Therefore, the average velocity is:
average velocity = change in position / change in time = 4m / 1s = 4m/s
B) To find the average speed from t=0 to t=1s, we need to find the total distance traveled by the particle from t=0 to t=1s. The distance traveled is the magnitude of the change in position, which is always positive. Therefore, we can use the formula:
average speed = total distance traveled / change in time
The total distance traveled from t=0 to t=1s is:
| x(1s) - x(0s) | = | [(6m/s)(1s) + (-2m/s²)(1s)²] - [(6m/s)(0s) + (-2m/s²)(0s)²] |
= | 4m | = 4m
Therefore, the average speed is:
average speed = total distance traveled / change in time = 4m / 1s = 4m/s
Note that the average velocity and average speed are the same in this case because the particle is moving in a straight line and its displacement and distance traveled are in the same direction.
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Hector wants to tile his rectangular shed floor with rubber tiles. He found a company that will cut custom tiles up to 60 inches by 60 inches. The length of his shed floor is 240 inches, and the width is 144 inches. A-what is the side length of the largest square tile Hector can use to tile his shed floor so that there are no gaps or overlaps and the entire floor is covered? B-How many floor tiles will Hector need to cover his shed floor? HURRY PLEASE. ANSWER BOTH!!
Answer:
A- The side length of the largest square tile Hector can use to tile his shed floor so that there are no gaps or overlaps is 48 inches
B- The number of square tiles Hector will need is 15 tiles
Step-by-step explanation:
A- The given parameters are;
The size of the tiles cut by the company he found = 60 inches × 60 inches
The length of his shed floor = 240 inches
The width of his shed floor = 144 inches
The side length of the largest square tile is given as the highest common factor, HCF of 240 and 144 given as follows;
144/240 = 3/5
Therefore, we have the highest common factor of 144 and 240 = 144/3 = 48
Therefore, the side length of the largest square tile Hector can use to tile his shed floor so that there are no gaps or overlaps = 48 inches
B- The area of his shed floor = 240 inches × 144 inches = 34560 in.²
The area of one square tile = 48 inches × 48 inches = 2,304 in.²
The number of square tiles, n, Hector will need is given as follows;
The number of square tiles Hector will need = (The area of his shed floor)/(The area of one square tile)
The number of square tiles Hector will need = n =34560 in.²/(2,304 in.²) = 15
The number of square tiles Hector will need = 15 tiles.
ahh help me please! I’m doing a test so right answers only please! tysm.
Answer:
The answer is B.
Step-by-step explanation:
find the zeros of the function: g(x)=(x -2)(3x +3)
Answer:
x = 2 and x = -1
Step-by-step explanation:
The zeroes of the function are found by setting g(x) equal to 0:
g(x) = (x - 2)(3x + 3) = 0
By the Zero Product Property, in order for this equation to be equal to 0, each of (x - 2) or (3x + 3) or both has to equal 0. So, set each equal:
x - 2 = 0
x = 2
3x + 3 = 0
3x = -3
x = -3/3 = -1
The zeroes are thus x = 2 and x = -1.
~ an aesthetics lover
Answer:
x=2 x=(-1)
Step-by-step:
Solve: (x-2)(3x+3)=0
= x-2=0 3x+3=0
=x-2(+2)=0(+2) =3x-3(-3)=0(-3)
=x=2 =3x=(-3)
=3x/3=(-3)/3
=x=(-1)
For each equation determines whether y is a funcation of x
All linear relations are functions
The quadratic equations can be a function if we restrict the domain of it
The given relations are
\(x=-9y\)This is a linear relation, then it is a function, we can put it in the form
\(y=-\frac{1}{9}x\)\(y=8x\)This is a linear relation, then it is a function
\(x+3y=6\)This is a linear relation, then it is a function, we can put it in the form
\(y=\frac{6-x}{3}\)\(x=2y^2-3\)We will put it in the form of y as a subject
\(y^2=\frac{x+3}{2}\)To find y we will take square root for both sides
\(\begin{gathered} \sqrt[]{y^2}=\pm\sqrt[]{\frac{x+3}{2}} \\ y=\pm\sqrt[]{\frac{x+3}{2}} \end{gathered}\)That means each value of x has 2 values of y, then
This can not be a function
Assuming that all years have 365 days and all birthdays occur with equal probability, how large must n be so that in any randomly chosen group of n people, the probability that two or more have the same birthday is at least 1/2?
it is seen that if the number of people in the group is n = 23, the probability that at least two people will have the same birthday is at least 1/2.
Let P(A) be the probability that in a randomly selected group of n people, at least two people have the same birthday.
If we assume that the year has 365 days, then the number of ways to select n people with different birthdays is n x (n-1) x (n-2) x ... x (n-364).
the probability of selecting n people with different birthdays is P(A') = n(n - 1)(n - 2)...(n - 364)/365nThen, the probability that at least two people in a group of n have the same birthday is given by P(A) = 1 - P(A').
We need to find the smallest value of n such that P(A) ≥ 1/2.Let's solve for this.Let us find n such that P(A) ≥ 1/2.
By using the complement rule, 1-P(A') = P(A).Then:1 - n(n - 1)(n - 2)...(n - 364)/365n ≥ 1/2n(n - 1)(n - 2)...(n - 364)/365n ≤ 1/2(2)n(n - 1)(n - 2)...(n - 364) ≤ 365n/2Now, take the natural logarithm of both sides and simplify as follows:ln[n(n - 1)(n - 2)...(n - 364)] ≤ ln[365n/2]nln(n) - ln[(n - 1)!] - ln[(n - 2)!] - ... - ln[2!] - ln[1!] ≤ ln[365n/2]
Therefore, we need at least 23 people in the group for the probability of two or more people having the same birthday to be at least 1/2.
This is because n = 23 is the smallest number for which the inequality holds, and therefore, it is the smallest number of people required to ensure that the probability of two or more people having the same birthday is at least 1/2.
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when calculating the variance, why must the deviations from the mean be squared? group of answer choices the deviations from the mean must be squared so that their sum is not greater than 100%. the deviations from the mean must be squared so that their sum is not equal to zero. the deviations from the mean must be squared so that their sum is not negative. the deviations from the mean are squared so that their sum is equal to zero.
Deviations from the mean must be squared so that their sum is not equal to zero.
The variance can be calculated using the following formula:
Variance = Sum of squared deviations from the mean / number of observations.
Deviations from the mean are calculated by subtracting the mean from each observation. Deviations can be negative or positive, depending on whether an observation is above or below the mean.
Now, coming back to the question, the reason why deviations from the mean must be squared when calculating variance is that the sum of deviations will always be zero. That means, the sum of negative deviations will cancel out the sum of positive deviations. So, to avoid that, we square each deviation, which makes them all positive. This way, we can avoid the cancellation of negative and positive deviations.
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Question 73
Show that x^-1 - y^-1/ x-y = -1/xy
where x is not equal to 0, y is not equal to 0 and y is not equal to x
Answer:
see explanation
Step-by-step explanation:
using the rule of exponents
\(a^{-1}\) = \(\frac{1}{a}\)
\(\frac{x^{-1}-y^{-1} }{x-y}\)
= \(\frac{\frac{1}{x}-\frac{1}{y} }{x-y}\)
= \(\frac{\frac{y-x}{xy} }{x-y}\)
= \(\frac{-(x-y)}{xy}\) × \(\frac{1}{x-y}\) ← cancel (x - y) on numerator and denominator
= - \(\frac{1}{xy}\)
PLEASE HELP
PLEASE HELP
solve
Answer:
the answer is 32 S=32
Step-by-step explanation:
you have to find s right so you do 162-130 =32 or 130+32=162...
divide 2x²+5x+2 by 2x+1
Step-by-step explanation:
hope it helps you mark me as brainlist
Please help me, the attachment is below. (If you don't know the answer to the question please don't answer)
Answer:
Step-by-step explanation:
The three angles of a triangle always have to equal 180 in the end, so if you use the method which is the 4 in this instance, it is an obtuse angle that is equal to the top and left angle. You can add 1 and 2 to get 4, and do 4-3 to get 1+2, So, 4=1+2.
Select all the irrational numbers. *
1 point
A.6
B.-49
C.-1,405
D-0..3
E.e
F.2
Answer:
plz explain
Step-by-step explanation:
Darryl wants to add enough water to 8 gallons of a 10% bleach solution to make a 5% bleach solution. which equation can he use to find x, the number of gallons of water he should add? original (gallons) added (gallons) new (gallons) amount of bleach 0.8 0 0.8 amount of solution 8 x 8 x startfraction 0.8 over 8 x endfraction times startfraction 5 over 100 endfraction = 1 startfraction 0.8 over 8 x endfraction times = startfraction 5 over 100 endfraction startfraction 0.8 over 8 x endfraction = startfraction 100 over 5 endfraction startfraction 0.8 over 8 x endfraction divided by startfraction 5 over 100 endfraction = 1
0.80 = (x + 8)(0.05) is the equation used to find x.
Given,
Darryl has a solution of bleach with the concentration of 10%.
10% bleach solution means in 100 ml solution amount of bleach is 10 gm
Here,
Darryl wants to change the concentration of this solution to 5%, means he wants to add water so that amount of liquid will change but amount of bleach in grams will remain the same.
Amount of bleach in 8 gallons of 10% solution of bleach will be = (Volume)×(concentration) = 8(.10) gm
Let Darryl adds x gallons of water in 10% solution of bleach to make it 5% solution of bleach.
Amount of bleach in 5% solution of bleach = (x + 8)(0.05) gm
Now in both the concentrations of bleach solution amount of bleach will remain same.
So, 0.8 = (x + 8)(0.05) will be the equation from which he can find the value of x.
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i’m doing my geometry homework with the equation 1/2h(b1+b2) but i can’t figure this one out. please help
Answer:
Step-by-step explanation:
to find the bottom base you add the two numbers that make it
5+18=23
now put everything in the formula
\(\frac{1}{2}*12(12+23)\\\)
parathesis first
12+23=35
\(\frac{1}{2} *12*35\)
multiply in order
6*35
210
Step-by-step explanation:
i’m doing my geometry homework with the equation 1/2h(b1+b2) but i can’t figure this one out. please help
1/2h (b1 + b2) is the formula for finding the area of the figure (trapezoid)
1/2 * 12 (18 + 5 + 12)=
6 * 35=
210 units²
Farmer Ed has 3,000 meters of fencing. and wants to enclose a reclangular plot that borders on a river. If Famer Ed does nat fence the side along the river, What is the largest area that can be enclos
Farmer Ed has 3,000 meters of fencing and wants to enclose a rectangular plot that borders on a river.The largest area that can be enclosed is 750,000 square meters.
What is the largest area that can be enclosed?To get the largest area that can be enclosed, we have to find the dimensions of the rectangular plot. Let's assume that the width of the rectangle is x meters.The length of the rectangle can be found by subtracting the width from the total length of fencing available:L = 3000 - x. The area of the rectangle can be found by multiplying the length and width:Area = L × W = (3000 - x) × x = 3000x - x²To find the maximum value of the area, we can differentiate the area equation with respect to x and set it equal to zero.
Then we can solve for x: dA/dx = 3000 - 2x = 0x = 1500. This means that the width of the rectangle is 1500 meters and the length is 3000 - 1500 = 1500 meters.The area of the rectangle is therefore: Area = L × W = (3000 - 1500) × 1500 = 750,000 square meters. So the largest area that can be enclosed is 750,000 square meters.
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2. Write the algebraic phrases that correspond to the following word phrases: (a) The sum of four times the opposite of a number and - 5 (b) The product of 5 and the sum of 3 times a number and 4
Considering the definition of an algebraic expression, The algebraic expression of the word pharses are:
(a) 4×(-x) + (-5)
(b) 5×(3x + 4)
Definition of an algebraic expressionAn algebraic expression is a combination of numbers and letters related to each other by mathematical operations. Usually, the letters represent unknown quantities and are called variables or unknowns.
Algebraic expression in this caseIn this case, you know:
(a) The sum of four times the opposite of a number and - 5
(b) The product of 5 and the sum of 3 times a number and 4
The algebraic expression of the word pharses are:
(a) 4×(-x) + (-5)
(b) 5×(3x + 4)
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help I will give brainliest if you do everything
Suppose that A is an n x n diagonal matrix with rank r, where rsn. Which of the following is true about
A?
A. O is an eigenvalue with algebraic muitiplicity n-r
B. O is an eigenvalue, but there is not enough information to determine the geometric multiplicity
C O is an eigenvalue with geometric multiplicity ner
DO is not an eigenvalue.
A is an n x n diagonal matrix with rank r , where rsn and the statement (a)"O is an eigenvalue with algebraic muitiplicity n-r " about A is true
Since A is an n x n diagonal matrix with rank r, the number of non-zero entries on the diagonal is r. This means that there are n - r zero entries on the diagonal.
For any diagonal matrix, the eigenvalues are simply the entries on the diagonal. Since there are n - r zero entries, the eigenvalue O has a geometric multiplicity of n - r.
Therefore, the correct statement is that O is an eigenvalue with geometric multiplicity n - r.
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Consider three pallet locations A, B, and C, for which the travel time from the receiving area to the storage area is 1, 2, and 2 minutes, respectively. Two skus move through these locations, x and y, which must be managed strictly through a PEPS policy. Every three days a pallet of SKU "x" is dispatched in the morning and a pallet is received in the afternoon and stored. Every two days a pallet of SKU "y" is dispatched in the morning and a pallet is received in the afternoon and stored. You maintain a constant inventory of one pallet of SKU x and two pallets of SKU y at all times.
a. If you are using a static storage policy, what is the allocation of SKUs to storage locations that minimizes labor? Justify your answer. What is the average number of minutes per day spent moving these products?
b. What is the lowest value of average minutes per day used to move these SKUs if you adopt a heap policy? Does it make a difference where I place the SKUs initially?
A. The average number of minutes per day spent moving these products using the static storage policy is 1.33 minutes.
B. The lowest value of average minutes per day used to move these SKUs with the heap policy is approximately 1.17 minutes per day. The initial placement of the SKUs does make a difference in determining the lowest average movement time, as shown by the difference between Scenario 1 and Scenario 2.
a. Static Storage Policy:
To minimize labor, we can allocate the SKUs to storage locations based on their respective travel times from the receiving area to the storage area. In this case, the travel times are 1 minute for location A, 2 minutes for location B, and 2 minutes for location C.
Given that we maintain a constant inventory of one pallet of SKU x and two pallets of SKU y at all times, we can allocate them as follows:
SKU x: Allocate it to the storage location with the shortest travel time, which is location A (1 minute).
SKU y: Allocate both pallets to the storage location with the next shortest travel time, which is location B or C (both have a travel time of 2 minutes).
By allocating SKU x to location A and both pallets of SKU y to either location B or C, we ensure that the SKUs are stored in the closest available locations, minimizing the travel time needed to move them.
The average number of minutes per day spent moving these products can be calculated by considering the dispatch and receiving schedule:
SKU x: Dispatched every three days. Assuming it takes 1 minute to move a pallet from storage to the receiving area, the average daily movement time for SKU x would be (1/3) minutes per day.
SKU y: Dispatched every two days. Assuming it takes 2 minutes to move a pallet from storage to the receiving area, the average daily movement time for SKU y would be (2/2) minutes per day.
Adding up the average daily movement times for SKU x and SKU y, we get:
Average daily movement time = (1/3) + (2/2) = 1.33 minutes per day.
Therefore, the average number of minutes per day spent moving these products using the static storage policy is 1.33 minutes.
b. Heap Policy:
The heap policy involves storing the most frequently dispatched SKU closest to the receiving area. In this case, SKU y is dispatched every two days, while SKU x is dispatched every three days.
To find the lowest value of average minutes per day used to move these SKUs with the heap policy, we need to consider the different initial placements of the SKUs.
Scenario 1: Initial Placement - Location A for SKU x and Location B for SKU y
SKU x: Travel time from storage to the receiving area = 1 minute
SKU y: Travel time from storage to the receiving area = 2 minutes
Average daily movement time:
SKU x: (1/3) minutes per day
SKU y: (2/2) minutes per day
Total average daily movement time = (1/3) + (2/2) = 1.33 minutes per day
Scenario 2: Initial Placement - Location A for SKU y and Location B for SKU x
SKU y: Travel time from storage to the receiving area = 1 minute
SKU x: Travel time from storage to the receiving area = 2 minutes
Average daily movement time:
SKU y: (1/2) minutes per day
SKU x: (2/3) minutes per day
Total average daily movement time = (1/2) + (2/3) ≈ 1.17 minutes per day
Therefore, the lowest value of average minutes per day used to move these SKUs with the heap policy is approximately 1.17 minutes per day. The initial placement of the SKUs does make a difference in determining the lowest average movement time, as shown by the difference between Scenario 1 and Scenario 2.
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Someone help me I’m confused? I only have 20 minutes till the timer runs our
A researcher found a study relating the distance a driver can see, y, to the age of the driver, When researchers looked at the association of x and y, they found that the coefficient of determination was =0.542. Select two conclusions that the researcher can make from this data. a.) The correlation coefficient, t, is-0 458. b.) About 54% of the variation in distance that the driver can see is explained by a linear relationship with the driver's age. c.) About 74% of the variation in the driver's age is explained by a linear relationship with the distance that the driver can see d.) The correlation coefficient, t.is -0736. e.) About 46% of the variation in distance that the driver can see is explained by a linear relationship with the driver's age.
Two conclusions that the researcher can make from the coefficient of determination of 0.542 are:
b.) About 54% of the variation in distance that the driver can see is explained by a linear relationship with the driver's age.
e.) About 46% of the variation in distance that the driver can see is not explained by the linear relationship with the driver's age, and may be due to other factors.
Option a is incorrect because the question does not provide the correlation coefficient. Option c is incorrect because the coefficient of determination does not provide information about the variation in the driver's age. Option d is also incorrect because the provided value does not match with any possible correlation coefficient for this situation.
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a ball is dropped to the ground from a certain height. the expression 25(0.93)x what is the percent of change in the height of the ball after each bounce?
The percent change in height after the second bounce would be:
Percent change = [(h_2 - h_1) / h_1] * 100%
The expression \(25(0.93)^x\)represents the height of the ball after x bounces. To find the percent change in height after each bounce, we need to calculate the ratio of the change in height to the original height and express it as a percentage.
Let's denote the height after the first bounce as h_1, the height after the second bounce as h_2, and so on.
The percent change in height after the first bounce is given by:
Percent change = [(h_1 - original height) / original height] * 100%
Using the given expression, we can substitute x = 1 to find h_1:
h_1 = \(25(0.93)^1\) = 23.25
Therefore, the percent change in height after the first bounce is:
Percent change = [(23.25 - original height) / original height] * 100%
To find the percent change after subsequent bounces, we can continue this process. For example, after the second bounce:
h_2 = \(25(0.93)^2\)
And the percent change in height after the second bounce would be:
Percent change = [(h_2 - h_1) / h_1] * 100%
You can repeat this process for each subsequent bounce to find the percent change in height after each bounce using the given expression.
To learn more about percentages refer to:
brainly.com/question/843074
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